IRT Equations for Frequency and Wavelength Shifts of Incoming Light in All Environments

"kenseto" wrote in message
...

This can be tested easily by measuring the the F_ab from a standard
light
source from geosynchroneous satellite. Then use the the measured F_ab
in
the
converted IRT equations to predict the incoming frequency and
wavelength
if
the incoming light from the satellite. If the predicted values agree
with
the measured value then the IRT equations are valid in a gravtational
environments

You use the words "if" and "can", which suggests that these HAVEN'T be
proven to work (at least, not yet)

Hey ****ing idiot runt how do you falsify a theory? Don't you do
experiments
to see if the predictions of the theory agree with experimental results?

Hey ****ing idiot runt .. HAVE there been experiements that show the
predictions of your theory agree // all you say is that it CAN be tested,
not that it HAS been tested.

You have said that IRT is a superset of SR. Well both Poincare and
Einstein prove the group structure of the SR transformations.

The group structure of the SR transformation never been proven. It is
assumed to be the true. Both Poincare and Einstein failed to realize that
group structure is valid only if the unit of measuring space (a meter
length=1/299,792,458 light-second) and time (1 clock second) are universal
constants. Since they are not

Why not .. how do you prove that they aren't in the inertial FoR SR deals
with?

then then Poincare and Einstein are wrong to
apply the math group theory to SR transforma tions.....The passage of an
observer A's clock second corresponds to the passage of less than a clock
second in B's frame

And vice versa .. nice an symmetric

If SR forms a group, and IRT doesn't, that means that there is
something fundamentally different between them. It also means that IRT
is unsound.

No idiot....group theory in SR is not valid

Why?

and besides there is no real
need or application for it.

If it isn't a group, then you can't do 'math' with it

You do this to a maddening degree - you say either SR and IRT are the
same, OR that IRT is something that SR isn't.

****ing idiot runt....IRT includes SR as a subset.
However, unlike SR, IRT
has an unlimited domain of applicability.
All the IRT eqautions are valid
for use in all environments....including gravity.
IRT also includes the
possibiltiy that the observer's clock can run at a slower rate than the
observed clcok.

So IRT has the constant speed of light in all iFoR?

And in what way is it different to GR (which also has SR as a subset and
works in all environments)