New Physics Based on Yoon's Universal Atomic Model

The energy emission taking place when orbital electron rings expand, can b=
e observed in the case when chemical explosives such as TNT (trinitrotoluen=
) explodes. The outermost orbital electron rings of their component atoms c=
ontributing to combine them, expand only a little bit in this case of explo=
sion, due to dissociation of TNT to form various kinds of gas molecules, su=
ch as H2O, CO2, and NO2 etc.

It is well known that the explosion of only about 7 kgs of uranium 235 pro=
duces such an enormous energy equivalent to that emitted by explosion of TN=
T 20,000 metric tons. The mass ratio of these two explosive materials is a=
bout, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium at=
om with radial parameter, say, =CE=B3=3D1/100, expands to be the orbital el=
ectron rings in K shell of newly created atoms that has radial parameter, s=
ay, =CE=B3=3D1/99.28, then the ratio of energy capacity of these two orbita=
l electron rings becomes the same as the mass ratio, 2.86x10^6 , as shown a=
bove when we estimate it with Eq.=E2=96=B3E=3DE'(1/r^4, previously posted. =
The difference of radial parameter between these two electron rings is neg=
ligibly small, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio of=
their energy capacity is enormous, as shown above. However, this energy em=
ission comes only from the expansion of orbital electron rings in K shell o=
f uranium 235. Other orbital electron rings in L, M, N,. . . .shells of ura=
nium 235 would also have to expand their orbital radii emitting huge energi=
es also as in the case of electron rings of K shell. Thus the explosion of =
only 7 kg of uranium 235 gives rise to producing such a tremendous energy.

The fundamental mechanism of emitting energy from nuclear fusion of deuter=
ons is exactly the same as that of nuclear fission of uranium 235. It is al=
so the expanding energy of electron rings. In the case of nuclear fission a=
tomic electron rings expand, while in the case of nuclear fusion nuclear e=
lectron rings associated in the structure of two deuterons expand, emitting=
nuclear energy. When nuclear electron rings of two deterons combine to bui=
ld a unified nuclear electron ring with pair electrons, they have to expand=
their orbital radii emitting energy, in order to bind four protons to buil=
d two neutrons and two protons in a helium nucleus. This is the nuclear fus=
ion energy. It is the same as that when two hydrogen atoms combine to form =
a hydrogen molecule having molecular electron rings carrying pair electrons=
, with their two single atomic electron rings, emitting energy.
A single nuclear electron ring that binds two protons in constructing a ne=
uteron, can emit =CE=B3-rays at the nearest distance to its two nuclear pro=
tons when it breaks. Since this single nuclear electron ring can emit =CE=
=B3-rays with wavelength 0.005 =E2=84=AB, its radial parameter must be, =CE=
=B3=3D1/430, when we estimate it with the same equation, =E2=96=B3E=3DE'(1/=
r^4) I posted above. If these single nuclear electron rings expand their or=
bital radii and emit energy equivalent to that energy given by explosion of=
7 kgs of uranium 235, their radial parameter has to expand from =CE=B3=3D1=
/430 to =CE=B3=3D1/429.991. The distinction between them is, =E2=96=B3=CE=
=B3=3D1/429.991-1/430=3D1/20,544,014. It is an awfully small expansion comp=
ared to that in the case of nuclear fission. However the energy emission in=
the process of nuclear fusion is the same as that in the case of nuclear f=
ission. The ratio of atomic volume of deuterium and helium is, D : He =3D 1=
4=2E1 : 31.8. The larger atomic volume of helium than deuterium is attribut=
ed to the reason that the helium nucleus is stabilized in the lowest energy=
level than deuteron. Nuclear fusion energy includes also the energy of orb=
ital electron rings of deuterium when they expand their orbital radii to be=
those of helium. newedana

The energy emission taking place when orbital electron rings expand, can b=
e observed in the case when chemical explosives such as TNT (trinitrotoluen=
) explodes. The outermost orbital electron rings of their component atoms c=
ontributing to combine them, expand only a little bit in this case of explo=
sion, due to dissociation of TNT to form various kinds of gas molecules, su=
ch as H2O, CO2, and NO2 etc.

It is well known that the explosion of only about 7 kgs of uranium 235 pro=
duces such an enormous energy equivalent to that emitted by explosion of TN=
T 20,000 metric tons. The mass ratio of these two explosive materials is a=
bout, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium at=
om with radial parameter, say, =CE=B3=3D1/100, expands to be the orbital el=
ectron rings in K shell of newly created atoms that has radial parameter, s=
ay, =CE=B3=3D1/99.28, then the ratio of energy capacity of these two orbita=
l electron rings becomes the same as the mass ratio, 2.86x10^6 , as shown a=
bove when we estimate it with Eq.=E2=96=B3E=3DE'(1/r^4, previously posted. =
The difference of radial parameter between these two electron rings is neg=
ligibly small, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio of=
their energy capacity is enormous, as shown above. However, this energy em=
ission comes only from the expansion of orbital electron rings in K shell o=
f uranium 235. Other orbital electron rings in L, M, N,. . . .shells of ura=
nium 235 would also have to expand their orbital radii emitting huge energi=
es also as in the case of electron rings of K shell. Thus the explosion of =
only 7 kg of uranium 235 gives rise to producing such a tremendous energy.

The fundamental mechanism of emitting energy from nuclear fusion of deuter=
ons is exactly the same as that of nuclear fission of uranium 235. It is al=
so the expanding energy of electron rings. In the case of nuclear fission a=
tomic electron rings expand, while in the case of nuclear fusion nuclear e=
lectron rings associated in the structure of two deuterons expand, emitting=
nuclear energy. When nuclear electron rings of two deterons combine to bui=
ld a unified nuclear electron ring with pair electrons, they have to expand=
their orbital radii emitting energy, in order to bind four protons to buil=
d two neutrons and two protons in a helium nucleus. This is the nuclear fus=
ion energy. It is the same as that when two hydrogen atoms combine to form =
a hydrogen molecule having molecular electron rings carrying pair electrons=
, with their two single atomic electron rings, emitting energy.
A single nuclear electron ring that binds two protons in constructing a ne=
uteron, can emit =CE=B3-rays at the nearest distance to its two nuclear pro=
tons when it breaks. Since this single nuclear electron ring can emit =CE=
=B3-rays with wavelength 0.005 =E2=84=AB, its radial parameter must be, =CE=
=B3=3D1/430, when we estimate it with the same equation, =E2=96=B3E=3DE'(1/=
r^4) I posted above. If these single nuclear electron rings expand their or=
bital radii and emit energy equivalent to that energy given by explosion of=
7 kgs of uranium 235, their radial parameter has to expand from =CE=B3=3D1=
/430 to =CE=B3=3D1/429.991. The distinction between them is, =E2=96=B3=CE=
=B3=3D1/429.991-1/430=3D1/20,544,014. It is an awfully small expansion comp=
ared to that in the case of nuclear fission. However the energy emission in=
the process of nuclear fusion is the same as that in the case of nuclear f=
ission. The ratio of atomic volume of deuterium and helium is, D : He =3D 1=
4=2E1 : 31.8. The larger atomic volume of helium than deuterium is attribut=
ed to the reason that the helium nucleus is stabilized in the lowest energy=
level than deuteron. Nuclear fusion energy includes also the energy of orb=
ital electron rings of deuterium when they expand their orbital radii to be=
those of helium. newedana

In article .com,
"newedana" wrote:
wrote:
why don't you just admit that you are Yoon himself, instead of
constantly using the referral 'according to Dr. Yoon'...


If you say so, I'm very flattered by you because Dr. Yoon's IQ is 250
or so according to Syd, the first author of the thread, "Yoonatom vs
Standard Model". om

You seem like the infamous psyco stalker with IQ 87, who used to live
in a poor remote village of Anu. Is bryant your real name?


and what is M? be clear when you write something. and hey stupid,

Don't you know M? stupid! It's alphabet letter,....... L, "M", N, ....
There are other things too, like A, B, C, D, .......

If you were in my class, I'll present you F triple plus. You don't know
what F is, either? Don't ask me, do your own homework by yourself.
idiot.


why must i take v/c neglible? the equation E=mc^2 holds for a mass at any
speed, not only when vc. it is an exact relation.... go back to
Halliday & Resnick (a proper textbook!) .....


Are you still worshiping unscientific E=mc^2? Are you really worshiping
it wholeheartedly? You should be either intoxicated with relativity and
QM or ignorant. Here is Dr. Yoon's New Physics for that symptoms. Or
are you just pretending to worship it on purpose? Then you're a coward.
You don't need to confess. Don't ask me why. idiot. I already said many
times. Think about it with your own head or mind if you've any.

Newedana wrote.


How about you and Dr. Yoon learing physics period. Then maybe he can come
up with "new physics."

In article . com,
"newedana" wrote:
The energy emission taking place when orbital electron rings


There are no such thing. Electrons only have probability regions.

expand, can be observed in the case when chemical explosives such as TNT
(trinitrotoluen) explodes. The outermost orbital electron rings of their
component atoms contributing to combine them, expand only a little bit in
this case of explosion, due to dissociation of TNT to form various kinds of
gas molecules, such as H2O, CO2, and NO2 etc.

Huh? The energy comes from bond energies. Period.

It is well known that the explosion of only about 7 kgs of uranium 235
produces an enormous energy equivalent to that emitted by explosion of TNT
20,000 metric tons. The mass ratio of these two explosive materials is
about, 1 : 2.86x10^6.

If the orbital electron rings in K shell of uranium atom with radial
parameter, say, γ=1/100, expands to be the orbital electron rings in K
shell of newly created atoms, such as Pb that has radial parameter, say,
γ=1/99.28, then the ratio of energy capacity of these two orbital electron
rings becomes identical to the mass ratio, 2.86x10^6, as shown above when we
estimate it with Eq.â–³E=E'[1/r^2 -1/(r+n)^2]^2. The difference of radial
parameter between these two electron rings is negligibly small, or
Δγ=1/99.28-1/100=1/13,789, but the ratio of their energy capacity is such
enormous, as shown above. However, this energy emission comes only from the
expansion of orbital electron rings in K shell of uranium 235. Other orbital
electron rings in L, M, N,. . . .shells of uranium 235 should also have to
expand their orbital radii emitting huge energies also as in the case of
electron rings of K shell. Thus the explosion of only 7 kg of uranium 235
gives rise to producing such a tremendous energy. newedanna wrote


Explained 60 years ago, doofus.

In article .com,
"newedana" wrote:
The energy emission taking place when orbital electron rings expand, can
be observed in the case when chemical explosives such as TNT
(trinitrotoluen) explodes. The outermost orbital electron rings of their
component atoms contributing to combine them, expand only a little bit in
this case of explosion, due to dissociation of TNT to form various kinds of
gas molecules, such as H2O, CO2, and NO2 etc.
It is well known that the explosion of only about 7 kgs of uranium 235
produces an enormous energy equivalent to that emitted by explosion of TNT
20,000 metric tons. The mass ratio of these two explosive materials is
about, 1 : 2.86x10^6.
If the orbital electron rings in K shell of uranium atom with radial
parameter, say, γ=1/100, expands to be the orbital electron rings in K
shell of newly created atoms, such as Pb that has radial parameter, say,
γ=1/99.28, then the ratio of energy capacity of these two orbital electron
rings becomes identical to the mass ratio, 2.86x10^6, as shown above when we
estimate it with Eq.â–³E=E'[1/r^2 -1/(r+n)^2]^2. The difference of radial
parameter between these two electron rings is negligibly small, or
Δγ=1/99.28-1/100=1/13,789, but the ratio of their energy capacity is such
enormous, as shown above. However, this energy emission comes only from the
expansion of orbital electron rings in K shell of uranium 235. Other orbital
electron rings in L, M, N,. . . .shells of uranium 235 should also have to
expand their orbital radii emitting huge energies also as in the case of
electron rings of K shell. Thus the explosion of only 7 kg of uranium 235
gives rise to producing such a tremendous energy. newedanna wrote


Hey, doofus, this was crap the first time you posted it; no need to post it
5 times (so far).

newedana wrote:
The energy emission taking place when orbital electron rings expand, can=
be observed in the case when chemical explosives such as TNT (trinitrotolu=
en) explodes. The outermost orbital electron rings of their component atoms=
contributing to combine them, expand only a little bit in this case of exp=
losion, due to dissociation of TNT to form various kinds of gas molecules, =
such as H2O, CO2, and NO2 etc.
It is well known that the explosion of only about 7 kgs of uranium 235 p=
roduces an enormous energy equivalent to that emitted by explosion of TNT 2=
0,000 metric tons. The mass ratio of these two explosive materials is abou=
t, 1 : 2.86x10^6.
If the orbital electron rings in K shell of uranium atom with radial par=
ameter, say, =CE=B3=3D1/100, expands to be the orbital electron rings in K =
shell of newly created atoms, such as Pb that has radial parameter, say, =
=CE=B3=3D1/99.28, then the ratio of energy capacity of these two orbital el=
ectron rings becomes identical to the mass ratio, 2.86x10^6, as shown above=
when we estimate it with Eq.=E2=96=B3E=3DE'[1/r^2 -1/(r+n)^2]^2. The diffe=
rence of radial parameter between these two electron rings is negligibly sm=
all, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio of their ene=
rgy capacity is such enormous, as shown above. However, this energy emissio=
n comes only from the expansion of orbital electron rings in K shell of ura=
nium 235. Other orbital electron rings in L, M, N,. . . .shells of uranium =
235 should also have to expand their orbital radii emitting huge energies a=
lso as in the case of electron rings of K shell. Thus the explosion of only=
7 kg of uranium 235 gives rise to producing such a tremendous energy. newe=
danna wrote

newedana wrote:
The energy emission taking place when orbital electron rings expand, can=
be observed in the case when chemical explosives such as TNT (trinitrotolu=
en) explodes. The outermost orbital electron rings of their component atoms=
contributing to combine them, expand only a little bit in this case of exp=
losion, due to dissociation of TNT to form various kinds of gas molecules, =
such as H2O, CO2, and NO2 etc.

It is well known that the explosion of only about 7 kgs of uranium 235 p=
roduces such an enormous energy equivalent to that emitted by explosion of =
TNT 20,000 metric tons. The mass ratio of these two explosive materials is=
about, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium =
atom with radial parameter, say, =CE=B3=3D1/100, expands to be the orbital =
electron rings in K shell of newly created atoms that has radial parameter,=
say, =CE=B3=3D1/99.28, then the ratio of energy capacity of these two orbi=
tal electron rings becomes the same as the mass ratio, 2.86x10^6 , as shown=
above when we estimate it with Eq.=E2=96=B3E=3DE'(1/r^4, previously posted=
.. The difference of radial parameter between these two electron rings is n=
egligibly small, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio =
of their energy capacity is enormous, as shown above. However, this energy =
emission comes only from the expansion of orbital electron rings in K shell=
of uranium 235. Other orbital electron rings in L, M, N,. . . .shells of u=
ranium 235 would also have to expand their orbital radii emitting huge ener=
gies also as in the case of electron rings of K shell. Thus the explosion o=
f only 7 kg of uranium 235 gives rise to producing such a tremendous energy.

The fundamental mechanism of emitting energy from nuclear fusion of deut=
erons is exactly the same as that of nuclear fission of uranium 235. It is =
also the expanding energy of electron rings. In the case of nuclear fission=
atomic electron rings expand, while in the case of nuclear fusion nuclear=
electron rings associated in the structure of two deuterons expand, emitti=
ng nuclear energy. When nuclear electron rings of two deterons combine to b=
uild a unified nuclear electron ring with pair electrons, they have to expa=
nd their orbital radii emitting energy, in order to bind four protons to bu=
ild two neutrons and two protons in a helium nucleus. This is the nuclear f=
usion energy. It is the same as that when two hydrogen atoms combine to for=
m a hydrogen molecule having molecular electron rings carrying pair electro=
ns, with their two single atomic electron rings, emitting energy.
A single nuclear electron ring that binds two protons in constructing a =
neuteron, can emit =CE=B3-rays at the nearest distance to its two nuclear p=
rotons when it breaks. Since this single nuclear electron ring can emit =
=CE=B3-rays with wavelength 0.005 =E2=84=AB, its radial parameter must be, =
=CE=B3=3D1/430, when we estimate it with the same equation, =E2=96=B3E=3DE'=
(1/r^4) I posted above. If these single nuclear electron rings expand their=
orbital radii and emit energy equivalent to that energy given by explosion=
of 7 kgs of uranium 235, their radial parameter has to expand from =CE=B3=
=3D1/430 to =CE=B3=3D1/429.991. The distinction between them is, =E2=96=B3=
=CE=B3=3D1/429.991-1/430=3D1/20,544,014. It is an awfully small expansion c=
ompared to that in the case of nuclear fission. However the energy emission=
in the process of nuclear fusion is the same as that in the case of nuclea=
r fission. The ratio of atomic volume of deuterium and helium is, D : He =
=3D 14.1 : 31.8. The larger atomic volume of helium than deuterium is attri=
buted to the reason that the helium nucleus is stabilized in the lowest ene=
rgy level than deuteron. Nuclear fusion energy includes also the energy of =
orbital electron rings of deuterium when they expand their orbital radii to=
be those of helium. newedana

Congrats Newedana. You made Dr. Yoon richer by $180.
I received the book yesterday.

Before you go on to so many topics. First justify that when electrons
move. The electric field at the front move back to the back. Dr. Yoon
said the field concept is wrong and these field lines are flexible
enough that they can move around the electron. Try to find proof of
this first before going to the dynamics details. Experiments done
in accelerators seem to show results that the field are all around it
even at the front. Try this java.

http://webphysics.davidson.edu/Apple...etard_FEL.html

Let's focus on this first.

Anyway. Even if Dr. Yoon is wrong in his atomic model. He shines in his
gel crystal theory in biochemistry. I don't know how much lab work
Dr. Yoon did, but maybe some of the explanations can be found in
the convensional physics model. He just have to look deeper for a
QM explanation of the gel crystal system. Anyway. I'll try to find
a QM counterpart for it.

later,

p6



newedana wrote:
newedana wrote:
The energy emission taking place when orbital electron rings expand, c=
an be observed in the case when chemical explosives such as TNT (trinitroto=
luen) explodes. The outermost orbital electron rings of their component ato=
ms contributing to combine them, expand only a little bit in this case of e=
xplosion, due to dissociation of TNT to form various kinds of gas molecules=
, such as H2O, CO2, and NO2 etc.

It is well known that the explosion of only about 7 kgs of uranium 235=
produces such an enormous energy equivalent to that emitted by explosion o=
f TNT 20,000 metric tons. The mass ratio of these two explosive materials =
is about, 1 : 2.86x10^6. If the orbital electron rings in K shell of uraniu=
m atom with radial parameter, say, =CE=B3=3D1/100, expands to be the orbita=
l electron rings in K shell of newly created atoms that has radial paramete=
r, say, =CE=B3=3D1/99.28, then the ratio of energy capacity of these two or=
bital electron rings becomes the same as the mass ratio, 2.86x10^6 , as sho=
wn above when we estimate it with Eq.=E2=96=B3E=3DE'(1/r^4, previously post=
ed. The difference of radial parameter between these two electron rings is=
negligibly small, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the rati=
o of their energy capacity is enormous, as shown above. However, this energ=
y emission comes only from the expansion of orbital electron rings in K she=
ll of uranium 235. Other orbital electron rings in L, M, N,. . . .shells of=
uranium 235 would also have to expand their orbital radii emitting huge en=
ergies also as in the case of electron rings of K shell. Thus the explosion=
of only 7 kg of uranium 235 gives rise to producing such a tremendous ener=
gy.

The fundamental mechanism of emitting energy from nuclear fusion of de=
uterons is exactly the same as that of nuclear fission of uranium 235. It i=
s also the expanding energy of electron rings. In the case of nuclear fissi=
on atomic electron rings expand, while in the case of nuclear fusion nucle=
ar electron rings associated in the structure of two deuterons expand, emit=
ting nuclear energy. When nuclear electron rings of two deterons combine to=
build a unified nuclear electron ring with pair electrons, they have to ex=
pand their orbital radii emitting energy, in order to bind four protons to =
build two neutrons and two protons in a helium nucleus. This is the nuclear=
fusion energy. It is the same as that when two hydrogen atoms combine to f=
orm a hydrogen molecule having molecular electron rings carrying pair elect=
rons, with their two single atomic electron rings, emitting energy.
A single nuclear electron ring that binds two protons in constructing =
a neuteron, can emit =CE=B3-rays at the nearest distance to its two nuclear=
protons when it breaks. Since this single nuclear electron ring can emit =
=CE=B3-rays with wavelength 0.005 =E2=84=AB, its radial parameter must be,=
=CE=B3=3D1/430, when we estimate it with the same equation, =E2=96=B3E=3DE=
'(1/r^4) I posted above. If these single nuclear electron rings expand thei=
r orbital radii and emit energy equivalent to that energy given by explosio=
n of 7 kgs of uranium 235, their radial parameter has to expand from =CE=B3=
=3D1/430 to =CE=B3=3D1/429.991. The distinction between them is, =E2=96=B3=
=CE=B3=3D1/429.991-1/430=3D1/20,544,014. It is an awfully small expansion c=
ompared to that in the case of nuclear fission. However the energy emission=
in the process of nuclear fusion is the same as that in the case of nuclea=
r fission. The ratio of atomic volume of deuterium and helium is, D : He =
=3D 14.1 : 31.8. The larger atomic volume of helium than deuterium is attri=
buted to the reason that the helium nucleus is stabilized in the lowest ene=
rgy level than deuteron. Nuclear fusion energy includes also the energy of =
orbital electron rings of deuterium when they expand their orbital radii to=
be those of helium. newedana

so you changed nick again eh p6 -- Zhayne -- Syd -- A.S. -- Q-on --
Qi-on -- What is Qi -- Landle -- Caltechdude -- Cinquirer. how
bout using the nick 'knucklehead'. it seems to suit you quite well now
that you have fallen for yet another crank.

wrote:
so you changed nick again eh p6 -- Zhayne -- Syd -- A.S. -- Q-on --
Qi-on -- What is Qi -- Landle -- Caltechdude -- Cinquirer. how
bout using the nick 'knucklehead'. it seems to suit you quite well now
that you have fallen for yet another crank.

Hey. I didn't say I believe it. I just got the book for
collection because I may feature all the crackpots atomic
models in a web site to introduce to kids why QM is almost
Godlike in its scope and all the rest are inferior. I'd
mention how Mccutcheon has electron that bounces off the
nucleus, how Y.Porat got sticks protruding from the nucleus
holding the electrons in place, how Dr. Yoon can model
everything as magnetic attraction and eliminate the coulomb
force, etc. Hmm.. Maybe I'd write a book that reads
"1001 Interpretations of Atomic Dynamics" or something
like that. If Mccutcheon book can be a bestseller. Why
not one that debunks all of the crankpots. Maybe you can
co-author it. Lol...

p6