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I'm looking for how much energy it would take to *fully* ionize
xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Ionization energies of the elements. http://en.wikipedia.org/wiki/Ionizat...f_the_elements However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? Bob Clark |
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On 24 sep, 14:13, Robert Clark wrote:
I'm looking for how much energy it would take to *fully* ionize xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Ionization energies of the elements.http://en.wikipedia.org/wiki/Ionizat...f_the_elements However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? Bob Clark I guess not. Even the CRC Handbook notes only the first 3. André Michaud |
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Robert Clark wrote:
I'm looking for how much energy it would take to *fully* ionize xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Ionization energies of the elements. http://en.wikipedia.org/wiki/Ionizat...f_the_elements However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? Look up "charge stripping" for naked nucleus injection into accelerators. If you are stooopid without a computer you are still stooopid with one. -- Uncle Al http://www.mazepath.com/uncleal/ (Toxic URL! Unsafe for children and most mammals) http://www.mazepath.com/uncleal/lajos.htm#a2 |
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Dear Robert Clark:
On Sep 24, 11:13 am, Robert Clark wrote: I'm looking for how much energy it would take to *fully* ionize xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Ionization energies of the elements. http://en.wikipedia.org/wiki/Ionizat...f_the_elements However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? I would think you could get some clue to the ionization energies by using positrons to neutralize orbital electrons, and reviewing the resulting spray. Are you expecting something odd? David A. Smith |
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Robert Clark wrote:
I'm looking for how much energy it would take to *fully* ionize xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Ionization energies of the elements. http://en.wikipedia.org/wiki/Ionizat...f_the_elements However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? Bob Clark have you looked in the NIST Atomic Spectra Database Levels yet? http://physics.nist.gov/PhysRefData/...vels_form.html enter Xe 53 to get the last (54th) electron ionization energy (41,299.7042eV) etc. or you could also try: http://www.camdb.ac.cn/e/ionization_potential/ |
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On Sep 24, 3:29 pm, dlzc wrote:
Dear Robert Clark: On Sep 24, 11:13 am, Robert Clark wrote: I'm looking for how much energy it would take to *fully* ionize xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Ionization energies of the elements. http://en.wikipedia.org/wiki/Ionizat...f_the_elements However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? I would think you could get some clue to the ionization energies by using positrons to neutralize orbital electrons, and reviewing the resulting spray. Are you expecting something odd? David A. Smith Thanks. Sabella's links look like they might give the answer. The question stems from this discussion: Newsgroups: sci.space.policy, sci.astro, sci.physics, sci.physics.relativity, sci.physics.fusion From: Robert Clark Date: Thu, 20 Sep 2007 13:47:28 -0700 Local: Thurs, Sep 20 2007 4:47 pm Subject: Stored ionized gas for ion drives. http://groups.google.com/group/sci.s...4c75eb5630f41d I wanted to use ions stored already in fully ionized form so that we could apply all the power available to accelerating the ions rather than some going to ionizing the gas. It is true that only a relatively low proportion of the power goes to ionizing the gas, such as xenon, in an ion drive. But the reason is that the xenon gas is only being partially ionized, perhaps only one or two electrons being knocked off. Then a gas that is fully ionized would undergo higher velocity since it would have a higher positive charge being acted on by the electrostatic forces. That the xenon is actually only minimally ionized in an ion drive is illuminated by the data Sabella supplied in his post: 41,000 eV required to remove the last electron from the xenon atom. 1 eV counts as about 100 kJ/mol. So this means removing that final electron would have required 4 billion joules per mol of xenon, about 30 million joules per gram. This is just for that single last electron. The total for removing all of them would be in the hundreds of millions of joules per gram. Bob Clark |
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On Sep 24, 11:13 am, Robert Clark wrote:
I'm looking for how much energy it would take to *fully* ionize xenon. I can find the 1st, 2nd and 3rd, ionization energy in several sources, for example he Some accelerator mass specs use 9 million volts and a thin carbon film to strip nuclei, presumably completely (since they go on to do mass separation on them.) So there you have an upper value to your 54th ionization constant. Dangerous Bill |
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Dear Robert Clark:
On Sep 25, 1:07 pm, Robert Clark wrote: .... However, the neutral xenon atom has 54 electrons, so the list should go up to 54, right? But I've never seen anything other than up to only the 3rd ionization energy for xenon. Have the higher ones not been measured? I would think you could get some clue to the ionization energies by using positrons to neutralize orbital electrons, and reviewing the resulting spray. Are you expecting something odd? Thanks. Sabella's links look like they might give the answer. The question stems from this discussion: Newsgroups: sci.space.policy, sci.astro, sci.physics, sci.physics.relativity, sci.physics.fusion From: Robert Clark Date: Thu, 20 Sep 2007 13:47:28 -0700 Local: Thurs, Sep 20 2007 4:47 pm Subject: Stored ionized gas for ion drives. http://groups.google.com/group/sci.s...frm/thread/109... I wanted to use ions stored already in fully ionized form so that we could apply all the power available to accelerating the ions rather than some going to ionizing the gas. A high temperature plasma. It is true that only a relatively low proportion of the power goes to ionizing the gas, such as xenon, in an ion drive. .... which is why that gas was chosen, because realtively little power is available. But the reason is that the xenon gas is only being partially ionized, perhaps only one or two electrons being knocked off. One. Then a gas that is fully ionized would undergo higher velocity since it would have a higher positive charge being acted on by the electrostatic forces. Please study "specific impulse". That the xenon is actually only minimally ionized in an ion drive is illuminated by the data Sabella supplied in his post: 41,000 eV required to remove the last electron from the xenon atom. 1 eV counts as about 100 kJ/mol. So this means removing that final electron would have required 4 billion joules per mol of xenon, about 30 million joules per gram. Much much more than you could ever get out as thrust. This is just for that single last electron. The total for removing all of them would be in the hundreds of millions of joules per gram. Take out that one, and it would avalanche the rest of them... in a plasma. http://www.journals.uchicago.edu/ApJ...016/17016.html I'm thinking you don't get 54 electrons removed at less than 1 million Kelvin. And has been pointed out, the neutrons hurt the specific impulse. Much more than the exposed 54 protons will allow acceleration. You'd be *much* better off with 54 individual protons, aka. hydrogen plasma. David A. Smith |
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Robert Clark wrote:
[snip] I wanted to use ions stored already in fully ionized form [snip crap] You are an idiot. Calculate the coulomb repulsion of a mole of Xe(54+) stored in a liter of volume. Whatcha gonna store it in, idiot? Presumably a material that does not contain electrons? Xe(54+) is gonna be a rather, ah, vigorous oxidizing agent. Then a gas that is fully ionized would undergo higher velocity since it would have a higher positive charge being acted on by the electrostatic forces. [snip rest of crap] ****ing imbecile. YOU DON'T WANT VELOCITY, JACKASS. You want momentum. Velocity is a waste of energy, (mv^2)/2m when momentum only builds as mv. You want the drive to **** lead balls. Bob Clark Ineducable idiot. -- Uncle Al http://www.mazepath.com/uncleal/ (Toxic URL! Unsafe for children and most mammals) http://www.mazepath.com/uncleal/lajos.htm#a2 |
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On Sep 25, 7:25 pm, Uncle Al wrote:
... Ineducable idiot. "The harshly you ridicule someone else, the more likely you are to be wrong yourself." - Anonymous |
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