A sufficient volume of compressed mass = zero c

This is somewhat bigger than quantum physics, suggesting as to what we
have been observing from Earth or via satellite is not exactly what we
might think it is. Instead of ignoring the regular laws of physics,
we might as well reconsider that a sufficient volume of compressed
mass = zero c

Earth surface escape velocity = 11.186 km/sec
Earth average volumetric density = 5.515 g/cm3

Black hole density = 1e24 g/cm3 1e27 kg/cm3 (1e33 kg/m3)

Planet mass multiplier for c=0:
a) Zero photon escape velocity multiplier 2.998e5/11.186 = 26.8e3
b) ??? for using surface rate of acceleration: 2.998e8/9.8 = 30.6e6

As having been first suggested by Painius: If gravity and mass are
fully linear to one another, whereas an Earth sized compressed average
density of 147.8e6 kg/m3 by rights should represent a surface gravity
that’s sufficient in order to exceed that of the surface photon radial
escape velocity of 299,800 km/s.

An Earth sized Sirius C, as anti-photon or absolute black (zero
albedo) surface of zero ‘c’, as a sufficient photon resting status, as
having its volumetric mass at 1.083e21 * 147.8e6 = 160.3e27 kg

Total Earthly body mass of 160e27 kg is roughly 8.06% the mass of Sol,
as not so hard for some of us to imagine a zero photon emitting planet
the size of Earth, although if having a 5 7 solar mass star to begin
with would certainly make the end result of Sirius C somewhat easier
to come by. At any rate, this kind of compressed density is nowhere
nearly as massive as the supposed black hole density of 1e27 1e33 kg/
m3.

Perhaps the Sirius star/solar system was once upon a time trinary, as
well as offering a local system of 3 stars plus viable planets,
whereas Sirius C at .06 solar mass is actually a bit smaller than
Earth, if not having become as compacted into being nearly as small as
that of Selene. In which case, our outside view of the surface of
Sirius C would seem kind of black hole like, only at best emitting
it’s surrounding Oort like atmospheric cloud of X-rays, gamma and
perhaps even some UV plus deep IR from whatever remains far enough
away from the surface. At the distance of 2r the gravity is 1/4th,
and thus photons should be easily escaping, unless the density of
Sirius C is simply greater than what I’m suggesting. A Selene/moon
volume size of Sirius C, whereas perhaps 0.25% solar mass would
certainly more than do the trick of its surface and vast bulk of
surrounding atmosphere being rather nicely cloaked by those resting or
captive photons.

This analogy also represents what little we’re seeing of Sirius B
isn’t but that of its outer most atmosphere, whereas any similar white
dwarf is equally cloaked within its own Oort cloud of gravity captive
photons that are oddly not supposed to represent mass. (sorry about
that pesky contradiction)

And once again, for otherwise using the surface rate of acceleration:
2.998e8/9.8 = 30.6e6 = 1.6876e11 kg/m3 as representing compressed mass
in the same volume of representing Earth’s average density is still
far from the suggested average density of any theoretical black hole.
So, for using the volume of Earth (1.083e21 m3), which one of these
compressed average densities works best for you?

a) 1.478e8 kg/m3
b) 1.6876e11 kg/m3

Rather unlikely we’ll need the greater compressed average density of
1.6876e11 kg/m3, even though this would certainly impose a surface
gravity that’s sufficient to exceed the surface photon radial escape
velocity of 299,800 km/s, as well as for any 183e30 kg planet the size
of Earth simply isn’t all that likely, since that would require a
rather super-massive stellar kind of evolution exceeding far and above
anything on record.

~ Brad Guth Brad_Guth Brad.Guth BradGuth BG / “Guth Usenet”