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When an initially stationary observer starts moving, with speed v, towards a source of waves, the frequency with which the wavecrests hit him shifts from f=c/L to f'=(c+v)/L, where c is the speed of the wavecrests relative to the stationary observer and L is the wavelength (for the sake of simplicity, the relativistic corrections are ignored):
http://www.hep.man.ac.uk/u/roger/PHY.../lecture18.pdf Roger Barlow, Professor of Particle Physics: "The Doppler effect - changes in frequencies when sources or observers are in motion - is familiar to anyone who has stood at the roadside and watched (and listened) to the cars go by. It applies to all types of wave, not just sound. (...) Moving Observer. Now suppose the source is fixed but the observer is moving towards the source, with speed v. In time t, ct/lambda waves pass a fixed point. A moving point adds another vt/lambda. So f'=(c+v)/lambda." The crucial question is: What is the speed of the wavecrests relative to the moving observer? The only reasonable answer is implicit in the quotation above and explicit in the following two quotations: The speed of the wavecrests relative to the observer shifts from c to c'=c+v: http://physics.bu.edu/~redner/211-sp...9_doppler.html Professor Sidney Redner: "The Doppler effect is the shift in frequency of a wave that occurs when the wave source, or the detector of the wave, is moving. Applications of the Doppler effect range from medical tests using ultrasound to radar detectors and astronomy (with electromagnetic waves). (...) We will focus on sound waves in describing the Doppler effect, but it works for other waves too. (...) Let's say you, the observer, now move toward the source with velocity vO. You encounter more waves per unit time than you did before. Relative to you, the waves travel at a higher speed: v'=v+vO. The frequency of the waves you detect is higher, and is given by: f'=v'/(lambda)=(v+vO)/(lambda)." http://faculty.washington.edu/wilkes...erference..pdf "Sound waves have speed c, and f and L are related by c=Lf. For an observer moving relative to medium with speed u, apparent propagation speed c' will be different: c'=c±u. Wavelength cannot change - it's a constant length in the medium, and same length in moving coordinate system (motion does not change lengths). Observed frequency has to change, to match apparent speed and fixed wavelength: f'=c'/L." The only reasonable answer (c'=c+v) is obviously fatal for special relativity so Einsteinians are forced to teach that, even though the frequency shifts from f=c/L to f'=(c+v)/L, the speed of LIGHT waves, unlike the speed of ANY OTHER waves, remains unchanged. That is, for all other waves the motion of the observer leads to c'=c+v but for light waves it leads to c'=c, Divine Einstein, yes we all believe in relativity, relativity, relativity. Clever Einsteinians do teach c'=c but internal suffering is unavoidable. According to the formula (frequency) = (speed of light)/(wavelength), if the frequency changes and the speed of light remains constant, the wavelength must change as well. But the motion of the observer obviously has nothing to do with the wavelength of the incoming wave - "motion does not change lengths". So the wavelength will have to change subjectively - in the measurements of the observer - while the wave itself remains unaffected: https://groups.google.com/d/msg/sci....0/1rvrcjF4JlMJ Tom Roberts: "Wavelength is not an intrinsic property of light, so it cannot be discussed independent of how it is measured. But it is clear that in vacuum the light ray itself is unchanged as it propagates. Differently moving observers will measure different wavelengths for a given light ray, because their MEASURING INSTRUMENTS are oriented differently in spacetime, and such a measurement inherently PROJECTS the light ray onto the measuring instrument." And the plight of clever Einsteinians does not end here. Even if the subjective variation of the wavelength is somehow interiorized, another haunting question remains: Why do the MEASURING INSTRUMENTS change the wavelength in such a way that the frequency shift measured by the observer (from f=c/L to f'=(c+v)/L) exactly mimics the frequency shift measured when the MEASURING INSTRUMENTS do not play tricks with the wavelength and the speed of the waves relative to the moving observer is c'=c+v? Is Nature mocking us, clever Einsteinians? Yet clever Einsteinians suffer only at night. In the morning they are happy again and have an answer to all questions: The wavelength (and everything else) changes the way we want because that's the way ahah ahah we like it, ahah ahah: http://www.youtube.com/watch?v=vEyfr10lgNw Pentcho Valev |
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