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Some troubling assumptions of SR
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Some troubling assumptions of SR
"Mitchell Jones" wrote in message ... .... The only attack on relativity that was posted in connection with that discussion was posted by me, and I assume from your comment that you disagree with it, since you characterized my analysis as "pitiable." So let me ask you a question: if someone told you that (a) automobile speeds are a universal constant the value of which is 50 mph, and (b) that the speed of each automobile has to be measured using an onboard clock that automatically registers 1 hour for every 50 miles traveled, would you accept his conclusion? If not, then why would you accept Einstein's statement that (a) the speed of light is a universal constant the value of which is 186,000 miles/sec, and (b) that the speed of light has to be measured using a clock in the vicinity of the lightpath which automatically registers 1 second for every 186,000 miles that light travels? In other words, why can't we follow standard practice, and use clocks calibrated to run at the same rate as standard time here on Earth? That's what we do when we measure the speeds of automobiles and everything else. Why must we make an exception for light? Enquiring minds want to know! :-) Enquiring minds would look up the definition of a second http://www.bipm.fr/en/si/si_brochure...-1/second.html "The second is the duration of 9192631770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium 133 atom. At its 1997 meeting the CIPM affirmed that: This definition refers to a caesium atom at rest at a temperature of 0K." This note was intended to make it clear that the definition of the SI second is based on a caesium atom unperturbed by black body radiation, that is, in an environment whose thermodynamic temperature is 0K. The frequencies of all primary frequency standards should therefore be corrected for the shift due to ambient radiation, as stated at the meeting of the Consultative Committee for Time and Frequency in 1999." That definition is used for all clocks regardless of what they are measuring and all clocks should be calibrated accordingly. George |
#553
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Some troubling assumptions of SR
On Mar 9, 4:30 am, "George Dishman" wrote:
On 9 Mar, 02:03, " wrote: On Mar 7, 5:15 am, "George Dishman" wrote: On 6 Mar, 05:47, " wrote: On Mar 3, 7:41 am, "George Dishman" wrote: wrote in oglegroups.com... ... Lets try this. You are standing in the open with no wind. An airplane passes by from left to right. If the airplane dropped a cannon ball observers on the plane would see the ball drop straight down, staying directly under the plane as it fell. The observer on the ground would see the ball dropping from left to right. Following its path back up leads to a point behind the current location of the plane, where the plane was when it dropped the ball. This is aberration. Just consider the airplane to be a stationary star and we are on the earth moving in our orbit. Have the airplane fly back in the opposit direction (we have continued our orbit under the stationary star) and the aberration angle changes direction. When the cannon ball was dropped a charge of black powder was lit off with a bang, leaving a cloud of smoke in the stationary air at the point where the ball was dropped. That is the point we will hear the sound come from in our stationary air (dragged aether). The airplane will have moved on in the time it took for the sound to reach us, so the sound will come from behind the airplane, just like the cannon ball. When the airplane flys back the other way the sound trails in the opposite direction. So far we agree. If you want the star to be at rest in the aether of space just change the airplane to a balloon floating back and forth in the jet streams. It wont effect the final leg of the sound's passage to us in our stationary air. That's where we disagree. Rather than the jet stream, suppose there is a uniform wind at all heights above 100m but the air in that last 100m is still. There is a shear at that height. Suppose someone on the balloon fires a gun to create a sound wavefront. The sound propagates vertically down through the air from the balloon as seen by someone in the balloon and the wavefront is always horizontal: b _|_ _|_ _|_ _|_ _|_ .... _|_ .... From the point of view of someone on the ground, the ballon and the sound waves are carried sideways by the wind but the wavefronts remain horizontal. When the sound reaches the shear, the balloon has drifte to 'b' from the point where the gun was fired at 'g' b g _/_ _/_ _/_ _/_ _/_ .... _/_ .... If there were a stationary observer at the bottom of the diagonal line watching b drift by, where would he hear the sound come from, b or g ? It appears to come from b because the direction is the normal to the wavefronts. The same is true in the completed diagram below so the aberration is the angle xob rather than xog. I would agree that an observer floating along just above the boundry in another balloon would hear the gun shot from b, but I have serious doubts about a stationary observer. The particles that are transfering the sound have some additional horizontal momentum for him due to the wind. You don't think that makes any difference? After the shear, the sound continues vertically and the ballon drifts on to 'x' which it reaches when the gunshot is heard on the ground by observer 'o': x b g _/_ _/_ _/_ _/_ _/_ .... _/_ .... shear _|_ _|_ ______o______ ground The aberration is quite different from an aircraft in uniformly moving air. As I said elsewhere it is easy to miss things when doing an analysis. Let's take a closer look at a wave front crossing the shear line. The whole wave front does not hit the shear line at the same instant. * * * * * * * * ' ---------------------------------------------- What happens when part of the front stops moving horizontal while the part that hasn't reached the shear line continues to move left until it also reaches the shear line? * * * * * * * * -----------------------'---------------------- * * * * * * * * -----------------------'---------------------- * * * * * * --------------------*---*--------------------- ' * * * * * * --------------------*---*--------------------- ' * * * * ----------------*---------*------------------- * * ' * * * * ----------------*---------*------------------- * * ' * * --------------*-----------*-------------- * * * * ' * * --------------*-----------*-------------- * * * * ' ------------*-------------*------------------- * * * * * * ' If you now plot where the center of the front is you get something like this. ------------*-------\-----*------------------- * \ * * \ * * \* '\ Does the ground observer hear the sound come from the center of this wave front? Yes, we use the down wind origin of the wave to calculate where the wave front will be, but that is not where the sound came from. It is where it appears to come from. Try drawing circles radiating out from the source. I disagree. This is what the real world experiment with sound demonstrates. When there is a cross wind between two stationary observers they still hear the sound come from the direction of the source, not the down wind center of the wave front. I have yet to be convinced of that. What was the link to your experimental evidence again? I provided no link. I was speaking of first hand observations you can make yourself. Surely you have been in open areas when the wind was blowing. Have you ever heard come from down wind of a stationary object? I have never tried it with equipment capable of measuring the angle accurately enough and I doubt you have either. If you have your eyes open, your brain identifies the source with a combination of what your hear and what you see. Try it wearing a blindfold and pointing to the source using sound alone, get a friend to put two stakes in the ground marking the direction, then take the blindfold off. You will need a high wind speed to get a measurable offset. I never have even when the distance was the better part of a mile and the wind strong. The distance doesn't matter, the sin of the angle is v/c where c is the speed of sound. When you view a car going by 40 feet away the angle defined by the car is much larger than it is when the car is 4000 feet away. If the car blows its horn at 40 feet and the sound is shifted back a foot it would still seem to come from the front of the car. The same angle at 4000 feet would shift the sound by 100 feet, or about 5 car lengths behind the car. Yes, whether it is one foot in 40 or 100 in 4000, the angle subtended at the listener is the same and it is that angle that you measure so the distance is of no interest in deciding whther you can measure the effect by ear or if you need instrumentation. I don't believe you could tell by ear without a very high wind speed. We were discussing what we have observed in real life, not what you would measure in some theoretical experiment. You yourself wrote above, "If you have your eyes open, your brain identifies the source with a combination of what your hear and what you see." When a car goes by at 30 mph that is 44 feet per second. At 40 feet with sound traveling at 1100 fps the car will have traveled 1.6 feet. If the car blows its horn which is in the grill the sound will still seem to come from under the hood of the car. That is a very close match with where you would expect the sound to be coming from so the shift isn't noticed. When a car 4000 feet away traveling at the same speed blows its horn the sound lags 160 feet behind. That is about 10 car lengths back. That is certainly far enough from the source to be noticed and that is at just 30 mph. And yes, our ability to sense the direction of a sound is quite accurate. I have often heard the sound from an airplane come from a point behind its current location, so I can detect a difference in direction if one exists. An aircraft travels at 600 mph, I doubt you have tried the experiment blindfold is as much as 60 mph when you would get 1/10th of the displacement. I have easily detected the shift with an old prop driven plane flying at ~100 mph. I can also detect it when cars drive by at ~60 mph if I am 100 yards or more from the highway. When a jet is traveling at 600 mph the effect is so great that it sometimes takes a few seconds to find the jet. I have also experienced traveling at high rates of speed near others at race tracks. So are you saying that you have experienced travelling at 60 mph parallel to another driver also moving at the same speed and can definitely say that when he shouted to you from the other car his voice did not appear to come from behind his car by 5 degrees? See the diagram below. I want to see some independent proof of that claim before I accept it. At the drag strip I have traveled parallel to another car at up to 140 mph and never noticed any shift in the direction of sound. Of course I may have been preoccupied, but I think I would have noticed. To determine the direction the sound is coming from the receiver needs at least two points. Right. Try this sketch: S --- wind | A--+--B A and B are microphones and S is a source, say a gun which emits a single spherical wavefront, or you can use a tone generator and measure phase difference. We are trying to duplicate a wave traveling in the aether. The signals in the wires travel faster than the sound waves so you are in effect using faster than light communication to determine the timing of the reception at A and B. But in a dragged aether, both the aether at ground level and the cables are at rest relative to the ground (which is how dragged aether explains the MMX) therefore the speed of the signals in the cables is equal. As long as the cables are the same length, there is no time difference introduced, the actual speed is irrelevant. snip as you did not comment .. How can blocking the line of sight path effect the path from down wind? Because the sound is actually coming from the object which hasn't moved but the wavefronts lie at an angle to the line of sight like a swimmer crossing a river, he has to face slightly upstream in order to swim perpendicular to the bank. When that swimmer reaches you, after leaving the bank at a point straight across, do you claim that he swam up from some point down stream because that is where the water is that he swam through? No, all I claim is that he is at the same angle to the bank as he would have been had he swum from some point downstream if the water was at rest. All we can measure is the apparent source of the starlight. George So we can agree that his path was straight across. Bruce |
#554
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Some troubling assumptions of SR
Mitchell Jones wrote:
If not, then why would you accept Einstein's statement that (a) the speed of light is a universal constant the value of which is 186,000 miles/sec, and Actually, as written, he proposed it as a postulate and ran with that to derive what the implications would be. Turns out that none of the implications have ever been refuted by experiment. (b) that the speed of light has to be measured using a clock in the vicinity of the lightpath which automatically registers 1 hour for every 186,000 miles that light travels? Can you produce an actual quotation from the 1905 paper that supports this statement of yours? Bob -- "Things should be described as simply as possible, but no simpler." A. Einstein |
#555
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Some troubling assumptions of SR
wrote in message ups.com... On Mar 9, 4:30 am, "George Dishman" wrote: On 9 Mar, 02:03, " wrote: On Mar 7, 5:15 am, "George Dishman" wrote: On 6 Mar, 05:47, " wrote: On Mar 3, 7:41 am, "George Dishman" wrote: wrote in oglegroups.com... ... Lets try this. You are standing in the open with no wind. An airplane passes by from left to right. If the airplane dropped a cannon ball observers on the plane would see the ball drop straight down, staying directly under the plane as it fell. The observer on the ground would see the ball dropping from left to right. Following its path back up leads to a point behind the current location of the plane, where the plane was when it dropped the ball. This is aberration. Just consider the airplane to be a stationary star and we are on the earth moving in our orbit. Have the airplane fly back in the opposit direction (we have continued our orbit under the stationary star) and the aberration angle changes direction. When the cannon ball was dropped a charge of black powder was lit off with a bang, leaving a cloud of smoke in the stationary air at the point where the ball was dropped. That is the point we will hear the sound come from in our stationary air (dragged aether). The airplane will have moved on in the time it took for the sound to reach us, so the sound will come from behind the airplane, just like the cannon ball. When the airplane flys back the other way the sound trails in the opposite direction. So far we agree. If you want the star to be at rest in the aether of space just change the airplane to a balloon floating back and forth in the jet streams. It wont effect the final leg of the sound's passage to us in our stationary air. That's where we disagree. Rather than the jet stream, suppose there is a uniform wind at all heights above 100m but the air in that last 100m is still. There is a shear at that height. Suppose someone on the balloon fires a gun to create a sound wavefront. The sound propagates vertically down through the air from the balloon as seen by someone in the balloon and the wavefront is always horizontal: b _|_ _|_ _|_ _|_ _|_ .... _|_ .... From the point of view of someone on the ground, the ballon and the sound waves are carried sideways by the wind but the wavefronts remain horizontal. When the sound reaches the shear, the balloon has drifte to 'b' from the point where the gun was fired at 'g' b g _/_ _/_ _/_ _/_ _/_ .... _/_ .... If there were a stationary observer at the bottom of the diagonal line watching b drift by, where would he hear the sound come from, b or g ? It appears to come from b because the direction is the normal to the wavefronts. The same is true in the completed diagram below so the aberration is the angle xob rather than xog. I would agree that an observer floating along just above the boundry in another balloon would hear the gun shot from b, but I have serious doubts about a stationary observer. The particles that are transfering the sound have some additional horizontal momentum for him due to the wind. You don't think that makes any difference? After the shear, the sound continues vertically and the ballon drifts on to 'x' which it reaches when the gunshot is heard on the ground by observer 'o': x b g _/_ _/_ _/_ _/_ _/_ .... _/_ .... shear _|_ _|_ ______o______ ground The aberration is quite different from an aircraft in uniformly moving air. As I said elsewhere it is easy to miss things when doing an analysis. Let's take a closer look at a wave front crossing the shear line. The whole wave front does not hit the shear line at the same instant. * * * * * * * * ' ---------------------------------------------- What happens when part of the front stops moving horizontal while the part that hasn't reached the shear line continues to move left until it also reaches the shear line? * * * * * * * * -----------------------'---------------------- * * * * * * * * -----------------------'---------------------- * * * * * * --------------------*---*--------------------- ' * * * * * * --------------------*---*--------------------- ' * * * * ----------------*---------*------------------- * * ' * * * * ----------------*---------*------------------- * * ' * * --------------*-----------*-------------- * * * * ' * * --------------*-----------*-------------- * * * * ' ------------*-------------*------------------- * * * * * * ' If you now plot where the center of the front is you get something like this. ------------*-------\-----*------------------- * \ * * \ * * \* '\ Does the ground observer hear the sound come from the center of this wave front? No, he hears it arrive from a direction perpendicular to the surface of the wavefront when it reaches him. That makes it a bit more complex and the easiest way to explain the effect may be to consider where someone needs to stand to hear the sound directly above them. When the wave you show first reaches the ground, the observer shown hears the source directly above. * * * * ----------------*---------*------------------- * * ________'________ I've skipped your intermediate diagrams and I think the second was one character out. The ' in this is half way between the two points where the wavefront reaches the ground and would be where the next wavefront touches down: * * --------------*-----------*-------------- * * ____*__'__*______ And here's the next. ------------*-------------*------------------- * * _*____'____*_____ Bear in mind the source is moving from right to left so the observer only sees it directly above at one particular time. In other words proper motion of the star would still be detectable but there is no aberration. It is like the plane overhead, the sound appears to come from behind but it also moves at the same speed as the plane. With the dragged aether and shear, the sound appears to come from the plane and still moves with the plane. Of course the plane would fall out of the sky if this actually happened, no air speed, but you should be able to follow what I mean. Yes, we use the down wind origin of the wave to calculate where the wave front will be, but that is not where the sound came from. It is where it appears to come from. Try drawing circles radiating out from the source. I disagree. This is what the real world experiment with sound demonstrates. When there is a cross wind between two stationary observers they still hear the sound come from the direction of the source, not the down wind center of the wave front. I have yet to be convinced of that. What was the link to your experimental evidence again? I provided no link. I was speaking of first hand observations you can make yourself. Surely you have been in open areas when the wind was blowing. Have you ever heard come from down wind of a stationary object? I have never tried it with equipment capable of measuring the angle accurately enough and I doubt you have either. If you have your eyes open, your brain identifies the source with a combination of what your hear and what you see. Try it wearing a blindfold and pointing to the source using sound alone, get a friend to put two stakes in the ground marking the direction, then take the blindfold off. You will need a high wind speed to get a measurable offset. I never have even when the distance was the better part of a mile and the wind strong. The distance doesn't matter, the sin of the angle is v/c where c is the speed of sound. When you view a car going by 40 feet away the angle defined by the car is much larger than it is when the car is 4000 feet away. If the car blows its horn at 40 feet and the sound is shifted back a foot it would still seem to come from the front of the car. The same angle at 4000 feet would shift the sound by 100 feet, or about 5 car lengths behind the car. Yes, whether it is one foot in 40 or 100 in 4000, the angle subtended at the listener is the same and it is that angle that you measure so the distance is of no interest in deciding whther you can measure the effect by ear or if you need instrumentation. I don't believe you could tell by ear without a very high wind speed. We were discussing what we have observed in real life, not what you would measure in some theoretical experiment. You yourself wrote above, "If you have your eyes open, your brain identifies the source with a combination of what your hear and what you see." When a car goes by at 30 mph that is 44 feet per second. At 40 feet with sound traveling at 1100 fps the car will have traveled 1.6 feet. If the car blows its horn which is in the grill the sound will still seem to come from under the hood of the car. That is a very close match with where you would expect the sound to be coming from so the shift isn't noticed. When a car 4000 feet away traveling at the same speed blows its horn the sound lags 160 feet behind. That is about 10 car lengths back. That is certainly far enough from the source to be noticed and that is at just 30 mph. And yes, our ability to sense the direction of a sound is quite accurate. What you wrote above was this: ... This is what the real world experiment with sound demonstrates. When there is a cross wind between two stationary observers they still hear the sound come from the direction of the source, not the down wind center of the wave front. We were talking about "two stationary observers", not a moving car. I have also experienced traveling at high rates of speed near others at race tracks. So are you saying that you have experienced travelling at 60 mph parallel to another driver also moving at the same speed and can definitely say that when he shouted to you from the other car his voice did not appear to come from behind his car by 5 degrees? See the diagram below. I want to see some independent proof of that claim before I accept it. At the drag strip I have traveled parallel to another car at up to 140 mph and never noticed any shift in the direction of sound. Of course I may have been preoccupied, but I think I would have noticed. I think it may be quite difficult to locate the exact source of the sound in that case. How far were you from the other car? .... When that swimmer reaches you, after leaving the bank at a point straight across, do you claim that he swam up from some point down stream because that is where the water is that he swam through? No, all I claim is that he is at the same angle to the bank as he would have been had he swum from some point downstream if the water was at rest. All we can measure is the apparent source of the starlight. So we can agree that his path was straight across. And we can agree he arrived at an angle. Neither of those seem particularly relevant though. George |
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Some troubling assumptions of SR
On Mar 12, 5:08 pm, Lester Zick wrote:
On Mon, 12 Mar 2007 12:58:35 -0400, Bob Kolker wrote: Lester Zick wrote: Also turns out that the one assumption of geometric contraction required to support that postulate has ever been supported by experiment either. Neither here nor there. The only thing that count are the predictions. Are they right (empirically) or are they wrong (empirically). Science is about making correct predictions. So, Bob, you're telling me that science is about fortune telling? I don't think so. Empiricism is about fortune telling but science is a trifle more analytical than that. Science has to tell us why one thing is true and another not. It doesn't really do a good job of that. Every scientific theory to date is an "effective" theory in the sense that there are certain things that are incorporated in the theory because they appear to be true, but not that they HAVE to be true at the exclusion of all other possibilities. In the course of finding a deeper theory, one sometimes finds that the reasons those things are true are that they are implied by other, more fundamental things that appear to be true (but do not HAVE to be true at the exclusion of all other possibities). To date, there is not a SINGLE scientific theory that has no empirically derived statements, and which as a whole MUST be true. You are welcome to try to find that "ultimate" theory, but again the figure of merit is not what you think science should be doing, but is instead *usefulness*. Einstein's postulate of a constant relative velocity of light is a very interesting prediction. It's not a prediction. It's an assumption, from which other predictions are made. That's why Einstein called it a *postulate*, not a theoretical prediction. PD Unfortunately the second order velocity dependent geometric anisometry on which it rests cannot be independently verified as a prediction. On the other hand the trifling prediction on which the success of Michelson-Morley rests is eminently capable of independent experimental verification which will deny the assumption on which Einstein's postulate rests. |
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Some troubling assumptions of SR
On Mar 12, 5:18 pm, "PD" wrote:
On Mar 12, 5:08 pm, Lester Zick wrote: On Mon, 12 Mar 2007 12:58:35 -0400, Bob Kolker wrote: Lester Zick wrote: Also turns out that the one assumption of geometric contraction required to support that postulate has ever been supported by experiment either. Neither here nor there. The only thing that count are the predictions. Are they right (empirically) or are they wrong (empirically). Science is about making correct predictions. So, Bob, you're telling me that science is about fortune telling? I don't think so. Empiricism is about fortune telling but science is a trifle more analytical than that. Science has to tell us why one thing is true and another not. It doesn't really do a good job of that. Every scientific theory to date is an "effective" theory in the sense that there are certain things that are incorporated in the theory because they appear to be true, but not that they HAVE to be true at the exclusion of all other possibilities. In the course of finding a deeper theory, one sometimes finds that the reasons those things are true are that they are implied by other, more fundamental things that appear to be true (but do not HAVE to be true at the exclusion of all other possibities). To date, there is not a SINGLE scientific theory that has no empirically derived statements, and which as a whole MUST be true. You are welcome to try to find that "ultimate" theory, but again the figure of merit is not what you think science should be doing, but is instead *usefulness*. Einstein's postulate of a constant relative velocity of light is a very interesting prediction. It's not a prediction. It's an assumption, from which other predictions are made. That's why Einstein called it a *postulate*, not a theoretical prediction. PD Actually as Einstein says in "Relativity" it is not an assumption, it is a stipulation. Everything is derived based on that fact. If you use the speed of light to measure a distance, and then use that distance to measure the speed of light, you had better come up with the speed you started with Bruce Unfortunately the second order velocity dependent geometric anisometry on which it rests cannot be independently verified as a prediction. On the other hand the trifling prediction on which the success of Michelson-Morley rests is eminently capable of independent experimental verification which will deny the assumption on which Einstein's postulate rests.- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - |
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Some troubling assumptions of SR
On Mar 12, 1:54 pm, "George Dishman" wrote:
wrote in message ups.com... On Mar 9, 4:30 am, "George Dishman" wrote: On 9 Mar, 02:03, " wrote: On Mar 7, 5:15 am, "George Dishman" wrote: On 6 Mar, 05:47, " wrote: On Mar 3, 7:41 am, "George Dishman" wrote: wrote in oglegroups.com... ... Lets try this. You are standing in the open with no wind. An airplane passes by from left to right. If the airplane dropped a cannon ball observers on the plane would see the ball drop straight down, staying directly under the plane as it fell. The observer on the ground would see the ball dropping from left to right. Following its path back up leads to a point behind the current location of the plane, where the plane was when it dropped the ball. This is aberration. Just consider the airplane to be a stationary star and we are on the earth moving in our orbit. Have the airplane fly back in the opposit direction (we have continued our orbit under the stationary star) and the aberration angle changes direction. When the cannon ball was dropped a charge of black powder was lit off with a bang, leaving a cloud of smoke in the stationary air at the point where the ball was dropped. That is the point we will hear the sound come from in our stationary air (dragged aether). The airplane will have moved on in the time it took for the sound to reach us, so the sound will come from behind the airplane, just like the cannon ball. When the airplane flys back the other way the sound trails in the opposite direction. So far we agree. If you want the star to be at rest in the aether of space just change the airplane to a balloon floating back and forth in the jet streams. It wont effect the final leg of the sound's passage to us in our stationary air. That's where we disagree. Rather than the jet stream, suppose there is a uniform wind at all heights above 100m but the air in that last 100m is still. There is a shear at that height. Suppose someone on the balloon fires a gun to create a sound wavefront. The sound propagates vertically down through the air from the balloon as seen by someone in the balloon and the wavefront is always horizontal: b _|_ _|_ _|_ _|_ _|_ .... _|_ .... From the point of view of someone on the ground, the ballon and the sound waves are carried sideways by the wind but the wavefronts remain horizontal. When the sound reaches the shear, the balloon has drifte to 'b' from the point where the gun was fired at 'g' b g _/_ _/_ _/_ _/_ _/_ .... _/_ .... If there were a stationary observer at the bottom of the diagonal line watching b drift by, where would he hear the sound come from, b or g ? It appears to come from b because the direction is the normal to the wavefronts. The same is true in the completed diagram below so the aberration is the angle xob rather than xog. I would agree that an observer floating along just above the boundry in another balloon would hear the gun shot from b, but I have serious doubts about a stationary observer. The particles that are transfering the sound have some additional horizontal momentum for him due to the wind. You don't think that makes any difference? After the shear, the sound continues vertically and the ballon drifts on to 'x' which it reaches when the gunshot is heard on the ground by observer 'o': x b g _/_ _/_ _/_ _/_ _/_ .... _/_ .... shear _|_ _|_ ______o______ ground The aberration is quite different from an aircraft in uniformly moving air. As I said elsewhere it is easy to miss things when doing an analysis. Let's take a closer look at a wave front crossing the shear line. The whole wave front does not hit the shear line at the same instant. * * * * * * * * ' ---------------------------------------------- What happens when part of the front stops moving horizontal while the part that hasn't reached the shear line continues to move left until it also reaches the shear line? * * * * * * * * -----------------------'---------------------- * * * * * * * * -----------------------'---------------------- * * * * * * --------------------*---*--------------------- ' * * * * * * --------------------*---*--------------------- ' * * * * ----------------*---------*------------------- * * ' * * * * ----------------*---------*------------------- * * ' * * --------------*-----------*-------------- * * * * ' * * --------------*-----------*-------------- * * * * ' ------------*-------------*------------------- * * * * * * ' If you now plot where the center of the front is you get something like this. ------------*-------\-----*------------------- * \ * * \ * * \* '\ Does the ground observer hear the sound come from the center of this wave front? No, he hears it arrive from a direction perpendicular to the surface of the wavefront when it reaches him. That makes it a bit more complex and the easiest way to explain the effect may be to consider where someone needs to stand to hear the sound directly above them. When the wave you show first reaches the ground, the observer shown hears the source directly above. * * * * ----------------*---------*------------------- * * ________'________ I've skipped your intermediate diagrams and I think the second was one character out. The ' in this is half way between the two points where the wavefront reaches the ground and would be where the next wavefront touches down: No, the ' was off center in the second diagram on purpose. The ' is on the vertical axis of the original wave front. When it hits the stationary air it stops moving to the left. That is what you have claimed happens. The rest of the wave is still up above the shear line, so it keeps moving. By the time the * on either side of the ' have moved down to the shear line they have moved over one space, so the ' is no longer centered between them. In the next view they stay stationary while the wave above the shear line continues to move over. In the end you get this. ------------*-------\-----*------------------- * \ * * \ * * \* '\ Draw a smooth curve through the points and you have the shape of the wave after it passes through the shear line. It is no longer circular. If you want the line through ' that is normal to the curve it would be the line perpendicular to the tangent at that point. Since the curve has a smaller radius to the right of ' than to the left, the tangent will not be horizontal and the normal will not be vertical. Yes, this is a crude ascii drawing and I did not allow for the fact that the wave continues to expand horizontally as it expands vertically, but I don't think there can be any disagreement that the wave front is no longer circular nor that the normal line is no longer vertical. * * --------------*-----------*-------------- * * ____*__'__*______ And here's the next. ------------*-------------*------------------- * * _*____'____*_____ Bear in mind the source is moving from right to left so the observer only sees it directly above at one particular time. In other words proper motion of the star would still be detectable but there is no aberration. It is like the plane overhead, the sound appears to come from behind but it also moves at the same speed as the plane. With the dragged aether and shear, the sound appears to come from the plane and still moves with the plane. Of course the plane would fall out of the sky if this actually happened, no air speed, but you should be able to follow what I mean. That's why we were using a floating balloon ;-) Yes, we use the down wind origin of the wave to calculate where the wave front will be, but that is not where the sound came from. It is where it appears to come from. Try drawing circles radiating out from the source. I disagree. This is what the real world experiment with sound demonstrates. When there is a cross wind between two stationary observers they still hear the sound come from the direction of the source, not the down wind center of the wave front. I have yet to be convinced of that. What was the link to your experimental evidence again? I provided no link. I was speaking of first hand observations you can make yourself. Surely you have been in open areas when the wind was blowing. Have you ever heard come from down wind of a stationary object? I have never tried it with equipment capable of measuring the angle accurately enough and I doubt you have either. If you have your eyes open, your brain identifies the source with a combination of what your hear and what you see. Try it wearing a blindfold and pointing to the source using sound alone, get a friend to put two stakes in the ground marking the direction, then take the blindfold off. You will need a high wind speed to get a measurable offset. I never have even when the distance was the better part of a mile and the wind strong. The distance doesn't matter, the sin of the angle is v/c where c is the speed of sound. When you view a car going by 40 feet away the angle defined by the car is much larger than it is when the car is 4000 feet away. If the car blows its horn at 40 feet and the sound is shifted back a foot it would still seem to come from the front of the car. The same angle at 4000 feet would shift the sound by 100 feet, or about 5 car lengths behind the car. Yes, whether it is one foot in 40 or 100 in 4000, the angle subtended at the listener is the same and it is that angle that you measure so the distance is of no interest in deciding whther you can measure the effect by ear or if you need instrumentation. I don't believe you could tell by ear without a very high wind speed. We were discussing what we have observed in real life, not what you would measure in some theoretical experiment. You yourself wrote above, "If you have your eyes open, your brain identifies the source with a combination of what your hear and what you see." When a car goes by at 30 mph that is 44 feet per second. At 40 feet with sound traveling at 1100 fps the car will have traveled 1.6 feet. If the car blows its horn which is in the grill the sound will still seem to come from under the hood of the car. That is a very close match with where you would expect the sound to be coming from so the shift isn't noticed. When a car 4000 feet away traveling at the same speed blows its horn the sound lags 160 feet behind. That is about 10 car lengths back. That is certainly far enough from the source to be noticed and that is at just 30 mph. And yes, our ability to sense the direction of a sound is quite accurate. What you wrote above was this: ... This is what the real world experiment with sound demonstrates. When there is a cross wind between two stationary observers they still hear the sound come from the direction of the source, not the down wind center of the wave front. We were talking about "two stationary observers", not a moving car. The whole conversation is still there if you want to look back. The moving car came up while dicussing if distance made any difference in our perception of where a sound comes from or whether it was strictly a matter of the angle. I have also experienced traveling at high rates of speed near others at race tracks. So are you saying that you have experienced travelling at 60 mph parallel to another driver also moving at the same speed and can definitely say that when he shouted to you from the other car his voice did not appear to come from behind his car by 5 degrees? See the diagram below. I want to see some independent proof of that claim before I accept it. At the drag strip I have traveled parallel to another car at up to 140 mph and never noticed any shift in the direction of sound. Of course I may have been preoccupied, but I think I would have noticed. I think it may be quite difficult to locate the exact source of the sound in that case. How far were you from the other car? Each car has a road the width of a two lane highway and there is a guard rail between the two cars. I would guess between 30 and 40 feet. An open exhaust header by the door is a fairly easy source to locate. When that swimmer reaches you, after leaving the bank at a point straight across, do you claim that he swam up from some point down stream because that is where the water is that he swam through? No, all I claim is that he is at the same angle to the bank as he would have been had he swum from some point downstream if the water was at rest. All we can measure is the apparent source of the starlight. So we can agree that his path was straight across. And we can agree he arrived at an angle. Neither of those seem particularly relevant though. George |
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Some troubling assumptions of SR
In article ,
"George Dishman" wrote: "Mitchell Jones" wrote in message ... ... The only attack on relativity that was posted in connection with that discussion was posted by me, and I assume from your comment that you disagree with it, since you characterized my analysis as "pitiable." So let me ask you a question: if someone told you that (a) automobile speeds are a universal constant the value of which is 50 mph, and (b) that the speed of each automobile has to be measured using an onboard clock that automatically registers 1 hour for every 50 miles traveled, would you accept his conclusion? If not, then why would you accept Einstein's statement that (a) the speed of light is a universal constant the value of which is 186,000 miles/sec, and (b) that the speed of light has to be measured using a clock in the vicinity of the lightpath which automatically registers 1 second for every 186,000 miles that light travels? In other words, why can't we follow standard practice, and use clocks calibrated to run at the same rate as standard time here on Earth? That's what we do when we measure the speeds of automobiles and everything else. Why must we make an exception for light? Enquiring minds want to know! :-) Enquiring minds would look up the definition of a second http://www.bipm.fr/en/si/si_brochure...-1/second.html "The second is the duration of 9192631770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium 133 atom. ***{Enquiring minds would also note that nothing in the above specifies the gravitational conditions to which the clock is subjected. They would note further that, according to the equations of physics, all motions are affected by the gravitational circumstances in the locality where the clocks are operating. To be specific, as gravitational acceleration increases, other things equal, clock rates slow down. The controlling formula is the "gravitational time dilation equation," which is as follows: t = T[1 - 2gr/c^2]^.5 In the above, T is the duration of a time interval as measured by a clock in deep space, where the acceleration due to gravity is trivially small, and t is the same time interval as measured by an identical clock subject to a gravitational acceleration of g at a distance r from a center of mass. Examination of the formula will make it clear to you that as g increases, other things equal, clocks slow down. That includes clocks based on the behavior of the Cesium 133 atom. Since the theory of relativity requires that we use "proper time" for our measurements, and defines "proper time" as the time measured by a clock in the same locality of the event being measured, that means we must count off 9,192,631,770 transition cycles of a Cesium 133 atom IN THE SAME LOCATION AS THE LIGHTPATH, when we measure out a second. Note specifically that there is no way to calibrate a clock so defined: if the Cesium 133 atom slows down in a high-g field, too bad. We are required to count off 9,192,631,770 transition cycles and call it a second, even if the Earth makes a complete circuit around its orbit while the cesium atom in question is doing its thing--which could very well be the case, if the value of g is high enough in the locality. Suppose, for example, that g is high enough so that the local clock runs half as fast as a clock on Earth that is using Central Standard Time. Since the speed of light, as measured by the local clock--i.e., the clock in the vicinity of the lightpath--is constant, and since the clock in question is running half as fast as a clock on Earth using Central Standard Time, it follows that the clock on Earth would count off 2 seconds while the clock near the lightpath counts off 1 second. And since light will travel 186,000 miles in the interval in question, it follows that if we use Central Standard Time to measure the interval, the speed of light is 93,000 miles/sec! Of course, the local clock only registered 1 second, and so if we rely on it, we have to conclude that the speed of light is 186,000 miles/sec at that location. But, again, if we use Central Standard Time, or any other variant of standard time used on Earth (Greenwich Mean Time, say), then the light took 2 seconds to travel 186,000 miles, and we have to conclude that the speed of light slowed by half in the high-g field. Result: we must conclude that lightspeed is not a universal constant. And you should note, George, that nothing whatsoever prevents us from using standard time other than the idiot definition which ties the second to a specific number of cesium atom transitions and Einstein's requirement that we use "proper time." There is no way to calibrate a cesium atom. It doesn't give a hoot how fast we want it to go. That means we must count off 9,192,631,770 transition cycles of a cesium 133 atom near the lightpath, which will take twice as long as counting off the same number of cycles of a cesium 133 atom on Earth. The result of such procedures is to force the speed of light to be a universal constant. We have adopted a "clock" that counts off a second every time light travels 186,000 miles, because the local clock speeds up or slows down in the exact same proportion as light speeds up or slows down. Of course, using such a "clock" is transparent nonsense. As I noted yesterday, it is precisely as absurd as claiming that the speed of an automobile is a universal constant, by requiring the use of local time within the car, where an hour is counted off every time the odometer advances by 50 miles. I would add that it is easy to calibrate clocks so that they match standard time, even if they are in a high-g field. To do that, we merely use the so called "gravitational time dilation" formula, given above. If, according to it, a clock at a particular location will tend to run at half the rate of an identical clock on Earth, then we simply use an onboard computer chip to double its readings before displaying them. And if we want to talk about events in locations where computer chips and clocks cannot exist, we simply reference standard time, measured by the clocks where we live, which of course would be adjusted by the use of such chips. This idea of using uncalibrated clocks at the location where a phenomenon is occurring, or of imagining such clocks if we can't actually go there, is simply insane. --Mitchell Jones}*** At its 1997 meeting the CIPM affirmed that: This definition refers to a caesium atom at rest at a temperature of 0K." This note was intended to make it clear that the definition of the SI second is based on a caesium atom unperturbed by black body radiation, that is, in an environment whose thermodynamic temperature is 0K. The frequencies of all primary frequency standards should therefore be corrected for the shift due to ambient radiation, as stated at the meeting of the Consultative Committee for Time and Frequency in 1999." ***{I repeat: the gravitational parameters are not specified. It should be explicitly stated that all clocks are to be calibrated to match the rates of clocks using standard time here on Earth, and it should be explicitly stated that relativistic "proper time" is not to be used. But no such requirements are set down. The result is exactly as I have described: the speed of light becomes a universal constant, not because laboratory measurement indicates it to be so, but in spite of the fact that all laboratory measurements using standard time indicate that it is not so. Let me say it again: you cannot accept the so called "gravitational time dilation" formula and use standard time, without concluding that the speed of light varies depending on gravitational parameters, the most important of which is g, the gravitational acceleration in the vicinity of the lightpath. And, let me emphasize, the formula is derived from laboratory measurements. It is a summary of peer-reviewed, generally accepted experimental results, and it says that clocks in high-g fields run slow, compared to clocks using standard time on Earth. The only way to reach the conclusion that the speed of light is constant, is to use clocks that speed up or slow down as light speeds up or slows down. If clocks calibrated to display standard time are used, one is forced inescapably to the conclusion that the speed of light is a variable, not a constant. Using clocks that speed up or slow down as the thing being measured speeds up or slows down, is a game for morons. By means of it, any motion whatsoever can be turned into a "universal constant." Bottom line: if we use standard time, then according to all the relevant experimental results and to the equations based on those results, the speed of light is not a constant. --Mitchell Jones}*** That definition is used for all clocks regardless of what they are measuring and all clocks should be calibrated accordingly. ***{You can't calibrate a cesium 133 atom, George. And all the relevant experimental results and the equations based on those results, indicate that a cesium 133 atom, and every other conventional physical process, runs slower in a high-g field than it does in a low-g field, other things equal. Thus if we use the definition of "second" that you quoted, and reference motions to Einstein's "proper time"--i.e., if we use local clocks--then we are not using standard time for our measurements. That means we are using uncalibrated clocks, and our results are a joke, not science. --MJ}*** George ************************************************** *************** If I seem to be ignoring you, consider the possibility that you are in my killfile. --MJ |
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Some troubling assumptions of SR
On Mar 12, 10:03 pm, "
wrote: On Mar 12, 5:18 pm, "PD" wrote: On Mar 12, 5:08 pm, Lester Zick wrote: On Mon, 12 Mar 2007 12:58:35 -0400, Bob Kolker wrote: Lester Zick wrote: Also turns out that the one assumption of geometric contraction required to support that postulate has ever been supported by experiment either. Neither here nor there. The only thing that count are the predictions. Are they right (empirically) or are they wrong (empirically). Science is about making correct predictions. So, Bob, you're telling me that science is about fortune telling? I don't think so. Empiricism is about fortune telling but science is a trifle more analytical than that. Science has to tell us why one thing is true and another not. It doesn't really do a good job of that. Every scientific theory to date is an "effective" theory in the sense that there are certain things that are incorporated in the theory because they appear to be true, but not that they HAVE to be true at the exclusion of all other possibilities. In the course of finding a deeper theory, one sometimes finds that the reasons those things are true are that they are implied by other, more fundamental things that appear to be true (but do not HAVE to be true at the exclusion of all other possibities). To date, there is not a SINGLE scientific theory that has no empirically derived statements, and which as a whole MUST be true. You are welcome to try to find that "ultimate" theory, but again the figure of merit is not what you think science should be doing, but is instead *usefulness*. Einstein's postulate of a constant relative velocity of light is a very interesting prediction. It's not a prediction. It's an assumption, from which other predictions are made. That's why Einstein called it a *postulate*, not a theoretical prediction. PD Actually as Einstein says in "Relativity" it is not an assumption, it is a stipulation. Everything is derived based on that fact. Well, the word "fact" is what tends to confuse. The data in direct and deliberate test of one-way measurement of the speed of light using two spatially separated clocks, are indeed rare, and so this being a "fact" as demonstrable measurement is not something that is usually cited. [That being said, there are ample indirect tests that make no relativistic assumptions, and in fact there are several cases of measurements that serve well as verification of the one-way measurement of the speed of light even if they aren't intended as experiments explicitly designed to test relativity. As an example, experiments tangent to the Advanced Photon Source routinely gate their instruments in accordance with flight time from the (moving) photon source.] The "facts" are what are measured, and these are tests of *implications* of this stipulation. When the implications are tested, this lends credibility to the correctness of the stipulation, without requiring a direct test of the stipulation itself. If you use the speed of light to measure a distance, and then use that distance to measure the speed of light, you had better come up with the speed you started with Yes, of course, but note the long time between 1905 and 1983, the latter being the date when distance was defined in terms of the speed of light. In the interim were all the manifold measurements that nailed down the correctness of the stipulation, which in turn *permitted* the definition of distance in terms of the speed of light. PD Unfortunately the second order velocity dependent geometric anisometry on which it rests cannot be independently verified as a prediction. On the other hand the trifling prediction on which the success of Michelson-Morley rests is eminently capable of independent experimental verification which will deny the assumption on which Einstein's postulate rests |
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