Quadibloc -- Seventh attempt.

"Quadibloc" wrote in message
...
(begin quote)
At the end of Section 3 we find the transformation derived:

tau=beta(t-vx/c^2),
xi=beta(x-vt),
eta=y,
zeta=z,
where beta=1/sqrt(1-v^2/c^2).

With trivial algebraic manipulation we can derive the inverse
transformation:

t=beta(tau+v(xi)/c^2),
x=beta(xi+v(tau)),
y=eta,
z=zeta.
(end quote)
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Not only is Savard hopeless at simple algebra, he quotes the drool of some
unnamed moron who is equally hopeless.
Perhaps he can show, step-by-step, his trivial derivation, like this:
xi = beta(x-vt)
Divide both sides of the equation by beta
xi/beta = beta(x-vt)/beta
Since beta/beta = 1,
xi/beta = 1*(x-vt)
Add vt to both sides of the equation
xi/beta +vt = (x-vt)+vt
Since vt - vt = 0,
x = xi/beta +vt

Why is Savard multiplying xi by beta instead of dividing?

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