![]() |
|
|
Thread Tools | Display Modes |
#1
|
|||
|
|||
![]()
The Value of heliocentric G
Using the formula P=sqrt((4pi2r3)/(G(msun+mplanet)) which was derived from Kepler’s third law, the value of the universal constant G can be tested. If we use G=6.673E-11, we get the following differences (in days) between observed (in Pluto’s case predicted) and calculated orbital periods: MERCURY 0.0360901 VENUS 0.0968106 EARTH 0.1922924 MARS 0.4646257 JUPITER 0.4408873 SATURN 5.5815260 URANUS 15.9874062 NEPTUNE 30.6686351 PLUTO -242.0601381 If however we use G=6.6676E-11 we get the following differences: MERCURY 0.0004931 VENUS 0.0058855 EARTH 0.0444906 MARS 0.1866821 JUPITER -1.3130826 SATURN 1.2278426 URANUS 3.5616361 NEPTUNE 6.3090054 PLUTO -278.7879300 If however we use G=6.66662E-11 we get the following differences: MERCURY -0.0059718 VENUS -0.0106276 EARTH 0.0176480 MARS 0.1362043 JUPITER -1.6316242 SATURN 0.4371626 URANUS 1.3049705 NEPTUNE 1.8850109 PLUTO -285.4581278 Peter Riedt |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
? heliocentric vs geocentric models ? | [email protected] | Amateur Astronomy | 99 | July 23rd 08 08:10 PM |
Heliocentric TDRS? | TVDad Jim | History | 35 | March 17th 07 04:10 PM |
The Heliocentric Universe | CoreyWhite | Astronomy Misc | 2 | March 9th 07 06:04 PM |
heliocentric longitude of the planets | user1 | Misc | 5 | January 26th 04 09:12 PM |
LEM's heliocentric orbit | RDG | History | 3 | November 28th 03 03:43 AM |