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In article . com,
"newedana" wrote: 1. The explanation of double slit experiment today uses the Bragg's law, nλ/2=D sin θ. However it does not say why light can diffract as it passes through a tiny hole. The light with incident angle 0 against the double slit plane ( in perpendicular to the double slit face) turns out to make angle θ after it passes through the double slits. Photon theory neither defines that photons have to repulse each other, nor admits that plane wave fronts slitted by tiny holes turn out to build spherical wave fronts. That is, Bragg's law was built in regardless of diffraction mechanism of light. How primitive is the current interpretation of double slit experiment and the the Bragg's law!. The same is the case of uncertainty principle. 2. Since the light refraction takes place when it is slitted with atomic nuclei, the star light bending near the sun is not due to the attraction of massive solar gravitation, but is due to the solar wind containing tremendous atomic nuclei which make it refract with the mechanism mentioned above. Ridiculous. Two words: Gravitational lensing. When the light run to the same direction as that of atomic nuclei building optical apertures that slit the light, there occurs the red-shift of light, while there takes place the blue-shift when they run in counter direction. So the red-shift of refracted star light is not due to losing its energy as it escapes from the solar gravitational filed, but is due to the reason, nuclear particles in the solar wind run to the same direction as that of star light travelling for the earth. Thus, Albert Einstein's explanation for these two phenomena are all incorrect. Imagine there is an light travelling in the space. Do you believe that this light can change its wavelength or frequency due to losing its energy? No! It loses only its intensity that is nothing to do with wavelength. This is the natural science! Albert Einstein fooled and toyed all of us with his general theory of rlativity. Yada, yada, yada. When is your Nobel coming? 3. How can electrons be ejected in the Photoelectric experiments if light is just wave? Nobody says "light is just wave". You're a century behind the times. Light is both a wave and a particle. Perhaps if you'd read Einstein instead of dismissing him, you wouldn't make such a fool of yourself. In Dr. Yoon's New Physics (www.yoonsatom.net) or (Yoonsphysics.blogspot.com), orbital electron of atom builds a micro persistent current ring around its nucleus. When this atomic orbital electron ring receives an external electromagnetic radiation whose frequency resonates to its inherent frequency (orbital electron ring has a fixed frequency determined by its radius), it takes up the wave energy and oscillates with the same frequency, while increasing its amplitude. However if it receives an electromagnetic radiation of a higher frequency but with non-resonant frequency, its ring form turns out to be broken and liberates the electron with its revolving kinetic energy that makes the photo-electric current. The shorter the radii of the electron ring, the higher the energy required to break it and the higher the kinetic energy of liberated electron. It is well known that alkali metals are very sensitive in Photoelectric Effect, because these metals have the outermost electron rings with the weakest tenacity against bombardment of radiation energy. The details are in Dr. Yoon's text(www.yoonsatom.net) X-rays and gamma rays can also break the outermost electron rings of atoms to ionize them, since these rays are difficult to be resonate to the frequency of orbital electron rings of atoms, and have a far greater energy level. Albert Einstein explains this Photoelectric Effect, the incident photons splash out electrons richly filled in the metal structure. How childish and primitive is his idea! newedana |
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