Pioneer 10 & 11 Spacecraft Deceleration Anomaly Revisited

http://groups-beta.google.com/group/...er+Anomaly&rnu
m=1&hl=en#86c8eff2e8ecdddb

Yes E^2 = energy/volume = pressure
but what E?

Reference:


Study of the Pioneer Anomaly:
A Problem Set Slava G. Turyshev,
Michael Martin Nieto,
and John D. Anderson
(Dated: February 24, 2005)
http://xxx.lanl.gov/abs/physic*s/0502123


TABLE IV: Error Budget: A Summary of Biases and
Uncertainties


Solar radiation pressure at many AU:


..03 (+/- .01) x 10^-8 cm/sec^2


is insignificant to observed deceleration of:


8.74 (+/- 1.33) x 10^-8 cm/sec^2


Actual pressure on Pioneer space craft in more in line
with vacuum energy


rho c^2


where


rho = ~6 x 10^-30 g/cm^2


corresponding to estimate of dark energy_matter density


Richard Saam

On Tue, 28 Jun 2005 10:09:22 -0400, "sue jahn"
wrote:

http://groups-beta.google.com/group/...er+Anomaly&rnu
m=1&hl=en#86c8eff2e8ecdddb

Yes E^2 = energy/volume = pressure
but what E?

Reference:


Study of the Pioneer Anomaly:
A Problem Set Slava G. Turyshev,
Michael Martin Nieto,
and John D. Anderson
(Dated: February 24, 2005)
http://xxx.lanl.gov/abs/physic*s/0502123


TABLE IV: Error Budget: A Summary of Biases and
Uncertainties


Solar radiation pressure at many AU:


.03 (+/- .01) x 10^-8 cm/sec^2


is insignificant to observed deceleration of:


8.74 (+/- 1.33) x 10^-8 cm/sec^2


Actual pressure on Pioneer space craft in more in line
with vacuum energy


rho c^2


where


rho = ~6 x 10^-30 g/cm^2


corresponding to estimate of dark energy_matter density


Richard Saam

Sue, Richard or anyone:
It takes pressure gradient to exert a force on the craft, not pressure
alone. Pressure you calculate is 10^-9 Pa. Now what?

John Polasek
http://www.dualspace.net

John C. Polasek wrote:

On Tue, 28 Jun 2005 10:09:22 -0400, "sue jahn"
wrote:


http://groups-beta.google.com/group/...er+Anomaly&rnu
m=1&hl=en#86c8eff2e8ecdddb

Yes E^2 = energy/volume = pressure
but what E?

Reference:


Study of the Pioneer Anomaly:
A Problem Set Slava G. Turyshev,
Michael Martin Nieto,
and John D. Anderson
(Dated: February 24, 2005)
http://xxx.lanl.gov/abs/physic*s/0502123


TABLE IV: Error Budget: A Summary of Biases and
Uncertainties


Solar radiation pressure at many AU:


.03 (+/- .01) x 10^-8 cm/sec^2


is insignificant to observed deceleration of:


8.74 (+/- 1.33) x 10^-8 cm/sec^2


Actual pressure on Pioneer space craft in more in line
with vacuum energy


rho c^2


where


rho = ~6 x 10^-30 g/cm^2


corresponding to estimate of dark energy_matter density


Richard Saam


Sue, Richard or anyone:
It takes pressure gradient to exert a force on the craft, not pressure
alone. Pressure you calculate is 10^-9 Pa. Now what?

John Polasek
http://www.dualspace.net


F = M a = Cd Area rho c^2

http://xxx.lanl.gov/abs/physic*s/0502122

M = 241,000 g

a = 8.74 x 10^-8 cm/sec^2

c = 3.00E+10 cm/sec

Area is Pioneer cross section area (parabolic dish)
= (pi/4)(274)^2 cm^2 = 58,965 cm^2

Solve for Cd

Cd = 66.2 unitless

The Cross sectional area of Pioneer is actually greater
than the 274 cm parabolic dish considering the booms
and other extremities.

So Cd probably is less.

An argument can be made that Cd could be accounted for
by conventional fluid mechanical Reynold's number
calculations related to drag coefficient (Cd).

Richard Saam

sue jahn wrote:
http://groups-beta.google.com/group/...er+Anomaly&rnu
m=1&hl=en#86c8eff2e8ecdddb

Yes E^2 = energy/volume = pressure
but what E?

Reference:


Study of the Pioneer Anomaly:
A Problem Set Slava G. Turyshev,
Michael Martin Nieto,
and John D. Anderson
(Dated: February 24, 2005)
http://xxx.lanl.gov/abs/physic*s/0502123


TABLE IV: Error Budget: A Summary of Biases and
Uncertainties


Solar radiation pressure at many AU:


.03 (+/- .01) x 10^-8 cm/sec^2


is insignificant to observed deceleration of:


8.74 (+/- 1.33) x 10^-8 cm/sec^2


Actual pressure on Pioneer space craft in more in line
with vacuum energy


rho c^2


where


rho = ~6 x 10^-30 g/cm^2


corresponding to estimate of dark energy_matter density
lets say space vacuum density


Richard Saam





F = M a = Cd Area rho c2

http://xxx.lanl.gov/abs/physic*s/0502122

M = 241,000 g

a = 8.74 x 10^-8 cm/sec2

c = 3.00E+10 cm/sec

Area is Pioneer cross section area
(parabolic dish radius R = 137 cm)
= pi R^2 cm^2 = 58,965 cm2

let rho = 6E-30 g/cc which is a value about 2/3 of
critical space density
(appropriate value for observed universe inflation)

rho =(3/(8*pi))*H^2/G = 9.56E-30 g/cc

whe

H = Hubble Constant 2.31E-18 /sec
or 71.23 km/sec/million parsec
G = Gravity Constant 6.674200E-08 cm^3 g^-1 sec^-2

Solve for Cd

F = M a = Cd Area rho c2

Cd = 66.2 unitless

Now in conventional fluid mechanics

http://www.ce.utexas.edu/prof/kinnas...Anal.htm#Graph

Cd = 66.2 would indicate a system in the laminar range
and the applicability of Stokes' law.

http://www.cord.edu/faculty/ulnessd/...nja/stokes.htm

F = M a =6 pi R n v

but for this analysis we say v = c so:

F = M a =6 pi R n c

whe
n = fluid visocity mc/A
or momentum transfer / A

solving for viscosity

n = 2.72E-16 g/(cm sec)

divide by c and

m/A = 9.08E-27 g/cm^2

A = 1.42E+03 cm^2

length = 37.73 cm

volume = 53701.22 cm^3

viscosity 2.72E-16 g/(cm sec)
m/area 9.08E-27 g/cm^2
area 1.42E+03 cm^2
length 37.73 cm
volume 53701.22 cm^3

mass in volume 3.22E-25 g
mass /me 353.71

This is a rather rough calculation
but it demonstrates that well designed
space craft
(of various shapes)
to follow Pioneer could find
valuable information about the space vacuum parameters.

Richard Saam

On Wed, 29 Jun 2005 15:56:50 GMT, Richard Saam wrote:

This is a rather rough calculation
but it demonstrates that well designed
space craft
(of various shapes)
to follow Pioneer could find
valuable information about the space vacuum parameters.

....So, when does Tony Vance show up to show how this all enters into
his Big Bertha Thing (dildo)?

OM

--

"No ******* ever won a war by dying for | http://www.io.com/~o_m
his country. He won it by making the other | Sergeant-At-Arms
poor dumb ******* die for his country." | Human O-Ring Society

- General George S. Patton, Jr

In the field of waste water, drinking water and
sanitation there is the concept of orthokinetic
flocculation which is generally mathematically expressed by

shear = sqrt(Power/(viscosity x Volume))

Given a tank (with "Volume" cm^3)
filled with water
(with absolute "viscosity" g/(cm sec))
(momentum transferred per surface area)
and this water containing particles,
a "Power" (erg/sec)
(motor driven impeller)
is introduced to provide "shear" (/sec) (dv/dx)
within the water.

v2 - Particle 2
/
/ ^
/ |
/ x
/
v1 - Particle 1

Particle 1 and Particle 2 move at different velocities
in the shear (v2-v1)/delta_x or dv/dx

Proper selection of shear ensures that particles remain
suspended in the fluid and if they aggregate or remain
separate.

It is interesting to note that shear (dv/dx) has units
of /time. This is the same unit as the Hubble constant
in cosmology.
Could the cosmos (volume) be observed as an
orthokinetic fluid medium with vacuum energy density
having a viscosity
such that observed Hubble "shear" is congruent with
galactic mass distribution with the universe?

Richard Saam

Richard Saam wrote:


It is interesting to note that shear (dv/dx) has units of /time. This
is the same unit as the Hubble constant in cosmology.
Could the cosmos (volume) be observed as an orthokinetic fluid medium
with vacuum energy density having a viscosity
such that observed Hubble "shear" is congruent with galactic mass
distribution with the universe?


Explain again how this lets us know that the universe is in the shape of
a banana. ;-)

Arthur

"Pat Flannery" wrote in message
...

Explain again how this lets us know that the universe is in the shape of a
banana. ;-)

Arthur

42

Ford

On Thu, 30 Jun 2005 16:28:45 GMT, Richard Saam wrote:

In the field of waste water, drinking water and
sanitation there is the concept of orthokinetic
flocculation which is generally mathematically expressed by

shear = sqrt(Power/(viscosity x Volume))

Given a tank (with "Volume" cm^3)
filled with water
(with absolute "viscosity" g/(cm sec))
(momentum transferred per surface area)
and this water containing particles,
a "Power" (erg/sec)
(motor driven impeller)
is introduced to provide "shear" (/sec) (dv/dx)
within the water.

v2 - Particle 2
/
/ ^
/ |
/ x
/
v1 - Particle 1

Particle 1 and Particle 2 move at different velocities
in the shear (v2-v1)/delta_x or dv/dx

Proper selection of shear ensures that particles remain
suspended in the fluid and if they aggregate or remain
separate.

It is interesting to note that shear (dv/dx) has units
of /time. This is the same unit as the Hubble constant
in cosmology.

No, its closest analogy is to angular velocity and rotation 1/t.

Could the cosmos (volume) be observed as an
orthokinetic fluid medium with vacuum energy density
having a viscosity
such that observed Hubble "shear" is congruent with
galactic mass distribution with the universe?

Richard Saam

John Polasek
http://www.dualspace.net

On Thu, 30 Jun 2005 11:52:22 -0500, Pat Flannery
wrote:

Explain again how this lets us know that the universe is in the shape of
a banana. ;-)

....I'm beginning to wonder if Vance's Syndrome is actually
contractable over usenet. At the rate we're going, John Keely will
resurrect himself and start infesting the group by next month.

OM

--

"No ******* ever won a war by dying for | http://www.io.com/~o_m
his country. He won it by making the other | Sergeant-At-Arms
poor dumb ******* die for his country." | Human O-Ring Society

- General George S. Patton, Jr