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What is the Meaning of ATO? the Space Station? Entry?
On Fri, 28 Jul 2006 10:57:08 -0500, George R. Kasica wrote:
After entry interface? Or, Abort To Orbit and redock with the Space Station if a heat shield failure has been detected during entry. Like doing a RTLS to the Space Station instead of KSC. \Ummmm..not on descent....once the deorbit burn is done, they're coming down someplace be it on house, farm, field, runway or cow, but they ARE coming down that's an unchangeable fact of physics. Not enough propellant to reverse the slowdown. I would have been writing this post too, a week ago. And really, for the most part, you and Greg are right. But, often when we hear something over and over again, we think it true. Must be, or why else would people be repeating it all the time. We don't even bother to examine a particular issue. Like, exactly when is the absolute last time the Space Shuttle can return to the Space Station or Orbit if something is wrong with the heatshield. We've heard it from everybody, I've even said it myself not too long ago, but is it really true? Is it an unchangeable fact of physics? The question of the Space Shuttle to make it back to the Space Station after the deorbit burn is really an aerobrake question. Or, really a question of what happens if the brakes are turned "off", during entry. Since STS-1, from an aerodynamic standpoint, the Orbiter has only flown one entry. Well, two if you count Columbia's last mission. Aerodynamically, they have all been one and the same. Like building an experimental aircraft, then only flying it at 40 degrees angle of attack. Keeping the envelope as small as possible, instead of expanding it towards any of the edges of the envelope. Forty degrees angle of attack is a high drag/high lift attitude. A useful attitude for aerobrake too, but not the only one. Maximum Lift/Drag angle of attack would be important too, especially for plane changes to rendezvous with an orbiting Space Station. The other one that comes to mind would be the Minimum Drag attitude (zero angle of attack). Both areas where the Orbiter has never flown on entry, but very important for aerobraking to the Space Station for Lunar/Mars returns and the aero(nobraking) Shuttle Entry Abort To Orbit question. Currently, the Orbiter plans for and reenters with the lift vector up, at 40 degree angle of attack. This make the deorbit burn larger and the perigee lower than an entry planned for with the lift vector down. How much of a difference in the perigee? I'm not sure. If the brakes are turned "off" (zero angle of attack/roll to heads up) to Abort back into Orbit, how much OMS fuel (deltaV) would be required to raise perigee up out of the atmosphere? Not really sure. But, I suspect it's not as much as most people would think and that the Orbiter has the capability of carry it. -- Craig Fink Courtesy E-Mail Welcome @ |
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What is the Meaning of ATO? the Space Station? Entry?
"snidely" wrote in message oups.com... Herb Schaltegger wrote: On Fri, 28 Jul 2006 14:04:41 -0500, Jeff Findley wrote Why don't you tell us the mass of fuel you'd need for an aerobraking return to ISS? Do the math and quit your hand waving. Better yet, quit posting stupid off-the-wall BS when you're apparently drunk. :-/ There has been an uneven quality to Craig's postings lately.... Bipolar disorder? There are effective treatments for that. I suggest he head to a mental health professional for an evaluation. Jeff -- "They that can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety" - B. Franklin, Bartlett's Familiar Quotations (1919) |
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What is the Meaning of ATO? the Space Station? Entry?
"Craig Fink" wrote in message news Currently, the Orbiter plans for and reenters with the lift vector up, at 40 degree angle of attack. This make the deorbit burn larger and the perigee lower than an entry planned for with the lift vector down. How much of a difference in the perigee? I'm not sure. If the brakes are turned "off" (zero angle of attack/roll to heads up) to Abort back into Orbit, how much OMS fuel (deltaV) would be required to raise perigee up out of the atmosphere? Not really sure. But, I suspect it's not as much as most people would think and that the Orbiter has the capability of carry it. Hand waving again. Clearly this depends a lot on the velocity that's been bled off by the atmosphere and by the original OMS de-orbit burn. Why don't you do us all a favor and look this up yourself. You're looking for a graph of the orbiter's altitude and velocity during descent. Also, you'll want to find out how much reserve OMS fuel is normally in the OMS pods *after* the de-orbit burn. Come back when you have the answers. Jeff -- "They that can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety" - B. Franklin, Bartlett's Familiar Quotations (1919) |
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What is the Meaning of ATO? the Space Station? Entry?
I said earlier in the thread, that a week about I would have agreed with
George, Greg and you. So, obviously, the concept is less that a week old, unless someone else has done it. Which may very well be the case. You want to take it a step further, sure, why not. Let put some actual numbers to it, how about we start with ii) grabbing nearest envelope in sight i) Boundary between Orbital and Entry. After the deorbit burn, what is the minimum drag deltaV (at perigee) required during the pass through the atmosphere? That's simply enough atmospheric drag to reduce apogee equal to perigee while inside the atmosphere. Circular orbit, inside the atmosphere, with the lift vector pointed down in a high drag attitude (40 degrees angle of attack). Very close to the deltaV of the OMS-1 burn for a standard insertion. 250, 300, 350 fps? So, what is the difference in drag between 0 degrees angle of attack and 40 degrees angle of attack? 30% maybe less? So, passing through the upper atmosphere at 0 degrees angle of attack would result in an apogee still above the atmosphere, only losing 100-200 fps due to drag. Orbital. While the same trajectory in a heads down 40 degree angle of attack would result in reentry and landing. Entry. ii) OMS fuel usage ATOSS, Available Delta_V = 1000 fps (OMS) + ?250? fps (RCS) = +1250 minus Delta_V premeco = 0 fps minus Delta_V OMS-2 circ = -300 fps minus Delta_V deorbit = -250 fps minus Delta_V circ = -300 fps Subtotal Delta_V available = 400 fps (for drag during atmospheric pass) So far it looks really good, 400 fps should be plenty to compensate for drag during a pass thru the upper atmosphere. iii) Entry heating. I don't think were talking about a great deal of heating here, resulting from a pass through the upper atmosphere. It's only 100-200 fps in drag. It's just not that much drag, energy being dissipated, or atmospheric heating. and finally, iv) Re-Docking at the Space Station Subtotal Delta_V available = 400 fps minus DeltaV atmospheric drag = -200 fps Subtotal Margin for ATOSS = 200 fps So, the Orbiter would arrive at the Space Station with 200 fps of OMS/RCS fuel in it's tanks. -- Craig Fink Courtesy E-Mail Welcome @ |
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What is the Meaning of ATO? the Space Station? Entry?
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What is the Meaning of ATO? the Space Station? Entry?
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What is the Meaning of ATO? the Space Station? Entry?
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What is the Meaning of ATO? the Space Station? Entry?
"Craig Fink" wrote in message news Subtotal Delta_V available = 400 fps (for drag during atmospheric pass) So you can only lose less than 300 miles per hour of velocity to drag before you can no longer "abort" back to orbit. If we assume that you'll lose the same amount due to drag dropping into the atmosphere that you'd lose while performing the OMS burn to get out, that's only 150 miles per hour that you can lose during descent before you have to abort back to orbit. That's less than one percent of orbital velocity, considering that ISS orbit is about 17500 miles per hour (from www.nasa.gov). So, exactly what use is this maneuver again? Jeff -- "They that can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety" - B. Franklin, Bartlett's Familiar Quotations (1919) |
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What is the Meaning of ATO? the Space Station? Entry?
-- Danny Dot www.mobbinggonemad.org "Craig Fink" wrote in message news I said earlier in the thread, that a week about I would have agreed with George, Greg and you. So, obviously, the concept is less that a week old, unless someone else has done it. Which may very well be the case. You want to take it a step further, sure, why not. Let put some actual numbers to it, how about we start with ii) grabbing nearest envelope in sight i) Boundary between Orbital and Entry. After the deorbit burn, what is the minimum drag deltaV (at perigee) required during the pass through the atmosphere? That's simply enough atmospheric drag to reduce apogee equal to perigee while inside the atmosphere. Circular orbit, inside the atmosphere, with the lift vector pointed down in a high drag attitude (40 degrees angle of attack). Very close to the deltaV of the OMS-1 burn for a standard insertion. 250, 300, 350 fps? So, what is the difference in drag between 0 degrees angle of attack and 40 degrees angle of attack? 30% maybe less? So, passing through the upper atmosphere at 0 degrees angle of attack would result in an apogee still above the atmosphere, only losing 100-200 fps due to drag. Orbital. While the same trajectory in a heads down 40 degree angle of attack would result in reentry and landing. Entry. ii) OMS fuel usage ATOSS, Available Delta_V = 1000 fps (OMS) + ?250? fps (RCS) = +1250 minus Delta_V premeco = 0 fps minus Delta_V OMS-2 circ = -300 fps minus Delta_V deorbit = -250 fps minus Delta_V circ = -300 fps Subtotal Delta_V available = 400 fps (for drag during atmospheric pass) So far it looks really good, 400 fps should be plenty to compensate for drag during a pass thru the upper atmosphere. iii) Entry heating. I don't think were talking about a great deal of heating here, resulting from a pass through the upper atmosphere. It's only 100-200 fps in drag. It's just not that much drag, energy being dissipated, or atmospheric heating. and finally, iv) Re-Docking at the Space Station Subtotal Delta_V available = 400 fps minus DeltaV atmospheric drag = -200 fps Subtotal Margin for ATOSS = 200 fps So, the Orbiter would arrive at the Space Station with 200 fps of OMS/RCS fuel in it's tanks. -- Craig Fink Courtesy E-Mail Welcome @ One thing to consider is at 0 degrees angle of attack, you are not generating any lift, just drag. I assume you are looking at changing inclination or something. Or are you looking at protecting for detecting a big hole in the TPS early in entry, then aborting to station rather than complete the entry. Is this correct? One problem is the deorbit burn can normally consume all of the OMS propellant. It would be easy enough to fly lift vector up and skip back up into the vacuum of space and light the OMS engines to get back into orbit. But, if this was a planned contingency, the OMS load would have to carry enough propellant to perform the burn. Today it does not carry this propellant. On a skip entry, I tried it once in the NASA simulator. I had been told that if you skipped, the shuttle would come in so steep on its second entry, it would burn up. The second entry was very benign actually. The shuttle never went to high drag on the second entry. If I had OMS propellant, I am certain I could have used the OMS to get back into orbit. One problem is the software in the shuttle. After it modes to entry, it can not at this time go back to orbit operations. This change to the software could be done I am certain. Another issue for an about back to station is time to rendezvous and consumables. It may take days to get back to station, and the shuttle may not have enough consumables to keep the crew alive. Danny Dot |
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