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Sidereal days - amateur question
Okay, it takes 365.25 (roughly) solar days to orbit the sun. So how many
sidereal days does it take? Can't find an answer to this anywhere and it's starting to bug me. If you know the answer could you also explain it please (if you have the time). I'm probably just being thick. Thanks in advance, Bish |
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Sidereal days - amateur question
"Bish Khan" wrote in message ... Okay, it takes 365.25 (roughly) solar days to orbit the sun. So how many sidereal days does it take? Can't find an answer to this anywhere and it's starting to bug me. If you know the answer could you also explain it please (if you have the time). I'm probably just being thick. Thanks in advance, One extra. :-) The stars rise 2 hours earlier, every month, so in a year, an 'extra' sideral day is fitted in (12*2). Best Wishes |
#3
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Sidereal days - amateur question
From surfing the 'net I find
"There is approximately 1 sidereal day more than the number of solar days in a year". You can dig thru this PDF file here for details: http://www.cgtp.duke.edu/~plesser/ph...ork/ex3ans.pdf. hth, Bob Doyle "Bish Khan" wrote in message ... Okay, it takes 365.25 (roughly) solar days to orbit the sun. So how many sidereal days does it take? Can't find an answer to this anywhere and it's starting to bug me. If you know the answer could you also explain it please (if you have the time). I'm probably just being thick. Thanks in advance, Bish |
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Sidereal days - amateur question
HI there. sidereal day. A sidereal day (how long it takes for the
Earth to rotate once with respect to the stars) is 23 hrs 56 minutes 4.092 seconds in length. A mean solar day is 24 hours 0 minutes 0.001 seconds long. Thus, the solar day is about 3.9318 minutes longer than the Sidereal day due to the fact that the Earth is moving about the sun in its orbit. We generally use the solar day for our standard of what a "day" actually is. There are actually several types of "years" used in Astronomy. The Sidereal Year (fixed star transit to fix star transit) is 365.256363 solar days long. The Tropical year (Equinox to equinox) is 365.242190 days. The Anomalistic Year (the time it takes the Earth to go from one perhelion to the next) is 365.259635 days. Clear skies to you. -- David W. Knisely Prairie Astronomy Club: http://www.prairieastronomyclub.org Hyde Memorial Observatory: http://www.hydeobservatory.info/ ********************************************** * Attend the 10th Annual NEBRASKA STAR PARTY * * July 27-Aug. 1st, 2003, Merritt Reservoir * * http://www.NebraskaStarParty.org * ********************************************** |
#5
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Sidereal days - amateur question
"Bish Khan" wrote in
: Okay, it takes 365.25 (roughly) solar days to orbit the sun. So how many sidereal days does it take? Can't find an answer to this anywhere and it's starting to bug me. If you know the answer could you also explain it please (if you have the time). The sidereal day is roughly 4 minutes shorter than the solar day. Convert 24 hours to minutes (multiply by 60). That's the length of the solar day. Subtract 4 minutes. That's the length of the siderial day. Divide the length of the solar day by the length of the siderial day and multiply that by 365.25. You'll get roughly 366.25 sidereal days in a year. Note that that is just one more sidereal day in the year. It's no coincidence. As we advance in our orbit around the sun, the Earth has to rotate a little bit "extra" each day to complete one solar day; i.e., to go from high noon to the next high noon at a given location. That's why the mean solar day is longer than the sidereal day. In the course of a year, the Earth has to turn a total on 1 "extra" time with respect to the stars. -- Steve Gray |
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