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In article , "Greg Neill" writes: over time. Interestingly, the behavior of the energies might be more intuitive if you were to switch to a rotating frame of reference in which the Earth and Moon are fixed! You would need to incorporate another potential term associated with the rotation proportional to the distance from the origin. I think you'll find that centrifugal potential goes as the square of the radius. force = m omega^2 r PE = 1/2 m omega^2 r^2 As a sanity check, note that this PE matches the KE of a "motionless" object viewed from the rotating frame. Choose an appropriate sign convention, of course. D'oh! Of course. I was writing faster than I was thinking. Again. Cheers. |
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