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Redshift without expansion
Reading Jan Pantelljes thread on redshift has got me
thinking again about how to try to explain redshift without expansion but still accomodating a constant c. At first it seems an intractible problem.But I realize that approaching it in the usual manner by accepting a constant c and an observed redshift and extrapolating a expanding universe to make everything fit isnt the only approach. Instead, I try to see if a constant c can be consistent with an observed redshift due to distance in a *non expanding universe*. So rather than checking whether space needs to be variable I check whether speed needs to be variable. And my results show that in fact with a non expanding universe c can still be constant. I believe that I can show this to be the case by using lateral thinking and treating light not as a particle but as a classical virtual wave. More specifically I treat light as an information wave expanding outwards from source facilitated by ever increasing rings of theoretical oscilatting points in space (or as below as observors at these theoretical points) with a decrease in frequency in oscillations where the distance increases. So rather than a photon travelling outwards I instead set up a thought experiment where at regular equally spaced points radiating out from the source I place observors who see light ever more redshifted the farther from source they are located. The 01 patterns refer to the frequency observed . So for instance whereas observor 1 observes 1 beat every 4 time units, observor 4 sees 1 beat every 10 time units. (ie lower frequency observed the farther away from source). As you can see if the distance between each observor and between observor 1 and source are equal then it becomes clear from the chart that the speed of light is constant even though the observed frequency becomes lower the farther from source. One extra point is that some critics will say.." but light appears to be disappearing as it expands outwards from source". Take for instance the light wave marked by `x`. It appears that it vanishes after observor 1. Yet this is an illusion because in fact light isnt treated as a moving photon but rather as a virtual wave tracing the pattern of beats observed emanating out from source.As the light is treated as a pattern of oscillting points in space in actual fact no energy is lost as all observors `see` light coming constantly from the source. Its just that the farther away one is from source the redder this light appears. Or in different terms the further from source the slower the measured frequency of light. It is an illusion that the light marked x disappears after observor 1. In fact as no object is moving no object gets lost. (Note that below distance is horizontal axis and time is the vertical axis) | | | | | Source observor1 observor2 observor3 observor4 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1x 0 1 0 0 0 0 0 0 0 1 1x 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 1 0 0 0 1 Ive repeated the pattern enough times to show that observor 4 sees a pattern that repeats at a frequency of 1/10. As you can see from this layout above each observor `sees` light at a certain frequency and that frequency decreases the farther away from source relative to distance , YET, at the same time the speed of the `wave` going out from source is constant. So to summarize; redshift and a constant c can be consistent with a non expanding universe as long as light is treated as a moving series of peaks due to stationary oscilatting points in space and not as a moving object like a photon. Sean |
#2
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Redshift without expansion
On a sunny day (18 Jun 2006 06:19:54 -0700) it happened "sean"
wrote in .com: So to summarize; redshift and a constant c can be consistent with a non expanding universe as long as light is treated as a moving series of peaks due to stationary oscilatting points in space and not as a moving object like a photon. Sean Hi, it does not make sense to me, yes you can set up those observers, but given c for lightspeed, and equal distance for observers, and you say f (color) changes [for those observers], then what makes it change? There ar several theories, 'tired light' was discussed here, some static 'electrostatic effect' was also discussed, the consensus is doppler, due to that the observers are moving away from each other, what do you propose the mechanism is here? |
#3
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Redshift without expansion
In article .com,
sean wrote: So to summarize; redshift and a constant c can be consistent with a non expanding universe as long as light is treated as a moving series of peaks due to stationary oscilatting points in space and not as a moving object like a photon. Explain why Cepheids and Type 1A SN are in agreement with the Hubble method of ascertainig distance...? -- The greatest enemy of science is pseudoscience. Jaffa cakes. Sweet delicious orangey jaffa goodness, and an abject lesson why parroting information from the web will not teach you cosmology. Official emperor of sci.physics. Please pay no attention to my butt poking forward, it is expanding. Relf's Law? "Bull**** repeated to the limit of infinity asymptotically approaches the odour of roses." |
#4
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Redshift without expansion
"sean" wrote in message oups.com... ... So rather than a photon travelling outwards I instead set up a thought experiment where at regular equally spaced points radiating out from the source I place observors who see light ever more redshifted the farther from source they are located. The 01 patterns refer to the frequency observed . So for instance whereas observor 1 observes 1 beat every 4 time units, observor 4 sees 1 beat every 10 time units. (ie lower frequency observed the farther away from source). As you can see if the distance between each observor and between observor 1 and source are equal then it becomes clear from the chart that the speed of light is constant even though the observed frequency becomes lower the farther from source. One extra point is that some critics will say.." but light appears to be disappearing as it expands outwards from source". Take for instance the light wave marked by `x`. It appears that it vanishes after observor 1. Yet this is an illusion because in fact light isnt treated as a moving photon but rather as a virtual wave tracing the pattern of beats observed emanating out from source.As the light is treated as a pattern of oscillting points in space in actual fact no energy is lost as all observors `see` light coming constantly from the source. The energy is proportional to the frequency so the fact that more distant observers see lower frequencies means that energy _is_ being lost however you explain it. Its just that the farther away one is from source the redder this light appears. Or in different terms the further from source the slower the measured frequency of light. It is an illusion that the light marked x disappears after observor 1. In fact as no object is moving no object gets lost. (Note that below distance is horizontal axis and time is the vertical axis) | | | | | Source observor1 observor2 observor3 observor4 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1u 1 0 0 0 0 0 0 0 0 1x 0 1 0 0 0 0 0 0 0 1v 1x 0 1 0 0 0 0 0 0 1w 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1y 1 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 1z 1 0 1 0 0 0 0 0 0 1 0 0 0 1 Ive repeated the pattern enough times to show that observor 4 sees a pattern that repeats at a frequency of 1/10. As you can see from this layout above each observor `sees` light at a certain frequency and that frequency decreases the farther away from source relative to distance , I think you got it wrong somewhere, observers 2, 3 and 4 all see the same frequency in your diagram. Also observer 2 doesn't see a consistent frequency, the gaps between the '1's are unequal. You also seem to have lost the cycles I have labelled 1u, 1v, 1w, 1y and 1z. George |
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Redshift without expansion
Dear Jan Panteltje:
"Jan Panteltje" wrote in message ... On a sunny day (18 Jun 2006 06:19:54 -0700) it happened "sean" wrote in .com: So to summarize; redshift and a constant c can be consistent with a non expanding universe as long as light is treated as a moving series of peaks due to stationary oscilatting points in space and not as a moving object like a photon. Hi, it does not make sense to me, yes you can set up those observers, but given c for lightspeed, and equal distance for observers, and you say f (color) changes [for those observers], then what makes it change? There ar several theories, 'tired light' was discussed here, some static 'electrostatic effect' was also discussed, the consensus is doppler, due to that the observers are moving away from each other, what do you propose the mechanism is here? Sounds like dispersion. As the "light wave" moves outwards from the source, a dispersive medium will remove energy from the wave, yielding a loss in energy (frequency). Of course a dispersive medium affects different wavelengths differently, and fails to describe the "red shift" of the duration of type Ia supernovae... David A. Smith |
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Redshift without expansion
Ive responded to all replies here in one post...
From: Jan Panteltje Hi, it does not make sense to me, yes you can set up those observers, but given c for lightspeed, and equal distance for observers, and you say f (color) changes [for those observers], then what makes it change? There ar several theories, 'tired light' was discussed here, some static 'electrostatic effect' was also discussed, the consensus is doppler, due to that the observers are moving away from each other, what do you propose the mechanism is here? Hi Jan. George pointed out errors and Ive fixed and simplified the illustration below so it should be clearer now hopefully? As far as the mechanism goes, well what Im doing here is only supplying redshifted data and showing that the data does indeed show light as a wave propogating out at constant speeds where the universe isnt expanding. As far as a mechanism goes well I dont know yet what the vacuum is or why reality exists. Then again no other theory except maybe creationism can say why we are here.And no theory has yet to explain what the vacuum is made of and how light can propogate as a wave in it. Certainly not the standard model. So I dont see the need to work out mechanisms just yet. Except to say that energy appears to propogate out through a vacuum and that we can detect it as oscillating frequencies of energy at points in space. Quite why light frequencies are observed to decrease the farther from source isnt something I can comment on except to say,.. Thats whats observed so we`ll have to accept it as fact. My advantage is that although I dont supply a explanation as to why the observors light gets redder with distance, I dont have to add in a expanding universe. Which isnt explained by BB theorists either. Its worth pointing out though that if light were to not decrease in observed frequency the farther from source in a non expanding universe it would then be travelling at infinite speeds Look at my graph and imagine if observor 1 and 2 were seeing the same freqeuncy. The lines would be horizontal and instantaneous travel would be a reality. Which isnt observed. In other words the data shows us that if light travels at a constant speed c , it would have to lose frequency with distance. So in a sense thats my explanation of why light redshifts. It has to to fit the mathematical model. That mathematicians (like Uncle phineas) havent realized this going back to when redshift was discovered is a monument to their collective stupidity. From: David A. Smith Sounds like dispersion. As the "light wave" moves outwards from the source, a dispersive medium will remove energy from the wave, yielding a loss in energy (frequency). Of course a dispersive medium affects different wavelengths differently, and fails to describe the "red shift" of the duration of type Ia supernovae... Ive already shown on newsgroups how these conclusions of SN never checked if the data fitted a non expanding model. Look at any paper and youll see that at no time is z replaced with 0 in any formula calculations. The second point is if you do substitute z with 0 then you can fit the available raw SN data to a non dilated template and show as a good a fit as that of a dilated template. The problem is that the data available in about 25% of cases at least has been altered to fit the dilated template by having its flux increased or decreased by up to 15% because the data DIDNT fit the dilated model. Read Knop 12 903 to see even he admits this fiddle. So in these examples the fit doesnt work as well to a non dilated template but..if one removes the 15% adjustment then all examples fit a non dilated template as well as a dilated template. From: George Dishman The energy is proportional to the frequency so the fact that more distant observers see lower frequencies means that energy _is_ being lost however you explain it. Im not exactly sure what you mean here. Are you saying that this idea cant work because each observor sees less energy in my model and that has to be explained by me as this isnt observed by astronomers. Or are you saying astronomers observe less energy and this isnt explained by my model? I think you got it wrong somewhere, observers 2, 3 and 4 all see the same frequency in your diagram. ? No. How did you figure that? Look again Observor 2 Also observer 2 doesn't see a consistent frequency, the gaps between the '1's are unequal. You also seem to have lost the cycles I have labelled 1u, 1v, 1w, 1y and 1z. Sorry Ive revised it so each observor should *now* have a constant observed frequency. Ive also reduced it to two observors at twice the distance and twice the frequency which represents the idea better as it can scale up or down infinitely. As you can see all light propogation is at the same speed and its constant in all examples. (distance across in units, time down in equal units per line) 0 1/2 1 Source observor1 observor2 0 0 0 1x 0 0 0 1x 0 1x 0 1x 0 0 0 1x 0 0 0 1x(yy) 0 1x 0 0 (yy) 0 0 0 1x 0 0 0 1x 0 1x 0 1x 0 0 0 1x 0 0 0 1x 0 1x 0 0 0 0 0 1x 0 0 0 1x 0 1x 0 1x As for your point that lines disappear as in example above..at (yy). This is an illusion as in fact these lines are virtual paths. They dont represent a photon travelling through space but rather show lines of peaks through space/time and are only there to show that the peaks of each freqeuncy which are themselves only abstract units can be traced through time at constant speeds. Dont forget speed is an abstract concept only on paper. We derive speed from mathematically combining distance and time. Which is what Ive done above. Instead of a object measured at various points in space/time and deriving an abstract speed. I measure frequencies at various points in space time and draw abstract lines from one peak to the next previous peak and back to source and derive a constant speed in all cases. Also please note,.. at (yy) in fact NO cycle is broken nor any interruption of energy is observed. See how observor 2 at (yy) experiences no loss of energy or interruption of observed frequency. Im open to you pointing out any other errors but it seems to me Ive got it above correct now and it is indisputable that the illustration shows a non expanding universe with a constant c where the observed frequency diminishes with distance. Sean |
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Redshift without expansion
On a sunny day (19 Jun 2006 09:07:43 -0700) it happened "sean"
wrote in .com: Its worth pointing out though that if light were to not decrease in observed frequency the farther from source in a non expanding universe it would then be travelling at infinite speeds This is not correct. What you say here is: 'Light frequency drops over distance.' And you are also implying that that has to do with the speed at which light travels. Whatever picture you may have of light, if we take a pond, throw a stone in it, we see a circular wave pattern emerging from where the stone hit the water. The wavelength (frequency) will not change. Ducks at fixed positions from the source (1 meter, 2 meters, etc) will bump up and down on those waves in the *same* frequency, and the pool was not expanding. (Somebody else give the particle 'photon' explanation, this was the 'wave' one). So I think you have some misunderstanding of what EM waves are. For a moment yesterday it thought you wanted to state that *time* changed, but this does not seem to be the case. You can see from above model that as a duck swims away from where the stone hit, the faster it goes the less bumps (wave maxima) it will pass per unit of time, it sees a lower 'frequency', Doppler effect. If the duck was fast enough, then it could even keep up with the wave and see DC (a fixed elevation level, it could always ride a 'high' (wave top) or 'low' (wave bottom, or anywhere in between.). |
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Redshift without expansion
"Jan Panteltje" wrote in message ... On a sunny day (19 Jun 2006 09:07:43 -0700) it happened "sean" wrote in .com: Its worth pointing out though that if light were to not decrease in observed frequency the farther from source in a non expanding universe it would then be travelling at infinite speeds This is not correct. What you say here is: 'Light frequency drops over distance.' And you are also implying that that has to do with the speed at which light travels. Whatever picture you may have of light, if we take a pond, throw a stone in it, we see a circular wave pattern emerging from where the stone hit the water. The wavelength (frequency) will not change. Ducks at fixed positions from the source (1 meter, 2 meters, etc) will bump up and down on those waves in the *same* frequency, and the pool was not expanding. If I understand Sean's diagram, he is suggesting that at some point after passing the first duck, every second wave vanishes for no apparent reason. The waves travel at constant speed but subsequent ducks observe a lower frequency. Of course the means the only frequency change that wouldn't produce sidebands would be a factor of two, think what would happen to the next duck if every third wave vanished. George |
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Redshift without expansion
George Dishman wrote: If I understand Sean's diagram, he is suggesting that at some point after passing the first duck, every second wave vanishes for no apparent reason. The waves travel at constant speed but subsequent ducks observe a lower frequency. Of course the means the only frequency change that wouldn't produce sidebands would be a factor of two, think what would happen to the next duck if every third wave vanished. These points lines defined by x`s arent waves . You say the duck would find every that every third wave vanished and this would disrupt its bobbing cycle. But look at the duck at observor 3 cycle before, during and after point BBB in time. Its cycle remains unchanged. Wheres the disrupted bobbing cycle? What wave disappears? Dont forget this is a schematic diagram with the lines of x`s only there to join up the observed peaks in space time and they arent meant to be or cannot be considered even by any stretch of the imagination as a wave. Their purpose is twofold. To show that the general flow of information of light is constant, which it does, and also as bar charts showing energy loss over distance. 0 1/2 1 Source observor1 observor2 0 0 0 1x 0 0 0 1x 0 1x 0 1x 0 0 0 1x 0 0 0 1x 0 1x 0 0 BBB 0 0 0 1x 0 0 0 1x 0 1x 0 1x Ive done a more detailed statistical version which Ill describe a bit more below, but its clear from the diagram that the `lines` you call waves reduce with distance . I think its an inverse proportional relationship which would be whats observed I think.Anyways the lines are a good indicator of flux/brightness relative to distance as well as indicating for all lines and all fractions a constant speed. So I must correct you again and say that theyre not waves and at no time is any observors cycle or observed frequency disrupted or is any information wave or anything else lost except for that mentioned above due to distance and brightness. But Ive listened to your criticism about the graph not working in 1/2`s and would like to correct that misunderstanding too. The chart does work 1/2 or 1/4 etc. The problem is that the above 2 observor graph is a template only showing how a frequency change can give a constant speed. Which it does. But it needs numbers and data fed into it to work on more levels and Ive done that to an extent now. Its more complex but what it works out to is Ive got the redshift halving each level of distance unit. Starting at frequencies 48,24,12,6,3,1.5,0.75 0.35, 0... And each level assigns to a standard distance. So 6 is 5 units, 3 is 4 units 1.5 3 units, 0.75 2 units0.375 1 unit. Seeing as 6 is z=5 Ive asigned each unit ~2.5 billion light years, but thats flexible. Ive used that because as best as I can find out z=5 is somewhere between 12-15 billion light years. Ive got ambiguous figures for this so if you know what z=5 is in light years please feel free.(also z=3,1.5 and 0.75 would be nice if you could) So if the universe is considered not to be expanding then I can give approximate distances from redshifts based on what my model calculates.. z=6 =~12.5 billion light years z=3 =~9-10 z=1.5 =~6-7.5 z=0.75 =~3-5 z=0.375 =~1-2.5 Im not sure if thats matched by whats assumed as distance from the expansion model , but Ill have to admit I cant figure out how a redshift of z=6 works out in distance. Even Neds page, although it gives lots of help doesnt like to say for sure if distance is `how far it was from us when the light left` or `how far the light has travelled since`. From what I can tell both are quite different numbers but you must be way more familiar with this than I. Sean www.gammarayburst.com |
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Redshift without expansion
On a sunny day (21 Jun 2006 05:50:20 -0700) it happened "sean"
wrote in .com: If the duck was fast enough, then it could even keep up with the wave and see DC (a fixed elevation level, it could always ride a 'high' (wave top) or 'low' (wave bottom, or anywhere in between.). Yes but as I say above were not talking now about ducks on water waves. My impression is that light does not propogate in the same mechanical way as the water waves? Sean I was under the impression Maxwell used fluid analogy top get his equations. I still cannot confuse myself enough to follow you reasoning in that example. The EM wave *moves*, and you will see amplitude variations (as the duck sees), the amount of bobbing of the duck is related to wave amplitude, the frequency to wave frequency (for stationary ducks), when one moves you get a frequency change. Its nature. |
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