A Space & astronomy forum. SpaceBanter.com

Go Back   Home » SpaceBanter.com forum » Others » Misc
Site Map Home Authors List Search Today's Posts Mark Forums Read Web Partners

Help on the freaking simple question that is ****ing me off at the moment



 
 
Thread Tools Display Modes
  #1  
Old September 18th 03, 04:01 AM
Zarkovic
external usenet poster
 
Posts: n/a
Default Help on the freaking simple question that is ****ing me off at the moment

Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow here
is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone on the
surface of the Earth, depending on their latitude. The equation will depend
on person's latitude, (Q), the radius of the Earth, (Re), and the period of
rotation, (T). ( I tried it, but nothing.) (Hints: the speed of a person on
a Northpole is 0 km/hr and speed of a person on the Equator is 1650 km/hr)


  #2  
Old September 18th 03, 04:12 AM
Martin
external usenet poster
 
Posts: n/a
Default

"Zarkovic" wrote in
news:ye9ab.8990$CU3.7779@pd7tw3no:

Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow
here is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone
on the surface of the Earth, depending on their latitude. The equation
will depend on person's latitude, (Q), the radius of the Earth, (Re),
and the period of rotation, (T). ( I tried it, but nothing.) (Hints:
the speed of a person on a Northpole is 0 km/hr and speed of a person
on the Equator is 1650 km/hr)




Speed = cosine(latitude)*1650

Martin Lewicki
  #3  
Old September 18th 03, 04:12 AM
Martin
external usenet poster
 
Posts: n/a
Default

"Zarkovic" wrote in
news:ye9ab.8990$CU3.7779@pd7tw3no:

Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow
here is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone
on the surface of the Earth, depending on their latitude. The equation
will depend on person's latitude, (Q), the radius of the Earth, (Re),
and the period of rotation, (T). ( I tried it, but nothing.) (Hints:
the speed of a person on a Northpole is 0 km/hr and speed of a person
on the Equator is 1650 km/hr)




Speed = cosine(latitude)*1650

Martin Lewicki
  #4  
Old September 18th 03, 04:30 AM
G.P
external usenet poster
 
Posts: n/a
Default


"Zarkovic" wrote in message
news:ye9ab.8990$CU3.7779@pd7tw3no...
Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow here
is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone on

the
surface of the Earth, depending on their latitude. The equation will

depend
on person's latitude, (Q), the radius of the Earth, (Re), and the period

of
rotation, (T). ( I tried it, but nothing.) (Hints: the speed of a person

on
a Northpole is 0 km/hr and speed of a person on the Equator is 1650 km/hr)


Assuming the earth is perfectly round:

Speed = [2 * Pi * Re * Cosine(Q)] / T

How it is done? just find the perimeter of the circle described by the
person as it rotates for the duration of the period T. Then divide that
perimeter by the period T to find the speed.

Am I doing your homework?

Guillermo


  #5  
Old September 18th 03, 04:30 AM
G.P
external usenet poster
 
Posts: n/a
Default


"Zarkovic" wrote in message
news:ye9ab.8990$CU3.7779@pd7tw3no...
Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow here
is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone on

the
surface of the Earth, depending on their latitude. The equation will

depend
on person's latitude, (Q), the radius of the Earth, (Re), and the period

of
rotation, (T). ( I tried it, but nothing.) (Hints: the speed of a person

on
a Northpole is 0 km/hr and speed of a person on the Equator is 1650 km/hr)


Assuming the earth is perfectly round:

Speed = [2 * Pi * Re * Cosine(Q)] / T

How it is done? just find the perimeter of the circle described by the
person as it rotates for the duration of the period T. Then divide that
perimeter by the period T to find the speed.

Am I doing your homework?

Guillermo


  #6  
Old September 18th 03, 04:43 AM
Zarkovic
external usenet poster
 
Posts: n/a
Default

Ahhh man, thanks guys. For some reason I turned my sphere around and I used
for equator speed cos (90) which equals to 0 , but I should have used cos
(0) instead. Sorry for the mix up, and thanks once again to both of you.


  #7  
Old September 18th 03, 04:43 AM
Zarkovic
external usenet poster
 
Posts: n/a
Default

Ahhh man, thanks guys. For some reason I turned my sphere around and I used
for equator speed cos (90) which equals to 0 , but I should have used cos
(0) instead. Sorry for the mix up, and thanks once again to both of you.


  #8  
Old September 18th 03, 12:53 PM
Ron Miller
external usenet poster
 
Posts: n/a
Default


"Zarkovic" wrote in message
news:ye9ab.8990$CU3.7779@pd7tw3no...
Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow here
is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone on

the
surface of the Earth, depending on their latitude. The equation will

depend
on person's latitude, (Q), the radius of the Earth, (Re), and the period

of
rotation, (T). ( I tried it, but nothing.) (Hints: the speed of a person

on
a Northpole is 0 km/hr and speed of a person on the Equator is 1650 km/hr)


I don't know what the radius of the earth would have to do with it. Your
speed depends on your perpendicular distance from the earth's axis (as
though the latitude you are at is the circumference of a wheel that is
spinning on the axis).

R


  #9  
Old September 18th 03, 12:53 PM
Ron Miller
external usenet poster
 
Posts: n/a
Default


"Zarkovic" wrote in message
news:ye9ab.8990$CU3.7779@pd7tw3no...
Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow here
is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone on

the
surface of the Earth, depending on their latitude. The equation will

depend
on person's latitude, (Q), the radius of the Earth, (Re), and the period

of
rotation, (T). ( I tried it, but nothing.) (Hints: the speed of a person

on
a Northpole is 0 km/hr and speed of a person on the Equator is 1650 km/hr)


I don't know what the radius of the earth would have to do with it. Your
speed depends on your perpendicular distance from the earth's axis (as
though the latitude you are at is the circumference of a wheel that is
spinning on the axis).

R


  #10  
Old September 18th 03, 01:56 PM
Roger Hamlett
external usenet poster
 
Posts: n/a
Default


"Ron Miller" wrote in message
...

"Zarkovic" wrote in message
news:ye9ab.8990$CU3.7779@pd7tw3no...
Hi guys, here is one question that I can't get for some reason, I just
can't. I come close to it, but everytime I am by 300km/hr off. Anyhow

here
is the question and could someone please tell me how it's done.

"Derive the equation from which you could calculate speeds of someone on

the
surface of the Earth, depending on their latitude. The equation will

depend
on person's latitude, (Q), the radius of the Earth, (Re), and the period

of
rotation, (T). ( I tried it, but nothing.) (Hints: the speed of a person

on
a Northpole is 0 km/hr and speed of a person on the Equator is 1650

km/hr)


I don't know what the radius of the earth would have to do with it. Your
speed depends on your perpendicular distance from the earth's axis (as
though the latitude you are at is the circumference of a wheel that is
spinning on the axis).

Because that perpendicular distance, is cos(Q)*Re...
You either have to have the radius of the Earth, or another way of working
out that perpendicular distance.

Best Wishes


 




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
PDF (Planetary Distance Formula) explains DW 2004 / Quaoar and Kuiper Belt hermesnines Astronomy Misc 10 February 27th 04 02:14 AM
Moon key to space future? James White Policy 90 January 6th 04 04:29 PM
ODDS AGAINST EVOLUTION (You listenin', t.o.?) Lord Blacklight Astronomy Misc 56 November 21st 03 02:45 PM
Very simple question Earth Resident Science 7 October 8th 03 12:09 AM
A Simple question!!!!!!! Paul Mannion History 1 August 9th 03 01:12 AM


All times are GMT +1. The time now is 01:02 PM.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.
Copyright ©2004-2024 SpaceBanter.com.
The comments are property of their posters.