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The fallacy of instantaneous gravity
The fallacy of instantaneous gravity.
The .html version is more user friendly http://members.optusnet.com.au/maxkeon/ofset.html The image depicts two identical sun sized planets in circular orbits around each other, separated by the orbit radius of mercury around the sun. The red planet shown at (1) is the apparent position of the relevant planet from the viewpoint of its companion at position (2). The degree of offset is according to the time distance between the orbiting planets times the true orbital speed around the center of mass for the system (L/c*v') : (5.8e10/3e8*23919 =193.3333 sec). The pointing direction of the apparent tangent at location (2) would appear to drive the planet outward. But that's not the case at all. http://members.optusnet.com.au/maxkeon/ofset.jpg The gforces drawing the planets toward each other are according to GM/r'^2 = 3.95e-2 m/s^2 where r' is the orbit diameter. While the centripetal acceleration is according to v'^2/r where r is the orbit radius around the Barycenter and v' is orbital speed relative to that radius (v'^2/r) = 1.976e-2, which is half that required for a sustainable orbit. The orbit would quickly collapse. The apparent changing position of the companion planet is proportional to the time length of the orbit diameter (193.33333 sec). And the resultant tangent offset of 368.7 meters resulting from the apparent planet shift of 4624366 meters gives an outward acceleration rate of 2*l/t^2 : 2*368.7/193.333^2 = .01973 m/s^2. The inward collapse is counteracted. The reasoning will be logically adaptable to every scenario. ----- Max Keon |
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The fallacy of instantaneous gravity
On Thursday, 7 March 2019 11:02:04 UTC+11, wrote:
The fallacy of instantaneous gravity. The .html version is more user friendly http://members.optusnet.com.au/maxkeon/ofset.html The image depicts two identical sun sized planets in circular orbits around each other, separated by the orbit radius of mercury around the sun. The red planet shown at (1) is the apparent position of the relevant planet from the viewpoint of its companion at position (2). The degree of offset is according to the time distance between the orbiting planets times the true orbital speed around the center of mass for the system (L/c*v') : (5.8e10/3e8*23919 =193.3333 sec). The pointing direction of the apparent tangent at location (2) would appear to drive the planet outward. But that's not the case at all. http://members.optusnet.com.au/maxkeon/ofset.jpg The gforces drawing the planets toward each other are according to GM/r'^2 = 3.95e-2 m/s^2 where r' is the orbit diameter. While the centripetal acceleration is according to v'^2/r where r is the orbit radius around the Barycenter and v' is orbital speed relative to that radius (v'^2/r) = 1.976e-2, which is half that required for a sustainable orbit. The orbit would quickly collapse. The apparent changing position of the companion planet is proportional to the time length of the orbit diameter (193.33333 sec). And the resultant tangent offset of 368.7 meters resulting from the apparent planet shift of 4624366 meters gives an outward acceleration rate of 2*l/t^2 : 2*368.7/193.333^2 = .01973 m/s^2. The inward collapse is counteracted. The reasoning will be logically adaptable to every scenario. --- Perhaps I haven't made myself very clear. In Newtonian gravity there was never an instantaneous link between gravitating masses, so the significance of GR's curved spacetime is diminished considerably. GR adds new dimension to something that was already geometrically correct. This three frame animation is the proof. http://members.optusnet.com.au/maxkeon/ofset2.gif (ESC halts the animation at any chosen frame (maybe)) ----- Max Keon (to be continued) |
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