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The Mass of the Sun cannot be determined
Formulas derived from Kepler’s planetary laws allow us to determine the masses of bodies in space because there is a direct relationship between orbiting and orbited bodies. Kepler observed these relationships for many years in the early 1600’s and expressed them in three laws following arduous calculations. In the case of the sun, the formulas will give the mass of the sun with the help of the gravitational constant G which was obtained first in 1798 by experiments in a laboratory by Cavendish. Knowing the orbital periods of planets and their distances from the sun we can use four methods to calculate the mass of the sun. All formulas may use pi (3.14), G (6.674E-11), r (mean distance to sun in m), r1 & r2 (perihelion in m), r3 (aphelion in m), v (volume in m^3) and p (period in seconds). I have selected nine solar planets for which these numbers are known. Kepler’s laws are generally precise but the planets do not conform to a single pattern of motion. Their orbits are ellipsis with varying eccentricity. This together with the fact that the value of G has not been established with accuracy or agreed to by different authorities means that the mass of the sun cannot be calculated exactly but only in a range of 1.425E+30 kg (1,425,079,319,967,270quadrillion kg) to 2.012E+30 kg (2,012,272,500,399,950quadrillion kg) depending on which planet is selected and what method of calculation is used. The four methods will produce a minimum of 36 values for the sun’s mass, four for each planet. Of the 36 results, 27 are different. The results of methods 1 and 2 are identical from different formulas. Method 1 using formula M = 4pi^2*r^3/G*p^2 MER 1,986,990,787,831,150,000,000,000,000,000 kg VEN 1,986,913,501,516,980,000,000,000,000,000 kg EAR 1,986,534,680,262,000,000,000,000,000,000 kg MAR 1,985,933,590,285,090,000,000,000,000,000 kg JUP 1,990,116,623,617,190,000,000,000,000,000 kg SAT 1,987,127,564,230,440,000,000,000,000,000 kg URA 1,986,638,525,992,780,000,000,000,000,000 kg NEP 1,986,698,146,207,950,000,000,000,000,000 kg PLU 1,999,277,113,439,190,000,000,000,000,000 kg Method 2 using formula M = 3pi*v/p^2/G; v = ((4*pi)/3)*r^3 (sphere volume) MER 1,987,288,553,571,870,000,000,000,000,000 kg VEN 1,987,211,255,675,760,000,000,000,000,000 kg EAR 1,986,832,377,651,520,000,000,000,000,000 kg MAR 1,986,231,197,596,680,000,000,000,000,000 kg JUP 1,990,414,857,788,270,000,000,000,000,000 kg SAT 1,987,425,350,468,140,000,000,000,000,000 kg URA 1,986,936,238,944,380,000,000,000,000,000 kg NEP 1,986,995,868,094,090,000,000,000,000,000 kg PLU 1,999,576,720,379,610,000,000,000,000,000 kg Method 3 using formula M = 3pi*v/p^2/G; v = (4/3)pi*r1*r2*r3 (ellipsoid volume) MER 1,547,150,779,827,070,000,000,000,000,000 VEN 1,970,304,157,432,980,000,000,000,000,000 EAR 1,945,942,171,226,160,000,000,000,000,000 MAR 1,785,945,874,890,820,000,000,000,000,000 JUP 1,885,248,776,143,060,000,000,000,000,000 SAT 1,862,700,964,929,320,000,000,000,000,000 URA 1,891,880,708,918,830,000,000,000,000,000 NEP 1,994,323,588,106,980,000,000,000,000,000 PLU 1,425,079,319,967,270,000,000,000,000,000 Method 4 same formulas as method 3 but adjusted for eccentricity MER 1,865,863,840,471,450,000,000,000,000,000 VEN 1,984,096,286,535,010,000,000,000,000,000 EAR 1,979,023,188,137,000,000,000,000,000,000 MAR 1,952,038,841,255,670,000,000,000,000,000 JUP 1,975,740,717,397,930,000,000,000,000,000 SAT 1,967,012,218,965,370,000,000,000,000,000 URA 1,980,799,102,238,020,000,000,000,000,000 NEP 2,012,272,500,399,950,000,000,000,000,000 PLU 1,778,498,991,319,150,000,000,000,000,000 We have 27 different numbers to choose from. But the problem is even greater. The value of G is not proven. We can use anything for G. The mass of the sun cannot be determined. Peter Riedt |
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Dear Peter Riedt:
On Mar 19, 7:07*pm, Peter Riedt wrote: The Mass of the Sun cannot be determined The mass of the Sun changes by about 1 part in 10^14 per year. So it'll be of some importance to know when the various measures were obtained. Did you remember to subtract out the masses of the planets further in? Kepler requires it. It is well known that G is a very squirrely number, and is usually only published to 6 sig figs. And I'd not worry about Pluto's orbit, until we know more about Tyche... David A. Smith |
#3
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On Mar 19, 7:07*pm, Peter Riedt wrote:
The Mass of the Sun cannot be determined Formulas derived from Kepler’s planetary laws allow us to determine the masses of bodies in space because there is a direct relationship between orbiting and orbited bodies. Kepler observed these relationships for many years in the early 1600’s and expressed them in three laws following arduous calculations. In the case of the sun, the formulas will give the mass of the sun with the help of the gravitational constant G which was obtained first in 1798 by experiments in a laboratory by Cavendish. Knowing the orbital periods of planets and their distances from the sun we can use four methods to calculate the mass of the sun. All formulas may use pi (3.14), G (6.674E-11), r (mean distance to sun in m), r1 & r2 (perihelion in m), r3 (aphelion in m), v (volume in m^3) and p (period in seconds). I have selected nine solar planets for which these numbers are known. Kepler’s laws are generally precise but the planets do not conform to a single pattern of motion. Their orbits are ellipsis with varying eccentricity. This together with the fact that the value of G has not been established with accuracy or agreed to by different authorities means that the mass of the sun cannot be calculated exactly but only in a range of 1.425E+30 kg (1,425,079,319,967,270quadrillion kg) to *2.012E+30 kg (2,012,272,500,399,950quadrillion kg) depending on which planet is selected and what method of calculation is used. The four methods will produce a minimum of 36 values for the sun’s mass, four for each planet. Of the 36 results, 27 are different. The results of methods 1 and 2 are identical from different formulas. Method 1 using formula M = 4pi^2*r^3/G*p^2 MER * * * *1,986,990,787,831,150,000,000,000,000,000 kg VEN * * * *1,986,913,501,516,980,000,000,000,000,000 kg EAR * * * *1,986,534,680,262,000,000,000,000,000,000 kg MAR * * * *1,985,933,590,285,090,000,000,000,000,000 kg JUP * * * *1,990,116,623,617,190,000,000,000,000,000 kg SAT * * * *1,987,127,564,230,440,000,000,000,000,000 kg URA * * * *1,986,638,525,992,780,000,000,000,000,000 kg NEP * * * *1,986,698,146,207,950,000,000,000,000,000 kg PLU * * * *1,999,277,113,439,190,000,000,000,000,000 kg Method 2 using formula M = 3pi*v/p^2/G; *v = ((4*pi)/3)*r^3 (sphere volume) MER * * * *1,987,288,553,571,870,000,000,000,000,000 kg VEN * * * *1,987,211,255,675,760,000,000,000,000,000 kg EAR * * * *1,986,832,377,651,520,000,000,000,000,000 kg MAR * * * *1,986,231,197,596,680,000,000,000,000,000 kg JUP * * * *1,990,414,857,788,270,000,000,000,000,000 kg SAT * * * *1,987,425,350,468,140,000,000,000,000,000 kg URA * * * *1,986,936,238,944,380,000,000,000,000,000 kg NEP * * * *1,986,995,868,094,090,000,000,000,000,000 kg PLU * * * *1,999,576,720,379,610,000,000,000,000,000 kg Method 3 using formula M = 3pi*v/p^2/G; v = (4/3)pi*r1*r2*r3 (ellipsoid volume) MER * * * *1,547,150,779,827,070,000,000,000,000,000 VEN * * * *1,970,304,157,432,980,000,000,000,000,000 EAR * * * *1,945,942,171,226,160,000,000,000,000,000 MAR * * * *1,785,945,874,890,820,000,000,000,000,000 JUP * * * *1,885,248,776,143,060,000,000,000,000,000 SAT * * * *1,862,700,964,929,320,000,000,000,000,000 URA * * * *1,891,880,708,918,830,000,000,000,000,000 NEP * * * *1,994,323,588,106,980,000,000,000,000,000 PLU * * * *1,425,079,319,967,270,000,000,000,000,000 Method 4 same formulas as method 3 but adjusted for eccentricity MER * * * *1,865,863,840,471,450,000,000,000,000,000 VEN * * * *1,984,096,286,535,010,000,000,000,000,000 EAR * * * *1,979,023,188,137,000,000,000,000,000,000 MAR * * * *1,952,038,841,255,670,000,000,000,000,000 JUP * * * *1,975,740,717,397,930,000,000,000,000,000 SAT * * * *1,967,012,218,965,370,000,000,000,000,000 URA * * * *1,980,799,102,238,020,000,000,000,000,000 NEP * * * *2,012,272,500,399,950,000,000,000,000,000 PLU * * * *1,778,498,991,319,150,000,000,000,000,000 We have 27 different numbers to choose from. But the problem is even greater. The value of G is not proven. We can use anything for G. The mass of the sun cannot be determined. Peter Riedt Even the best peers are guessing at this, and satellite trajectories continually adjusted to suit. There's still no objective science as to raw ice coexisting in 1 AU space, and even less objective science pertaining to ice or water existing/coexisting on our physically dark moon. http://translate.google.com/# Brad Guth, Brad_Guth, Brad.Guth, BradGuth, BG / “Guth Usenet” |
#4
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On Mar 21, 12:11*am, dlzc wrote:
Dear Peter Riedt: On Mar 19, 7:07*pm, Peter Riedt wrote: The Mass of the Sun cannot be determined The mass of the Sun changes by about 1 part in 10^14 per year. *So it'll be of some importance to know when the various measures were obtained. Did you remember to subtract out the masses of the planets further in? *Kepler requires it. It is well known that G is a very squirrely number, and is usually only published to 6 sig figs. And I'd not worry about Pluto's orbit, until we know more about Tyche... David A. Smith David, the orbital periods and distances of the planets from the sun would change if the mass of the sun changes significantly due to loss by radiation but this effect has not been observed. Peter Riedt |
#5
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On Mar 21, 2:29*am, Brad Guth wrote:
On Mar 19, 7:07*pm, Peter Riedt wrote: The Mass of the Sun cannot be determined Formulas derived from Kepler’s planetary laws allow us to determine the masses of bodies in space because there is a direct relationship between orbiting and orbited bodies. Kepler observed these relationships for many years in the early 1600’s and expressed them in three laws following arduous calculations. In the case of the sun, the formulas will give the mass of the sun with the help of the gravitational constant G which was obtained first in 1798 by experiments in a laboratory by Cavendish. Knowing the orbital periods of planets and their distances from the sun we can use four methods to calculate the mass of the sun. All formulas may use pi (3.14), G (6.674E-11), r (mean distance to sun in m), r1 & r2 (perihelion in m), r3 (aphelion in m), v (volume in m^3) and p (period in seconds). I have selected nine solar planets for which these numbers are known. Kepler’s laws are generally precise but the planets do not conform to a single pattern of motion. Their orbits are ellipsis with varying eccentricity. This together with the fact that the value of G has not been established with accuracy or agreed to by different authorities means that the mass of the sun cannot be calculated exactly but only in a range of 1.425E+30 kg (1,425,079,319,967,270quadrillion kg) to *2.012E+30 kg (2,012,272,500,399,950quadrillion kg) depending on which planet is selected and what method of calculation is used. The four methods will produce a minimum of 36 values for the sun’s mass, four for each planet. Of the 36 results, 27 are different. The results of methods 1 and 2 are identical from different formulas. Method 1 using formula M = 4pi^2*r^3/G*p^2 MER * * * *1,986,990,787,831,150,000,000,000,000,000 kg VEN * * * *1,986,913,501,516,980,000,000,000,000,000 kg EAR * * * *1,986,534,680,262,000,000,000,000,000,000 kg MAR * * * *1,985,933,590,285,090,000,000,000,000,000 kg JUP * * * *1,990,116,623,617,190,000,000,000,000,000 kg SAT * * * *1,987,127,564,230,440,000,000,000,000,000 kg URA * * * *1,986,638,525,992,780,000,000,000,000,000 kg NEP * * * *1,986,698,146,207,950,000,000,000,000,000 kg PLU * * * *1,999,277,113,439,190,000,000,000,000,000 kg Method 2 using formula M = 3pi*v/p^2/G; *v = ((4*pi)/3)*r^3 (sphere volume) MER * * * *1,987,288,553,571,870,000,000,000,000,000 kg VEN * * * *1,987,211,255,675,760,000,000,000,000,000 kg EAR * * * *1,986,832,377,651,520,000,000,000,000,000 kg MAR * * * *1,986,231,197,596,680,000,000,000,000,000 kg JUP * * * *1,990,414,857,788,270,000,000,000,000,000 kg SAT * * * *1,987,425,350,468,140,000,000,000,000,000 kg URA * * * *1,986,936,238,944,380,000,000,000,000,000 kg NEP * * * *1,986,995,868,094,090,000,000,000,000,000 kg PLU * * * *1,999,576,720,379,610,000,000,000,000,000 kg Method 3 using formula M = 3pi*v/p^2/G; v = (4/3)pi*r1*r2*r3 (ellipsoid volume) MER * * * *1,547,150,779,827,070,000,000,000,000,000 VEN * * * *1,970,304,157,432,980,000,000,000,000,000 EAR * * * *1,945,942,171,226,160,000,000,000,000,000 MAR * * * *1,785,945,874,890,820,000,000,000,000,000 JUP * * * *1,885,248,776,143,060,000,000,000,000,000 SAT * * * *1,862,700,964,929,320,000,000,000,000,000 URA * * * *1,891,880,708,918,830,000,000,000,000,000 NEP * * * *1,994,323,588,106,980,000,000,000,000,000 PLU * * * *1,425,079,319,967,270,000,000,000,000,000 Method 4 same formulas as method 3 but adjusted for eccentricity MER * * * *1,865,863,840,471,450,000,000,000,000,000 VEN * * * *1,984,096,286,535,010,000,000,000,000,000 EAR * * * *1,979,023,188,137,000,000,000,000,000,000 MAR * * * *1,952,038,841,255,670,000,000,000,000,000 JUP * * * *1,975,740,717,397,930,000,000,000,000,000 SAT * * * *1,967,012,218,965,370,000,000,000,000,000 URA * * * *1,980,799,102,238,020,000,000,000,000,000 NEP * * * *2,012,272,500,399,950,000,000,000,000,000 PLU * * * *1,778,498,991,319,150,000,000,000,000,000 We have 27 different numbers to choose from. But the problem is even greater. The value of G is not proven. We can use anything for G. The mass of the sun cannot be determined. Peter Riedt Even the best peers are guessing at this, and satellite trajectories continually adjusted to suit. *There's still no objective science as to raw ice coexisting in 1 AU space, and even less objective science pertaining to ice or water existing/coexisting on our physically dark moon. *http://translate.google.com/# *Brad Guth, Brad_Guth, Brad.Guth, BradGuth, BG / “Guth Usenet”- Hide quoted text - - Show quoted text - Brad, agreed. |
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Dear Peter Riedt:
On Mar 20, 5:01*pm, Peter Riedt wrote: On Mar 21, 12:11*am, dlzc wrote: On Mar 19, 7:07*pm, Peter Riedt wrote: The Mass of the Sun cannot be determined The mass of the Sun changes by about 1 part in 10^14 per year. *So it'll be of some importance to know when the various measures were obtained. Did you remember to subtract out the masses of the planets further in? *Kepler requires it. It is well known that G is a very squirrely number, and is usually only published to 6 sig figs. And I'd not worry about Pluto's orbit, until we know more about Tyche... David, the orbital periods and distances of the planets from the sun would change if the mass of the sun changes significantly due to loss by radiation but this effect has not been observed. Mass loss due to solar wind has been measured. So you report false significant figures out beyond 6 or 7, and really should not. As to "affect on orbits", it should (at least) show / permit a secular increase in orbital eccentricity. http://www.springerlink.com/content/lt25548256n76128/ David A. Smith |
#7
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On Mar 22, 4:54*am, dlzc wrote:
Dear Peter Riedt: On Mar 20, 5:01*pm, Peter Riedt wrote: On Mar 21, 12:11*am, dlzc wrote: On Mar 19, 7:07*pm, Peter Riedt wrote: The Mass of the Sun cannot be determined The mass of the Sun changes by about 1 part in 10^14 per year. *So it'll be of some importance to know when the various measures were obtained. Did you remember to subtract out the masses of the planets further in? *Kepler requires it. It is well known that G is a very squirrely number, and is usually only published to 6 sig figs. And I'd not worry about Pluto's orbit, until we know more about Tyche... David, the orbital periods and distances of the planets from the sun would change if the mass of the sun changes significantly due to loss by radiation but this effect has not been observed. Mass loss due to solar wind has been measured. *So you report false significant figures out beyond 6 or 7, and really should not. *As to "affect on orbits", it should (at least) show / permit a secular increase in orbital eccentricity.http://www.springerlink.com/content/lt25548256n76128/ David A. Smith- Hide quoted text - - Show quoted text - David, is it possible that the mass of the sun will accrete as it sweeps space? It would compensate lossess due to radiation. Peter Riedt |
#8
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Dear Peter Riedt:
On Mar 21, 6:37*pm, Peter Riedt wrote: On Mar 22, 4:54*am, dlzc wrote: On Mar 20, 5:01*pm, Peter Riedt wrote: On Mar 21, 12:11*am, dlzc wrote: On Mar 19, 7:07*pm, Peter Riedt wrote: The Mass of the Sun cannot be determined The mass of the Sun changes by about 1 part in 10^14 per year. *So it'll be of some importance to know when the various measures were obtained. Did you remember to subtract out the masses of the planets further in? *Kepler requires it. It is well known that G is a very squirrely number, and is usually only published to 6 sig figs. And I'd not worry about Pluto's orbit, until we know more about Tyche... David, the orbital periods and distances of the planets from the sun would change if the mass of the sun changes significantly due to loss by radiation but this effect has not been observed. Mass loss due to solar wind has been measured. *So you report false significant figures out beyond 6 or 7, and really should not. *As to "affect on orbits", it should (at least) show / permit a secular increase in orbital eccentricity. http://www.springerlink.com/content/lt25548256n76128/ David, is it possible that the mass of the sun will accrete as it sweeps space? It would compensate *lossess due to radiation. No, it is not possible without increasing drag, pressure, and so on. This would have killed the inner solar system long ago (asteroids, moons at least). Note that solar wind has been observed reaching as far as the heliosheath, and yes some "accretion" will start about here, but drift off with the "galactic wind". David A. Smith |
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