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#11
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Can you actually see in real-time the
motion of this sound? I don't think so. The evidence that it's a sound wave seems to be the geometry of the pattern itself. Since there's no long-term observations to determine actual velocity of the waves, the question remains open as to whether they're 'gravity waves' propagating at c or sound waves in interstellar gas. IF they are GWs, their chaotic pattern suggests a violent event in the object's past. Possibly the merger of a binary BH pair and subsequent ringdown to the now-quiescent state. oc Anti-spam address: oldcoot88atwebtv.net Change 'at' to@ |
#12
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"Jay Windley" wrote...
in message ... "Rusty Shackleford" wrote in message m... | | Is this an Aetherist interpretation of sound? No. The black hole in question sits in a big gas cloud, which provides a medium in which sound can propagate. If a black hole farts in a cloud of gas, and no one is there to hear it, does it make a sound? Yes! The alternating zones of compaction and rarefaction -- which is how physicists define sound -- can be seen in the photographs. Whether those waves are detected mechanically by a membrane or optically by a telescope makes little difference. Estimates of the density of the the material and the measurable wavelength give us the frequency. -- | The universe is not required to conform | Jay Windley to the expectations of the ignorant. | webmaster @ clavius.org 'Lo Jay and Rusty -- Nope, sorry i disagree... what you describe may be sound *waves* but it is *not* "sound." Sound, in order to *be* sound, must be *heard*. If not heard, then it is not "sound," but merely "sound waves." To use your common analogy, if a tree falls in the forest, and there is no animal/plant(?) around with the ability to hear the tree falling, then the falling tree will not generate sound, i.e., the tree will not be heard. It shall, of course, generate sound *waves*, which will dissipate without being heard. hth happy days and... starry starry nights! -- Life without love is A lamp with no oil, Love without prejudice A world with no soil, A tool with no toil. Paine Ellsworth |
#13
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"Jay Windley" wrote...
in message ... "Rusty Shackleford" wrote in message m... | | Is this an Aetherist interpretation of sound? No. The black hole in question sits in a big gas cloud, which provides a medium in which sound can propagate. If a black hole farts in a cloud of gas, and no one is there to hear it, does it make a sound? Yes! The alternating zones of compaction and rarefaction -- which is how physicists define sound -- can be seen in the photographs. Whether those waves are detected mechanically by a membrane or optically by a telescope makes little difference. Estimates of the density of the the material and the measurable wavelength give us the frequency. -- | The universe is not required to conform | Jay Windley to the expectations of the ignorant. | webmaster @ clavius.org 'Lo Jay and Rusty -- Nope, sorry i disagree... what you describe may be sound *waves* but it is *not* "sound." Sound, in order to *be* sound, must be *heard*. If not heard, then it is not "sound," but merely "sound waves." To use your common analogy, if a tree falls in the forest, and there is no animal/plant(?) around with the ability to hear the tree falling, then the falling tree will not generate sound, i.e., the tree will not be heard. It shall, of course, generate sound *waves*, which will dissipate without being heard. hth happy days and... starry starry nights! -- Life without love is A lamp with no oil, Love without prejudice A world with no soil, A tool with no toil. Paine Ellsworth |
#14
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"Painius" wrote in message ... | | Sound, in order to *be* sound, must be *heard*. If not | heard, then it is not "sound," but merely "sound waves." What does it mean to "hear"? Hearing is the detection of sound waves. Sound waves can be detected via a number of methods. Just because you favor a particular method, and your cranium is equipped with one, doesn't mean that's the only way. -- | The universe is not required to conform | Jay Windley to the expectations of the ignorant. | webmaster @ clavius.org |
#15
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"Painius" wrote in message ... | | Sound, in order to *be* sound, must be *heard*. If not | heard, then it is not "sound," but merely "sound waves." What does it mean to "hear"? Hearing is the detection of sound waves. Sound waves can be detected via a number of methods. Just because you favor a particular method, and your cranium is equipped with one, doesn't mean that's the only way. -- | The universe is not required to conform | Jay Windley to the expectations of the ignorant. | webmaster @ clavius.org |
#16
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Jay W. asks,
What does it mean to "hear"? Hearing is the detection of sound waves. Sound waves can be detected via a number of methods. You got a point there, Jay. "Hearing" is a rather ambiguous term. We can 'hear' radio signals using a suitable downconversion device (i.e., a radio). And we can also hear into the ultrasonic range using a converter. When 'gravity waves' are finally detected and amplified sufficiently, we would actually hear them directly, since their frequency range is expected to overlap the human auditory range. (Look Ma, no downconversion!) oc Anti-spam address: oldcoot88atwebtv.net Change 'at' to@ |
#17
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Jay W. asks,
What does it mean to "hear"? Hearing is the detection of sound waves. Sound waves can be detected via a number of methods. You got a point there, Jay. "Hearing" is a rather ambiguous term. We can 'hear' radio signals using a suitable downconversion device (i.e., a radio). And we can also hear into the ultrasonic range using a converter. When 'gravity waves' are finally detected and amplified sufficiently, we would actually hear them directly, since their frequency range is expected to overlap the human auditory range. (Look Ma, no downconversion!) oc Anti-spam address: oldcoot88atwebtv.net Change 'at' to@ |
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