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In article .com,
"Brad Guth" wrote: You're the one that doesn't believe in using the regular laws of physics, nor believing in the replicated hard-science that easily proves we haven't walked on that salty and otherwise gamma plus extra hard-X-ray by day worth of a physically dark and nasty moon. Brad, A word of advice: Before you can cite the "regular laws of physics," you first must understand them! Orbital mechanics and rocket propulsion are part of these laws, too! Just where in hell did the "salty moon" stuff come from? |
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Before you can cite the "regular laws of physics," you first must
understand them! Orbital mechanics and rocket propulsion are part of these laws, too! Orval Fairbairn, I fully agree, thus how the heck did that massively inert slug of our Saturn V plus having loads of unusable fuel tonnage and even a few extra tonnes worth of ice manage what can't seem to get accomplished at half the payload using the most new and improved composites of the very best rocket-science upon Earth? Just where in hell did the "salty moon" stuff come from? From NASA, bless their little perpetrated cold-war hearts. However, the thick icy proto-moon part was all me, though based upon other accepted science that seems perfectly fine and dandy as long as such icy moon science doesn't pertain to our moon, especially if it's salty ice. If the moon landing was faked... As within that context; how exactly does one safely go about accomplishing such an extensive deorbit and down-range past such pesky mascons and supposedly land upon that absolutely dark and nasty moon without having involved a good set of momentum reaction wheels, and without a beforehand freaking clue as to programming those onboard rad-hard CPUs for continually calculating their constantly shifting CG as well as the free-fall potential and of their final velocity upon whatever landing, or rather impact should one component out of tens of thousands if not hundreds of thousands pitch a suckerpunch? Free fall simulators or the available calculators for such are mostly terrestrial, which is downright terribly odd since we've supposedly been to and walked upon that physically dark and nasty moon of ours, and for that accomplishment you'll certainly need to know beforehand on behalf of all of those pesky mascons and that of your untested and thus unproven fly-by-rocket landers that didn't even have benefit og momentum reaction wheels, of such a R&D testy suckers that you'd need to realize beforehand of exactly whatever it is that you'll be dealing with, yet the free fall of anything upon our moon is oddly limited to at best infomercial-science and via easily fabricated video, that for all sorts of good reasons simply don't even remotely look as though having been situated upon our moon as raw solar illuminated. Here's a good little free fall and graphic animation demo for those NASA/Apollo video clips of stuff dropping from a meter above the lunar deck. http://physics.bu.edu/~duffy/java/Freefall2.html at 1.623 ms/s = 1.11 seconds, which is actually involving quite a few video frames (33.3 to being exact) that which never once quite seemed to record upon any slower action than whatever a 9.81 m/s/s environment had to offer. Solving Free-Fall Problems : this one's sufficiently good enough for the task of dropping a javelin probe into that extremely dusty, salty and otherwise gamma and hard-X-ray nasty moon of ours. http://www.batesville.k12.in.us/phys...l_problems.htm Without getting my dyslexic self too technical, in other words a little averaging and involving zilch worth of friction, whereas we're going to start off by using the following examples as based upon this previous link: 1000 second free fall as based upon 1.62 m/s/s V(f) becomes 1000 * 1.62 = 1620 m/s Distance traveled = 3.24 km 10,000 sec free fall as based upon using 1.6 m/s/s V(f) becomes 16 km/s Distance becomes 32 km (that's just using up 1.84% of 1r) 100,000 sec free fall as based upon the average of 1.25 m/s/s V(f) becomes 125 km/s Distance = 250 km (that's just having used up 14.4% of 1r) 1e6 sec free fall as based upon the average of 0.541 m/s/s V(f) becomes worth 541 km/s Distance = 1082 km (that's using up 62% of 1r) Obviously it's worth a whole lot more complex set of calculations that should be processed as second by second and meter per meter, whereas otherwise you may change those numbers around in order to suit and/or moderate whatever game plan you'd like to end up with. However, and no matters what you'd like to ignore or exclude, if to be incoming as a free-fall from the moon L-1 that's roughly 59,562 km above, as nearly directly aligned with the moderating gravity influence of mother Earth, whereas it's going to take considerable time and, upon arrival is where that javelin probe is still going to be making damn good velocity, especially since the starting point of L-1 represents a mere 163 m/s worth of orbital velocity, and that orbital influence gets down to a wussy 4.6264 m/s upon impact. Even though folks here in Usenet naysay land have been doing all they can to snooker if not fully assimilate the likes of myself, please go right ahead and use the very most conservative numbers you can imagine, as in no matters what, lo and behold it's still offering an impressive V(f) worth of final velocity that we're having to deal with. Even the volumes upon volumes of our official NASA web pages offers us village idiots nothing, not even so much as an external link as to calculating a free-falling object as pertaining specifically to that of our moon, much less as having been deployed away from LL-1. Everything is pretty much sequestered as being terrestrial related, exactly as though they've never been to the moon (robotically nor in person). - Brad Guth |
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![]() I've been watching the Shuttle (STS-121) in orbit and docked with the ISS. The astronauts have begun their space walk and I've noticed that in all the video and still shots they are showing, there are no stars in the background. Why do you suppose that is ?? |
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On 8 Jul 2006 12:17:51 -0700, in a place far, far away,
" made the phosphor on my monitor glow in such a way as to indicate that: I've been watching the Shuttle (STS-121) in orbit and docked with the ISS. The astronauts have begun their space walk and I've noticed that in all the video and still shots they are showing, there are no stars in the background. Why do you suppose that is ?? Well, duhhhh! They're obviously faking it on a movie set. With their top-secret zero-gravity machine. |
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In article ,
h (Rand Simberg) wrote: *From:* h (Rand Simberg) *Date:* Sat, 08 Jul 2006 19:26:15 GMT On 8 Jul 2006 12:17:51 -0700, in a place far, far away, " made the phosphor on my monitor glow in such a way as to indicate that: I've been watching the Shuttle (STS-121) in orbit and docked with the ISS. The astronauts have begun their space walk and I've noticed that in all the video and still shots they are showing, there are no stars in the background. Why do you suppose that is ?? Well, duhhhh! They're obviously faking it on a movie set. With their top-secret zero-gravity machine. It's done in a pool of very clear water with no bubbles AT ALL !!!!!!! :-) Malcolm B |
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wrote:
I've been watching the Shuttle (STS-121) in orbit and docked with the ISS. The astronauts have begun their space walk and I've noticed that in all the video and still shots they are showing, there are no stars in the background. Why do you suppose that is ?? Simple; would you folks like some internet posted examples, of film and/or of CCD obtained images that unavoidably included our physically dark moon along with a few other pesky items, such as Mars, Jupiter, Venus and Mercury, plus even a few of those having included the brighter of available stars? Actually from the vantage of photographing from the actual lunar surface it would have been impossible not to have included a few other items, of at least one or two extras at a time none the less. Too bad we can't get a terrestrial look-see at Sirius within frame as parked next to the physically dark terrain of our gamma and hard-X-ray nasty moon that's still a rather salty moon none the less. That's rather odd, since the relatively **** poor DR of unfiltered Kodak film has absolutely no problems in recording better than a dozen other items (obviously not all at the same time) in addition to the physically dark moon of 0.07 albedo, as being unavoidably within the same frame. Of course, the MESSENGER mission further proves that you can intentionally select the lower portion of any given CCD DR and/or spectrum band-pass and thus easily filter out in order to suit whatever you'd like to have depicted (a three year old kid should know how to accomplish that much). The MESSENGER dynamic range was intentionally set so freaking low that even the 0.07 albedo moon didn't record, thus only of whatever was of 0.1 albedo or brighter could be recorded, although extra special efforts were also made in order to avoid including the likes of any other illuminated planets that would otherwise have been recorded, especially including Venus as being out of sight and thus out of mind. Why are only Jewish Republicans as incest dumb and dumber perverts like yourself? What other part(s) of your mostly Jewish and thereby Republican incest infomercial-science, that which simply can not be replicated unless you're God or a member in good standing with your Third Reich, should we believe in? Please be absolutely specific, and I shall specifically reply as to exactly whatever it is that you've got to offer. Would you folks like another list of primary or of worthy sub-topics to select from? - "If you're not looking for the truth, you will not find it." -Brad Guth "To believe with certainty we must begin with doubting." -Stanislaus I "The real voyage of discovery consists not in seeking new landscapes, but having new eyes." -Marcel Proust "Truth is given, not to be contemplated, but to be done. Life is an action, not a thought." -F.W. Robertson ~ Even Kurt Vonnegut would have to agree that; WAR is WAR, thus "in war there are no rules" - In fact, war has been the very reason why honest folks are having to deal with the likes of others that haven't been playing by whatever the supposed rules, such as our resident LLPOF warlord(GW Bush) having invented WMD seems to come to mind. Life upon Venus, a township w/Bridge & ET/UFO Park-n-Ride Tarmac: http://guthvenus.tripod.com/gv-town.htm The Russian/China LSE-CM/ISS (Lunar Space Elevator) http://guthvenus.tripod.com/lunar-space-elevator.htm Venus ETs, plus the updated sub-topics; Brad Guth / GASA-IEIS http://guthvenus.tripod.com/gv-topics.htm |
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![]() Christ Brad, I just asked a simple question and then you start up with all your incest clone crapola. Simple; would you folks like some internet posted examples, of film and/or of CCD obtained images that unavoidably included our physically dark moon along with a few other pesky items, such as Mars, Jupiter, Venus and Mercury, plus even a few of those having included the brighter of available stars? No, I just want an answer to my question, why are there no stars in the background during the recent ISS/Shuttle space walk ?? I mean the cameras of today must be 10 thousand humdred million times better than the cameras of Apollo, why no stars ?? "If you're not looking for the truth, you will not find it." You are the one who is not looking for the truth. |
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On 8 Jul 2006 14:13:20 -0700, "
wrote: No, I just want an answer to my question, why are there no stars in the background during the recent ISS/Shuttle space walk ?? I mean the cameras of today must be 10 thousand humdred million times better than the cameras of Apollo, why no stars ?? The same reason that there aren't stars in the Apollo photographs. The camera is set to photograph something pretty bright, and the stars are very dim in comparison. --- Replace you know what by j to email |
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Jud McCranie wrote:
On 8 Jul 2006 14:13:20 -0700, " wrote: No, I just want an answer to my question, why are there no stars in the background during the recent ISS/Shuttle space walk ?? I mean the cameras of today must be 10 thousand humdred million times better than the cameras of Apollo, why no stars ?? The same reason that there aren't stars in the Apollo photographs. The camera is set to photograph something pretty bright, and the stars are very dim in comparison. --- That old NASA/Apollo infomercial argument about "no stars" being the norm wasn't valid in the beginning, and it certainly isn't valid now. The dynamic range(DR) of their Kodak film was in fact sufficient to have included a dozen or more items besides the moon and Earth, and of those CCD images of today are offering a good 32 fold better yet at having extended that DR capability that should knock our socks off with having unavoidably included a few stars, with some of those best performing CCDs being capable of offering better than a 100:1 improved DR ratio. Therefore, it is not the "10 thousand hundred million times better than the cameras of Apollo" as stipulated by "Secret237", but none the less it's an impressive improvement, though still offering somewhat less pixel density or population per mm capability since the positive transparency/slide film can be scanned down to something below a micron which is typically 10 fold better off than what the average camera lens can manage to transfer. Without having involved a narrow visual spectrum bandpass and/or at least that of a near-UV and UV cutoff applied to the lens, the likes of the bluish Spica and especially the far-blue, violet, near-UV and the considerable UV-a spectrum worth of those Sirius stars are going to be unavoidably showing up in those unfiltered images. So, besides the obvious planets that should have been available, such as in relationship to the physically dark lunar horizon; where the heck were the likes of Spica or Sirius throughout those NASA/Apollo missions? Besides a number of such stars, Venus should have been downright pesky in at least two of the Apollo missions, as unavoidably getting into several of those unfiltered Kodak moments. Seems that you'd also have wanted to have intentionally included the rather nearby impressive likes of Venus as could only have been included as easily photographed from the moon. After all, the average terrain of our moon is worthy of something similar to the likes of sooty coal, of 0.07 albedo and otherwise typically being illuminated at something less than a 45 degree of that raw solar influx (actually of most missions being accomplished shortly after sunrise, thus perhaps as little as 10 degrees above the horizon), of which unless looking towards the direction of the sun is going to photograph at a much darker amount of surface reflected light, and as only having been recorded as darker yet because of their having used a polarised optical element, whereas earthshine that's capable of being as illuminating as 76 fold greater intensity than moonshine should have given a few faint but otherwise easily recorded shadows within those primary solar shadows. Those well published images via "moonpans" of a typically 55% reflective lunar terrain that's rather similar to that of a guano island that has been artificially dusted with the likes of portland cement and cornmeal plus the available guano itself is not exactly what our moon should have looked like. The red white and blue American flags as having been Xenon lamp spectrum illuminated is yet another rather obvious photographic error that shouldn't need any further argument. Moon and Spica (first magnitude of 0.98) http://pages.prodigy.net/pam.orman/j...051225_02.html Date: December 25, 2005 Time: 6:35 a.m. MST Location: Phoenix, Arizona Camera: Olympus OM-1 35mm SLR on fixed tripod Film: Fuji Provia 100F slide Focal length: 600 mm (200mm lens with 3X tele-extender Apertu f/11 (effective f/32) Exposure time: approximately 1/2 second Scanner: Nikon Coolscan LS-2000 (cropped slightly) Sirius at a visual and terrestrial atmospheric filtered magnitude of -1.42 is essentially a humanly visual 2.44 magnitude brighter item than Spica, and if that same look-see at Sirius were having been photographed as from the physically dark lunar deck without optical filters (as NASA/Apollo claimed) is where it would be easily have been recorded as 10+ times again as vibrant as Spica would have recorded upon the very same Kodak film exposure, that's actually relatively sensitive to the near-UV and UV-a. Sirius being a G2V as opposed to the somewhat wussy Spica and of it's B1V spectrum is once again where that lack of an atmosphere and thus having absolutely no attenuated near-UV or UV-a as photon filtering is a pretty damn hard factor to ignore, which should therefore have offered a rather impressive vibrance of Sirius to behold, and otherwise unavoidable as to keeping such pesky bright stars continually out of frame. Although, it's only so much worse off for the task of having to keep the likes of other nearby planets and especially that of the 80+% albedo of Venus out of each and every one of those frames, and I believe we're talking about thousands upon thousands of such frames as being a rather neat trick. You see, or rather it's of what you folks simply don't humanly see, whereas the unfiltered Kodak eye does in fact perceive as it photographically should have recorded upon that Kodak film, a wider than human spectrum that's actually extremely sensitive to the near-UV and UV-a part of the starshine spectrums (including that one of our own star), as being of what really counts the most if taking those unfiltered pictures from the naked moon. Of those bluish bright stars like Spica and even the photographically brighter Sirius would each have delivered quite the added illumination benefit if those items were being photographed as optically unfiltered and from our physically dark and atmospherically naked moon. Would you folks like to see some other examples of our moon as having been photographed along with other planets and stars, or would you care to discuss the gamma and hard-X-ray aspects of our naked moon that's offering worse off radiation dosage than what the worse of our Van Allen belts have to offer? - Brad Guth |
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