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Moon tidal locking inevitable by now?
Hi! I wasn't sure whether to start a new thread or tease this one out
a bit. I am not a mathematician nor an astronomer, just a layman trying to figure this out: A question has been plaguing me as a friend and I discuss "tidal lock." Putting the physics of tidal lock aside (the Earth "commands" the moon to do this as I understand) I am wondering what the odds of tidal lock occurring would be if the Earth were not forcing the situation. In other words, what would be the odds of the moon orbiting and spinning at the same rate by happenstance? If the orbit took even 28.3 days and the spin took 27.31 days, it wouldn't be very many years for us to see the other side. The odds must be infinitesimally small for them to go on like that for millennia, is that correct? Is there any math that could prove this? Thank you for any wisdom. |
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Moon tidal locking inevitable by now?
On Monday, March 3, 2014 3:19:02 AM UTC-5, wrote:
A question has been plaguing me as a friend and I discuss "tidal lock." Putting the physics of tidal lock aside (the Earth "commands" the moon to do this as I understand) I am wondering what the odds of tidal lock occurring would be if the Earth were not forcing the situation. In other words, what would be the odds of the moon orbiting and spinning at the same rate by happenstance? I don't think there's enough information to answer your question. Tidal lock, as the name suggests, is a tidal force. The moon is an imperfect nearly spherical body, and not a perfect test particle. I think your question could be simplified to ask, what if the moon were small enough that tidal forces upon it were negligible. Then there would be negligible tides on the moon, negligible tidal dissipation in the moon, and so no change in the rotation rate of the moon.... and no tidal locking. Even if that were the case, the moon still raises tides on the *earth*. This is a dissipative process. The rotation rate of the earth would be changed, and the earth-moon orbit would be changed. In other words, the earth moon system is not fixed, even if one can ignore tidal locking of the moon's rotation rate. So then the question becomes: of all the possible starting points for the earth-moon system, what fraction of them will evolve to have exactly today's orbital parameters? I don't think we have enough information about possible starting points or exact evolutionary processes to make a good estimate to answer this question. And furthermore, asking for an exact match to today's parameters is guaranteed to give an infinitesimally small answer, because there are infinitely many possible orbits. Common practice is to ask for the probability over a finite range of parameters. (or, to quote the differential probability) CM |
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Moon tidal locking inevitable by now?
In article ,
Craig Markwardt wrote: I don't think we have enough information about possible starting points or exact evolutionary processes to make a good estimate to answer this question. We have enough moons in our Solar System to at least get some idea of under what conditions it should be probable or improbable. |
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Moon tidal locking inevitable by now?
On Mon, 03 Mar 14, " wrote:
If the orbit took even 28.3 days and the spin took 27.31 days, it wouldn't be very many years for us to see the other side. The odds must be infinitesimally small for them to go on like that for millennia, is that correct? Is there any math that could prove this? This is just a mathematical question. Suppose the fastest possible lunar rotation is once-around per hour (can't be bothered to calculate true bound where the surface reaches escape velocity), so the full range is between once-per-hour prograde and retrograde -- assuming axial tilt is normal to orbital plane here. Next, for the moon to appear to be locked to Earth-orbit over millenia means the synchronicity hasn't varied more than 5% over 4000 years (roughly), so over 4000 years a once-per-hour rotation is 35 million rotations x 2 = 70 million range from prograde to retrograde, out which we select 10% (5% prograde to retrograde) of one of those values, so that's 1 possibility out of 700 million, taking each possibility to be a 10% slice of a fixed number of rotations over a 4000 year period. So the odds of this happening randomly are 1 / 700,000,000. Eric |
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