chapter 12 : the 2.71K cosmic microwave blackbody radiation #192 AtomTotality theory

I am on chapter 12 discussing the fact that the cosmic
microwave radiation is blackbody and that means only one thing-- the
cosmos is the inside of some container
and the only suitable container is an atom, a cosmic
atom. The fact it is quantized is another clue that the
cosmos is a atom since only atoms are quantized.

The basic structure of this chapter centers on the work
done by DeBroglie where in his book he considers atoms and electrons
to be containers and thus allow
a thermodynamic.

Now the Big Bang theory heralded the 2.71K as supporting their theory
as a cosmic explosion, but because CMBR is quantized at 2.71K, the
more and
more it looks that the CMBR disproves the Big Bang
Theory since no explosion can be quantized nor can
a explosion be blackbody.

Chapter (12) uniform blackbody 2.71 K cosmic microwave background
radiation


Atom Totality theory explains uniform blackbody 2.71 K cosmic
microwave background radiation (CMBR) as the inside of an
electron shell forms a blackbody cavity.

First question to those who know physics, can you
really have a
blackbody radiation such as the ones that Planck had
studied and
had researched and used to form the foundation of
quantum mechanics
that is not uniform? That it may have fluctuations and ripples?
Second question,
can the Cosmos really have a blackbody radiation and
not be a cavity?
Such as the cavity of the 5f6 of 231Pu?
Third question, can you really have a blackbody cavity
as the Cosmos itself and not be an Atom?

-------

Subject: Minimum Coulomb Interactions for
plutonium
Date: 30 Sep 1995 02:39:12 GMT

In article
(Hauke Reddmann)
writes:

And Pu is then the case where even the Schroedinger
equation can't be written out. (Remember that Pu has
a so high
mass number that relativistic effects come in.) In
this case you
use approximations, like treating closed shells as a
spherically
symmetric potential. Of course the calculations then
are not
nearly exact as in the H case.
So, which value should YOU use? As you are sort of a
neopythagorean, I fear you won't be satisfied with
approximations
and must use the 95!/2 value. Even worse, this only
nails down
the coulomb interactions. There are loads of

second-order effects

due to spin dependent interactions.
Hope this helps. This post got very long, but you
see what happens
when you get into the realm of "dirty" science, with
all sorts of
models, approximations and calculations.

Thank you very much both Hauke Reddmann and Gerald
L. Hurst.
The Coulombic states is a very large number indeed.
And it is
commonsense and intuition that says that a neon atom
is held in
place by lots more than just 190 things going on. Neon
is held up
by at least 10^7 things going on.

I can use any of these large numbers for plutonium,
(2^188 x2x2x2) of (n,L,M_L,m_s), or the 95!/2, or the
one which
I favor the most since as of recent it comes from the
Hydrogen
Atom Systems where all the forces are either Coulombic
or
Radioactivity. Thus 231PU is ((2^231) x2x2x2) or that of
232!/2.
With those large numbers it really does not matter
for the
difference of one more electron and proton in the next
element
after plutonium, which is element 95. These numbers
are so huge
and that is what is needed in order to compose a
thermodynamics.
I could not compose a satisfying thermodynamics for
plutonium
with just 94x187 = 17578 things going on.

The cosmic microwave background radiation is
blackbody radiation.
The fact that it is blackbody seems to have escaped
the attention of
virtually every physicist and scientist alive except
me. For if they
deny that they missed it, and understood what it means
to be blackbody
and the implication of something "being" a blackbody,
because blackbody
directly implies a structure, yes, a structure, then
ask them what
structure they understood it to be if they claim they
understood it
initially? An onion?
I have combed every science magazine and journal and
have never seen
any physicist or writer display that math logic
reasoning and well
thinking for all mention blackbody but noone said or
printed the next
logical step, if blackbody then it is a structure. Our
observable
universe is a structure itself.
I knew the structure to be a blackbody cavity
because the 94th+93rd
electron space is a blackbody cavity and that is why
the night sky is
black because it is a blackbody cavity. Get it --
blackbody means
black.

The book LA THERMODYNAMIQUE DE LA PARTICULE ISOLEE
(OU THERMODYNAMIQUE CACHEE DES PARTICULES)
(btw, I like that title with the word "cachee"
and obviously this book is written in French and it is
one of the
greatest books ever written. It is truly amazing of
the dazzling genius
of Debroglie to have anticipated so much in advance)
written by
Debroglie, 1964, considers the relativistic
fluctuations of mass of
subatomic particles such as the protons, electrons.
And then associates
temperature with a relativistic statistical mechanic.

I am following Debroglie's intuition, except
replacing relativistic
mass fluctuations with statistical quantum
fluctuations of the Coulomb
interactions for a plutonium atom in order to derive
an intrinsic
associated temperature for an electron cavity, which
is simply the
space occupied by an electron of 231 plutonium atom.
Let me use 95!/2 or either 232!/2 as the "Coulombic
states" and with
this large number of statistical interactions, I
propose to find an
intrinsic temperature for the 94th electron of an
isolated plutonium
atom.
From pages 94-101, Debroglie works with the formula
1/T = dS/dL
where T is temperature, dS is the derivative of
entropy with respect to
the lagrangian L which is kinetic energy of a system
minus the
potential energy of that system. Debroglie derives
the formula m_0cc =
kT_0 , then where M_0 is proportional to the factor
e^(S/k) as M_0 =
m_0 thus the entropy is proportional to the Boltzmann
factor
e^(-M_0/m_0), thence 1/T = e^(-M_0/m_0)/ d L. Now
taking the idea of a
neutron of a neptunium atom radioactively growing to
transform into a
plutonium atom in which the term d L is very close to
1 by the factor
(neutron/neutron) - ((proton + electron)/neutron).
So 1/T =
e^(-188/186) K/1 which is 1/T = 1/e^(188/186) K. So
the thermodynamic
of the isolated plutonium atom or the blackbody
temperature of a
plutonium atom is e^188/186 K which is the value of
2.74 degrees
Kelvin. The presently determined value by the COBE
satellite for the
cosmic background microwave temperature of the
observable universe is
2.735 + 0.06 K. I assert that it is not coincidence
that the value for
the cosmic background microwave radiation temperature
of 2.7 is close
to the value of the number e in maths.


Archimedes Plutonium
www.iw.net/~a_plutonium
whole entire Universe is just one big atom
where dots of the electron-dot-cloud are galaxies