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#1
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The energy emission taking place when orbital electron rings expand, can b=
e observed in the case when chemical explosives such as TNT (trinitrotoluen= ) explodes. The outermost orbital electron rings of their component atoms c= ontributing to combine them, expand only a little bit in this case of explo= sion, due to dissociation of TNT to form various kinds of gas molecules, su= ch as H2O, CO2, and NO2 etc. It is well known that the explosion of only about 7 kgs of uranium 235 pro= duces an enormous energy equivalent to that emitted by explosion of TNT 20,= 000 metric tons. The mass ratio of these two explosive materials is about,= 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium atom with radial param= eter, say, =CE=B3=3D1/100, expands to be the orbital electron rings in K sh= ell of newly created atoms, such as Pb that has radial parameter, say, =CE= =B3=3D1/99.28, then the ratio of energy capacity of these two orbital elect= ron rings becomes identical to the mass ratio, 2.86x10^6, as shown above wh= en we estimate it with Eq.=E2=96=B3E=3DE'[1/r^2 -1/(r+n)^2]^2. The differen= ce of radial parameter between these two electron rings is negligibly small= , or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio of their energy= capacity is such enormous, as shown above. However, this energy emission c= omes only from the expansion of orbital electron rings in K shell of uraniu= m 235. Other orbital electron rings in L, M, N,. . . .shells of uranium 235= should also have to expand their orbital radii emitting huge energies also= as in the case of electron rings of K shell. Thus the explosion of only 7 = kg of uranium 235 gives rise to producing such a tremendous energy. newedan= na wrote |
#2
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The energy emission taking place when orbital electron rings expand, can b=
e observed in the case when chemical explosives such as TNT (trinitrotoluen= ) explodes. The outermost orbital electron rings of their component atoms c= ontributing to combine them, expand only a little bit in this case of explo= sion, due to dissociation of TNT to form various kinds of gas molecules, su= ch as H2O, CO2, and NO2 etc. It is well known that the explosion of only about 7 kgs of uranium 235 pro= duces an enormous energy equivalent to that emitted by explosion of TNT 20,= 000 metric tons. The mass ratio of these two explosive materials is about,= 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium atom with radial param= eter, say, =CE=B3=3D1/100, expands to be the orbital electron rings in K sh= ell of newly created atoms, such as Pb that has radial parameter, say, =CE= =B3=3D1/99.28, then the ratio of energy capacity of these two orbital elect= ron rings becomes identical to the mass ratio, 2.86x10^6, as shown above wh= en we estimate it with Eq.=E2=96=B3E=3DE'[1/r^2 -1/(r+n)^2]^2. The differen= ce of radial parameter between these two electron rings is negligibly small= , or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio of their energy= capacity is such enormous, as shown above. However, this energy emission c= omes only from the expansion of orbital electron rings in K shell of uraniu= m 235. Other orbital electron rings in L, M, N,. . . .shells of uranium 235= should also have to expand their orbital radii emitting huge energies also= as in the case of electron rings of K shell. Thus the explosion of only 7 = kg of uranium 235 gives rise to producing such a tremendous energy. newedan= na wrote |
#3
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![]() newedana wrote: The energy emission taking place when orbital electron rings expand, can= be observed in the case when chemical explosives such as TNT (trinitrotolu= en) explodes. The outermost orbital electron rings of their component atoms= contributing to combine them, expand only a little bit in this case of exp= losion, due to dissociation of TNT to form various kinds of gas molecules, = such as H2O, CO2, and NO2 etc. It is well known that the explosion of only about 7 kgs of uranium 235 p= roduces an enormous energy equivalent to that emitted by explosion of TNT 2= 0,000 metric tons. The mass ratio of these two explosive materials is abou= t, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium atom with radial par= ameter, say, =CE=B3=3D1/100, expands to be the orbital electron rings in K = shell of newly created atoms, such as Pb that has radial parameter, say, = =CE=B3=3D1/99.28, then the ratio of energy capacity of these two orbital el= ectron rings becomes identical to the mass ratio, 2.86x10^6, as shown above= when we estimate it with Eq.=E2=96=B3E=3DE'[1/r^2 -1/(r+n)^2]^2. The diffe= rence of radial parameter between these two electron rings is negligibly sm= all, or =CE=94=CE=B3=3D1/99.28-1/100=3D1/13,789, but the ratio of their ene= rgy capacity is such enormous, as shown above. However, this energy emissio= n comes only from the expansion of orbital electron rings in K shell of ura= nium 235. Other orbital electron rings in L, M, N,. . . .shells of uranium = 235 should also have to expand their orbital radii emitting huge energies a= lso as in the case of electron rings of K shell. Thus the explosion of only= 7 kg of uranium 235 gives rise to producing such a tremendous energy. newe= danna wrote |
#4
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newedana wrote:
The energy emission taking place when orbital electron rings expand, can be observed in the case when chemical explosives such as TNT (trinitrotoluen) explodes. The outermost orbital electron rings of their component atoms contributing to combine them, expand only a little bit in this case of explosion, due to dissociation of TNT to form various kinds of gas molecules, such as H2O, CO2, and NO2 etc. It is well known that the explosion of only about 7 kgs of uranium 235 produces an enormous energy equivalent to that emitted by explosion of TNT 20,000 metric tons. The mass ratio of these two explosive materials is about, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium atom with radial parameter, say, γ=1/100, expands to be the orbital electron rings in K shell of newly created atoms, such as Pb that has radial parameter, say, γ=1/99.28, then the ratio of energy capacity of these two orbital electron rings becomes identical to the mass ratio, 2.86x10^6, as shown above when we estimate it with Eq.△E=E'[1/r^2 -1/(r+n)^2]^2. The difference of radial parameter between these two electron rings is negligibly small, or Δγ=1/99.28-1/100=1/13,789, but the ratio of their energy capacity is such enormous, as shown above. However, this energy emission comes only from the expansion of orbital electron rings in K shell of uranium 235. Other orbital electron rings in L, M, N,. . . .shells of uranium 235 should also have to expand their orbital radii emitting huge energies also as in the case of electron rings of K shell. Thus the explosion of only 7 kg of uranium 235 gives rise to producing such a tremendous energy. newedanna wrote Explain why the energy E released in uranium fission is related to the mass lost in such a fission process, ***ACCORDING TO OBSERVATIONS***, by E = mc^2. Or shut up, you brain-dead idiot who doesn't care at all for experimental evidence and can't face the real world. Bye, Bjoern |
#5
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In article . com,
"newedana" wrote: The energy emission taking place when orbital electron rings There are no such thing. Electrons only have probability regions. expand, can be observed in the case when chemical explosives such as TNT (trinitrotoluen) explodes. The outermost orbital electron rings of their component atoms contributing to combine them, expand only a little bit in this case of explosion, due to dissociation of TNT to form various kinds of gas molecules, such as H2O, CO2, and NO2 etc. Huh? The energy comes from bond energies. Period. It is well known that the explosion of only about 7 kgs of uranium 235 produces an enormous energy equivalent to that emitted by explosion of TNT 20,000 metric tons. The mass ratio of these two explosive materials is about, 1 : 2.86x10^6. If the orbital electron rings in K shell of uranium atom with radial parameter, say, γ=1/100, expands to be the orbital electron rings in K shell of newly created atoms, such as Pb that has radial parameter, say, γ=1/99.28, then the ratio of energy capacity of these two orbital electron rings becomes identical to the mass ratio, 2.86x10^6, as shown above when we estimate it with Eq.△E=E'[1/r^2 -1/(r+n)^2]^2. The difference of radial parameter between these two electron rings is negligibly small, or Δγ=1/99.28-1/100=1/13,789, but the ratio of their energy capacity is such enormous, as shown above. However, this energy emission comes only from the expansion of orbital electron rings in K shell of uranium 235. Other orbital electron rings in L, M, N,. . . .shells of uranium 235 should also have to expand their orbital radii emitting huge energies also as in the case of electron rings of K shell. Thus the explosion of only 7 kg of uranium 235 gives rise to producing such a tremendous energy. newedanna wrote Explained 60 years ago, doofus. |
#6
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There are no such thing. Electrons only have probability regions.
Explained 60 years ago, doofus. You are really do not know what is science and what is fraudulent story. newedana |
#7
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newedana wrote:
There are no such thing. Electrons only have probability regions. Explained 60 years ago, doofus. You are really do not know what is science and what is fraudulent story. newedana Does "Pot. Kettle. Black." say anything to you? Bye, Bjoern |
#8
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In article . com,
"newedana" wrote: There are no such thing. Electrons only have probability regions. Explained 60 years ago, doofus. You are really do not know what is science and what is fraudulent story. newedana Au contraire, I can distinguish between science and quackery. You obviously cannot. Tell us your science background. Degrees, training, employment. |
#9
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What is the chemical bond? How can bond reliase energy when decomposes
and rebuilds another bonds? Do you now the mechanism of emitting energy? I forggot QM men do not know any mechanisms but do only calculation and arbitrary stupid interpretations! newedana |
#10
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newedana the village idiot of sci.physics wrote:
[snip meaningless, useless crap writteb by the village idiot] geez, you are so boring and incompetent. go and bury your useless head in sand. |
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