![]() |
|
|
Thread Tools | Display Modes |
#32
|
|||
|
|||
![]()
On 25 Feb, 12:15, Anthony Ayiomamitis
wrote: wrote: On 25 Feb, 01:54, Anthony Ayiomamitis wrote: Anthony Ayiomamitis wrote: Chris L Peterson wrote: On Sun, 25 Feb 2007 01:43:12 +0200, Anthony Ayiomamitis wrote: My master luminance file is available at http://www.perseus.gr/Downloads/M67-...ce.zipandwhich is 5.7 Mb in size. It is based on an average combine of five six-min subs. Hi Anthony- Hi Chris, Using Maxim and IRAF, I measured the average FWHM for stars in this image at 4.2 pixels, 5.4 arcseconds. With AIP I got values all over the place. I've previously determined in tests that AIP does not generate accurate FWHM values. The ~5" FWHM of this image is typical of what I'd expect for a 30 minute exposure under fair to good seeing conditions. Are you sure this is just the stacked, calibrated image? The histogram is completely abnormal. Stars are clipping at about 6500, and the dimmest values are around 5300. I'd expect to see a range of data from about 0 to 65535 (the full 16-bit range of the camera). If all you did was align and average, I'd have to say something went very wrong. I owe you an apology ... this includes RL and DDP (please see the name of the file). Damn it! Please redownload the same zip which has been replaced and includes the master luminance with only an align and average combine. PS. Using MAXIM/DL, please check out the FWHM for the star with centroid 303.474 and 698.294 (at 1.176!). Other sample stars are below 1.40. Enjoy! Anthony.- Hide quoted text - - Show quoted text - I tested it using both MaximDL and IRIS. Maxim gave an average of 2.3 over a sample of 20 stars ad mid-point of the hystogram. Iris fared a bit tighter, at around 2.1. I'd say that the average fwhm was at around 2.9", which is ok for clusters or start fields imaging but FAR from being an excellent seeing. Andrea, as I mention to Chris in my other reply, the raws were characterized with lower FWHM's and I forgot to apply the image scale. The latter, of course, is an automatic 27% error. Ooops! BTW, there is a lot of thermal noise. I'd venture to suggest that you create a map of hot pixels and kill 'em before creating the luminance file. Can I trouble you for two to three sample pixel coordinates for my education and I will proceed with building a defective pixel map. As I use CCDSoft for reduction, I will check if it can import such a map. If not, I will start doing reduction within AIP4Win which can accomodate such a map. I hope you got the answer. Otherwise I'll repost here. Andrea T. |
#33
|
|||
|
|||
![]()
On Sun, 25 Feb 2007 14:12:25 +0200, Anthony Ayiomamitis
wrote: Thanks for the information and feedback Chris! I wish I had kept the raw files since the values there were less than the master file. Of course, I would have more confidence on the master file which is based on the average of the five raws. Oh yeah, one more thing ... due to my excitement, I was a little too quick and forgot to apply the image scale to the FWHM I was getting immediately after each download. Oops! FYI, with your camera and scope you can calculate the smallest possible FWHM possible. Assuming your source varies from 400nm to 650nm, that your optics are perfect, and that there is perfect seeing, you'd get a FWHM of 0.73 pixels to 0.85 pixels (the former being the actual value for the central diffraction peak, and the latter the value if that peak is fit to a Gaussian, which the better FWHM calculators do). _________________________________________________ Chris L Peterson Cloudbait Observatory http://www.cloudbait.com |
#34
|
|||
|
|||
![]()
I suspect that gravitational interaction isn't sufficient between two
otherwise unrelated stars in an open cluster for this mechanism to work, but I haven't thought about it that much. And I suspect that even if several stars were close enough for such an interaction, the result would be stars flung in all directions, not dragged into a line. Maybe they've been lined up for a trick shot, like in snooker ? -- Boo |
#35
|
|||
|
|||
![]()
Chris L Peterson wrote:
On Sun, 25 Feb 2007 14:12:25 +0200, Anthony Ayiomamitis wrote: Thanks for the information and feedback Chris! I wish I had kept the raw files since the values there were less than the master file. Of course, I would have more confidence on the master file which is based on the average of the five raws. Oh yeah, one more thing ... due to my excitement, I was a little too quick and forgot to apply the image scale to the FWHM I was getting immediately after each download. Oops! FYI, with your camera and scope you can calculate the smallest possible FWHM possible. Assuming your source varies from 400nm to 650nm, that your optics are perfect, and that there is perfect seeing, you'd get a FWHM of 0.73 pixels to 0.85 pixels (the former being the actual value for the central diffraction peak, and the latter the value if that peak is fit to a Gaussian, which the better FWHM calculators do). Cool and thanks for the baseline numbers! Can I get the math behind these numbers for my education? Anthony. |
#36
|
|||
|
|||
![]() |
#37
|
|||
|
|||
![]()
On Mon, 26 Feb 2007 00:48:18 +0200, Anthony Ayiomamitis
wrote: Cool and thanks for the baseline numbers! Can I get the math behind these numbers for my education? In a perfect, unobstructed system with no seeing effects, a star forms a simple diffraction pattern described by a Bessel function. Since that function is non-monotonic, "FWHM" isn't really defined, but I took it simply as the FWHM of the central peak. I plotted the function an determined empirically that the FWHM is about 45% of the full diameter to the first minimum. The diameter of the central peak is 2.44 * lambda * f. For your scope, f is 7.5, so the disk is 7.3um across at 400nm, and 12um across at 650nm. BTW, this is why you don't normally see diffraction patterns in images- the patterns for different wavelengths blur together. I took 12um at the disk size; 45% of this is 5.4um, which is 0.72 pixels with your 7.5um pixel camera. If you try to fit the central peak and first ring to a Gaussian, the resulting function is slightly broader. I did this empirically in Mathematica, giving a FWHM of 6.4um, or 0.85 pixels. In reality, the widths are probably a little wider. I simplified the problem by treating the central peak as if it were produced by a monochromatic 650nm source. Because the source is broadband, the peak isn't described exactly by the function I used, but is a convolution of many functions. However, I think the numbers are close enough to give an idea of what "perfect" means in your system. It's worth noting, too, that there is no hard definition of FWHM, which is why you can't compare numbers produced by different programs. Algorithms may use fitting or not, and they handle the noise floor and background differently. Given a purely Gaussian PSF (which is itself a simplification), which does have a well defined FWHM, I've measured the FWHM calculation accuracy in the following programs, ordered best to worst: psfmeasure (IRAF), Maxim (v4), CCDSoft (v5), AIP (v1 and v2). _________________________________________________ Chris L Peterson Cloudbait Observatory http://www.cloudbait.com |
#38
|
|||
|
|||
![]()
Chris L Peterson wrote:
On Mon, 26 Feb 2007 00:48:18 +0200, Anthony Ayiomamitis wrote: Cool and thanks for the baseline numbers! Can I get the math behind these numbers for my education? In a perfect, unobstructed system with no seeing effects, a star forms a simple diffraction pattern described by a Bessel function. Since that function is non-monotonic, "FWHM" isn't really defined, but I took it simply as the FWHM of the central peak. I plotted the function an determined empirically that the FWHM is about 45% of the full diameter to the first minimum. The diameter of the central peak is 2.44 * lambda * f. For your scope, f is 7.5, so the disk is 7.3um across at 400nm, and 12um across at 650nm. BTW, this is why you don't normally see diffraction patterns in images- the patterns for different wavelengths blur together. I took 12um at the disk size; 45% of this is 5.4um, which is 0.72 pixels with your 7.5um pixel camera. If you try to fit the central peak and first ring to a Gaussian, the resulting function is slightly broader. I did this empirically in Mathematica, giving a FWHM of 6.4um, or 0.85 pixels. In reality, the widths are probably a little wider. I simplified the problem by treating the central peak as if it were produced by a monochromatic 650nm source. Because the source is broadband, the peak isn't described exactly by the function I used, but is a convolution of many functions. However, I think the numbers are close enough to give an idea of what "perfect" means in your system. It's worth noting, too, that there is no hard definition of FWHM, which is why you can't compare numbers produced by different programs. Algorithms may use fitting or not, and they handle the noise floor and background differently. Given a purely Gaussian PSF (which is itself a simplification), which does have a well defined FWHM, I've measured the FWHM calculation accuracy in the following programs, ordered best to worst: psfmeasure (IRAF), Maxim (v4), CCDSoft (v5), AIP (v1 and v2). Thanks for the illuminating (no pun intended) discussion and insights! Anthony. |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
M67/NGC 2682 under very good seeing! | Anthony Ayiomamitis | Amateur Astronomy | 40 | February 26th 07 06:34 PM |
Good Vibrations, Good Morning.... | Craig Fink | Space Shuttle | 3 | December 19th 06 02:04 AM |
Good Vibrations, Good Morning.... | Craig Fink | Space Station | 3 | December 19th 06 02:04 AM |
Good morning or good evening depending upon your location. I want to ask you the most important question of your life. Your joy or sorrow for all eternity depends upon your answer. The question is: Are you saved? It is not a question of how good | OM | History | 0 | April 22nd 05 08:37 AM |
How good is good enough? | Amateur Astronomy | 14 | February 16th 04 04:44 PM |