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Practical astronomy
It is common among empiricists to attribute a variation in the Earth's
rotation to so-called tidal friction - http://bowie.gsfc.nasa.gov/ggfc/tides/intro.html Notwithstanding the silly reasoning behind variations in axial rotation using the return of a star to a location using the calendrically based 23 hour 56 min value,would anyone here care to put the depth of the ocean (average depth 2 miles) in context with the Earth's diameter (6 900 miles) using the size of a bowling ball as a gauge (12 inches/215 mm). The idea is to appreciate the power of geodynamics rather than have it subservient to the surface ocean.So,in terms of millimeters or fractions of an inch,how thin is the ocean with respect to planetary diameter in terms of the veneer on a bowling ball ? |
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Practical astronomy
On Fri, 4 Jul 2008 09:06:50 -0700 (PDT), oriel36
wrote: The idea is to appreciate the power of geodynamics rather than have it subservient to the surface ocean.So,in terms of millimeters or fractions of an inch,how thin is the ocean with respect to planetary diameter in terms of the veneer on a bowling ball ? Do you think that dragging a 50um film of fluid over the surface of a bowling ball wouldn't have any effect on its rotation? Nonsense. There are good mathematical models of Earth's rotation that demonstrate how both solid-Earth tides and ocean tides contribute to the observed long and short term rotational rate variation. The actual forces that the ocean is able to exert on the Earth are very small, but so is the net effect of those forces. _________________________________________________ Chris L Peterson Cloudbait Observatory http://www.cloudbait.com |
#3
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Practical astronomy
On Jul 4, 10:06*am, oriel36 wrote:
would anyone here care to put the depth of the ocean (average depth 2 miles) in context with the Earth's diameter (6 900 miles) using the size of a bowling ball as a gauge (12 inches/215 mm). It is well known that the mountains and oceans of the Earth are extremely tiny compared to the Earth. But then, the variations in the period of the Earth's rotation are also very tiny, only able to be detected now that atomic clocks are available. So it is unclear to me where the contradiction lies. The Earth's diameter is 7,923 miles, so we're talking about .003 inches being the equivalent of 2 miles. (Incidentally, 12 inches is just over 30 centimeters: about 305 mm. It is entirely possible that a "12 inch" bowling ball might actually be exactly 300 mm in diameter, since slide rules and phonograph records, for example, are in such metric sizes.) John Savard |
#4
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Practical astronomy
In article ,
Chris L Peterson wrote: On Fri, 4 Jul 2008 09:06:50 -0700 (PDT), oriel36 wrote: The idea is to appreciate the power of geodynamics rather than have it subservient to the surface ocean.So,in terms of millimeters or fractions of an inch,how thin is the ocean with respect to planetary diameter in terms of the veneer on a bowling ball ? Do you think that dragging a 50um film of fluid over the surface of a bowling ball wouldn't have any effect on its rotation? Nonsense. If the bowling ball was floating freely in space, and if its rotation rate was monitored to millisecond accuracy over several centuries, it could have a noticeable effect. Because I think you agree with me than however small that effect may be, it must still be somewhat larger than zero... There are good mathematical models of Earth's rotation that demonstrate how both solid-Earth tides and ocean tides contribute to the observed long and short term rotational rate variation. The actual forces that the ocean is able to exert on the Earth are very small, but so is the net effect of those forces. _______________________________________________ __ Chris L Peterson Cloudbait Observatory http://www.cloudbait.com -- ---------------------------------------------------------------- Paul Schlyter, Grev Turegatan 40, SE-114 38 Stockholm, SWEDEN e-mail: pausch at stjarnhimlen dot se WWW: http://stjarnhimlen.se/ |
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Practical astronomy
On Jul 4, 11:13 am, Quadibloc wrote:
[...] (Incidentally, 12 inches is just over 30 centimeters: about 305 mm. It is entirely possible that a "12 inch" bowling ball might actually be exactly 300 mm in diameter, since slide rules and phonograph records, for example, are in such metric sizes.) Hmmm, my bowling ball is at home (I'm away at a BBQ) so I can't measure it; Wikipedia to the rescue: http://en.wikipedia.org/wiki/Bowling_ball " Regulation ten-pin bowling balls must weigh no more than " 16 pounds (7.2 kg) (governing bodies do not regulate how " light a bowling ball may be) and have a diameter of 8.5 " inches (21.6 cm). |
#7
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Practical astronomy
On Jul 4, 11:42*am, Chris L Peterson wrote:
On Fri, 04 Jul 2008 18:15:02 GMT, (Paul Schlyter) wrote: If the bowling ball was floating freely in space, and if its rotation rate was monitored to millisecond accuracy over several centuries, it could have a noticeable effect. *Because I think you agree with me than however small that effect may be, it must still be somewhat larger than zero... Yes, that's exactly my point. Gerald apparently thinks that because the ocean is only a tiny component of the Earth, it can't have any effect. He overlooks the fact that the effect is itself very small, only detectable with extremely precise instrumentation (or very long observation), *just like the variation in rotation of a bowling ball would be tiny- but likely detectable- if you applied some viscous force to a thin film of fluid on its surface. _________________________________________________ Chris L Peterson Cloudbait Observatoryhttp://www.cloudbait.com I do not overlook facts,I enjoy working with rotational dynamics in a way you can't even imagine,at least not just yet.The idea is to get familiar with rotational dynamics and its effects such as the how rotational geodynamics of the molten/flexible interior causes the Earth to deviate from a perfect sphere and is involved in the motion of the fractured crust.This requires a good appreciation between the relative layers such as crust is to oceanic depth and from there to the enormous rotating interior,an interior which in itself is in a flexible and molten state. In short,you are perfectly entitled to believe that the ocean slows the Earth's rotation down 1 second over a short period but that means you have little appreciation of rotational dynamics and how it generates the planetary profile and subsequently how the geodynamics affects the motion of the thin surface crust. This is how an astronomer thinks in this wonderful era where you mesh evolutionary geology and crustal dynamics with rotational dynamics.The last time I looked,you lot were still working with a geostationary convection cells mechanism for crustal motion whereas I find it easier to work with rotational geodynamics influencing crustal geodynamics. Rather than kill the conversation,consider the relationship of oceanic depth to planetary crustal depth and then look at the rotating molten/ flexible interior,if you stil think the ocean,which is moving with the rotating Earth,slows the planet down then so be it .This is practical astronomy that is closer to home and people can enjoy in the ;long run. |
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Why do you even bother with that nutbar? It's obvious he has the mentality
of a flat earth type.! Yes, that's exactly my point. Gerald apparently thinks that because the ocean is only a tiny component of the Earth, it can't have any effect. He overlooks the fact that the effect is itself very small, only detectable with extremely precise instrumentation (or very long observation), just like the variation in rotation of a bowling ball would be tiny- but likely detectable- if you applied some viscous force to a thin film of fluid on its surface. _________________________________________________ Chris L Peterson Cloudbait Observatory http://www.cloudbait.com |
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Practical astronomy
On Jul 4, 1:18 pm, " wrote:
On Jul 4, 11:13 am, Quadibloc wrote: [...] (Incidentally, 12 inches is just over 30 centimeters: about 305 mm. It is entirely possible that a "12 inch" bowling ball might actually be exactly 300 mm in diameter, since slide rules and phonograph records, for example, are in such metric sizes.) Hmmm, my bowling ball is at home (I'm away at a BBQ) so I can't measure it; Wikipedia to the rescue: http://en.wikipedia.org/wiki/Bowling_ball " Regulation ten-pin bowling balls must weigh no more than " 16 pounds (7.2 kg) (governing bodies do not regulate how " light a bowling ball may be) and have a diameter of 8.5 " inches (21.6 cm). Then he was right about how big a bowling ball was in millimeters, even if he had its size in inches wrong. John Savard |
#10
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Practical astronomy
On Jul 4, 11:43*am, Chris L Peterson wrote:
On Fri, 4 Jul 2008 09:06:50 -0700 (PDT), oriel36 wrote: The idea is to appreciate the power of geodynamics rather than have it subservient to the surface ocean.So,in terms of millimeters or fractions of an inch,how thin is the ocean with respect to planetary diameter in terms of the veneer on a bowling ball ? Do you think that dragging a 50um film of fluid over the surface of a bowling ball wouldn't have any effect on its rotation? Nonsense. There are good mathematical models of Earth's rotation that demonstrate how both solid-Earth tides and ocean tides contribute to the observed long and short term rotational rate variation. The actual forces that the ocean is able to exert on the Earth are very small, but so is the net effect of those forces. _________________________________________________ Chris L Peterson Cloudbait Observatoryhttp://www.cloudbait.com True, but... Trying to talk sense to Oriel? Not unlike teaching a pig to dance. It just annoys the pig and gets you dirty. My apologies to pigs, most of whom I've met display better manners and more wisdom than Gerald Oriole does. LOL. \ |
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