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Brightest flash ever recorded
Nowadays there are orbiting satellites that detect gamma rays. On
December 27th, 2004 they detected a flash. If this had been visible light it would have lit up the entire sky more brightly than the full moon. Some satellites were disabled and the Earth's atmosphere was affected. It turns out this flash, which lasted two tenths of a second, came from a neutron star on the other side of our galaxy when the crust of the star split open. The crust of the star was a mile thick and is made of polymerized iron, which has a strength of well over a billion times that of steel. Over time the magnetic field of the star builds up inside of the star which eventually is able to completely crack through a mile of polymerized iron and release all that energy. http://www.space.com/1601-huge-quake-cracks-star.html I wanted more detail. As best I could understand it is this. The core of a neutron star produces a strong magnetic field. The core is surrounded by a superconducting layer. Superconductors don't like magnetic fields, but if the field is strong enough it forms a sort of horizontal tornado in the superconductor that carries the magnetic field. These tornadoes tend to grow, but are blocked by the superstrong iron crust. The crust is also a superconductor so it doesn't want the magnetic field either, but is too stiff and tough for the atoms to move so a tornado can't form in the crust. Basically you have the strongest magnet in the universe contained by the strongest iron in the universe. In some neutron stars the magnetic force of the tornado eventually builds up enough to fracture the crust, the tornado escapes, and its energy is released. Kaboom! The crust vibrated like a bell when the crack opened. I would think this the loudest sound possible in this Universe. The width of the crack vibrated at that frequency, so also did the intensity of the gamma rays, and the pitch could be measured exactly. It was 100 cycles a second, about the same pitch as the lowest note on a guitar. The same sort of thing happens on the Sun. Tornadoes, aka flux tubes, form in the material of the sun and tend to grow. The tube of the tornado forms an arch, and the two ends of the arch are seen as a pair of sunspots. As the arch grows the sunspots move further apart. Eventually the arch may blow off of the sun as a solar flare. In high school they showed us a movie of a solar flare with a diameter equal to that of the sun itself. Here's a spectacular video of an M-class flare. http://www.youtube.com/watch?v=RnJBTmaRURU There is an X class which is even larger. |
#2
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Brightest flash ever recorded
On 06/02/2011 03:55 AM, Frisbieinstein wrote:
http://www.space.com/1601-huge-quake-cracks-star.html I wanted more detail. As best I could understand it is this. The core of a neutron star produces a strong magnetic field. The core is surrounded by a superconducting layer. Superconductors don't like magnetic fields, but if the field is strong enough it forms a sort of horizontal tornado in the superconductor that carries the magnetic field. These tornadoes tend to grow, but are blocked by the superstrong iron crust. The crust is also a superconductor so it doesn't want the magnetic field either, but is too stiff and tough for the atoms to move so a tornado can't form in the crust. Basically you have the strongest magnet in the universe contained by the strongest iron in the universe. In some neutron stars the magnetic force of the tornado eventually builds up enough to fracture the crust, the tornado escapes, and its energy is released. Kaboom! Now, the core of a neutron star is obviously made of neutronium -- i.e. the material so dense that electrons get crushed into protons and then get turned into neutrons! I don't think that stuff would be conductive, let alone superconductive: electrons can't pass through that. Now as for the crust of the neutron star, that's made of white dwarf star material. Specifically, iron white dwarf star material, the densest of all white dwarf star materials -- just one step below neutronium in density. As such, even though it's unimaginably dense compared to any materials we have on Earth, it is still softer than neutronium which is even more dense. So when it comes to a contest of strength between white dwarf material and neutronium, neutronium will always win out. Regarding whether regions of a neutron star are superconductive, they may be, but I don't think it's necessarily the case. But even if it were superconductive, where do you get the idea that superconductors don't like magnetic fields? Superconductors produce their own magnetic fields, just by the classical laws of electromagnetism they must produce magnetic fields as electricity flows through a material. Now superconductors on Earth may not like external magnetic fields, because they might affect their superconductivity, but their own magnetic fields are fine. Near a neutron star, there is no stronger magnetic field than that of the neutron star itself, so there is no magnetic field that can affect its superconductivity. All that stuff about tornados and stuff, I don't think it has anything to do with reality. A tornado implies to me a very localized area of torsional strain. A magnetic field isn't that localized, it twists and turns around the entire neutron star. If it creates a break in a certain portion of the neutron star's crust, then that was likely the weakest part of the crust, but the strain would've affected all parts of the crust equally more or less. Local variations of magnetic fields are caused by competing magnetic fields. They'll either work to reduce the local magnetic field, or work to weaken it. Yousuf Khan |
#3
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Brightest flash ever recorded
On Jun 9, 7:14*am, Yousuf Khan wrote:
On 06/02/2011 03:55 AM, Frisbieinstein wrote: http://www.space.com/1601-huge-quake-cracks-star.html I wanted more detail. *As best I could understand it is this. *The core of a neutron star produces a strong magnetic field. *The core is surrounded by a superconducting layer. *Superconductors don't like magnetic fields, but if the field is strong enough it forms a sort of horizontal tornado in the superconductor that carries the magnetic field. *These tornadoes tend to grow, but are blocked by the superstrong iron crust. *The crust is also a superconductor so it doesn't want the magnetic field either, but is too stiff and tough for the atoms to move so a tornado can't form in the crust. *Basically you have the strongest magnet in the universe contained by the strongest iron in the universe. *In some neutron stars the magnetic force of the tornado eventually builds up enough to fracture the crust, the tornado escapes, and its energy is released. *Kaboom! Now, the core of a neutron star is obviously made of neutronium -- i.e. the material so dense that electrons get crushed into protons and then get turned into neutrons! I don't think that stuff would be conductive, let alone superconductive: electrons can't pass through that. Now as for the crust of the neutron star, that's made of white dwarf star material. Specifically, iron white dwarf star material, the densest of all white dwarf star materials -- just one step below neutronium in density. As such, even though it's unimaginably dense compared to any materials we have on Earth, it is still softer than neutronium which is even more dense. So when it comes to a contest of strength between white dwarf material and neutronium, neutronium will always win out. Regarding whether regions of a neutron star are superconductive, they may be, but I don't think it's necessarily the case. But even if it were superconductive, where do you get the idea that superconductors don't like magnetic fields? Superconductors produce their own magnetic fields, just by the classical laws of electromagnetism they must produce magnetic fields as electricity flows through a material. Now superconductors on Earth may not like external magnetic fields, because they might affect their superconductivity, but their own magnetic fields are fine. Near a neutron star, there is no stronger magnetic field than that of the neutron star itself, so there is no magnetic field that can affect its superconductivity. All that stuff about tornados and stuff, I don't think it has anything to do with reality. A tornado implies to me a very localized area of torsional strain. A magnetic field isn't that localized, it twists and turns around the entire neutron star. If it creates a break in a certain portion of the neutron star's crust, then that was likely the weakest part of the crust, but the strain would've affected all parts of the crust equally more or less. Local variations of magnetic fields are caused by competing magnetic fields. They'll either work to reduce the local magnetic field, or work to weaken it. * * * * Yousuf Khan I of course have no idea, but the experts seem to be saying that neutron star cores are superconductive and that this is confirmed by experimental evidence. http://www.ualberta.ca/~heinke/CasA/Cooling.html |
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Brightest flash ever recorded
On 11/06/2011 6:13 AM, Frisbieinstein wrote:
I of course have no idea, but the experts seem to be saying that neutron star cores are superconductive and that this is confirmed by experimental evidence. http://www.ualberta.ca/~heinke/CasA/Cooling.html According to that link, the only place where superconductivity will exist is in the protons: " When two neutrons pair up, they fall into a lower-energy state. The extra energy is released as neutrinos, which easily escape from the neutron star into space. Thus the pairing of neutrons rapidly cools the neutron star. Neutron pairs may be broken (by being "bumped" by other neutrons), and re-form; every time a pair forms, neutrinos are emitted. This cooling by pair formation can only happen when the neutron star interior is cool enough to become a superfluid. The Page and Shternin groups are able to explain the rapid neutron star cooling by saying that the neutrons have only recently become superfluid--giving a superfluid transition temperature of 0.5-1 billion degrees K. They also need proton superconductivity to exist in the neutron star, in order to suppress other cooling mechanisms until neutron pair formation starts the rapid cooling. " http://www.ualberta.ca/~heinke/CasA/Cooling.html So the superfluidity of the neutrons have nothing to do with superconductivity, just of the protons. Yousuf Khan |
#5
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Brightest flash ever recorded
On Jun 13, 12:59*pm, Yousuf Khan wrote:
On 11/06/2011 6:13 AM, Frisbieinstein wrote: I of course have no idea, but the experts seem to be saying that neutron star cores are superconductive and that this is confirmed by experimental evidence. http://www.ualberta.ca/~heinke/CasA/Cooling.html According to that link, the only place where superconductivity will exist is in the protons: " When two neutrons pair up, they fall into a lower-energy state. The extra energy is released as neutrinos, which easily escape from the neutron star into space. Thus the pairing of neutrons rapidly cools the neutron star. Neutron pairs may be broken (by being "bumped" by other neutrons), and re-form; every time a pair forms, neutrinos are emitted. This cooling by pair formation can only happen when the neutron star interior is cool enough to become a superfluid. The Page and Shternin groups are able to explain the rapid neutron star cooling by saying that the neutrons have only recently become superfluid--giving a superfluid transition temperature of 0.5-1 billion degrees K. They also need proton superconductivity to exist in the neutron star, in order to suppress other cooling mechanisms until neutron pair formation starts the rapid cooling. "http://www.ualberta.ca/~heinke/CasA/Cooling.html So the superfluidity of the neutrons have nothing to do with superconductivity, just of the protons. * * * * Yousuf Khan Right. But what I have been told is that the neutrons have enough beta decay to also be a superconductor. I haven't gotten around to doing a calculation -- it would probably be wrong anyway -- but my guess is that there is enough beta decay to make the entire core superconductive. There isn't much, but the material is so extremely dense that even if a very small percentage of charged particles are available, in absolute terms it could be enough. I first came across this when I was told that the rotating superfluid neutrons generate a strong magnetic field. That was a surprise. |
#6
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Brightest flash ever recorded
On 13/06/2011 11:17 AM, Frisbieinstein wrote:
Right. But what I have been told is that the neutrons have enough beta decay to also be a superconductor. I haven't gotten around to doing a calculation -- it would probably be wrong anyway -- but my guess is that there is enough beta decay to make the entire core superconductive. There isn't much, but the material is so extremely dense that even if a very small percentage of charged particles are available, in absolute terms it could be enough. I first came across this when I was told that the rotating superfluid neutrons generate a strong magnetic field. That was a surprise. I'd say at the edges of the neutronium you'd actually get escape of the electrons, but anywhere down towards the centre you'll get the electron getting recaptured. So if there is going to be any conductivity, it'll have to be the border region between the neutronium and the dwarf star material. Yousuf Khan |
#7
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Brightest flash ever recorded
On Jun 16, 5:26*am, Yousuf Khan wrote:
On 13/06/2011 11:17 AM, Frisbieinstein wrote: Right. *But what I have been told is that the neutrons have enough beta decay to also be a superconductor. *I haven't gotten around to doing a calculation -- it would probably be wrong anyway -- but my guess is that there is enough beta decay to make the entire core superconductive. *There isn't much, but the material is so extremely dense that even if a very small percentage of charged particles are available, in absolute terms it could be enough. I first came across this when I was told that the rotating superfluid neutrons generate a strong magnetic field. *That was a surprise. I'd say at the edges of the neutronium you'd actually get escape of the electrons, but anywhere down towards the centre you'll get the electron getting recaptured. So if there is going to be any conductivity, it'll have to be the border region between the neutronium and the dwarf star material. * * * * Yousuf Khan THE ASTROPHYSICAL JOURNAL, 492:267–280, 1998 January 1 © 1998. The American Astronomical Society. All rights reserved. Printed in U.S.A. Neutron Star Magnetic Field Evolution, Crust Movement, and Glitches MALVIN RUDERMAN TIANHUA ZHU, AND KAIYOU CHEN Physics Department and Columbia Astrophysics Laboratory, Columbia University, 538 West 120th Street, New York, NY 10027 Received 1997 April 25; accepted 1997 August 13 In a type II superconductor, expected to be present below the crust and perhaps all the way down to the central core, ---- So that's a definite maybe. |
#8
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Brightest flash ever recorded
On Jun 9, 9:14Â*pm, Yousuf Khan wrote:
On 06/02/2011 03:55 AM, Frisbieinstein wrote: http://www.space.com/1601-huge-quake-cracks-star.html All that stuff about tornados and stuff, I don't think it has anything to do with reality. A tornado implies to me a very localized area of torsional strain. A magnetic field isn't that localized, it twists and turns around the entire neutron star. If it creates a break in a certain portion of the neutron star's crust, then that was likely the weakest part of the crust, but the strain would've affected all parts of the crust equally more or less. THE ASTROPHYSICAL JOURNAL, 492:267–280, 1998 January 1 © 1998. The American Astronomical Society. All rights reserved. Printed in U.S.A. Neutron Star Magnetic Field Evolution, Crust Movement, and Glitches MALVIN RUDERMAN TIANHUA ZHU, AND KAIYOU CHEN Physics Department and Columbia Astrophysics Laboratory, Columbia University, 538 West 120th Street, New York, NY 10027 Received 1997 April 25; accepted 1997 August 13 A spinning-down (spinning-up) neutron star's neutron superfluid vortex array must expand (contract). Because the core of a neutron vortex and a flux tube interact strongly as they pass through each other, the moving vortices will push on the proton's flux-tube array (Sauls 1989; Srinivasan et al. 1990; Ruderman 1991a, 1991b), forcing it either (a) to move together with the vortices or (b) to be cut through if the flux-tube array cannot respond fast enough to take part in the vortex motion. Section 2 discusses possible relationships among a pulsar's Ω, B, and rate of change of spin ($\mathstrut{{\ucpmathaccent{{\Omega}} {), which discriminate between these two behaviors. In case a the evolution of the magnetic field at the core-crust interface is well determined by the initial magnetic field configuration and subsequent changes in stellar Ω. In case b the core-crust interface field would evolve more slowly relative to changes in Ω, although qualitative features of the evolution should be similar to those of case a. Some microphysics and observations, considered in §§ 2 and 3, support case a behavior for pulsars whose spin-down (or spin-up) ages, T$ \mathstrut{_{s}}$=| Ω/2$\mathstrut{{\ucpmathaccent{{\Omega}}{ |, are not less than those of Vela-like radio pulsars (Ts ∼ 104 yr) and case b behavior for the much more rapidly spinning-down Crab-like radio pulsars (Ts ∼ 103 yr). Between the stellar core and the world outside it there is a solid crust with a very high electrical conductivity. If the crust were absolutely rigid and a perfect conductor, then its response to changes in the core magnetic field would be limited to rigid crust rotations. Of course neither is the case. A high density of core flux tubes merges into a smooth field when passing through the crust. Because of the almost rigid crust's high conductivity, it, at least temporarily, freezes in place the capitals of the core's flux tubes. As these flux tube capitals at the crust- core interface are pushed by a moving core neutron vortex array, a large stress builds up in the crust. This stress will be relaxed when the crust is stressed beyond its yield strength, or, if the buildup is slow enough, by dissipation of the crustal eddy currents that hold the magnetic field in place as it passes from the core through the crust. The shear modulus of a crust is well described quantitatively, ---- The crustal cracking has to do with the magnetic field of the core. The flux tubes freeze to the crust, then are pushed by the superfluid vortices. The crust may shear. By the way, studies of precessing neutron stars indicate that the vortices are not pinned in such stars. If they were, the star would precess much faster. |
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