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#1
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Every action has equal & opposite reaction?
A rocket only has a push to have it go forward. No opposite direction
needed. Go figure Bert |
#2
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Every action has equal & opposite reaction?
"G=EMC^2 Glazier" wrote...
in message ... A rocket only has a push to have it go forward. No opposite direction needed. Go figure Bert Actually, whether it's up in the air or out in space, Bert, the "thrust" that's needed to "push" a jet or a rocket is provided by a reaction engine that forces a fast moving jet of fluid in the rearward direction. This is in direct accordance with Isaac Newton's laws of motion. The jet of fluid discharged in the "opposite" direction makes the jet or rocket move in the forward direction. Also, small directional thrusters use this same law of motion in space to precisely move a spacecraft in several different directions. They're used for such things as docking with other spacecraft, orientation of the vehicle for proper reentry into the atmosphere, and so on. This is what's happening when you hear an astronaut ready the ship for a "two-second burn". happy days and... starry starry nights! -- Indelibly yours, Paine Ellsworth P.S.: Thank YOU for reading! P.P.S.: http://painellsworth.net |
#3
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Every action has equal & opposite reaction?
Painius I see it the way it is. Pressure on one side is pushing the
cylinder,and on the opposite side no pressure. Let it be in the Earth's atmosphere or the vacuum of space does not matter. Think what is happening when you were a kid and released the end of a toy balloon. The pressure push was on the end that was closed. pressure no pressure That is reality Newton was not all wrong on this but I'm 100% right For I'm calling it the way it is Bert |
#4
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Every action has equal & opposite reaction?
"G=EMC^2 Glazier" wrote...
in message ... Painius I see it the way it is. Pressure on one side is pushing the cylinder,and on the opposite side no pressure. Let it be in the Earth's atmosphere or the vacuum of space does not matter. Think what is happening when you were a kid and released the end of a toy balloon. The pressure push was on the end that was closed. pressure no pressure That is reality Newton was not all wrong on this but I'm 100% right For I'm calling it the way it is Bert Still not sure what you're saying, Bert. When i was a kid and released a toy balloon, the air from the inside of the balloon rushed out the open end and pushed the balloon all around in a chaotic motion. And it's still the same Newtonian law of motion at work: To every action there is an equal and opposite reaction. happy days and... starry starry nights! -- Indelibly yours, Paine Ellsworth P.S.: Thank YOU for reading! P.P.S.: http://painellsworth.net |
#5
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Every action has equal & opposite reaction?
On Jul 1, 8:11*am, "Painius" wrote:
"G=EMC^2 Glazier" wrote... The pressure push was on the end that was closed. * Still not sure what you're saying, Bert. *When i was a kid and released a toy balloon, the air from the inside of the balloon rushed out the open end and pushed the balloon all around in a chaotic motion. Bert is picturing the reactive force as being against the closed end of the balloon, thus pushing the balloon in that direction. But the *center of reactive pressure* is actually at the small point of the nozzle aperture. Thus the balloon is 'pushed around chaotically' instead of in a straight line. If you remember Goddard's first rockets, he mounted the engine on `top` of the whole assembly to achieve stability by the pendulum effect. |
#6
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Every action has equal & opposite reaction?
Painius Not arguing the air went out the open end,but their was pressure
on the closed end and this pressure is the push force that pushed the balloon forward. The gas going out need not push against anything. Try to picture inside the action taking place Bert |
#7
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Every action has equal & opposite reaction?
oc Controlling the opening controls the pressure. Greater pressure
faster the rocket goes. Release the pressure all at once and there is no push. Pressure goes to less or no pressure. Like heat goes to cold. Well Painius & oc think about it my way instead of Newtons,and it fits too Bert |
#8
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Every action has equal & opposite reaction?
"G=EMC^2 Glazier" wrote...
in message ... Painius Not arguing the air went out the open end,but their was pressure on the closed end and this pressure is the push force that pushed the balloon forward. The gas going out need not push against anything. Try to picture inside the action taking place Bert Okay, i get it. You're saying that there is a pressure difference between the inside of the balloon and the outside of the balloon at the closed end. And that it is this pressure on the inside at the closed end that pushes the balloon. And this pressure, that is there inside the inflated balloon all the time and pushing outward on the inside walls of the balloon, is the force that pushes the balloon when the little nozzle is opened at the opposite end from the closed end. Have i got it right so far, Bert? Now, this pressure on the inside walls of the balloon, BEFORE the open end is opened, is pretty much the same amount of pressure on every square inch of the inside of the balloon, correct? So if the pressure is pretty much equal at all points on the inside walls of the balloon, then what exactly happens AT THE VERY MOMENT that the balloon is opened? If it is the pressure on the inside walls of the balloon that drives the balloon forward and away from the open end, then why doesn't the balloon go left or right when the open end is opened? Why does the balloon aways go in the direction that is opposite from the opened end? I guess what i'm asking you, Bert, is how does the pressure, that is equal at all points on the inside of the balloon just before opening the nozzle, how and why does that pressure all move instantly to the closed end and then push JUST at the inside wall at the closed end? Why doesn't the pressure continue to push with equal force on every square inch of the inside walls of the balloon? Don't you find it suspicious that this pressure that you say is at the closed end of the balloon just happens to instantly concentrate itself at the end of the balloon that is precisely "opposite" from the open end of the balloon? And what happens to the pressure, which I assume is supposed to concentrate in the nose of a jet plane, when the pilot turns off the jet engine? Where does it go? And why does it go? And how did the pressure get there to the nose of the airplane in the first place? There has to be a *source* for the force, Bert. What is the source of the forward pressure? What *causes* it? Have you fired a gun? Have you felt the recoil or "kick" just as the bullet leaves the gun? How do you explain this shoulder-wrenching "kick"? happy days and... starry starry nights! -- Indelibly yours, Paine Ellsworth P.S.: Thank YOU for reading! P.P.S.: http://painellsworth.net |
#9
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Every action has equal & opposite reaction?
On Jul 1, 9:02*am, (G=EMC^2 Glazier) wrote:
The gas going out need not push against anything. Correct. Newton's 3rd law. Try to picture inside the action taking place. The only 'action taking place' relevant to propulsion occurs at the nozzle itself. That's the point where the reactive 'push' force is generated, not inside the balloon. Now instead of a balloon, think of a liquid fuel rocket. The combustion chamber is tiny, and is at the bottom of the rocket and vents through a nozzle. The reactive force is generated right there, not up 'inside' the rocket. Gyro-controlled active vanes or gimbals direct the flow to keep the rocket stable. The balloon has no such control, so it skeedaddles chaotically all over the place. |
#10
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Every action has equal & opposite reaction?
Painius You ended with the closed end of he gun. Here you are given me
the visa versa. Balloon filed with air of 35psi with no opening stays put. It has equal pressure on every square inch inside. Its rubber sides have blown up and it is a ball because its inside pressure is greater than the 14,5 pressure outside. Poke a pin in it and it will explode(I love to do that ) Make he right size hole and the pressure on the inside rubber will push against that 14.5 because it is about 21 psi stronger. Its the end that still has the pressure but yes it is losing it.fast Its not the open nozzle that is doing any pushing. Well Painius lets put it down as thinking in the right direction,and that is the push direction(had to get that in) Newton still had it kind of right Go figure Bert |
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