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Moonlight physics question



 
 
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  #1  
Old March 18th 05, 11:02 PM
Alex
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Default Moonlight physics question

Today it was sunny. I stood with the sun behind me (and my shadow in
front of me) and looked up and to my right at the moon, which was
approximately half lit up. Imagine the right half were lit, then rotate
anti-clockwise 45 degrees (top left to bottom right).

How's that then?
  #2  
Old March 19th 05, 12:01 AM
Ryan Evans
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Default

His pattern indicates 2-dimensional thinking,
Spock

Imagine the sun directly behind you and the moon directly in front. The
upper part of the moon will be lit.
Now imagine moving left partially around the world(or rotating ccw in place)
keeping the sun behind you. You will see the upper right
of the moon lit.


RE

"Alex" wrote in message
...
Today it was sunny. I stood with the sun behind me (and my shadow in
front of me) and looked up and to my right at the moon, which was
approximately half lit up. Imagine the right half were lit, then rotate
anti-clockwise 45 degrees (top left to bottom right).

How's that then?



  #3  
Old March 19th 05, 02:11 AM
Double-A
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Ryan Evans wrote:
His pattern indicates 2-dimensional thinking,
Spock

Imagine the sun directly behind you and the moon directly in front.

The
upper part of the moon will be lit.
Now imagine moving left partially around the world(or rotating ccw in

place)
keeping the sun behind you. You will see the upper right
of the moon lit.


RE



If the Sun is directly behind you and the Moon is directly in front of
you, then the whole Moon should be lit.

Double-A

  #4  
Old March 19th 05, 02:51 AM
Ryan Evans
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Default

above horizon.

"Double-A" wrote in message
oups.com...

Ryan Evans wrote:
His pattern indicates 2-dimensional thinking,
Spock

Imagine the sun directly behind you and the moon directly in front.

The
upper part of the moon will be lit.
Now imagine moving left partially around the world(or rotating ccw in

place)
keeping the sun behind you. You will see the upper right
of the moon lit.


RE



If the Sun is directly behind you and the Moon is directly in front of
you, then the whole Moon should be lit.

Double-A



  #5  
Old March 19th 05, 06:47 AM
Odysseus
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Default

Alex wrote:

Today it was sunny. I stood with the sun behind me (and my shadow in
front of me) and looked up and to my right at the moon, which was
approximately half lit up. Imagine the right half were lit, then rotate
anti-clockwise 45 degrees (top left to bottom right).


This sort of thing?

http://www.astropix.com/HTML/L_STORY/MOONILL.HTM

How's that then?


Ryan's quote from "Mister Spock" probably sums it up.

--
Odysseus
  #6  
Old March 21st 05, 03:17 AM
Ryan Evans
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Default

Say you're looking perpendicular at a straight fence. The center post would
appear a certain height. The one to the left and the one to the right would
appear a little smaller, since they are farther away. The next outer ones
would apear
smaller yet. So the straight line that is the top or bottom of the fence
would follow an apparent curve.

Let the sun be at the top of the fence way to the right and the moon at the
top of the fence in the middle.


RE


"Odysseus" wrote in message
...
Alex wrote:

Today it was sunny. I stood with the sun behind me (and my shadow in
front of me) and looked up and to my right at the moon, which was
approximately half lit up. Imagine the right half were lit, then rotate
anti-clockwise 45 degrees (top left to bottom right).


This sort of thing?

http://www.astropix.com/HTML/L_STORY/MOONILL.HTM

How's that then?


Ryan's quote from "Mister Spock" probably sums it up.

--
Odysseus



 




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