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Hadron Mass Spectrum From First Principles



 
 
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Old December 21st 09, 05:53 AM posted to sci.astro
Knecht
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Default Hadron Mass Spectrum From First Principles

If you don't mind I'll get back to the science of this thread.

Kerr solution: J = aGM^2/c

m(n) = [n]^1/2 [constant], i.e., sqrt[n] [constant]

whe a = 1/n and
constant = corrected Planck mass = 674 Mev

-n----n]^1/2[constant]----Empirical mass---Agreement

1/36------112.3------muon 105.7------------94.0 %
1/25------134.8------pion 134.98-----------99.9 %
1/2--------476.6-----kaon 497.7-------------95.8 %
3/4--------583.7-----eta 547.8--------------93.4%
1----------674---------Planck mass-------- -----
2----------953.2-------proton 938-------------98.3 %
2----------953.2-------neutron939.2?--------98.5%
2----------953.2-------eta' 958--------------99.5 %
3--------1167.4-------Lambda 1115.7------95.4 %
3--------1167.4-------Sigma 1192----------97.9 %
4--------1348.0-------Xi 1314.8------------97.5 %
5--------1507.1-------N ~ 1450------------96.1 %
6--------1651---------Omega 1672.5-------98.7 %
7--------1783---------TAU 1784.1---------99.95%
8--------1906.3-------D 1864.-------------97.8 %
10------2131.4-------D(s) 2112.2-----------99.1 %
12------2334.8-------Lam(c)2284.9---------97.8%

Well, that is the 16 most common and stable of the
particles observed, with the exception of the electron
which has n = 1/(1319)^2 and I want to study that a
bit more. Maybe only a full K-N solution will suffice here.

My argument is that this high degree of ordering
demands an explanation. The fact that it was achieved
with the admittedly very approximate Kerr solution
makes things even more interesting. The fact that
Discrete Scale Relativity is definitively required to
determine the crucial value of the corrected Planck
mass should be fully appreciated.

Barking dogs may now start barking.
Scientists will undoubtedly start thinking.

Happy Winter Solstice [33rd anniversary of DSR]
Robert L. Oldershaw
www.amherst.edu/~rloldershaw
 




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