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GETTING RID OF EINSTEIN RELATIVITY
"Henri Wilson" HW@.... wrote in message
... On Fri, 22 Jun 2007 16:01:28 -0700, Dono wrote: On Jun 22, 3:34 pm, "Jeckyl" wrote: However, that SR says that there is a finite maximum speed that is the same in all iFoR (as given by Lorentz transforms) is not dependant on anything acutally being able to attain that speed. The lorentz transforms do not induce the constancy of speed of light, quite the other way around, the form of the Lorentz transforms is a consequence (among other things) of the POSTULATE of constancy of light speed. In light of this, your sentence : "However, that SR says that there is a finite maximum speed ....as GIVEN BY Lorentz transforms" ....is grossly incorrect.If you try to debunk cranks like Wilson, try at least to learn your SR. Is this the same Wilson who has shown conclusively that most star brightness variation can be attributed directly to c+v effects? What you morons can't see is that Einstein merely used the conclusions of LET as his second postulate then worked the maths backwards. It is a blatant case of plagiarisation. It achieved nothing new. It sidetracked physics by ignoring truth just as Earth Centrism did for centuries before. It is now clear that light travels ballistically, at least in deep space. Around large masses like Earth, there usually exists some kind of local EM speed control 'medium' which could easily make LET and Einstein's postulate appear to be somewhat true under lab conditions. It is only because of the extreme difficulty involved with measuring OW light speed from moving sources that SR has lasted this long. And nothing to do with the fact that it correctly predicts experimental results and observation .. including time dilation affecting the decay of sub-atomic particles etc .. things that ballistic theory does not account for. |
#102
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GETTING RID OF EINSTEIN RELATIVITY
On Jun 23, 4:24 pm, "Jeckyl" wrote:
"Dono" wrote in message oups.com... Another content free post. Congratulations! Well .. thanks for the report card. You obviously have nothing worthwhile saying .. you're just stalking me because you're ****ed off that you were wrong and your arrogance and lack of understanding was made so apparent. It wasn't just the misinterpretation of a result (as was pointed out very clearly to you) .. that would be fine .. its all the (incorrect) mathematic justification and (incorrect) different ways of looking at it and (incorrect) plain-nonsense arguments you gave to defend yourself, all the while attack the person trying to help you. Truly sad. maybe when you grow up, you'll learn. Yet another content free posting. Why don't you revisit your BS solution to the problem you keep refering to? |
#103
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GETTING RID OF EINSTEIN RELATIVITY
"Dono" wrote in message
oups.com... On Jun 23, 4:24 pm, "Jeckyl" wrote: "Dono" wrote in message oups.com... Another content free post. Congratulations! Well .. thanks for the report card. You obviously have nothing worthwhile saying .. you're just stalking me because you're ****ed off that you were wrong and your arrogance and lack of understanding was made so apparent. It wasn't just the misinterpretation of a result (as was pointed out very clearly to you) .. that would be fine .. its all the (incorrect) mathematic justification and (incorrect) different ways of looking at it and (incorrect) plain-nonsense arguments you gave to defend yourself, all the while attack the person trying to help you. Truly sad. maybe when you grow up, you'll learn. Yet another content free posting. Why don't you revisit your BS solution to the problem you keep refering to? Yet another content free posting. Why don't you revisit your BS solution to the problem? |
#104
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GETTING RID OF EINSTEIN RELATIVITY
On Jun 24, 8:02 am, "Jeckyl" wrote:
"Dono" wrote in message oups.com... On Jun 23, 4:24 pm, "Jeckyl" wrote: "Dono" wrote in message groups.com... Another content free post. Congratulations! Well .. thanks for the report card. You obviously have nothing worthwhile saying .. you're just stalking me because you're ****ed off that you were wrong and your arrogance and lack of understanding was made so apparent. It wasn't just the misinterpretation of a result (as was pointed out very clearly to you) .. that would be fine .. its all the (incorrect) mathematic justification and (incorrect) different ways of looking at it and (incorrect) plain-nonsense arguments you gave to defend yourself, all the while attack the person trying to help you. Truly sad. maybe when you grow up, you'll learn. Yet another content free posting. Why don't you revisit your BS solution to the problem you keep refering to? Yet another content free posting. Why don't you revisit your BS solution to the problem?- Hide quoted text - - Show quoted text - I did. In the process I pointed out all the errors in what you call your "solution" |
#105
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GETTING RID OF EINSTEIN RELATIVITY
"Dono" wrote in message
ups.com... On Jun 24, 8:02 am, "Jeckyl" wrote: "Dono" wrote in message oups.com... On Jun 23, 4:24 pm, "Jeckyl" wrote: "Dono" wrote in message groups.com... Another content free post. Congratulations! Well .. thanks for the report card. You obviously have nothing worthwhile saying .. you're just stalking me because you're ****ed off that you were wrong and your arrogance and lack of understanding was made so apparent. It wasn't just the misinterpretation of a result (as was pointed out very clearly to you) .. that would be fine .. its all the (incorrect) mathematic justification and (incorrect) different ways of looking at it and (incorrect) plain-nonsense arguments you gave to defend yourself, all the while attack the person trying to help you. Truly sad. maybe when you grow up, you'll learn. Yet another content free posting. Why don't you revisit your BS solution to the problem you keep refering to? Yet another content free posting. Why don't you revisit your BS solution to the problem?- Hide quoted text - - Show quoted text - I did. In the process I pointed out all the errors in what you call your "solution" There were no errors in my solution .. .the only errors are yours. You don't understand SR .. that much is blatantly obvious. you simply blindly plug values into the equations you've just learnt and don't know how to apply them or what they mean. see http://en.wikipedia.org/wiki/Time_di..._time_dilation |
#106
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GETTING RID OF EINSTEIN RELATIVITY
Jeckyl wrote: "Dono" wrote in message ups.com... On Jun 24, 8:02 am, "Jeckyl" wrote: "Dono" wrote in message oups.com... On Jun 23, 4:24 pm, "Jeckyl" wrote: "Dono" wrote in message groups.com... Another content free post. Congratulations! Well .. thanks for the report card. You obviously have nothing worthwhile saying .. you're just stalking me because you're ****ed off that you were wrong and your arrogance and lack of understanding was made so apparent. It wasn't just the misinterpretation of a result (as was pointed out very clearly to you) .. that would be fine .. its all the (incorrect) mathematic justification and (incorrect) different ways of looking at it and (incorrect) plain-nonsense arguments you gave to defend yourself, all the while attack the person trying to help you. Truly sad. maybe when you grow up, you'll learn. Yet another content free posting. Why don't you revisit your BS solution to the problem you keep refering to? Yet another content free posting. Why don't you revisit your BS solution to the problem?- Hide quoted text - - Show quoted text - I did. In the process I pointed out all the errors in what you call your "solution" There were no errors in my solution .. .the only errors are yours. You don't understand SR .. that much is blatantly obvious. you simply blindly plug values into the equations you've just learnt and don't know how to apply them or what they mean. Jeckyl, Jeckyl, Jeckyl, Dono, Dono, Dono! Why don't you ask Master Tom Roberts to resolve your problem? You don't believe Master Tom Roberts is a reliable hypnotist anymore? Bellicose zombies in Einstein criminal cult are not programmed to fight one another. Pentcho Valev |
#107
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GETTING RID OF EINSTEIN RELATIVITY
On 21 Jun, 17:47, Tom Roberts wrote:
For a complete description and simulations on how classical theory does predict the observed results of both sagnac and MMx. See the sagnac 1-3 simulations at... http://www.youtube.com/profile?user=jaymoseleygrb sean wrote: On 20 Jun, 14:51, Tom Roberts wrote: sean wrote: the sagnac source is essentially identical to the MMx in that they both rotate around an axis . The instruments are VERY different: Sagnac's has a large enclosed area, and the MMX has zero enclosed area, and this makes all the difference as far as rotation is concerned. You arent reading my words. Notice I say source not setup. The two sources are the same. Thats different from saying the setups are the same. Yes, I read that. But having similar sources is NOT sufficient -- the instruments are sufficiently different that the similarity of their sources does not matter. The Sagnac interferometer can detect its rotation, and the Michelson interferometer cannot. No problem here with this. But please note I never said MMx did detect the rotation. All I say/said is that the sources motion are the same. For instance what I mean is this.. Take both the MMx and the sagnac experiments. Remove the mirrors( or ring fibre) and detector from sagnac and the mirrors and detector from MMx. What do you have left? Two sources rotating around a central axis To me except for a diameter difference the two sources are essentially doing the same thing. Therefore it seems a rational conclusion to say that light must propagate away from these two sources in the same way for both. And theres only two options. Either both rotating sources have light leaving them at c in all directions or both have light leaving at variable speeds in all directions. The problem with SR seems to be that it says that sometimes the sources act one way *(sagnac) and sometimes another. I dont know about you but I thought any good theory has to be universally consistent? Obviously SR isnt when it comes to rotating sources. If you have a source rotating around an axis x at an tangental velocity of v . And the axis x is not moving in the frame of reference(the source S is rotating around the static axis X) Then the question is , in SR, or relativity , in this frame of reference ,... is the light speed c relative to the rotating source or is the light speed c+-v relative to the rotating source? This depends in detail on what you mean by "speed" -- at base your confusions are related to PUNs on that word. In particular, "speed relative to the source" is meaningless - one can measure and define speed only relative to a COORDINATE SYSTEM. You can choose a coordinate system in which the source is at rest, which is the usual thing to do in this case, but when the source is rotating around an axis then so are these coordinates, and things get both complicated and ambiguous (you could choose any of several different rotating coordinates in which the source is at rest). This is what Im trying to get you to define one way or another. Because above you say if the source is rotating then one has to take into account the rotating coordinates as you say above.As SR does with sagnac. But why doesnt it make the same decisions with MMx? Itis also rotating yet SR calculates it as if it isnt. And the usual excuse is that the rotation is too small to effect the MMX observations. But thats not true, because the rotation is large enouh to effect apath difference in a ring gyro . Dont forget sagnac may be a different setup then MMX but they both measure the same thing... path difference. Therefore if a shorter path difference in a ring gyro can effect a fringe shift then a longer path difference in a MMx experiment would also be subject to the same measureable path difference on each arm,... BUt it isnt. And thats because light always travels at c in the source frame only. Not in any other frame as SR would mislead us into believing In SR, any light ray will move in vacuum with speed c relative to any inertial frame. A direct consequence of this is that in general the speed will not be c relative to a NON-inertial frame (e.g. a rotating system). This is not observed. In MMx where the source is what you call non inertial the light is *always* observed to be at c. Contrary to what you say SR would predict If the axis of your rotation is at rest in some inertial frame, we can use that inertial frame and its known (vacuum) speed of light to compute what would be measured in the rotating system. But to do that one must select a specific rotating system. For different choices of system and light path, one can obtain the following values for the 1-way speed of light: c for a radial light path * c*g for a radial light path # c+v for a counter-rotating circular path * c-v for a co-rotating circular path * (c+v)*g for a counter-rotating circular path # (c-v)*g for a co-rotating circular path # (circular paths are centered on and normal to the rotation axis, and they go once around the rotating system) * "steal" the time coordinate from the inertial frame of the center (i.e. use clocks at rest in the inertial frame) # using a clock at rest in the rotating system; g=1/sqrt(1-v^2/c^2) where v is the speed of the clock relative to the inertial frame. So the last two entries are most natural for a rotating system (I gave the full list because otherwise your "c+-v" would not be present at all). Note that by looking at the very same light rays in the inertial frame one concludes they travel with speed c relative to that frame, so this is all consistent. Those circular paths go all the way around the rotating system, so one needs only a single clock to make the measurement. If you attempted to make a measurement only half the way around one of these circles, you would find that there are several different ways to synchronize the two clocks that are required, and the result varies depending on which you chose -- the ambiguities get MUCH worse. The middle entries, c+v and c-v, are ultimately due to measuring the distance traveled in one frame (the rotating one), but measuring time of flight in a DIFFERENT frame (the inertial frame). The ratio of measurements made in different frames is not "speed" in any sense. That's why I said you used PUNs on "speed". This still ignores the contradiction at the heart of SR. I assume you say above that in a rotating source SR calculates distance in the rotating frame and time in the inertial. To start with this is an irrelevent distinction as classical theory has the flight time the same in all frames and it still is able to explain both sagnac and MMx results. So why relativists feel it neccesary to construct such an elaborate artifice when classicals simpler one does just as well. But secondly you ignore that fact that SR is being inconsistent. Because in sagnac from what I see it measures the distance travelled in the inertial frame whereas in MMx it measures the distance travelled in the rotating frame. If you can answer this then Ill show you how SR cannot predict both sagnac and MMx without contradicting itself. You are confused. You seem to be trying to use a "sound bite" approach to relativity, which is woefully inadequate. One cannot make crisp conclusions using phrases like "speed relative to the source" -- it's easy to get contradictions using such nebulous phrases. Fortunately, SR itself has no such difficulties. IOW the contradictions you find are an artifact of your poor understanding of SR, not from SR itself. No how could it be a contradiction due to my understanding of SR? Youve just clarified that SR calculates distance in the rotating and time in the inertial. If thats true then its your statement not mine that is inconsistent as we both know thatin sagnac the only way SR can explain the fringe shift is by measuring the distance travelled in the *inertial frame*. Not the rotating frame. Sean www.gammarayburst.com |
#108
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GETTING RID OF EINSTEIN RELATIVITY
On 21 Jun, 17:47, Tom Roberts wrote:
For a complete description and simulations on how classical theory does predict the observed results of both sagnac and MMx. See the sagnac 1-3 simulations at... http://www.youtube.com/profile?user=jaymoseleygrb sean wrote: On 20 Jun, 14:51, Tom Roberts wrote: sean wrote: the sagnac source is essentially identical to the MMx in that they both rotate around an axis . The instruments are VERY different: Sagnac's has a large enclosed area, and the MMX has zero enclosed area, and this makes all the difference as far as rotation is concerned. You arent reading my words. Notice I say source not setup. The two sources are the same. Thats different from saying the setups are the same. Yes, I read that. But having similar sources is NOT sufficient -- the instruments are sufficiently different that the similarity of their sources does not matter. The Sagnac interferometer can detect its rotation, and the Michelson interferometer cannot. No problem here with this. But please note I never said MMx did detect the rotation. All I say/said is that the sources motion are the same. For instance what I mean is this.. Take both the MMx and the sagnac experiments. Remove the mirrors( or ring fibre) and detector from sagnac and the mirrors and detector from MMx. What do you have left? Two sources rotating around a central axis To me except for a diameter difference the two sources are essentially doing the same thing. Therefore it seems a rational conclusion to say that light must propagate away from these two sources in the same way for both. And theres only two options. Either both rotating sources have light leaving them at c in all directions or both have light leaving at variable speeds in all directions. The problem with SR seems to be that it says that sometimes the sources act one way *(sagnac) and sometimes another. I dont know about you but I thought any good theory has to be universally consistent? Obviously SR isnt when it comes to rotating sources. If you have a source rotating around an axis x at an tangental velocity of v . And the axis x is not moving in the frame of reference(the source S is rotating around the static axis X) Then the question is , in SR, or relativity , in this frame of reference ,... is the light speed c relative to the rotating source or is the light speed c+-v relative to the rotating source? This depends in detail on what you mean by "speed" -- at base your confusions are related to PUNs on that word. In particular, "speed relative to the source" is meaningless - one can measure and define speed only relative to a COORDINATE SYSTEM. You can choose a coordinate system in which the source is at rest, which is the usual thing to do in this case, but when the source is rotating around an axis then so are these coordinates, and things get both complicated and ambiguous (you could choose any of several different rotating coordinates in which the source is at rest). This is what Im trying to get you to define one way or another. Because above you say if the source is rotating then one has to take into account the rotating coordinates as you say above.As SR does with sagnac. But why doesnt it make the same decisions with MMx? Itis also rotating yet SR calculates it as if it isnt. And the usual excuse is that the rotation is too small to effect the MMX observations. But thats not true, because the rotation is large enouh to effect apath difference in a ring gyro . Dont forget sagnac may be a different setup then MMX but they both measure the same thing... path difference. Therefore if a shorter path difference in a ring gyro can effect a fringe shift then a longer path difference in a MMx experiment would also be subject to the same measureable path difference on each arm,... BUt it isnt. And thats because light always travels at c in the source frame only. Not in any other frame as SR would mislead us into believing In SR, any light ray will move in vacuum with speed c relative to any inertial frame. A direct consequence of this is that in general the speed will not be c relative to a NON-inertial frame (e.g. a rotating system). This is not observed. In MMx where the source is what you call non inertial the light is *always* observed to be at c. Contrary to what you say SR would predict If the axis of your rotation is at rest in some inertial frame, we can use that inertial frame and its known (vacuum) speed of light to compute what would be measured in the rotating system. But to do that one must select a specific rotating system. For different choices of system and light path, one can obtain the following values for the 1-way speed of light: c for a radial light path * c*g for a radial light path # c+v for a counter-rotating circular path * c-v for a co-rotating circular path * (c+v)*g for a counter-rotating circular path # (c-v)*g for a co-rotating circular path # (circular paths are centered on and normal to the rotation axis, and they go once around the rotating system) * "steal" the time coordinate from the inertial frame of the center (i.e. use clocks at rest in the inertial frame) # using a clock at rest in the rotating system; g=1/sqrt(1-v^2/c^2) where v is the speed of the clock relative to the inertial frame. So the last two entries are most natural for a rotating system (I gave the full list because otherwise your "c+-v" would not be present at all). Note that by looking at the very same light rays in the inertial frame one concludes they travel with speed c relative to that frame, so this is all consistent. Those circular paths go all the way around the rotating system, so one needs only a single clock to make the measurement. If you attempted to make a measurement only half the way around one of these circles, you would find that there are several different ways to synchronize the two clocks that are required, and the result varies depending on which you chose -- the ambiguities get MUCH worse. The middle entries, c+v and c-v, are ultimately due to measuring the distance traveled in one frame (the rotating one), but measuring time of flight in a DIFFERENT frame (the inertial frame). The ratio of measurements made in different frames is not "speed" in any sense. That's why I said you used PUNs on "speed". This still ignores the contradiction at the heart of SR. I assume you say above that in a rotating source SR calculates distance in the rotating frame and time in the inertial. To start with this is an irrelevent distinction as classical theory has the flight time the same in all frames and it still is able to explain both sagnac and MMx results. So why relativists feel it neccesary to construct such an elaborate artifice when classicals simpler one does just as well. But secondly you ignore that fact that SR is being inconsistent. Because in sagnac from what I see it measures the distance travelled in the inertial frame whereas in MMx it measures the distance travelled in the rotating frame. If you can answer this then Ill show you how SR cannot predict both sagnac and MMx without contradicting itself. You are confused. You seem to be trying to use a "sound bite" approach to relativity, which is woefully inadequate. One cannot make crisp conclusions using phrases like "speed relative to the source" -- it's easy to get contradictions using such nebulous phrases. Fortunately, SR itself has no such difficulties. IOW the contradictions you find are an artifact of your poor understanding of SR, not from SR itself. No how could it be a contradiction due to my understanding of SR? Youve just clarified that SR calculates distance in the rotating and time in the inertial. If thats true then its your statement not mine that is inconsistent as we both know thatin sagnac the only way SR can explain the fringe shift is by measuring the distance travelled in the *inertial frame*. Not the rotating frame. Sean www.gammarayburst.com |
#109
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GETTING RID OF EINSTEIN RELATIVITY
On 20 Jun, 14:51, Tom Roberts wrote:
sean wrote: to see how classical theory only can explain both sagnac and MMx . Sure, certain classical theories can explain them both. So what? There are MANY other experiments that such theories cannot explain; SR on the other hand explains them all (within its domain). Name these experiments. this is a false claim by you as there are NO experiments that classical cannot explain. Whereas as Ive hown SR cannot explian both sagnac and MMx See the simulations at... http://www.youtube.com/watch?v=QLSfmvFcLB8 which clearly show that Classical theory can explain bothy sagnac and MMx See the FAQ for over a hundred experiments that confirm SR; most of them are completely inconsistent with any classical theory (i.e. pre-SR). To start with you dont seem to understand that the sagnac source is essentially identical to the MMx in that they both rotate around an axis . The instruments are VERY different: Sagnac's has a large enclosed area, and the MMX has zero enclosed area, and this makes all the difference as far as rotation is concerned. Rubbish. You ignore the fact that regardless of the setups of both experiments the source in both does exactly teh same thing...It rotates about a central axis. Which is one reason why any physics students should not read your faq. Its misinformation based on false evidence.The proof you rely on at your faq is in fact false evidence Yet SR says that a source that rotates around an axis sometimes has light leaving it at variable speeds (when SR tries to explain sagnac) and sometimes has light leaving it at constant speeds(when SR tries to explain MMx). This is complete nonsense. You should learn about SR before attempting to describe what it says. And you should learn about the differences in these two experiments and their instruments. shrug Even a pseudoscientist like yourself should be able to see this inherent contradiction in SR. More like your inabilty to supply proof that classical cannot explain any known experiment or your inabilty to refute why SR predicts inconsistent speeds of light for the same frame. (Ie Sr predicts that in an inertial frame sometimes light is at c (sagnac) and sometimes its variable(MMx). Bad science without proof. Supply evidence for your arguments Tom. Not hand waving rhetoric) Sean www.gammarayburst.com see.. http://www.youtube.com/watch?v=QLSfmvFcLB8 for a full explanation of how SR and the standard model cannot explain grb`s , sagnac and MMx . And how classical theory is able to completely explain all known observations. |
#110
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GETTING RID OF EINSTEIN RELATIVITY
sean wrote:
On 20 Jun, 14:51, Tom Roberts wrote: sean wrote: to see how classical theory only can explain both sagnac and MMx . Sure, certain classical theories can explain them both. So what? There are MANY other experiments that such theories cannot explain; SR on the other hand explains them all (within its domain). Name these experiments. See http://math.ucr.edu/home/baez/physic...periments.html Ive hown SR cannot explian both sagnac and MMx You are wrong. SR does indeed explain both MMX and Sagnac. shrug See the simulations at... http://www.youtube.com/watch?v=QLSfmvFcLB8 which clearly show that Classical theory can explain bothy sagnac and MMx Sure, if one makes very specific assumptions about "classical theory" -- specifically that the ether is fully dragged by the earth. That assumption, however, is inconsistent with observations of stellar aberration. My point is that a given theory must explain ALL of the experiments, not just a specific pair you happen to like. The experiments on relativistic kinematics and the speed of light from moving sources are tests that classical theories simply cannot explain at all. The fact that some other theories also explain these two experiments does not diminish the ability of SR to do so. But SR explains a much wider class of experiments than the classical theories, which is of course why we use SR today and not those old theories. Tom Roberts |
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