A Space & astronomy forum. SpaceBanter.com

Go Back   Home » SpaceBanter.com forum » Astronomy and Astrophysics » Astronomy Misc
Site Map Home Authors List Search Today's Posts Mark Forums Read Web Partners

Precession of Mercury's longitude of perihelion - (so called "anomaly")



 
 
Thread Tools Display Modes
  #121  
Old May 24th 07, 02:48 AM posted to sci.astro,sci.physics,sci.physics.relativity
[email protected]
external usenet poster
 
Posts: 3
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")

Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?

If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?

Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!

  #122  
Old May 24th 07, 11:30 AM posted to sci.astro,sci.physics,sci.physics.relativity
Dirk Van de moortel
external usenet poster
 
Posts: 247
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!


The point is that the engineer doesn't understand what percentages are.
Do you understand the meaning of the percent-sign?

Dirk Vdm


  #123  
Old May 24th 07, 12:17 PM posted to sci.astro,sci.physics,sci.physics.relativity
Androcles[_2_]
external usenet poster
 
Posts: 1,040
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


wrote in message
oups.com...
: Assume measurement accuracy to "within 43 arc seconds" per century.
:
: Assume 1 Earth century = 415 Mercury orbits
:
: ~~~~~~
:
: 415 orbits * 360 degrees = 149400 degrees per century
: 149400 degrees * 60 arc minutes = 8964000 arc minutes per century
: 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
: century.
:
:
: 43
: -------------------------------- = 0.0000000799494273389855719 =
: 7.9949E-8
: 537840000
:
: Are we all on the same page so far?
:
: If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
: not equal to 7.9949E-6 percent?
:
: Am I suffering from a brain embolism here or something?? 'Cause it's
: either that or I'm completely missing the point of
: http://users.telenet.be/vdmoortel/di...rcentages.html.
:
: For the love of god, help!

Dork is beyond help. As long as he only writes to his computer
he can stay indoors without a straight-jacket.



  #124  
Old May 24th 07, 07:39 PM posted to sci.astro,sci.physics,sci.physics.relativity
OG
external usenet poster
 
Posts: 780
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


"Dirk Van de moortel" wrote
in message ...

wrote in message
oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Far more interesting is that it's completely irrelevant how many orbits
Mercury makes in a century. All we're interested in is how accurately we can
measure the orbital elements which can be done from as few as 3 measurements
to far higher accuracy than "43 arc seconds".



  #125  
Old May 24th 07, 07:44 PM posted to sci.astro,sci.physics,sci.physics.relativity
Dirk Van de moortel
external usenet poster
 
Posts: 247
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


"OG" wrote in message ...

"Dirk Van de moortel" wrote in message ...

wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Far more interesting is that it's completely irrelevant how many orbits Mercury makes in a century. All we're interested in is how
accurately we can measure the orbital elements which can be done from as few as 3 measurements to far higher accuracy than "43 arc
seconds".


All I am interested in here, is how Androcles manages to **** up
*every* equation or calculation a nine years old should be able to
handle without any problem :-)

Dirk Vdm


  #126  
Old May 26th 07, 11:18 PM posted to sci.astro,sci.physics,sci.physics.relativity
[email protected]
external usenet poster
 
Posts: 3
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


Dirk Van de moortel wrote:
wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!


The point is that the engineer doesn't understand what percentages are.
Do you understand the meaning of the percent-sign?

Dirk Vdm


Hah...obviously not.

Assume a 15 question quiz. You answer 11 correct out of 15. Your
percentage score is:

11/15 = .73/1 = x/100.

..731(100)/1 = x(100)/100

73.1(1)/1 = x(1)

73.1 = x

So, you answered 26.9 percent wrong.

26.9 = y

26.9/(1)(100) = y/(1)(100)

..269 = y/100

So...

4ish/15 = .269 = y/100 = roughly 26.9 percent.

Assume 5.3784E8 arcseconds per one century rotation. This number can
be + or - 43 arcseconds. Percent error, right?

43 arcseconds/5.3784E8 arcseconds = 7.9949E-8/1 = x/100

7.9949E-8(100)/1 = x(100)/100

7.9949E-6(1)/1 = x(1)

7.9949E-6 = x

Mercury's orbit is 5.3784E8 arcsecond's per century, +/- 43
arcseconds, or +/- 7.9949E-6 percent, from what I understand from
dumb****dore's previous statements.

Conversely, if I work your answer backwards, I get:

7.9949E-4 = x

7.9949E-4/1(100) = x/1(100)

7.9949E-6/1 = x/100

y arcseconds/5.3784E8 arcseconds = 7.9949E-6/1 = 7.9949E-4/100

y = 4298.0 arcseconds per century.

--------

So, the million dollar question is: who is missing a factor of 100
here? Me, Dumb****dore, VDM, everyone? Where, if I'm wrong, is the
missing factor coming from?

  #127  
Old May 26th 07, 11:18 PM posted to sci.astro,sci.physics,sci.physics.relativity
[email protected]
external usenet poster
 
Posts: 3
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


Dirk Van de moortel wrote:
wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!


The point is that the engineer doesn't understand what percentages are.
Do you understand the meaning of the percent-sign?

Dirk Vdm


Hah...obviously not.

Assume a 15 question quiz. You answer 11 correct out of 15. Your
percentage score is:

11/15 = .73/1 = x/100.

..731(100)/1 = x(100)/100

73.1(1)/1 = x(1)

73.1 = x

So, you answered 26.9 percent wrong.

26.9 = y

26.9/(1)(100) = y/(1)(100)

..269 = y/100

So...

4ish/15 = .269 = y/100 = roughly 26.9 percent.

Assume 5.3784E8 arcseconds per one century rotation. This number can
be + or - 43 arcseconds. Percent error, right?

43 arcseconds/5.3784E8 arcseconds = 7.9949E-8/1 = x/100

7.9949E-8(100)/1 = x(100)/100

7.9949E-6(1)/1 = x(1)

7.9949E-6 = x

Mercury's orbit is 5.3784E8 arcsecond's per century, +/- 43
arcseconds, or +/- 7.9949E-6 percent, from what I understand from
dumb****dore's previous statements.

Conversely, if I work your answer backwards, I get:

7.9949E-4 = x

7.9949E-4/1(100) = x/1(100)

7.9949E-6/1 = x/100

y arcseconds/5.3784E8 arcseconds = 7.9949E-6/1 = 7.9949E-4/100

y = 4298.0 arcseconds per century.

--------

So, the million dollar question is: who is missing a factor of 100
here? Me, Dumb****dore, VDM, everyone? Where, if I'm wrong, is the
missing factor coming from?

  #128  
Old May 27th 07, 09:55 AM posted to sci.astro,sci.physics,sci.physics.relativity
Dirk Van de moortel
external usenet poster
 
Posts: 247
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


wrote in message ups.com...

Dirk Van de moortel wrote:
wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!


The point is that the engineer doesn't understand what percentages are.
Do you understand the meaning of the percent-sign?

Dirk Vdm


Hah...obviously not.


% is an abreviation of 1/100


Assume a 15 question quiz. You answer 11 correct out of 15. Your
percentage score is:

11/15 = .73/1 = x/100.


Yes.
11/15 = 11/15 * 1
= 11/15 * 100 %
= 73.1 %
and that should be all there is to it.

Dirk Vdm


  #129  
Old May 27th 07, 09:56 AM posted to sci.astro,sci.physics,sci.physics.relativity
Dirk Van de moortel
external usenet poster
 
Posts: 247
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")


wrote in message ups.com...

Dirk Van de moortel wrote:
wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?


Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?


It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!


The point is that the engineer doesn't understand what percentages are.
Do you understand the meaning of the percent-sign?

Dirk Vdm


Hah...obviously not.


% is an abbreviation of 1/100


Assume a 15 question quiz. You answer 11 correct out of 15. Your
percentage score is:

11/15 = .73/1 = x/100.


Yes.
11/15 = 11/15 * 1
= 11/15 * 100 %
= 73.3 %
and that should be all there is to it.

Dirk Vdm


  #130  
Old May 27th 07, 07:24 PM posted to sci.astro,sci.physics,sci.physics.relativity
John C. Polasek
external usenet poster
 
Posts: 102
Default Precession of Mercury's longitude of perihelion - (so called "anomaly")

On Sun, 27 May 2007 08:55:16 GMT, "Dirk Van de moortel"
wrote:


wrote in message ups.com...

Dirk Van de moortel wrote:
wrote in message oups.com...
Assume measurement accuracy to "within 43 arc seconds" per century.

Assume 1 Earth century = 415 Mercury orbits

~~~~~~

415 orbits * 360 degrees = 149400 degrees per century
149400 degrees * 60 arc minutes = 8964000 arc minutes per century
8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per
century.


43
-------------------------------- = 0.0000000799494273389855719 =
7.9949E-8
537840000

Are we all on the same page so far?

Sure.


If so, what the hell am I missing when 7.9949E-8 parts out of 100 is
not equal to 7.9949E-6 percent?

N parts out 100 is N %. N = N.
It is, but that is not what he is saying.
7.9949E-8 times 100 is not 7.9949E-6 percent
It is
7.9949E-6
and it is
7.9949E-4 percent


Am I suffering from a brain embolism here or something?? 'Cause it's
either that or I'm completely missing the point of
http://users.telenet.be/vdmoortel/di...rcentages.html.

For the love of god, help!

The point is that the engineer doesn't understand what percentages are.
Do you understand the meaning of the percent-sign?

Dirk Vdm


Hah...obviously not.


% is an abreviation of 1/100


Assume a 15 question quiz. You answer 11 correct out of 15. Your
percentage score is:

11/15 = .73/1 = x/100.


Yes.
11/15 = 11/15 * 1
= 11/15 * 100 %
= 73.1 %
and that should be all there is to it.

Dirk Vdm

 




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
HOW COLUMBUS DISCOVERED AMERICA -- Why He Was Called "The Homing Pigeon" Ed Conrad Astronomy Misc 1 April 29th 07 02:24 AM
"VideO Madness" "Pulp FictiOn!!!," ...., and "Kill Bill!!!..." Colonel Jake TM Misc 0 August 26th 06 09:24 PM
"VideO Madness" "DO yOu want?!?!?!..." 'and' "GoD HATES FAGS!!!..." Colonel Jake TM Misc 0 August 13th 06 07:28 AM


All times are GMT +1. The time now is 07:13 AM.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.
Copyright ©2004-2024 SpaceBanter.com.
The comments are property of their posters.