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We compare the mass of the earth to the mass of the sun, and multiply
that ratio by the distance between them. Let the mass of the earth be M_e and the mass of the sun be M_s. Let the distance between them be r. (M_e)r/(M_s)= (5.976E27)(1.495979E13cm)/(1.989E33) =4.495E7cm=449.5km We now divide that result by the radius of the earth, R_e: 449.5km/6378.5k=0.07 Hydrogen is the most abundant element in the universe and nitrogen is the most abundant element in the earth atmosphere. We now compare their molar masses: H/N=1.01/14.01=0.07 And we see that H/N=(M_e)r/(M_s)(R_e) Ian Beardsley |
#2
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Ian Beardsley wrote:
We compare the mass of the earth to the mass of the sun, and multiply that ratio by the distance between them. Let the mass of the earth be M_e and the mass of the sun be M_s. Let the distance between them be r. (M_e)r/(M_s)= (5.976E27)(1.495979E13cm)/(1.989E33) =4.495E7cm=449.5km We now divide that result by the radius of the earth, R_e: 449.5km/6378.5k=0.07 Hydrogen is the most abundant element in the universe and nitrogen is the most abundant element in the earth atmosphere. We now compare their molar masses: H/N=1.01/14.01=0.07 And we see that H/N=(M_e)r/(M_s)(R_e) Ian Beardsley Crank Information http://www.google.com/search?q=numer...Awww.crank.net http://www.csicop.org/cgi-bin/search...i?q=numerology |
#3
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Ian Beardsley wrote:
We compare the mass of the earth to the mass of the sun, and multiply that ratio by the distance between them. Let the mass of the earth be M_e and the mass of the sun be M_s. Let the distance between them be r. (M_e)r/(M_s)= (5.976E27)(1.495979E13cm)/(1.989E33) =4.495E7cm=449.5km We now divide that result by the radius of the earth, R_e: 449.5km/6378.5k=0.07 Hydrogen is the most abundant element in the universe and nitrogen is the most abundant element in the earth atmosphere. We now compare their molar masses: H/N=1.01/14.01=0.07 And we see that H/N=(M_e)r/(M_s)(R_e) Ian Beardsley Crank Information http://www.google.com/search?q=numer...Awww.crank.net http://www.csicop.org/cgi-bin/search...i?q=numerology |
#5
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![]() mystic math Group: sci.astro.amateur Date: Thu, Jul 1, 2004, 9:25pm From: (Ian=A0Beardsley) We compare the mass of the earth to the mass of the sun, and multiply that ratio by the distance between them. Let the mass of the earth be M_e and the mass of the sun be M_s. Let the distance between them be r. (M_e)r/(M_s)=3D (5.976E27)(1.495979E13cm)/(1.989E33) =3D4.495E7cm=3D449.5km We now divide that result by the radius of the earth, R_e: 449.5km/6378.5k=3D0.07 Hydrogen is the most abundant element in the universe and nitrogen is the most abundant element in the earth atmosphere. We now compare their molar masses: H/N=3D1.01/14.01=3D0.07 And we see that H/N=3D(M_e)r/(M_s)(R_e) Ian Beardsley ----------------------------------- Now it becomes mystic. We apply the same concept to mars and get the same result. The most abundant gas in the mars atmophere is CO_2. (H)/(CO_2)=3D 1.01/44.01=3D0.02 M_m=3Dmass of mars, M_s=3Dmass of sun, r =3D the distance between them and= R_m =3D the radius of mars. We have (M_m)r/(M_s)(R_m)=3D0.02 M_m=3D6.418E26g r=3D2.279409E13cm M_s=3D1.989E33g R_m=3D3.393096E8cm (H)/(CO_2)=3D(M_m)(r)/(M_s)(R_m) Keep in mind these equations hold for a solar system that is at its peak as an orderly arrangement of parts. Eventually the order will degenerate. The sun is losing mass every day and therefore r for any of the planets will grow. The data for this study comes from "Handbook of Space Astronomy and Astrophysics" by Martin V. Zombeck, 1982 Cambridge University Press. Ian Beardsley |
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#7
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#8
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![]() mystic math (now it becomes mystic) Group: sci.astro.amateur Date: Fri, Jul 2, 2004, 5:17am (PDT+7) From: (Sam=A0Wormley) Crank Information =A0=A0=A0=A0http://www.google.com/search?q=3Dnumerology+site%3Awww.crank.n= et http://www.csicop.org/cgi-bin/search...q=3Dnumerology -------------------------------------------- Por dios, there is nothing cranky about it!!! Ian |
#9
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![]() mystic math (now it becomes mystic) Group: sci.astro.amateur Date: Fri, Jul 2, 2004, 5:17am (PDT+7) From: (Sam=A0Wormley) Crank Information =A0=A0=A0=A0http://www.google.com/search?q=3Dnumerology+site%3Awww.crank.n= et http://www.csicop.org/cgi-bin/search...q=3Dnumerology -------------------------------------------- Por dios, there is nothing cranky about it!!! Ian |
#10
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We have read your post and we have marked you uninteresting.
Denis -- DT Replace nospam with the antithesis of hills |
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