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#121
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
Assume measurement accuracy to "within 43 arc seconds" per century.
Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! |
#122
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! The point is that the engineer doesn't understand what percentages are. Do you understand the meaning of the percent-sign? Dirk Vdm |
#123
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
wrote in message oups.com... : Assume measurement accuracy to "within 43 arc seconds" per century. : : Assume 1 Earth century = 415 Mercury orbits : : ~~~~~~ : : 415 orbits * 360 degrees = 149400 degrees per century : 149400 degrees * 60 arc minutes = 8964000 arc minutes per century : 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per : century. : : : 43 : -------------------------------- = 0.0000000799494273389855719 = : 7.9949E-8 : 537840000 : : Are we all on the same page so far? : : If so, what the hell am I missing when 7.9949E-8 parts out of 100 is : not equal to 7.9949E-6 percent? : : Am I suffering from a brain embolism here or something?? 'Cause it's : either that or I'm completely missing the point of : http://users.telenet.be/vdmoortel/di...rcentages.html. : : For the love of god, help! Dork is beyond help. As long as he only writes to his computer he can stay indoors without a straight-jacket. |
#124
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
"Dirk Van de moortel" wrote in message ... wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Far more interesting is that it's completely irrelevant how many orbits Mercury makes in a century. All we're interested in is how accurately we can measure the orbital elements which can be done from as few as 3 measurements to far higher accuracy than "43 arc seconds". |
#125
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
"OG" wrote in message ... "Dirk Van de moortel" wrote in message ... wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Far more interesting is that it's completely irrelevant how many orbits Mercury makes in a century. All we're interested in is how accurately we can measure the orbital elements which can be done from as few as 3 measurements to far higher accuracy than "43 arc seconds". All I am interested in here, is how Androcles manages to **** up *every* equation or calculation a nine years old should be able to handle without any problem :-) Dirk Vdm |
#126
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
Dirk Van de moortel wrote: wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! The point is that the engineer doesn't understand what percentages are. Do you understand the meaning of the percent-sign? Dirk Vdm Hah...obviously not. Assume a 15 question quiz. You answer 11 correct out of 15. Your percentage score is: 11/15 = .73/1 = x/100. ..731(100)/1 = x(100)/100 73.1(1)/1 = x(1) 73.1 = x So, you answered 26.9 percent wrong. 26.9 = y 26.9/(1)(100) = y/(1)(100) ..269 = y/100 So... 4ish/15 = .269 = y/100 = roughly 26.9 percent. Assume 5.3784E8 arcseconds per one century rotation. This number can be + or - 43 arcseconds. Percent error, right? 43 arcseconds/5.3784E8 arcseconds = 7.9949E-8/1 = x/100 7.9949E-8(100)/1 = x(100)/100 7.9949E-6(1)/1 = x(1) 7.9949E-6 = x Mercury's orbit is 5.3784E8 arcsecond's per century, +/- 43 arcseconds, or +/- 7.9949E-6 percent, from what I understand from dumb****dore's previous statements. Conversely, if I work your answer backwards, I get: 7.9949E-4 = x 7.9949E-4/1(100) = x/1(100) 7.9949E-6/1 = x/100 y arcseconds/5.3784E8 arcseconds = 7.9949E-6/1 = 7.9949E-4/100 y = 4298.0 arcseconds per century. -------- So, the million dollar question is: who is missing a factor of 100 here? Me, Dumb****dore, VDM, everyone? Where, if I'm wrong, is the missing factor coming from? |
#127
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
Dirk Van de moortel wrote: wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! The point is that the engineer doesn't understand what percentages are. Do you understand the meaning of the percent-sign? Dirk Vdm Hah...obviously not. Assume a 15 question quiz. You answer 11 correct out of 15. Your percentage score is: 11/15 = .73/1 = x/100. ..731(100)/1 = x(100)/100 73.1(1)/1 = x(1) 73.1 = x So, you answered 26.9 percent wrong. 26.9 = y 26.9/(1)(100) = y/(1)(100) ..269 = y/100 So... 4ish/15 = .269 = y/100 = roughly 26.9 percent. Assume 5.3784E8 arcseconds per one century rotation. This number can be + or - 43 arcseconds. Percent error, right? 43 arcseconds/5.3784E8 arcseconds = 7.9949E-8/1 = x/100 7.9949E-8(100)/1 = x(100)/100 7.9949E-6(1)/1 = x(1) 7.9949E-6 = x Mercury's orbit is 5.3784E8 arcsecond's per century, +/- 43 arcseconds, or +/- 7.9949E-6 percent, from what I understand from dumb****dore's previous statements. Conversely, if I work your answer backwards, I get: 7.9949E-4 = x 7.9949E-4/1(100) = x/1(100) 7.9949E-6/1 = x/100 y arcseconds/5.3784E8 arcseconds = 7.9949E-6/1 = 7.9949E-4/100 y = 4298.0 arcseconds per century. -------- So, the million dollar question is: who is missing a factor of 100 here? Me, Dumb****dore, VDM, everyone? Where, if I'm wrong, is the missing factor coming from? |
#128
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
wrote in message ups.com... Dirk Van de moortel wrote: wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! The point is that the engineer doesn't understand what percentages are. Do you understand the meaning of the percent-sign? Dirk Vdm Hah...obviously not. % is an abreviation of 1/100 Assume a 15 question quiz. You answer 11 correct out of 15. Your percentage score is: 11/15 = .73/1 = x/100. Yes. 11/15 = 11/15 * 1 = 11/15 * 100 % = 73.1 % and that should be all there is to it. Dirk Vdm |
#129
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
wrote in message ups.com... Dirk Van de moortel wrote: wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! The point is that the engineer doesn't understand what percentages are. Do you understand the meaning of the percent-sign? Dirk Vdm Hah...obviously not. % is an abbreviation of 1/100 Assume a 15 question quiz. You answer 11 correct out of 15. Your percentage score is: 11/15 = .73/1 = x/100. Yes. 11/15 = 11/15 * 1 = 11/15 * 100 % = 73.3 % and that should be all there is to it. Dirk Vdm |
#130
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Precession of Mercury's longitude of perihelion - (so called "anomaly")
On Sun, 27 May 2007 08:55:16 GMT, "Dirk Van de moortel"
wrote: wrote in message ups.com... Dirk Van de moortel wrote: wrote in message oups.com... Assume measurement accuracy to "within 43 arc seconds" per century. Assume 1 Earth century = 415 Mercury orbits ~~~~~~ 415 orbits * 360 degrees = 149400 degrees per century 149400 degrees * 60 arc minutes = 8964000 arc minutes per century 8964000 arc minutes * 60 arc seconds = 537840000 arc seconds per century. 43 -------------------------------- = 0.0000000799494273389855719 = 7.9949E-8 537840000 Are we all on the same page so far? Sure. If so, what the hell am I missing when 7.9949E-8 parts out of 100 is not equal to 7.9949E-6 percent? N parts out 100 is N %. N = N. It is, but that is not what he is saying. 7.9949E-8 times 100 is not 7.9949E-6 percent It is 7.9949E-6 and it is 7.9949E-4 percent Am I suffering from a brain embolism here or something?? 'Cause it's either that or I'm completely missing the point of http://users.telenet.be/vdmoortel/di...rcentages.html. For the love of god, help! The point is that the engineer doesn't understand what percentages are. Do you understand the meaning of the percent-sign? Dirk Vdm Hah...obviously not. % is an abreviation of 1/100 Assume a 15 question quiz. You answer 11 correct out of 15. Your percentage score is: 11/15 = .73/1 = x/100. Yes. 11/15 = 11/15 * 1 = 11/15 * 100 % = 73.1 % and that should be all there is to it. Dirk Vdm |
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