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#1
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Hi
I would like to draw a realistic representation of an elliptical orbit with a simple computer drawing program. Given the semi-major axis and eccentricity, is there a formula that converts these into the lengths of the major and minor axes so that I can enter these values into the the "circle" function to make the ellipse? TIA Marty |
#2
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"Martin Lewicki" wrote in message
... Hi I would like to draw a realistic representation of an elliptical orbit with a simple computer drawing program. Given the semi-major axis and eccentricity, is there a formula that converts these into the lengths of the major and minor axes so that I can enter these values into the the "circle" function to make the ellipse? If a = semimajor axis b = semiminor axis c = half the distance between foci e = eccentricity then a^2 = b^2 + c^2 (True for any conic section orbit) and e = c/a (True for any conic section orbit but the parabola, where c -- infinite) so that b^2 = a^2 - (e*a)^2 b = a*sqrt(1 - e^2) |
#3
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Greg Neill wrote:
"Martin Lewicki" wrote in message ... snip So for a semimajor axis = 2 eccentricity = 0.5 semiminor axis = 1.73205.... Easier just to write "sqrt3". and distance of object (focus 1) from perihelion (q) is a*(1-e) = 1 Correct? Looks good. And don't forget, the aphelion radius is a*(1+e) = 3 units And by way of a 'reality check', you can verify that the sum of the apoapsis and periapsis distances is equal to 2a, the length of the major axis: here 3 + 1 = 4 = 2*2. -- Odysseus |
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