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Why are the 'Fixed Stars' so FIXED?



 
 
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Old May 5th 07, 09:55 AM posted to sci.physics.relativity,sci.astro
George Dishman[_1_]
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Default Why are the 'Fixed Stars' so FIXED?


"Henri Wilson" HW@.... wrote in message
...
On Fri, 4 May 2007 22:39:58 +0100, "George Dishman"
wrote:
"Henri Wilson" HW@.... wrote in message
. ..
On 4 May 2007 01:41:03 -0700, George Dishman
wrote:

On 4 May, 00:35, HW@....(Henri Wilson) wrote:

...

No George, have another look at:
www.users.bigpond.com/hewn/efdrag.jpg

The peak velocity curve is in phase with the peak brightness curve,
which in in phase with hte eclipses.

I had another look Henry, it is a fake again! The top is a cut-off
ellipse and
you have then drawn a number of dots along the actual curve by hand.

Of course.

Show a screen capture from your program, state the orbital parameters
and
_copy_ the curve onto a composite diagram like mine showing both
luminosity
and velocity curves with the correct relative phasing:

http://www.georgedishman.f2s.com/Henri/EF_Dra.png

You are a charlatan Henry, a plain old fraud.

George, my diagram was never supposed to be accurate. It was merely
demonstrating the basic idea.
I will make a more accurate one for you if you like.


Use your program. Set up orbital parameters that match
one of the velocity curves using the green curve (I know
it is supposed to be luminosity but it also matches
velocity with a different scale as we have discussed and
I guess you haven't added the "red curve" yet). The
luminosity variation will be small and the dips are due
solely to the eclipses.

Now adjust your speed equalisation distance until you get
the phase right relative to the eclipses which tell you
when the stars are on the LoS. You will find the effect
is pure VDoppler.


You're losing it George.


I'm not the one being forced to fake results.

The EF Dra curve is that of a star in a small circular orbit. It is being
eclipsed by a large close and cool object (maybe even a gas cloud). The
second
spectrum is just a reflection of the starlight by the WCH.


Sorry Henry, that's not possible, reflection cannot
provide enough light from the second source and the
mass ratio (from the velocity ratio) requires it to
be a star.

George


 




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