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L'Hospital's rule for functions several variables
On Aug 11, 4:29 am, novis wrote:
dear all, is there any concept of L'Hospital's rule for functions several variables? If yes, then what is the corresponding analogue for function of several variables? Thanks For example function of two independent variables x, y, this rule would go like the following: f(x_0,y_0)=0, g(x_0,y_0)=0 , lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = ? lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] (f_x+f_y (dy/dx))/(g_x+g_y (dy/dx))= lim_[(x,y)-(x_0,y_0)] (f_x (dx/dy)+f_y)/(g_x (dx/dy)+g_y)= In order limit to exist these must be independent of dy/dx or dx/dy (limit must be independent of the path how to approach the point (x_0,y_0)). Condition f_x / g_x = f_y / g_y must thus be fullfilled in order that unique limit exist. lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] f_x / g_x = lim_[(x,y)-(x_0,y_0)] f_y / g_y. I thing that this can be similarly be generalized to functions of several independent variables, but now the condition of existence of the unique limit would be little different. Hannu |
#2
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L'Hospital's rule for functions several variables
On Aug 11, 12:12 pm, Hannu Poropudas wrote:
On Aug 11, 4:29 am, novis wrote: dear all, is there any concept of L'Hospital's rule for functions several variables? If yes, then what is the corresponding analogue for function of several variables? Thanks For example function of two independent variables x, y, this rule would go like the following: f(x_0,y_0)=0, g(x_0,y_0)=0 , lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = ? lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] (f_x+f_y (dy/dx))/(g_x+g_y (dy/dx))= lim_[(x,y)-(x_0,y_0)] (f_x (dx/dy)+f_y)/(g_x (dx/dy)+g_y)= In order limit to exist these must be independent of dy/dx or dx/dy (limit must be independent of the path how to approach the point (x_0,y_0)). Condition f_x / g_x = f_y / g_y must thus be fullfilled in order that unique limit exist. lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] f_x / g_x = lim_[(x,y)-(x_0,y_0)] f_y / g_y. I thing that this can be similarly be generalized to functions of several independent variables, but now the condition of existence of the unique limit would be little different. Hannu For example, does (x^2 - y^2)/(x^2 + y^2) have a unique value at origin? If y/x = m as a given direction, then it may be (1 - m^2)/(1 + m^2). |
#3
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L'Hospital's rule for functions several variables
In article om,
Hannu Poropudas wrote: On Aug 11, 4:29 am, novis wrote: dear all, is there any concept of L'Hospital's rule for functions several variables? If yes, then what is the corresponding analogue for function of several variables? Thanks For example function of two independent variables x, y, this rule would go like the following: f(x_0,y_0)=0, g(x_0,y_0)=0 , lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = ? lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] (f_x+f_y (dy/dx))/(g_x+g_y (dy/dx))= lim_[(x,y)-(x_0,y_0)] (f_x (dx/dy)+f_y)/(g_x (dx/dy)+g_y)= In order limit to exist these must be independent of dy/dx or dx/dy (limit must be independent of the path how to approach the point (x_0,y_0)). Condition f_x / g_x = f_y / g_y must thus be fullfilled in order that unique limit exist. lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] f_x / g_x = lim_[(x,y)-(x_0,y_0)] f_y / g_y. I thing that this can be similarly be generalized to functions of several independent variables, but now the condition of existence of the unique limit would be little different. Hannu It's easy to see lim_[(x,y)-(x_0,y_0)] f_x / g_x = lim_[(x,y)-(x_0,y_0)] f_y / g_y = L does not imply lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = L, or even that the last limit exists. |
#4
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L'Hospital's rule for functions several variables
On Aug 11, 9:12 am, Hannu Poropudas wrote:
On Aug 11, 4:29 am, novis wrote: dear all, is there any concept of L'Hospital's rule for functions several variables? If yes, then what is the corresponding analogue for function of several variables? Thanks For example function of two independent variables x, y, this rule would go like the following: f(x_0,y_0)=0, g(x_0,y_0)=0 , lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = ? lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] (f_x+f_y (dy/dx))/(g_x+g_y (dy/dx))= lim_[(x,y)-(x_0,y_0)] (f_x (dx/dy)+f_y)/(g_x (dx/dy)+g_y)= In order limit to exist these must be independent of dy/dx or dx/dy (limit must be independent of the path how to approach the point (x_0,y_0)). Condition f_x / g_x = f_y / g_y must thus be fullfilled in order that unique limit exist. lim_[(x,y)-(x_0,y_0)] f(x,y)/ g(x,y) = lim_[(x,y)-(x_0,y_0)] f_x / g_x = lim_[(x,y)-(x_0,y_0)] f_y / g_y. I thing that this can be similarly be generalized to functions of several independent variables, but now the condition of existence of the unique limit would be little different. Hannu is hopital not hospital you moron |
#5
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L'Hospital's rule for functions several variables
On Aug 12, 1:55 pm, gimp wrote:
On Aug 11, 9:12 am, Hannu Poropudas wrote: On Aug 11, 4:29 am, novis wrote: dear all, is there any concept of L'Hospital's rule for functions several variables? If yes, then what is the corresponding analogue for function of several variables? Thanks ---- Hannu is hopital not hospital you moron If the French circonflex was not emphasized here im maths, is it so bad? |
#6
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L'Hospital's rule for functions several variables
Narasimham wrote:
On Aug 12, 1:55 pm, gimp wrote: On Aug 11, 9:12 am, Hannu Poropudas wrote: On Aug 11, 4:29 am, novis wrote: dear all, is there any concept of L'Hospital's rule for functions several variables? If yes, then what is the corresponding analogue for function of several variables? Thanks ---- Hannu is hopital not hospital... If the French circonflex was not emphasized here im maths, is it so bad? Many different spellings (capitalized ell or not, circumflex or not, ess or not) are found in the literature and, I suspect, during the man's lifetime. The only wrong version would have both a circumflex and an ess. -- Stephen J. Herschkorn Math Tutor on the Internet and in Central New Jersey and Manhattan |
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