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Lorentz transforms physical incoherence
_______________________________________ (Based on an example presented by Daryl McCullough) We assume that a rocket is moving at speed v = 0.866 c relative to the Earth, and we want to know what is the relationship between the coordinates of an event, in the frame of the Earth, and the coordinates of the same event, in the frame of the rocket. We assume that the rocket passes the Earth at an event with Earth-coordinates tR=0, xR=0 and with rocket-coordinates tR'=0, xR'=0. (The primed variables are observed in the rocket frame). Let's pick an event E, in this case an explosion, that takes place on a planet, at rest relatively to the Earth. The planet is situated at a distance xE form the Earth, and the explosion is observed after a time interval tE, hence the Earth coordinates of the event E are (xE, tE), and the corresponding rocket coordinates are (xE', tE'). For simplicity, let's assume that the Earth, the planet, and the rocket are all lined up, so that we only need to consider the x-axis. In this scenario, the distances are expressed in light-years (ly), and the times in years. After a time interval T, the rocket will be at a distance v*T from the Earth, hence the distance between the rocket and the event E is D = xE-vT. In the rocket frame, the corresponding distance is D' = D/gamma (as v = 0.866 c, gamma = 1/sqrt(1-v^2/c^2) = 2). Let xE = 3 ly and tE = 5 years. Examples: 1) After a time interval T = xE/v, D = 0 and D' = 0. Let's notice that T' = T/gamma. This is always the case, as the ratio T/T' depends on the velocity of the rocket, not on its position. 2) Let's take an arbitrary value T, for instance T = 10 years. From the formula D = xE -vT, we get D = 3-0.866*10 = -5.66 ly, and D' = D/gamma = -2.83 ly. T' = T/gamma = 5 years. 3) Let's take T = 9.608 years. Then D = 3-0.866*9.608 = -5.32 ly D' = D/gamma = -5.32/2 = -2.66 ly Of course, T' = 9.608/2 = 4.804 years. Let's notice that those results have been obtained by applying "Lorentzian" formulae. Now let's use the Lorentz (or rather Einstein) transformations: t' = gamma(t-vx/c^2) and x' = gamma(x-vt) Using the above notation, we get tE' = gamma(tE-v*xE/c^2), thus = 2(5-0.866*3) = 4.804 years D' = gamma(xE-v*tE) = gamma(3-0.866*5) = -2.66 ly, which is exactly the value obtained in example 3, by using T = tE'*gamma = 9.608 years. Thus, gamma(xE-v*tE) = (xE-vT)/gamma. But, in fact, *there is no physical relation between time and position*. When the rocket travels an arbitrary distance v*T wrt the Earth, T' is always given by T/gamma, in other words, T' is independant from v*T. If T = tE = 5 years, T' = 5/2 = 2.5 years, not 4.804 years, and of course, D = xE-v*tE = 3-0.866*5 = -1.33 ly, and D'= D/gamma = -0.665 ly, not -2.66 ly. (notice "en passant" that -0.665*gamma^2 = -2.66) Let's now illustrate the physical incoherence of the Lorentz time transformation tE' = gamma(tE-v*xE/c^2). We have mathematically seen above that gamma (xE-v*tE) = (xE-v*T)/gamma, or gamma^2 (v*tE - xE) = v*T - xE (1) Let's tE = xE/v + delta t, thus delta t = tE - xE/v v*delta t = v*tE - xE Replacing (v*tE - xE) by v*delta t in relation (1), one gets gamma^2 * v*delta t = v*T - xE v*T = xE + gamma^2 * v*delta t T = xE/v + gamma^2 * delta t, T = xE/v + gamma^2 * (tE - xE/v) (2) And indeed, with xE=3, tE=5 and gamma=2, equation (2) leads to T = 3/0.866 + 4(5 - 3/0.866) = 3.464 + 4(5 - 3.464) = 9.608 years Equation (2) shows that the t' in the Lorentz time transform t' = gamma(t-vx/c^2), expressed in the Earth frame by T = t'*gamma, corresponds to the time tau needed by the rocket to travel the distance xE at the velocity v, increased by the difference between the time coordinate tE of the event E and the time tau, multiplied by the factor gamma^2. If the Lorentz time transformation were coherent, the correction by gamma^2 would also apply to tau, not only to the difference (tE-tau). Indeed, there is no physical justification for not treating homogenously the time coordinate tE. Btw, such fancy correction by gamma^2 leads to absurdities. For instance, when v is close to the speed of light, the time corresponding to the product gamma^2(tE-tau) can exceed the age of the Universe! The incoherence of the Lorenz time transform is very obvious when the event coordinates are (xE=0, tE=5). Then the transform gives T = gamma^2 * tE = 4 * 5 = 20 years, instead of T = 5 years! Marcel Luttgens |
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