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Pluto’s orbital Period
Using the formula P=sqrt((4pi2r3)/(G(msun+mplanet)) which was derived from Kepler’s planetary laws, and using a value of 0.000000000066662 for the gravitational constant G we get the following differences (in days) between the observed (in the case of Pluto predicted) and calculated orbital periods: MERCURY -0.0059718 VENUS -0.0106276 EARTH 0.0176480 MARS 0.1362043 JUPITER -1.6316242 SATURN 0.4371626 URANUS 1.3049705 NEPTUNE 1.8850109 PLUTO -285.4581278 The value of G used produces a difference of between -2 and +2 days for the first 8 planets, sufficient to prove Kepler and Cavendish correct. In the case of Pluto the difference of -285 days suggests that one or more of the predicted orbital period (247.7years) or mass or mean distance from the sun are wrong. Peter Riedt |
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