CCD charge transfer

On Wednesday, June 1, 2016 at 12:00:54 AM UTC-4, wrote=
[[Mod. note -- 41 excessively-quoted lines snipped here. -- jt]]
I'm trying to account (in theory) for a source of evanescent waves
(fringes) across the pixel array, with frequencies quantized as
nu_n =3D n(nu_o), where n is integer quantum mode n=3D(NdP_n/h),
N is array dim in unit pixels, d is pixel dim. P_n =3D (h/Nd)n is
momentum, h is Planck's constant, nu_o is detector fundamental
frequency nu_o =3D (c/d)/N and c is light velocity in vacuum.

What could "diffract" during charge xfer/readout?

Thanks again,
mark jonathan horn

Not sure if the answer will make sense as the terminology used could
sound unfamiliar. For this reason a video of a CCD I.C.

Photon sensor cell information is transferred off the array by an
analog bucket brigade. The reason for this is an A/D converted for
every cell is too costly therefore all cell for a X line are read
by one A/D converted for voltage to brightness. The important point
is the data is always clocked out in the same direction. If your
diffraction is always to the right or left of source then you have
your answer. It happened in the bucket brigade transfer. On the
other hand if it is a X + and - and Y + an - transfer then a cell
to cell should be the focus of attention.

There is a third viable that should be considered. CCDs are noisy
therefore software logarithms are applied to average out noise. The

[[Mod. note -- I speculate that the word "logarithms" in the above
line might be a typo for "algorithms". -- jt]]

jest of it is a 9 pixel block negative cross parity check. That is
a month full but it boils down to all 9 pixels should have a similar
brightness has it is on the limits of focus. If one or two of the
pixels in this block are different then they are considered to be
the result of random noise therefore replaced by an average data
of neighboring cells. Make sure your camera is in "raw mode" without
noise correction software. This could make the diffraction you are
looking for clearer.

Good luck with chasing down your diffraction.

https://www.youtube.com/watch?v=3DXkput-1xNYE