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Electrostatic potential between the Sun and the Earth
What is the electrostatic potential between the sun and the earth?
Also how does the electrostatic force between the sun and the earth compare to the gravitational force between the sun and the earth? |
#2
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Electrostatic potential between the Sun and the Earth
"Duncan Macdonald" wrote in message ...
What is the electrostatic potential between the sun and the earth? Also how does the electrostatic force between the sun and the earth compare to the gravitational force between the sun and the earth? Should be very low, practical zero. What creates electrostatic potential is electrical charge, which results from the proton/electron imbalance. Neither the Sun nor the Earth have any significant charge in the body as a whole. The Sun, being hotter, does lose some electrons, but the effect is ultimately insignificant. Electrical force at the particle level is much stronger than gravity, and can even overpower nuclear forces. However, gravitational force adds up much more efficiently at the larger scale, thus being the dominating force for all cosmic objects. Vlad |
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Electrostatic potential between the Sun and the Earth
Why would the potential of the sun be near zero ?
Assuming that the sun started off with no net charge, the following conditions should soon (in astronomical terms) leave the sun with a high positive charge. 1) Electrons weigh a lot less than protons 2) It therefore takes far less energy to accelerate an electron to escape velocity than it does to accelerate a proton to escape velocity 3) The initial solar wind should therefore have more electrons than protons in it until the positive charge built up on the sun to the point that it exerted sufficient extra attractive force on the electrons and repulsive force on the protons to cause the solar wind to be neutral. I do not know what this potential would be but I doubt that it is anything near zero. |
#4
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Electrostatic potential between the Sun and the Earth
"Duncan Macdonald" wrote in message
... Why would the potential of the sun be near zero ? Assuming that the sun started off with no net charge, the following conditions should soon (in astronomical terms) leave the sun with a high positive charge. 1) Electrons weigh a lot less than protons 2) It therefore takes far less energy to accelerate an electron to escape velocity than it does to accelerate a proton to escape velocity 3) The initial solar wind should therefore have more electrons than protons in it until the positive charge built up on the sun to the point that it exerted sufficient extra attractive force on the electrons and repulsive force on the protons to cause the solar wind to be neutral. I do not know what this potential would be but I doubt that it is anything near zero. Any net charge would attract its opposite and there would quickly arise a cancellation. Net electric charge is not very long-lived in the universe. Note that a large component of the solar wind is protons. Eventually these would "sop up" any lone electrons and form hydrogen. |
#5
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Electrostatic potential between the Sun and the Earth
For the current net solar wind to be electrically neutral, there has to be
something compensating for the fact that electrons can be accelerated to solar escape velocity more easily than protons. The only mechanism that I can see that could do the compensation is for the sun to have a net positive charge. This is a dynamically generated and maintained charge - if the potential falls then more electrons escape and the potential increases, if the potential rises then fewer electrons escape and the potential decreases. When (in several billion years) the sun has finally cooled down to a black dwarf, there will be no solar wind and the charge will finally drop to zero as there will be nothing to maintain the charge but at the moment the solar energy generation provides the power source to maintain the charge. |
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Electrostatic potential between the Sun and the Earth
Midjis wrote
I do recall - I think - reading something at one point about electrical 'interference' (if that is the right word) between Io and Jupiter. Does this occur? If so I assume it would be due to electrical activity in Jupiter's high atmosphere and the intensely volcanic nature of Io (which I assume is itself a consequence of the moon's proximity to such a large gravity source) You may be thinking of the flux tube between Io and Jupiter (detected by Voyager). Try this link http://www.solarviews.com/eng/vgrjup.htm and scroll down to Magnetosphere Denis -- DT Replace nospam with the antithesis of hills |
#7
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Electrostatic potential between the Sun and the Earth
In message , Duncan
Macdonald writes For the current net solar wind to be electrically neutral, there has to be something compensating for the fact that electrons can be accelerated to solar escape velocity more easily than protons. The only mechanism that I can see that could do the compensation is for the sun to have a net positive charge. This is a dynamically generated and maintained charge - if the potential falls then more electrons escape and the potential increases, if the potential rises then fewer electrons escape and the potential decreases. When (in several billion years) the sun has finally cooled down to a black dwarf, there will be no solar wind and the charge will finally drop to zero as there will be nothing to maintain the charge but at the moment the solar energy generation provides the power source to maintain the charge. There seems to be a large literature on electron velocity in the solar wind, most of which is way over my head! But I suspect that your comment that electrons "can" be accelerated to higher speed is irrelevant. As soon as any such charge separation occurred electrostatic effects would come into play, and they are much larger than gravity. I did notice that John Gard's site at http://www.1stardrive.com/solar/wind.htm seems to support your view. -- What have they got to hide? Release the full Beagle 2 report. Remove spam and invalid from address to reply. |
#8
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Electrostatic potential between the Sun and the Earth
"Duncan Macdonald" wrote in message . ..
Assuming that the sun started off with no net charge, the following conditions should soon (in astronomical terms) leave the sun with a high positive charge. 1) Electrons weigh a lot less than protons 2) It therefore takes far less energy to accelerate an electron to escape velocity than it does to accelerate a proton to escape velocity 3) The initial solar wind should therefore have more electrons than protons in it until the positive charge built up on the sun to the point that it exerted sufficient extra attractive force on the electrons and repulsive force on the protons to cause the solar wind to be neutral. I do not know what this potential would be but I doubt that it is anything near zero. The process is pretty much as you have outlined. Still, calculation based on the positive potential energy of a proton being equal to the negative gravitational energy gives the maximim possible electrical potential of ~2000 volts. Actual value of the solar potential is significantly smaller, taking into account its radiation-pressure (thermal) forces (and some other factors). It is very low; "practical zero" was meant to characterize its force relative to that of the gravity, as stated in the initial question. Vlad |
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Electrostatic potential between the Sun and the Earth
"DM" == Duncan Macdonald writes:
DM What is the electrostatic potential between the sun and the earth? DM Also how does the electrostatic force between the sun and the DM earth compare to the gravitational force between the sun and the DM earth? Let's turn the question around. How much charge would have to be on the Earth and Sun for their electrostatic attraction (or repulsion) to equal their gravitational attraction? Because both forces are 1/r^2 forces, our problem simplifies to G*M_E*M_S = Q_E*Q_S/(4*pi*eps_0). Let's assume that the ratio of the charges is the same as the ratio of the masses, M_E/M_S = Q_E/Q_S = 3E-6. Knowing a few other constants, G = 6.67E-11 N m^2/kg^2 and eps_0 = 8.8542E-12 farad/m, we find that Q_E*Q_S = 8.9E34, or with our simplifying assumption, Q_S = 5.2E20 C. The charge on an electron is 1.6E-19 C, so this charge is equivalent to 3.2E39 electrons on the Sun. That sounds like a big number, but remember that the mass of the Sun is M_S = 2E30 kg and the mass of a hydrogen atom is about 1.67E-27 kg, or that there are about 1.2E57 hydrogen atoms or electrons in the Sun. We conclude that if the charge on the Sun deviated from neutral by more than about one part in 1E17, the electrostatic forces would begin to overwhelm the gravitational forces. In other words, the Sun is neutral to a very good approximation. -- Lt. Lazio, HTML police | e-mail: No means no, stop rape. | http://patriot.net/%7Ejlazio/ sci.astro FAQ at http://sciastro.astronomy.net/sci.astro.html |
#10
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Electrostatic potential between the Sun and the Earth
Interesting!
Changing the subject a bit ... The Earth is (I'm assuming) very nuetral electrostatically so even if the Sun had a strong electrostatic field about it, there would be no effect ... We know that there is a steady stream of charged particles (mostly electrons (I assume)) leaving the Sun (The Solar Wind) ... what is the electrostatic strength of this field I wonder? Suppose two white dwarf stars were orbiting one another ... would the electrostatic forces between them be significant (assuming White Dwarfs have Solar Winds too)? Al "Joseph Lazio" wrote in message ... "DM" == Duncan Macdonald writes: DM What is the electrostatic potential between the sun and the earth? DM Also how does the electrostatic force between the sun and the DM earth compare to the gravitational force between the sun and the DM earth? Let's turn the question around. How much charge would have to be on the Earth and Sun for their electrostatic attraction (or repulsion) to equal their gravitational attraction? Because both forces are 1/r^2 forces, our problem simplifies to G*M_E*M_S = Q_E*Q_S/(4*pi*eps_0). Let's assume that the ratio of the charges is the same as the ratio of the masses, M_E/M_S = Q_E/Q_S = 3E-6. Knowing a few other constants, G = 6.67E-11 N m^2/kg^2 and eps_0 = 8.8542E-12 farad/m, we find that Q_E*Q_S = 8.9E34, or with our simplifying assumption, Q_S = 5.2E20 C. The charge on an electron is 1.6E-19 C, so this charge is equivalent to 3.2E39 electrons on the Sun. That sounds like a big number, but remember that the mass of the Sun is M_S = 2E30 kg and the mass of a hydrogen atom is about 1.67E-27 kg, or that there are about 1.2E57 hydrogen atoms or electrons in the Sun. We conclude that if the charge on the Sun deviated from neutral by more than about one part in 1E17, the electrostatic forces would begin to overwhelm the gravitational forces. In other words, the Sun is neutral to a very good approximation. -- Lt. Lazio, HTML police | e-mail: No means no, stop rape. | http://patriot.net/%7Ejlazio/ sci.astro FAQ at http://sciastro.astronomy.net/sci.astro.html |
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