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In sci.astro.amateur gwatts wrote:
Radium wrote: Hi: What is the highest radio frequency used for radio astronomy? According to the link below, it is 3438 GHz: http://books.nap.edu/openbook.php?re...=11719&page=11 Is 3438 GHz the highest radio frequency used for radio astronomy? If you read on a little farther you'll find 'blurring the distinction between radio astronomy and infrared astronomy.' So where do you want to draw the line between radio astronomy and infrared astronomy? There's you're answer. Hi, Radium, gwatts, and all. I'd agree that the real question here may be where to draw the line between radio and infrared, and thus between radio astronomy and infrared astronomy. What I learned about 40 years ago was that while the line wasn't a clear one, the shortest or highest-frequency range of radio waves traditionally placed in that classification were "millimeter waves" with a wavelength of 1-10mm. Given that the speed of light, c, is very close to 3 x 10^10 centimeters per second, so that a 1 cm or 10mm wave would have a frequency of around 30 Gz, this category (also known as Extremely High Frequency or EHF) has a 30-300GHz range. A frequency of 3438 GHz, with a wavelength a bit shorter than 100 microns, would thus be about an order of magnitude higher in frequency than the top of the EHF range. While I'm not sure if there's a specific technical name for this range (analogous to the various categories of radio waves like EHF), my first layperson's guess would be that it could be considered very far infrared (that is, far from the visual spectrum and close to radio). It's interesting question how radio and infrared astronomy are distinguished: mainly by the nature of the waves, or also by the apparatus used. I'd like to to learn more of this myself. Again, I'd emphasize that in giving the range for EHF, I'm not saying that anything above 300 GHz wouldn't be considered radio, only mentioning this category as an example of what was traditionally considered near the top of the radio spectrum. Maybe Laura or others could comment more expertly on this. Most appreciatively, Margo Schulter Lat. 38.566 Long. -121.430 |
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