Formula for calculating Julian Dates

["Vandija Sanoth"; Sun, 14 Sep 2003 18:07:39 GMT]

I just have
one follow-up question.

I have a formula to compute the Julian date. What I really need now is a way
to compute the current UT time into the decimal numbers following the whole
date numbers. Can the decimal time-notation be reliably calculated
independent of the date, since it's only based on the time of day? I would
imagine that there is a simple formula. I'd sincerly appreciate any help.

(FYI, here the macro that gives me the Julian date:

macro InsertJulianDate()
{
int y, m, d, j;
GetDate(y, m, d);
j = d - 32075 + 1461 *(y + 4800 + (m - 14)/12)/4 + 367* (m -2 -
(m - 14)/12*12)/12 - 3*((y + 4900 + (m - 14)/12)/100)/4;
PutInt(j);
}

Now I just need the time too. Thanks!)
--
Vandija Sanoth )