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Calculating stellar temperature at a distance?



 
 
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Old January 17th 14, 09:07 PM posted to sci.astro
Brad Guth[_3_]
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Default Calculating stellar temperature at a distance?

On Friday, January 17, 2014 3:41:51 AM UTC-8, Yousuf Khan wrote:
On 17/01/2014 4:52 AM, Martin Brown wrote:

The inner HZ limit is a bit surprising to me. I hadn't realised we on


Earth were quite so close to the water loss runaway greenhouse limit.




Also the outer limit for Mars being wet and warm isn't yet realised so


the model must still be incomplete (or Mars initial atmosphere denser).




It's likely that the rest of credit for keeping a planet habitable is
the planet itself. I think if either Mars or Venus had a powerful
magnetic field like the Earth, they would've remained habitable too.
Venus lost most of its water due to solar winds stripping it of its
hydrogen. The solar winds wouldn't have had so much of an effect had it
had a magnetic field. Similarly, Mars wouldn't have had so much of its
entire atmosphere stripped away, had it not been for the solar wind.

The Earth without a magnetic field is as dead a planet as these other two.

Yousuf Khan


The core of Venus is simply too newish or fission active to offer a magnetic component. The bulk of such fission elements probably didn't come from our sun.

Lots of magnetic doom and gloom offered within the following link.

http://www.youtube.com/watch?v=ILdFD-VShJM
 




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