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![]() Christ Brad, I just asked a simple question and then you start up with all your incest clone crapola. Simple; would you folks like some internet posted examples, of film and/or of CCD obtained images that unavoidably included our physically dark moon along with a few other pesky items, such as Mars, Jupiter, Venus and Mercury, plus even a few of those having included the brighter of available stars? No, I just want an answer to my question, why are there no stars in the background during the recent ISS/Shuttle space walk ?? I mean the cameras of today must be 10 thousand humdred million times better than the cameras of Apollo, why no stars ?? "If you're not looking for the truth, you will not find it." You are the one who is not looking for the truth. |
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On 8 Jul 2006 14:13:20 -0700, "
wrote: No, I just want an answer to my question, why are there no stars in the background during the recent ISS/Shuttle space walk ?? I mean the cameras of today must be 10 thousand humdred million times better than the cameras of Apollo, why no stars ?? The same reason that there aren't stars in the Apollo photographs. The camera is set to photograph something pretty bright, and the stars are very dim in comparison. --- Replace you know what by j to email |
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Jud McCranie wrote:
On 8 Jul 2006 14:13:20 -0700, " wrote: No, I just want an answer to my question, why are there no stars in the background during the recent ISS/Shuttle space walk ?? I mean the cameras of today must be 10 thousand humdred million times better than the cameras of Apollo, why no stars ?? The same reason that there aren't stars in the Apollo photographs. The camera is set to photograph something pretty bright, and the stars are very dim in comparison. --- That old NASA/Apollo infomercial argument about "no stars" being the norm wasn't valid in the beginning, and it certainly isn't valid now. The dynamic range(DR) of their Kodak film was in fact sufficient to have included a dozen or more items besides the moon and Earth, and of those CCD images of today are offering a good 32 fold better yet at having extended that DR capability that should knock our socks off with having unavoidably included a few stars, with some of those best performing CCDs being capable of offering better than a 100:1 improved DR ratio. Therefore, it is not the "10 thousand hundred million times better than the cameras of Apollo" as stipulated by "Secret237", but none the less it's an impressive improvement, though still offering somewhat less pixel density or population per mm capability since the positive transparency/slide film can be scanned down to something below a micron which is typically 10 fold better off than what the average camera lens can manage to transfer. Without having involved a narrow visual spectrum bandpass and/or at least that of a near-UV and UV cutoff applied to the lens, the likes of the bluish Spica and especially the far-blue, violet, near-UV and the considerable UV-a spectrum worth of those Sirius stars are going to be unavoidably showing up in those unfiltered images. So, besides the obvious planets that should have been available, such as in relationship to the physically dark lunar horizon; where the heck were the likes of Spica or Sirius throughout those NASA/Apollo missions? Besides a number of such stars, Venus should have been downright pesky in at least two of the Apollo missions, as unavoidably getting into several of those unfiltered Kodak moments. Seems that you'd also have wanted to have intentionally included the rather nearby impressive likes of Venus as could only have been included as easily photographed from the moon. After all, the average terrain of our moon is worthy of something similar to the likes of sooty coal, of 0.07 albedo and otherwise typically being illuminated at something less than a 45 degree of that raw solar influx (actually of most missions being accomplished shortly after sunrise, thus perhaps as little as 10 degrees above the horizon), of which unless looking towards the direction of the sun is going to photograph at a much darker amount of surface reflected light, and as only having been recorded as darker yet because of their having used a polarised optical element, whereas earthshine that's capable of being as illuminating as 76 fold greater intensity than moonshine should have given a few faint but otherwise easily recorded shadows within those primary solar shadows. Those well published images via "moonpans" of a typically 55% reflective lunar terrain that's rather similar to that of a guano island that has been artificially dusted with the likes of portland cement and cornmeal plus the available guano itself is not exactly what our moon should have looked like. The red white and blue American flags as having been Xenon lamp spectrum illuminated is yet another rather obvious photographic error that shouldn't need any further argument. Moon and Spica (first magnitude of 0.98) http://pages.prodigy.net/pam.orman/j...051225_02.html Date: December 25, 2005 Time: 6:35 a.m. MST Location: Phoenix, Arizona Camera: Olympus OM-1 35mm SLR on fixed tripod Film: Fuji Provia 100F slide Focal length: 600 mm (200mm lens with 3X tele-extender Apertu f/11 (effective f/32) Exposure time: approximately 1/2 second Scanner: Nikon Coolscan LS-2000 (cropped slightly) Sirius at a visual and terrestrial atmospheric filtered magnitude of -1.42 is essentially a humanly visual 2.44 magnitude brighter item than Spica, and if that same look-see at Sirius were having been photographed as from the physically dark lunar deck without optical filters (as NASA/Apollo claimed) is where it would be easily have been recorded as 10+ times again as vibrant as Spica would have recorded upon the very same Kodak film exposure, that's actually relatively sensitive to the near-UV and UV-a. Sirius being a G2V as opposed to the somewhat wussy Spica and of it's B1V spectrum is once again where that lack of an atmosphere and thus having absolutely no attenuated near-UV or UV-a as photon filtering is a pretty damn hard factor to ignore, which should therefore have offered a rather impressive vibrance of Sirius to behold, and otherwise unavoidable as to keeping such pesky bright stars continually out of frame. Although, it's only so much worse off for the task of having to keep the likes of other nearby planets and especially that of the 80+% albedo of Venus out of each and every one of those frames, and I believe we're talking about thousands upon thousands of such frames as being a rather neat trick. You see, or rather it's of what you folks simply don't humanly see, whereas the unfiltered Kodak eye does in fact perceive as it photographically should have recorded upon that Kodak film, a wider than human spectrum that's actually extremely sensitive to the near-UV and UV-a part of the starshine spectrums (including that one of our own star), as being of what really counts the most if taking those unfiltered pictures from the naked moon. Of those bluish bright stars like Spica and even the photographically brighter Sirius would each have delivered quite the added illumination benefit if those items were being photographed as optically unfiltered and from our physically dark and atmospherically naked moon. Would you folks like to see some other examples of our moon as having been photographed along with other planets and stars, or would you care to discuss the gamma and hard-X-ray aspects of our naked moon that's offering worse off radiation dosage than what the worse of our Van Allen belts have to offer? - Brad Guth |
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The reason the Apollo astronaut photos that were taken while on the
Moon contains no stars in the pictures can be explained in this manner: If you were to stand on the Moon each square meter of lunar soil would reflect about 10% of the light it receives, which works out to be about one 125 Watt incandescent light bulb for every one square meter. This would be for early morning on the Moon, as the day goes on the surface brightness goes up. This would ruin your night vision making it very hard to see any stars at all in the sky. (Not to mention you would also be wearing sun glasses) You would have to seek some type of shade and wait several seconds before your eyes would adapt to the darkness. But if you were, say behind a large boulder you would still have to look toward and over the large boulder, not looking at the bright surface behind you, in order to see stars. Of course the dark side of the boulder would still reflect some of the lunar surface behind you, so even standing behind a large boulder it would be difficult to see stars. You would be able to see the dark side of the boulder, as your eyes adjusted to the darkness, from the reflection of the lunar surface. Brightness (APPARENT (or visual) magnitude, NOT ABSOLUTE MAGNITUDE ) Sun -26.72 Full Earth (as seen from the Moon) -13.8 Full Moon (as seen from the Earth) -12.6 Venus -4.4 Mars -2.8 Jupiter -2.0 Sirus -1.46 Canopus -0.72 A star that is one magnitude number lower than another star is about two-and-a-half times brighter. A magnitude 3 star is 2.5 times brighter than a magnitude 4 star. A magnitude 4 star is 2.5 times brighter than a magnitude 5 star. A star that is five magnitude numbers lower than another star is exactly 100 times brighter. A magnitude 1 star is 100 times brighter than a magnitude 6 star. mf - mb = x (mf = magnitude faintest) -12.6 - -26.72 = x -12.6 - -26.72 = 14.12 x = 14.12 2.5x = variation in brightness 2.514.12 = variation in brightness 2.514.12 = 415,827 Difference in brightness between the Sun and Moon is 415,827 times. (This is a conservative number) This variation in brightness between the Sun and Moon is the reason there are no photos of the Sun and Moon together in the same frame without the Sun being masked off. Now, the variation in brightness in this photo of the Moon and Spica (magnitude of .98) http://pages.prodigy.net/pam.orman/j...051225_02.html The Moon in this photo is about 40% full not as bright as a full Moon with a magnitude of about -9 so this means a variation in brightness between the two objects of 10 magnitudes or about 9,500 times. Solar illumination on the Moon is about 110,000 lumens per square meter when the Sun is directly overhead. If the Sun is not directly overhead the intensity of sunlight per unit area is decreased. A typical Sun elevation during the Apollo landings was about 20 degrees, thus the illumination per square meter was about 22,000 lumens. Since the Moon's surface reflects only about 10% of the light it receives, each square meter of surface reflects about 2200 lumens. This is about equivalent to the luminosity of a 125-watt incandescent light bulb every square meter. This is more than enough to ruin my night-vision !! A 60-watt incandescent bulb, for example, produces about 800 lumens. (read the package) Object Lumens/square meter Apparent Magnitude Sun 110 E3 -26.72 Full Moon 0.267 -12.6 Full Earth 0.800 -13.8 Venus 1.4 E-4 -4.4 0 Magnitude Star 2.65 E-6 0 1st Magnitude Star 1.0 E-6 1 6th Magnitude Star 1.0 E-8 6 Therefore the variation in brightness between the surface of the Moon and say Venus is over 15 Million times. Whereas the variation in brightness between the surface of the Moon and ½ full Earth is about 10,000 times, a much easier photo. Please let me know if I've many any mistakes. (Only objects brighter than -4.0 can cast a shadow so therefore only the Sun, Moon and Venus can cast a shadow on Earth and the Sun, Earth and Venus can cast a shadow on the Moon.) |
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What an absolute certified liar, liar and pants on fire borg you are
(incest cloned none the less). If you can photograph the physically dark moon, it's therefore technically impossible not to have photographed Venus, and from time to time within the same frame as that of the dark and nasty moon itself. Christ almighty on a stick, there's even official NASA/Apollo Ektachrome as having our sun and moon within the same frame. I guess the DR of that film was even better off when having been extra double-IR boiled and otherwise gamma and hard-X-ray radiated to death. Your infomercial-science simply isn't worth crapolla, even if it's flowing like gang busters up hill. Therefore the variation in brightness between the surface of the Moon and say Venus is over 15 Million times. Whereas the variation in brightness between the surface of the Moon and ½ full Earth is about 10,000 times, a much easier photo. Get rid of the atmospheric filtering and spectrum skew, eliminate any optical filters (except for the polarised element that should have made their guano and portland cement lunar surface darker) and try that math once again, as to what the naked Kodak eye would have unavoidably recorded. Grain per grain, or pixel per pixel (not of each whole target), as such Venus simply would not have been 15 million times less bright than the physically dark moon (we're talking nearly open pit coal mine dark). Further proof that you're a liar, your "½ full Earth" was not depicted as 10,000 times brighter than the moon (try 5 fold brighter). You can not use the whole target whenever you've got more a full photographic grain or pixel worth of image to work with, which proves that you're a liar because you claim being such an all-knowing wizard. Here's a nifty moon phase simulator link (recently contributed by Ami Silberman), and for otherwise having A-17 at roughly 30°E is making it look as though they had gotten that artificial image of Earth sufficiently correct, even though it's still a xenon illuminated moon that's very guano and otherwise portland cement like. http://astro.unl.edu/naap/lps/animations/lps.swf http://www.hq.nasa.gov/office/pao/Hi...-134-20384.jpg However, I still don't agree with the roughly 10% phase of Earth as being that of a sufficient amount for the A-14 mission as situated 17 degrees west. So, basically you're saying that I'm right about Venus hiding along with all of those WMD, Usama bin Laden and of a few other pesky items of sufficient photons that should have been available to their unfiltered Kodak eye that should have recorded more than any human spectrum of whatever's within that otherwise crystal clear black sky, especially within such EVAs of Apollo 11, 14 and 16 would have been technically difficult if not impossible to have excluded such a bright Venus. As for my being incorrect as to the illuminated phase of Earth as viewed by their A-17 mission, whereas having supposedly landed roughly 30 degrees East would have seen Earth as slightly greater than half phase illuminated for their first EVA (I hadn't realized how far East the supposed landing site was situated on that passive guano and portland cement moon of their's). http://www.hq.nasa.gov/office/pao/Hi...87-cropped.jpg http://rst.gsfc.nasa.gov/Sect19/Sect19_6.html Apollo 17 being 30° E (46 hours 18 minutes) * Landing: 113.00 GET * EVA-1 o Start: 117.00 GET, 15.3 deg. o Finis: 124.25 GET, 19.0 deg. * EVA-2 o Start: 140.50 GET, 27.3 deg. o Finis: 148.25 GET, 31.2 deg. * EVA-3 o Start: 163.50 GET, 39.0 deg. o Finis: 170.75 GET, 42.6 deg. At 75 lunar surface hours of having unavoidably received worse than Van Allen TBI gamma and hard-X-ray that's not even the least bit attenuated while in those 75 orbits (148 hours worth of somewhat spacecraft shielded dosage), seems a neat trick all by itself. However, the rather unusually slim crescent of Earth as depicted from Apollo-14 seems a bit of a reciprocal or inverse stretch of the imagination, even if having waited to the very last moment of their second EVA should have shown a greater illuminated phase worth of Earth. As it stands, it's looking as though having been an extra day's worth of phase rotation past their last EVA. http://www.hq.nasa.gov/office/pao/Hi...4/20149603.jpg http://www.lpi.usra.edu/resources/ap.../?AS14-66-9329 http://www.lpi.usra.edu/resources/ap.../?AS14-66-9331 A-14 being 17° W (28 hours 17 minutes) * Landing: 108.25 GET * EVA-1 o Start: 113.50 GET, 13.0 deg. o Finis: 118.50 GET, 15.5 deg. * EVA-2 o Start: 131.25 GET, 22.0 deg. o Finis: 135.75 GET, 24.3 deg. At 33.5 lunar surface hours of unavoidably receiving worse than Van Allen TBI gamma and hard-X-ray that's not the least bit attenuated while in those 34 orbits (66.5 hours worth of somewhat spacecraft shielded dosage) is still representing another neat trick. Here's a good amount of xenon spot illumination that's roughly 16 hours past sunrise, and otherwise offering mostly way under exposed images, except for those impressive dynamic range examples as having included the xenon lamp array itself (don't pay any attention to the images as having those pesky short shadows, simply because of their having moved that xenon lamp a bit closer). http://www.lpi.usra.edu/resources/ap.../?AS12-46-6789 http://www.lpi.usra.edu/resources/ap.../?AS12-46-6824 http://www.lpi.usra.edu/resources/ap.../?AS12-49-7225 There are however a few of those believable images from orbit, of Earth and of the somewhat dark golden/brownish orb that looks as though a rather mineral/element rich moon that's not all that reflective. http://www.lpi.usra.edu/resources/ap...m/magazine/?46 http://www.lpi.usra.edu/resources/ap...m/magazine/?47 Apollo 12 * Landing: 110.50 GET * EVA-1 o Start: 115.25 GET, 7.5 deg. o Finis: 119.25 GET, 9.5 deg. * EVA-2 o Start: 131.50 GET, 15.8 deg. o Finis: 135.50 GET, 17.8 deg. Once again, the impressive DR of that Kodak film is really something extra special whenever the physically dark moon itself and the sun are depicted within the same frame. Of course, their xenon lamp array as simulating that sun is not nearly as intensive nor as spectrum skewed as the raw unfiltered sun. http://www.lpi.usra.edu/resources/ap.../?AS12-47-6951 http://www.lpi.usra.edu/resources/ap.../?AS12-47-6997 http://www.lpi.usra.edu/resources/ap.../?AS12-49-7215 http://www.lpi.usra.edu/resources/ap.../?AS12-49-7245 http://www.lpi.usra.edu/resources/ap...?AS15-87-11745 Here's a good collection of their guano island moon shots, of what's typically of 0.55 to 0.65 albedo (reference moonsuit being 0.85 Albedo) for as far as their unfiltered Kodak eye could see, and we're talking of 10+ km worth in all directions, and of being well past 45 degrees of sunrise to boot, which exceeds their EVA-3. http://www.lpi.usra.edu/resources/ap.../magazine/?117 Notice how the raw UV-a and near-UV spectrum of our sun is nowhere to being found. These images each look as though past 60 degrees of sunrise. http://www.lpi.usra.edu/resources/ap...AS16-117-18849 http://www.lpi.usra.edu/resources/ap...AS16-117-18850 http://www.lpi.usra.edu/resources/ap...AS16-117-18827 http://www.lpi.usra.edu/resources/ap...AS16-117-18828 Whomever had the job of scanning these images was also all over the place with those color saturation settings. For the most part the overall color saturation isn't even half of what that Ektachrome should have had to offer, even though there's only so much you can do with such a guano island and portland cement moon having a few good items of known color and contrast for our reference. I hadn't realize they'd painted the nearly paper thin aluminum of their Apollo-11 lander such a dark gray or flat black (they must have needed the extra heat). http://www.nasa.gov/multimedia/image...ature_195.html Here are a few more of those somewhat corrected color and proper saturation images of Earth and our physically dark moon, plus a little something star like. http://www.permanent.com/t-index.htm http://www.hq.nasa.gov/office/pao/Hi...hotos/6550.jpg http://nssdc.gsfc.nasa.gov/image/pla..._earthrise.jpg http://nssdc.gsfc.nasa.gov/image/pla...earth_moon.jpg http://www.spaceshots.com/Merchant2/...0001/b2103.jpg http://www.tsgc.utexas.edu/images/pl...n/earthr2.html http://antwrp.gsfc.nasa.gov/apod/ap020127.html Here's a few other pesky examples of Venus and our moon http://www.dustbunny.com/afk/planets/earth/moon.html http://boojum.as.arizona.edu/~jill/N...n-venus-sm.jpg http://www.cabrillo.edu/~rnolthenius.../moonVenus.jpg http://www.starfirestudios.com/LUNAR/venus-moon.html http://www.myastroshop.com.au/news/venus-moon.asp http://www.sas.org.au/noleen/noleen.htm http://www.sas.org.au/noleen/3.Wan%2...us%2025398.jpg (notice how the saturation of Venus is nearly as great as the moon, even though extensively filtered by Earth's atmosphere) Venus (a long ways off compared to A-14 and A-16) and our moon via earthshine as obtained from Clementine (notice the rather bluish earthshine and of the violet spectrum of Venus without any polluted atmospheric filter getting in the way). http://www.cmf.nrl.navy.mil/clementi...t/sunrise.html http://www.cmf.nrl.navy.mil/clementi...s/venusbw5.tif Once external to our global warming and otherwise polluted atmosphere, Venus becomes not only much brighter to the human exe but otherwise unavoidably and somewhat extremely brighter plus a little color saturation skewed towards violet as observed by the unfiltered Kodak eye, as easily obtained by what that excellent DR worthy Ektachrome film should have recorded, with loads of photons to spare. There is simply no good excuse for A-11, A-14 and A-16 not having recorded the absolute impressive vibrance of Venus, as obtained from such extensive EVAs or for that matter from orbit as having the better of camera and telephoto lens, plus nearly unlimited film to burn. Without atmospheric filtration, stars of near-UV and UV-a, such as Sirius, should have been burning holes in that unfiltered film. Here's some of that vacuum boil-off of the sodium atmosphere that our physically dark moon has to work with (I wonder why no sodium was ever one of the elements returned as within a lunar sample). http://sirius.bu.edu/planetary/moon.html - Brad Guth |
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Nope, just going by the numbers, you do believe in math don't you ??
Our math that is ... .... and that's the surface of the Moon being about 10,000 times brighter than the 1/2 full Earth, not the other way around. These were just rough numbers just to give someone the idea of what we are talking about when we say we can photograph the surface of the Moon and Venus in the same frame. YES it can be done, but someone would have to go out of their way to do it, it is not as easy as you make it seem, you say it should be unavoidable, it is not, that's what my numbers were supposed to show. It's hard enough just to find Venus without having your eyes adapted to the darkness and with your sunvisor down, I don't know, I've never gone out to look at the stars while wearing sunglasses, have you ?? Just like there are no stars in the ISS/Shuttle flights, it's not all that easy to do and everybody knows it, except you it seems, there is a vast difference in brightness, even your own eyes adjust to the variance in brightness. They had adjusted their cameras to expose brighter objects than that of the relatively dim (low lumens) stars, as they should have. Stars are just not very bright, just like you. (sorry, I shouldn't have said that, I just couldn't resist !!) |
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In message . com,
" writes The reason the Apollo astronaut photos that were taken while on the Moon contains no stars in the pictures can be explained in this manner: snip Please let me know if I've many any mistakes. (Only objects brighter than -4.0 can cast a shadow so therefore only the Sun, Moon and Venus can cast a shadow on Earth and the Sun, Earth and Venus can cast a shadow on the Moon.) I wish I thought all your hard work was appreciated by the kooks. I've mentioned this before, but the fact that you can't easily see or photograph stars from the Moon in daylight has been known and published for at least 50 years - in his novel "A Fall of Moondust" Arthur Clarke describes a TV camera with a "Star Gate" setting. In the story the camera does have the dynamic range to see stars, but it's usually turned off because that's not what the eye sees. It's only people who believe what they see on "Star Trek" or in Herge's "Explorers on the Moon" who expect to see stars. But I don't follow some of your argument. Venus is much brighter than an equivalent area of Moon, so you should be able to see it if you know where to look and it isn't obscured by glare (highly likely, I suspect). And the Earth is only about 10 x brighter than the Moon, not 10,000, so exposures showing both in the same frame are correctly exposed. |
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In article . com,
says... The reason the Apollo astronaut photos that were taken while on the Moon contains no stars in the pictures can be explained in this manner: No, you are confusing how the eye responds to light with how photographic film responds to light. Photographic film requires a certain minimum exposure to get any image at all. (Keyword: threshold) Anything that falls below the threshold will not appear on the film. With exposure set to keep sunlit white astronaut space suits from being overexposed, stars fall well below threshold. Your local public library will have books by Ansel Adams about this subject. They are worth reading... -- Kevin Willoughby lid What gets measured gets done. -- David Patterson Posted Via Usenet.com Premium Usenet Newsgroup Services ---------------------------------------------------------- ** SPEED ** RETENTION ** COMPLETION ** ANONYMITY ** ---------------------------------------------------------- http://www.usenet.com |
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Kevin Willoughby,
Kodak has all the necessary physics and replicated hard-science of everything that's photographic. There's no if's, and's or but's about it; we haven't landed upon that moon of ours, not even robotically without having involved the creation of a small impact crater. If that physically dark moon can be recorded as depicted as so nicely saturating throughout each frame, then there's no doubt whatsoever as to allowing Venus and even the Sirius star system (if available) to making their locations known to those unfiltered Kodak moments. The Kodak Ektachrome "threshold", along with their having used that polarised filter, is worth nearly 10 f/stops, which equals a dynamic contrast ratio of 1023:1 For Christ's sake, folks, even those terrestrial hocus-pocus NASA/Apollo images prove that much. Besides, those extra white moonsuits of 0.85 albedo can be a little over saturated by at least one if not a couple of f/stops, without such negatively or otherwise adversely impacting the rest of the image that actually matters the most anyway, especially since we all know what a moonsuit is supposed to look like. What we don't know is the color saturations as provided by the raw sunlight, or of the near-blue of the unavoidable secondary/recoil of having to deal with the considerable solar UV-a energy. That film was more than a little UV-a sensitive, and certainly a whole lot better off at being near-UV sensitive than any human eye. - Brad Guth Kevin Willoughby wrote: In article . com, says... The reason the Apollo astronaut photos that were taken while on the Moon contains no stars in the pictures can be explained in this manner: No, you are confusing how the eye responds to light with how photographic film responds to light. Photographic film requires a certain minimum exposure to get any image at all. (Keyword: threshold) Anything that falls below the threshold will not appear on the film. With exposure set to keep sunlit white astronaut space suits from being overexposed, stars fall well below threshold. Your local public library will have books by Ansel Adams about this subject. They are worth reading... -- Kevin Willoughby lid What gets measured gets done. -- David Patterson Posted Via Usenet.com Premium Usenet Newsgroup Services ---------------------------------------------------------- ** SPEED ** RETENTION ** COMPLETION ** ANONYMITY ** ---------------------------------------------------------- http://www.usenet.com |
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