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Playing with E=m.c^2



 
 
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  #1  
Old August 28th 11, 12:45 PM posted to sci.astro,sci.physics
Ollie B Bimmol
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Posts: 34
Default Playing with E=m.c^2

If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?

Ollie

  #2  
Old August 28th 11, 03:44 PM posted to sci.astro,sci.physics
bert
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Posts: 1,997
Default Playing with E=m.c^2

On Aug 28, 7:45*am, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?

Ollie


Light(photons) do not change their speed. Photons don't bounce. All
this comes out of imperial bad thinking. I have better thinking than
they. TreBert
  #3  
Old August 28th 11, 04:01 PM posted to sci.astro,sci.physics
bert
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Posts: 1,997
Default Playing with E=m.c^2

On Aug 28, 7:45*am, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?

Ollie


It comes from a star moving away from us.(red) Redder if the star is
dense and large. Photons don't slow down. Their wave gets longer.
Gamma and red go at the same speed.White a mix of colors all go at
same speed
  #4  
Old August 28th 11, 04:23 PM posted to sci.astro,sci.physics
Yousuf Khan[_2_]
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Posts: 1,692
Default Playing with E=m.c^2

On 28/08/2011 7:45 AM, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?


I don't see how a decrease in light speed would lead to mass being
created. What has one got to do with the other?

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?


A decrease (or an increase for that matter) cannot be detected by us.
The speed of light is what determines both time and distance for us. If
light speed was changing, then time and distance would change equally
for us, and it would look like the exact same speed to us all over
again. We cannot detect light speed changing while we're inside the
universe itself, we could only detect it if we were outside of the
universe looking in somehow.

Yousuf Khan
  #5  
Old August 28th 11, 07:18 PM posted to sci.astro,sci.physics
Ollie B Bimmol
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Posts: 34
Default Playing with E=m.c^2

On a sunny day (Sun, 28 Aug 2011 11:23:31 -0400) it happened Yousuf Khan
wrote in :

On 28/08/2011 7:45 AM, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?


I don't see how a decrease in light speed would lead to mass being
created. What has one got to do with the other?


In the above formula, for E is constant, and m increasing, then c must decrease.

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?


A decrease (or an increase for that matter) cannot be detected by us.
The speed of light is what determines both time and distance for us. If
light speed was changing, then time and distance would change equally
for us, and it would look like the exact same speed to us all over
again. We cannot detect light speed changing while we're inside the
universe itself, we could only detect it if we were outside of the
universe looking in somehow.


Could you elaborate a bit on why that is so?

Yousuf Khan

  #6  
Old August 29th 11, 03:15 PM posted to sci.astro,sci.physics
dlzc
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Posts: 1,426
Default Playing with E=m.c^2

Dear Ollie B Bimmol:

On Aug 28, 11:18*am, Ollie B Bimmol wrote:
On a sunny day (Sun, 28 Aug 2011 11:23:31 -0400) it happened Yousuf Khan
wrote in :

On 28/08/2011 7:45 AM, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor
removed, so constant, that then mass HAS to be
created?


I don't see how a decrease in light speed would lead
to mass being created. What has one got to do with
the other?


In the above formula, for E is constant, and m increasing,
then c must decrease.


The formula equates energy and matter at one time, not over changes in
c. The derivation of the equation required that c be constant in time
(or at least not be a function of velocity).

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?


A decrease (or an increase for that matter) cannot be detected
by us. The speed of light is what determines both time and
distance for us. If light speed was changing, then time and
distance would change equally for us, and it would look like
the exact same speed to us all over again. We cannot detect
light speed changing while we're inside the universe itself, we
could only detect it if we were outside of the universe looking
in somehow.


Could you elaborate a bit on why that is so?


He covered that in the beginning of the paragraph. He and our
instruments have a size (and calibration) based on c-moderated
forces. If you decrease c, everything gets smaller than before, so
that light can make it "there and back again" to maintain stability.
So it looks to us like light from the old Universe has the same energy
of emission than before, but is anomalously large (as compared to
before the change).

David A. Smith
  #7  
Old August 29th 11, 07:12 PM posted to sci.astro,sci.physics
Ollie B Bimmol
external usenet poster
 
Posts: 34
Default Playing with E=m.c^2

dlzc wrote: in

Dear Ollie B Bimmol:

On Aug 28, 11:18*am, Ollie B Bimmol wrote:
On a sunny day (Sun, 28 Aug 2011 11:23:31 -0400) it happened Yousuf Khan
wrote in :

On 28/08/2011 7:45 AM, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor
removed, so constant, that then mass HAS to be
created?


I don't see how a decrease in light speed would lead
to mass being created. What has one got to do with
the other?


In the above formula, for E is constant, and m increasing,
then c must decrease.


The formula equates energy and matter at one time, not over changes in
c. The derivation of the equation required that c be constant in time
(or at least not be a function of velocity).

Or expanding on that, could it be that the redshift we see,
comes from a decreasing speed of light,
creating mass for the objects in the universe?


A decrease (or an increase for that matter) cannot be detected
by us. The speed of light is what determines both time and
distance for us. If light speed was changing, then time and
distance would change equally for us, and it would look like
the exact same speed to us all over again. We cannot detect
light speed changing while we're inside the universe itself, we
could only detect it if we were outside of the universe looking
in somehow.


Could you elaborate a bit on why that is so?


He covered that in the beginning of the paragraph. He and our
instruments have a size (and calibration) based on c-moderated
forces. If you decrease c, everything gets smaller than before, so
that light can make it "there and back again" to maintain stability.
So it looks to us like light from the old Universe has the same energy
of emission than before, but is anomalously large (as compared to
before the change).

David A. Smith


Thank you, this is very interesting, and I see you know a lot about it.
The other poster mentioned aether, and my question was if light would speed up if we removed the aether.
Then I thought of an experiment to remove the aether.
Michelson and Morley at one pint assumed their null result was due to the aether moving with earth.
So, if it is moving with the observer, then how about this:
Use a transparent vacuum rotating cylinder.
Shine a laser through the middle. Speed it up, the aether will be centrifuged to the sides,
then shine the laser through the center and via a mirror through also the side.
Combine the recieved pulses and see if there is a time difference from
the centre where the aether has been a little removed,
Would this work?

Ollie
  #8  
Old August 30th 11, 04:59 PM posted to sci.astro,sci.physics
dlzc
external usenet poster
 
Posts: 1,426
Default Playing with E=m.c^2

Dear Ollie B Bimmol:

On Aug 29, 11:12*am, Ollie B Bimmol wrote:
....
The other poster mentioned aether, and my question was if light
would speed up if we removed the aether. Then I thought of an
experiment to remove the aether. Michelson and Morley at one
pint assumed their null result was due to the aether moving with
earth.


What they succeeded in showing was that an aether that ignored the
Earth, but propagated light, did not work. That left a dragged
aether, the Lorentz aether (which propagates the Earth and light
similarly), and no aether.

So, if it is moving with the observer, then how about this:


Dragged aether has been obviated by high speed stellar motions. The
light passing "behind" fast moiving stars or planets is not "dragged"
out of position.

The Lorentz aether does not survive gravitation, or at the least has
some observability problems (which may just be the mathematics
applied).

Ultimately Nature does not care about the mental crutches we use in
our attempts to describe Her. Whatever tools we use, is a matter of
taste, until we get wrong answers.

David A. Smith
  #9  
Old August 29th 11, 09:13 PM posted to sci.astro,sci.physics
Yousuf Khan[_2_]
external usenet poster
 
Posts: 1,692
Default Playing with E=m.c^2

On 28/08/2011 2:18 PM, Ollie B Bimmol wrote:
On a sunny day (Sun, 28 Aug 2011 11:23:31 -0400) it happened Yousuf Khan
wrote :

On 28/08/2011 7:45 AM, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?


I don't see how a decrease in light speed would lead to mass being
created. What has one got to do with the other?


In the above formula, for E is constant, and m increasing, then c must decrease.


That's not what the formula means. The formula simply shows that mass
and energy are the same things. Specifically, mass is a very special
form of energy. Think of all of the particles that make up your body and
keep it together. Each one of those particles is actually a form of
locked up energy. Each particle is really a knot or a string of energy
trapped into the shape of that particle, endlessly flowing around inside
that knot unable to escape. On the other hand free-flowing energy is
what we traditionally think of as energy, it is what flows from particle
to particle across distances of space. The most common form of
free-flowing energy we think of is the electromagnetic energy, which is
represented by the photons.

So if we were able to completely dismantle the particles in your body,
and let all of their energy flow out freely, then that's how much energy
you'd have released.

A decrease (or an increase for that matter) cannot be detected by us.
The speed of light is what determines both time and distance for us. If
light speed was changing, then time and distance would change equally
for us, and it would look like the exact same speed to us all over
again. We cannot detect light speed changing while we're inside the
universe itself, we could only detect it if we were outside of the
universe looking in somehow.


Could you elaborate a bit on why that is so?


Don't think of the speed of light in terms of miles/second or km/sec.
Another way to look at the speed of light is that it represents the time
it takes energy to flow within the smallest unit of space in universe,
within the smallest unit of time in the universe. The smallest unit of
space is called a Planck Length, and the smallest unit of time is called
a Planck Time. There is no length smaller than a Planck Length, or a
time shorter than a Planck Time. The speed of light is 1 Planck
Length/Planck Time. When you look at it this way, you notice that the
speed of light is equal to exactly 1! Nothing can be simpler. And when
you look at it this way, you understand why the speed of light is what
it is.

Yousuf Khan
  #10  
Old August 30th 11, 09:25 AM posted to sci.astro,sci.physics
Ollie B Bimmol
external usenet poster
 
Posts: 34
Default Playing with E=m.c^2

Yousuf Khan wrote:

On 28/08/2011 2:18 PM, Ollie B Bimmol wrote:
On a sunny day (Sun, 28 Aug 2011 11:23:31 -0400) it happened Yousuf Khan
wrote :

On 28/08/2011 7:45 AM, Ollie B Bimmol wrote:
If E=m.c^2
then can we say that if lightspeed was to decrease,
and energy in the universe was neither added nor removed, so constant,
that then mass HAS to be created?

I don't see how a decrease in light speed would lead to mass being
created. What has one got to do with the other?


In the above formula, for E is constant, and m increasing, then c must decrease.


That's not what the formula means. The formula simply shows that mass
and energy are the same things. Specifically, mass is a very special
form of energy. Think of all of the particles that make up your body and
keep it together. Each one of those particles is actually a form of
locked up energy. Each particle is really a knot or a string of energy
trapped into the shape of that particle, endlessly flowing around inside
that knot unable to escape. On the other hand free-flowing energy is
what we traditionally think of as energy, it is what flows from particle
to particle across distances of space. The most common form of
free-flowing energy we think of is the electromagnetic energy, which is
represented by the photons.

So if we were able to completely dismantle the particles in your body,
and let all of their energy flow out freely, then that's how much energy
you'd have released.


Ah, so you say we are made of energy, just in a different form, called 'mass'?


A decrease (or an increase for that matter) cannot be detected by us.
The speed of light is what determines both time and distance for us. If
light speed was changing, then time and distance would change equally
for us, and it would look like the exact same speed to us all over
again. We cannot detect light speed changing while we're inside the
universe itself, we could only detect it if we were outside of the
universe looking in somehow.


Could you elaborate a bit on why that is so?


Don't think of the speed of light in terms of miles/second or km/sec.
Another way to look at the speed of light is that it represents the time
it takes energy to flow within the smallest unit of space in universe,
within the smallest unit of time in the universe. The smallest unit of
space is called a Planck Length, and the smallest unit of time is called
a Planck Time. There is no length smaller than a Planck Length, or a
time shorter than a Planck Time. The speed of light is 1 Planck
Length/Planck Time. When you look at it this way, you notice that the
speed of light is equal to exactly 1! Nothing can be simpler. And when
you look at it this way, you understand why the speed of light is what
it is.


That sounds very simple, but how do you find a Planck length or time?
For the length did you simply divide the meter unit by some number
so it fits nicely?
Should we make new rulers and clocks?
Seems much simpler with those units.
How many cm is a Planck?

And why cannot you break the ruler at 1 Planck into say half a Planck?
What is stopping it? We can break the atom into pieces?
or is Planck length and Planck time just ad hoc?



Yousuf Khan

 




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