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Hi group!
Let's say - there was a habitable planet around Alpha Centauri-A - at 1,2 AU - A & B are at closest approach (11,2 AU) - B is at opposition, getting the planet as close as 10 AU to B - A is 90° below the horizon, B is 90° above the horizon At 10 AU Alpha Centauri-B's apparent magnitude is -20,9, which makes it 223 times dimmer than our sun. My question now is what are the light levels like at that time? I mean, we all know what light levels a full moon produces, but what is "223 times dimmer than our sun" like? I witnessed a partial eclipse back in 1999, when the moon covered 99% of the sun where I live. With the sun at ~55° above the horizon it was still pretty bright (clear skies). Compared to that light levels on the planet around Alpha Centauri A would still be 2 times dimmer (magnitude-light levels?), but I guess this means "no night" during that time of the year nevertheless. What do you think (and feel free to correct any mistakes/wrong assumptions)? |
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In article , Mr. 4X wrote:
time? I mean, we all know what light levels a full moon produces, but what is "223 times dimmer than our sun" like? Well, maybe like night in a modern city which has lots of street lights. I heard a statistic recently that normal office lighting is around 1/500th of the brightness of midday sunshine. You could estimate the difference by comparing the settings that an auto-exposure camera gives you. -- Aidan Karley, Aberdeen, Scotland, Location: 57°10'11" N, 02°08'43" W (sub-tropical Aberdeen), 0.021233 |
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