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The transition from heliocentric to the galactic axis
Gerald Kelleher replied to Jeff Root:
If anything good comes from this thread,it will probably be recognising that the major institutions make the fundamental error of incorporating axial tilt or equatorial orientation as a factor in the Equation of Time In that case, show us the error in the graph you linked to: http://sundials.org/faq/eotgraph.gif And what the correct graph would be. The graph is fine,axial tilt as a component factor is not. The page that the graph is on says the graph shows the effects of Earth's axial tilt and the ellipticity of Earth's orbit. One particular point among many brought up in the discussion over the last number of weeks is that the major institutions inserted an axial orientation component into the Equation of Time and this is a major error. You said that the graph is fine, and I agree. It includes the effect of axial orientation. If it did not, it would be wrong by up to ten minutes, often in the wrong direction. If the graph showed only the effect due to the ellipticity of Earth's orbit, it would have only one peak and one valley. The component due to the ellipticity of Earth's orbit causes the time that the Sun crosses the meridian to vary by almost +/- 8 minutes over the course of a year, while the component due to the tilt of Earth's axis with respect to the Sun causes the time that the Sun crosses the meridian to vary by about +/- 10 minutes over the course of half a year. The result of combining them is two unequal peaks and two unequal valleys in the equation of time, as shown in the graph you linked to: http://sundials.org/faq/eotgraph.gif How do you explain the fact that it has two unequal peaks and two unequal valleys? You typed a lot, but you didn't answer my question. How do you explain the fact that the graph of the equation of time that you provided a link to has two unequal peaks and two unequal valleys? -- Jeff, in Minneapolis .. |
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The transition from heliocentric to the galactic axis
"George Dishman" wrote in message ...
"Oriel36" wrote in message om... "George Dishman" wrote in message ... "Oriel36" wrote in message om... "George Dishman" wrote in message ... "Oriel36" wrote in message om... If you believe that there is a constant 1 degree displacement (which is your priviledge) I can only assume that it is for the benefit of retaining a 'celestial pole' ... No, it is purely a consequence of Copernicus. If the Earth goes round the Sun in 365 days, it moves round the Sun by 360/365 degrees per day. That's all there is to it. This is what has been at the bottom of all the disagreements we have had recently and is why I went to the trouble of drawing the web page. Gerald, I carefully read all the rest of your post and there isn't a single word that addresses the actual topic. Please respond to what I wrote. George http://www.dishman.me.uk/George/SolarDay/index.htm Your graphics represent the creation of a celestial pole .. Rubbish, you are hallucinating. The diagram is stripped to the basics and shows _only_ the Earth moving round the Sun, just pure Copernicus, nothing more. If you choose the sidereal parameter you are obliged to introduce the celestial pole.Your diagrams are in conflict with Kepler's laws of planetary motion and especially his second law,as the Earth axially rotates through different distances there is no uniform displacement of 1 degree from natural noon cycle to noon cycle,there is no means to introduce the Equation of Time,the sidereal parameter requires the local stars as reference,in fact the diagrams are a insult to intelligence and while I have no doubt they look like an achievement to you and the rest for somebody at my level,by the grace of God, who can interpret these things instead of finding somebody to discuss how to model the cosmos off the changing orientation of the local Milky Way stars to the remaining galaxies,I find myself back in the astronomical stone age pointing out that you can't even get the first two rotations of the Earth correct. The only benefit I have is that the aetherists/relativist is cut from the same cloth and I do not make the distinction between you,they are no better or worse that you are when it all comes down to it,but it is unforgivable that anyone who calls themselves an astronomer would find any satisfaction in the destruction of the work of Copernicus, Kepler and Roemer for these silly spacetime notions which have nothing to do with astronomy and less to doo with reality. There are only two rotations involved,count them,just two rotations .. Correct and the diagrams show nothing but those two. Now try to address the point instead of inventing non-existent distractions: if the Earth completes one orbit around the Sun in a little more than 365 days, it moves round the Sun a little less than one degree per day, true or false? George |
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The transition from heliocentric to the galactic axis
Gerald Kelleher replied to Jeff Root:
If anything good comes from this thread,it will probably be recognising that the major institutions make the fundamental error of incorporating axial tilt or equatorial orientation as a factor in the Equation of Time In that case, show us the error in the graph you linked to: http://sundials.org/faq/eotgraph.gif And what the correct graph would be. The graph is fine,axial tilt as a component factor is not. The page that the graph is on says the graph shows the effects of Earth's axial tilt and the ellipticity of Earth's orbit. One particular point among many brought up in the discussion over the last number of weeks is that the major institutions inserted an axial orientation component into the Equation of Time and this is a major error. You said that the graph is fine, and I agree. It includes the effect of axial orientation. If it did not, it would be wrong by up to ten minutes, often in the wrong direction. If the graph showed only the effect due to the ellipticity of Earth's orbit, it would have only one peak and one valley. The component due to the ellipticity of Earth's orbit causes the time that the Sun crosses the meridian to vary by almost +/- 8 minutes over the course of a year, while the component due to the tilt of Earth's axis with respect to the Sun causes the time that the Sun crosses the meridian to vary by about +/- 10 minutes over the course of half a year. The result of combining them is two unequal peaks and two unequal valleys in the equation of time, as shown in the graph you linked to: http://sundials.org/faq/eotgraph.gif How do you explain the fact that it has two unequal peaks and two unequal valleys? You typed a lot, but you didn't answer my question. I most certainly did. No, you typed some ideas which relate to my question, but you didn't answer my question. How do you explain the fact that the graph of the equation of time that you provided a link to has two unequal peaks and two unequal valleys? It is called pure fiction,error,plain wrong,take your pick You can see that the graph has two unequal peaks and two unequal valleys. You said that it is "fine". You can calculate what the equation of time would be if you did not include the effect of axial orientation. That equation would give only a single peak and a single valley. How do you explain the fact that the graph of the equation of time that you provided a link to has two unequal peaks and two unequal valleys? -- Jeff, in Minneapolis .. |
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The transition from heliocentric to the galactic axis
Gerald Kelleher replied to Jeff Root:
If anything good comes from this thread,it will probably be recognising that the major institutions make the fundamental error of incorporating axial tilt or equatorial orientation as a factor in the Equation of Time In that case, show us the error in the graph you linked to: http://sundials.org/faq/eotgraph.gif And what the correct graph would be. The graph is fine,axial tilt as a component factor is not. The page that the graph is on says the graph shows the effects of Earth's axial tilt and the ellipticity of Earth's orbit. One particular point among many brought up in the discussion over the last number of weeks is that the major institutions inserted an axial orientation component into the Equation of Time and this is a major error. You said that the graph is fine, and I agree. It includes the effect of axial orientation. If it did not, it would be wrong by up to ten minutes, often in the wrong direction. If the graph showed only the effect due to the ellipticity of Earth's orbit, it would have only one peak and one valley. The component due to the ellipticity of Earth's orbit causes the time that the Sun crosses the meridian to vary by almost +/- 8 minutes over the course of a year, while the component due to the tilt of Earth's axis with respect to the Sun causes the time that the Sun crosses the meridian to vary by about +/- 10 minutes over the course of half a year. The result of combining them is two unequal peaks and two unequal valleys in the equation of time, as shown in the graph you linked to: http://sundials.org/faq/eotgraph.gif How do you explain the fact that it has two unequal peaks and two unequal valleys? You typed a lot, but you didn't answer my question. I most certainly did. No, you typed some ideas which relate to my question, but you didn't answer my question. How do you explain the fact that the graph of the equation of time that you provided a link to has two unequal peaks and two unequal valleys? It is called pure fiction,error,plain wrong,take your pick You can see that the graph has two unequal peaks and two unequal valleys. You said that it is "fine". You can calculate what the equation of time would be if you did not include the effect of axial orientation. That equation would give only a single peak and a single valley. How do you explain the fact that the graph of the equation of time that you provided a link to has two unequal peaks and two unequal valleys? Gerald, Yet again you have replied with comments related to my question but without answering my question. Evidently you do not know why the graph of the equation of time contains two unequal peaks and two unequal valleys. -- Jeff, in Minneapolis .. |
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The transition from heliocentric to the galactic axis
"George Dishman" wrote in message ...
Thank you Gerald, you have at least tried to address the issue this time. I feel we can make some progress now. The only progress you are making is into the mire,you give the rotation period of the Earth as 23 hours 56 min while your beloved experiments with Foucault's pendulum tell you it is 24 hours per 360 degrees off the Earth's axis. If you are 1 hour/15 degrees West of the Greenwich meridian simultaneously you are 345 degrees/23 hours East of Greenwich meridian,as these meridians are fixed and the Earth rotates beneath Foucault's pendulum,the grid system of Lat/Long would collapse if you linked the rotation period to 23 hours 56 min. Even if you want to appeal to the slowing of the pendulum at lower latitudes down to the Equator,at any given latitude that circles the planet,it still reflects equable motion and again,the motion at the axis free of gravitation effects will dictate that the rotation of the Earth on its axis is 360 degrees per 24 hours. http://www.si.edu/resource/faq/nmah/pendulum.htm "Oriel36" wrote in message om... If you choose the sidereal parameter you are obliged to introduce the celestial pole. and later you say: the sidereal parameter requires the local stars as reference, I did not "choose the sidereal parameter" and to make that clear I have not shown any stars on the diagrams. I want to discuss _only_ the rotational and orbital motion of the Earth and leave consideration of the stars for a subsequent thread. Your diagrams are in conflict with Kepler's laws of planetary motion and especially his second law,as the Earth axially rotates through different distances there is no uniform displacement of 1 degree from natural noon cycle to noon cycle, The diagrams are not in conflict with Kepler's laws because I was careful to show only a single displacement of the Earth. This is quite deliberate to ensure there is no implication of uniformity. In addition, the text on the third diagram states "The orbit of the Earth is not a circle but an ellipse and the Earth moves faster along its path when closer to the Sun." so there is no basis for your criticism in this case. If I were to add further symbols representing further movements of the Earth, I could vary the displacements to represent the variation described by the second law but I will not do that at least until we get past the present sticking point. Which is - you wish to retain the rotation period as 23 hours 56 minutes sidereal day by means of circumpolar motion whereas the longitude/time coordinates dictate that it is 24 hours per 360 degrees without having to create a celestial pole. Nice choice George,you managed to reintroduce the geocentric sytem. there is no means to introduce the Equation of Time, The means would be to extend the series of diagrams but I do not intend to do that at this stage. Again this is deliberate because you are discussing the Equation of Time with Jeff and I specifically do not want this conversation to be sidetracked into that topic. I want to keep it focussed on Copernicus first. snip pointless insults What's the point,you want to keep the celestial pole as a reference and you are most welcome to it. There are only two rotations involved,count them,just two rotations .. Correct and the diagrams show nothing but those two. Now try to address the point instead of inventing non-existent distractions: if the Earth completes one orbit around the Sun in a little more than 365 days, it moves round the Sun a little less than one degree per day, true or false? Now that I have made it clear that I am not implying uniformity of orbital motion (the amount actually ranges between 0.96 and 1.01 degrees per day but I don't want to get into nitpicking over decimals.)and that I am not at this stage considering sidereal aspects or the Equation of Time but leaving them for future discussions, can you agree with my key point here, that if the Earth moves once round the Sun in a year, it moves approximately one degree per day? George Are you still at a level of the "Earth moves around the Sun,the lack of precision is just too childish for me as the Equation of Time relies specifically between the natural variation from noon to noon or in other words when a location rotates to face the Sun to when it axially repeats it and the difference with a constant axial rotation designated by men as 24 hours per 360 degrees. At least George,you and the aetherist share something in common and thank God I have never shared anything with either.I suggest you maintain your correspondence with the aetherist or those who want 6 dimensions of this and 10 dimensions of that,the best that can be said of it is that it is harmless,the worse is that it robbed the great astronomers of their insights and diluted the once noble tradition of astronomy. |
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The transition from heliocentric to the galactic axis
"Oriel36" wrote in message ... "George Dishman" wrote in message ... Thank you Gerald, you have at least tried to address the issue this time. I feel we can make some progress now. The only progress you are making is into the mire,you give the rotation period of the Earth as 23 hours 56 min while your beloved experiments with Foucault's pendulum tell you it is 24 hours per 360 degrees off the Earth's axis. http://www.si.edu/resource/faq/nmah/pendulum.htm Oh dear, some web sites over-simplify for the general public to the point of error. A brief search shows there are others that round off to the nearest hour too. At least this page gets it right: http://www.griffithobs.org/exhibits/.../pendulum.html "[The Foucault Pendulum] would seem to progress around the dial and make a complete turn in one sidereal day, which is equal to about 23 hours and 56 minutes of solar time." snip bit on longitude, dealt with below Now that I have made it clear that I am not implying uniformity of orbital motion (the amount actually ranges between 0.96 and 1.01 degrees per day but I don't want to get into nitpicking over decimals.)and that I am not at this stage considering sidereal aspects or the Equation of Time but leaving them for future discussions, can you agree with my key point here, that if the Earth moves once round the Sun in a year, it moves approximately one degree per day? Are you still at a level of the "Earth moves around the Sun,the lack of precision is just too childish for me .. Are you denying that the Earth moves around the Sun? I can't honestly believe you would, yet either you do or you seem to ignore its consequences. If you want me to be more precise I will be, but when I have in the past you have gone off at a tangent. You are keeping to the point this time so let's give it a try: .. as the Equation of Time relies specifically between the natural variation from noon to noon or in other words when a location rotates to face the Sun to when it axially repeats it and the difference with a constant axial rotation designated by men as 24 hours per 360 degrees. Apart from the last three words, that is all correct but let's add some detail. The time from noon to noon varies as you say. The Earth moves round the sun once in a year of 365.25 days so it moves round by 0.9856 degrees per day _on_average_. Men designated the average or _mean_ time from noon to noon as 24h exactly, that is why our original universal standard was called Greenwich MEAN Time. The Equation of Time compares the variation of actual noon to GMT noon again as you say, but the details of that can be left to a later discussion as the problem at the moment is that you are ignoring the 0.9856 degrees resulting from the orbital motion of the Earth. Since the Earth has to make one turn plus, _on_average_ an extra 0.9856 degrees, clearly in 24 hours the Earth turns through 360.9856 degrees. In doing so it carries with it the surface features whose locations we define in terms of exactly 360 degrees of longitude (and latitude and altitude as well of course). snip more insults, Gerald getting it wrong then insulting others only reflects on you George |
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The transition from heliocentric to the galactic axis
"George Dishman" wrote in message ...
"Oriel36" wrote in message ... "George Dishman" wrote in message ... Thank you Gerald, you have at least tried to address the issue this time. I feel we can make some progress now. The only progress you are making is into the mire,you give the rotation period of the Earth as 23 hours 56 min while your beloved experiments with Foucault's pendulum tell you it is 24 hours per 360 degrees off the Earth's axis. http://www.si.edu/resource/faq/nmah/pendulum.htm Oh dear, some web sites over-simplify for the general public to the point of error. There is no such thing as the 'general public' unless you wish to discrimate it against numbskulls who designate themselves as physicists.I have the satisfaction of knowing that despite a century of having this spacetime nonsense shoved down their throats,the so-called 'general public' are rediscovering how clocks act as ruler via the longitude problem and there is not a blessed thing you can do about it. A brief search shows there are others that round off to the nearest hour too. At least this page gets it right: Take it up with the Smithsonian,if any measurement taken along two points of latitude will indicate at the polar axis the Earth rotates through 360 degrees in 24 hours and this makes sense in terms of longitude,clocks,geometry and astronomy,you will have to live with it. http://www.griffithobs.org/exhibits/.../pendulum.html "[The Foucault Pendulum] would seem to progress around the dial and make a complete turn in one sidereal day, which is equal to about 23 hours and 56 minutes of solar time." Oh dear,oh dear,oh dear. Keep your sidereal parameter !,to keep it you have to create a celestial pole with the 'fixed stars' rotating about the Earth,great if you are a geocentrist but useless if you wish to use the rotation of the local Milky Way stars and the changing orientation to the remaining galaxies. snip bit on longitude, dealt with below Now that I have made it clear that I am not implying uniformity of orbital motion (the amount actually ranges between 0.96 and 1.01 degrees per day but I don't want to get into nitpicking over decimals.)and that I am not at this stage considering sidereal aspects or the Equation of Time but leaving them for future discussions, can you agree with my key point here, that if the Earth moves once round the Sun in a year, it moves approximately one degree per day? Are you still at a level of the "Earth moves around the Sun,the lack of precision is just too childish for me .. Are you denying that the Earth moves around the Sun? I can't honestly believe you would, yet either you do or you seem to ignore its consequences. You become emboldened because this material does'nt generate participation from others,the precision required to seperate axial rotation of 24 hours/360 degrees from the natural variation of axial rotation as the Earth rotates to face the Sun directly,the alignment is called 'Noon' does'nt leave much room for the simplistic 'Earth moves around the Sun'.The Equation of Time is an expression of Kepler's second law and Newton was expressing it as the difference betwqeen absolute time and relative so it turns out that if an idiot tried to dissolve the distinction he would effectively be destroying Kepler's second law,great !,wonderful ! instead we inherited a century full of 'frames of reference' garbage instead. If you want me to be more precise I will be, but when I have in the past you have gone off at a tangent. You are keeping to the point this time so let's give it a try: .. as the Equation of Time relies specifically between the natural variation from noon to noon or in other words when a location rotates to face the Sun to when it axially repeats it and the difference with a constant axial rotation designated by men as 24 hours per 360 degrees. Apart from the last three words, that is all correct but let's add some detail. The time from noon to noon varies as you say. The alignment of any location on Earth with the Sun is called noon,the simplistic might think it is when the Sun is highest in the sky but geometrically it is the Earth rotating to face the Sun.There is a variation in the alignment from when the Earth rotates to face the Sun to when it axially repeats it.This is the natural day. Really,really clever men worked out that although there is a variation in the alignment as the axial cycle repeats itself,that by adding and substracting minutes it was possible to even out the variation,they did not have to justify the motion of the Earth as 24 hours per 360 degrees by any observed external celestial motion.As any given coordinate of longitude that stretches from pole to pole faces the Sun directly,by applying the Equation of Time it is tantamount to allowing the Earth to drift against the alignment of noon,sometimes before the alignment and sometime after it in accordance with Kepler's second law. Foucault's pendulum indicates what everyone should already know,that as time and longitude coordinates are fixed insofar as if you are 15 degrees/1 hour West of Greenwich meridian you are also 345 degrees/23 hours East of Greenwich as all nautical charts indicate,try to invoke 23 hours 56 minutes into the Lat/Long grid system and the whole thing collapses including the reasons why accurate clocks were developed in the first place. How wonderful you all are,the rich heritage which belongs to humanity is in the hands of men like yourself who try their level best to conceal the ingenious and intricate insights which make the principle of clocks as physical rulers of distance so you can bootle 'time' up in a dimension with cheap imaging tricks. The Earth moves round the sun once in a year of 365.25 days so it moves round by 0.9856 degrees per day _on_average_. Men designated the average or _mean_ time from noon to noon as 24h exactly, that is why our original universal standard was called Greenwich MEAN Time. For those who really would like to become familiar with clocks as rulers of distance it is fairly easy to determine what constitutes the word 'noon'.It is a geometric alignment with a location/meridian on Earth with the Sun,you do not need to bring 'time' into it.Kepler's second law tells you that there is a variation in the distance covered by the Earth from one point in its elliptical orbit to another(if this elliptical orbit were broken into 360 degree segments)and still there is no 'time' involved just pure geometry. When the navigators,for each approrpriate day in an elliptical cycle, added and subtracted minutes via the Equation of Time when they determined their location's alignment with the Sun,what they effectively were doing was reducing the variation to a constant,they could afforded to allow the rotation of the Earth in 24 hours through 360 degrees to drift against natural noon because over the course of an annual orbit the additions and subtractions even out. Natural noon to natural noon is the variation in the rotation of a longitude meridian to face the Sun to when it axially repeats it,the process of reducing the variation by addition and subtraction of minutes over the course of an annual orbital rotational cycle is what makes clocks and their subdivisions possible. The Equation of Time compares the variation of actual noon to GMT noon again as you say, but the details of that can be left to a later discussion as the problem at the moment is that you are ignoring the 0.9856 degrees resulting from the orbital motion of the Earth. Perhaps you may think I have not given your diagrams much thought but I did George but it amounts to astronomical forensics and that I dislike.The sidereal parameter is observer based,to someone else the diagrams in your website look reasonable but unfortunately you place the apical angle at the Sun whereas the sidereal parameter is based on the Earth to the Sun and to a local reference star.The problem is that when you include a reference star and set the thing in motion you are back with a geocentric observer-based format with circumpolar motion,celestial pole and what have you. Since the Earth has to make one turn plus, _on_average_ an extra 0.9856 degrees, clearly in 24 hours the Earth turns through 360.9856 degrees. In doing so it carries with it the surface features whose locations we define in terms of exactly 360 degrees of longitude (and latitude and altitude as well of course). snip more insults, Gerald getting it wrong then insulting others only reflects on you George Last year we corresponded on how 'accelerating' expansion can be perceived as rotation,at least a greater rotation than galactic rotation.Because clocks measure increasing distance away from the planetary axis for each corresponding clock subdivision it is possible to translate acceleration into rotation if this feature is acknowledged but of course we are back with clocks as rulers of distance.The material under discussion here meshes in with a greater rotation than galactic rotation,it can be as simple as that everything in the Universe up to the galactic scale appears to rotate, moon around the Earth,Earth around the Sun etc or as complex as galactic structure and formation indicates a greater rotation but without making use of the changing orientation of the local stars to the remaining galaxies in is impossible to factor in what the true structure and motion of the cosmos is from the apparent when men are prepared to bypass the changing orientation of the local stars and its effects on what we see and how we see the relationship between galaxies to these reference stars and ultimately to each other. The Equation of Time discriminates between axial rotation and an axis of rotation centred on the Sun even though we do not directly perceive the heliocentric axis directly,the next progression is how we perceive stellar rotation around the galactic axis,if because of the scales involved are enormous we can perceive the changing orientation of the local stars to the other galaxies in principle rather than observation.This is what is at stake but experience tells me that it sometimes happens that regardless of how I may consider the importance of observations that 'free creations of the mind' have more appeal to the imagination. If it is said that Newton predicts elliptical orbits without refering to the work of Kepler,what can be a greater insult than that,perhaps I would object that you cannot set these historical figures as puppets to sell a theory for it is insincere at best and diminishes the whole study of natural phenomena at worst. |
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The transition from heliocentric to the galactic axis
"Oriel36" wrote in message m... "George Dishman" wrote in message ... "Oriel36" wrote in message ... "George Dishman" wrote in message ... Thank you Gerald, you have at least tried to address the issue this time. I feel we can make some progress now. The only progress you are making is into the mire,you give the rotation period of the Earth as 23 hours 56 min while your beloved experiments with Foucault's pendulum tell you it is 24 hours per 360 degrees off the Earth's axis. http://www.si.edu/resource/faq/nmah/pendulum.htm Oh dear, some web sites over-simplify for the general public to the point of error. .... A brief search shows there are others that round off to the nearest hour too. At least this page gets it right: Take it up with the Smithsonian, I have done so. I'll leave this for the moment. if any measurement taken along two points of latitude will indicate at the polar axis the Earth rotates through 360 degrees in 24 hours and this makes sense in terms of longitude,clocks,geometry and astronomy,you will have to live with it. "If" is the key there, they actually indicate the lesser time. http://www.griffithobs.org/exhibits/.../pendulum.html Much of the rest of your post is related to this so I'll have to come back to that but perhaps we can clarify one other aspect in the meantime. .... Are you denying that the Earth moves around the Sun? I can't honestly believe you would, yet either you do or you seem to ignore its consequences. You become emboldened because this material does'nt generate participation from others,the precision required to seperate axial rotation of 24 hours/360 degrees from the natural variation of axial rotation as the Earth rotates to face the Sun directly,the alignment is called 'Noon' does'nt leave much room for the simplistic 'Earth moves around the Sun'. So you _are_ denying Copernicus! The Earth moves round the sun once in a year of 365.25 days so it moves round by 0.9856 degrees per day _on_average_. Men designated the average or _mean_ time from noon to noon as 24h exactly, that is why our original universal standard was called Greenwich MEAN Time. ..Kepler's second law tells you that there is a variation in the distance covered by the Earth from one point in its elliptical orbit to another(if this elliptical orbit were broken into 360 degree segments)and still there is no 'time' involved just pure geometry. Kepler's second law is that the segments of the orbit include equal areas in equal _times_. Perhaps you may think I have not given your diagrams much thought but I did George but it amounts to astronomical forensics and that I dislike.The sidereal parameter is observer based, Your "forensics" are flawed, my diagrams are not "observer based". to someone else the diagrams in your website look reasonable but unfortunately you place the apical angle at the Sun ... I had assumed you were familiar with Kepler's Second Law since you have brought it up many times. Although the natural days vary, in a constant period (say 24h), the line from the Earth to the Sun will sweep out a constant area. That area is given by (a * r^2)/2 where a is the angle at the Sun and r is the radius. (The angle is in radians of course.) Have you ever actually used Kepler's Second Law? George |
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The transition from heliocentric to the galactic axis
"George Dishman" wrote in message ...
"Oriel36" wrote in message m... "George Dishman" wrote in message ... "Oriel36" wrote in message ... "George Dishman" wrote in message ... Thank you Gerald, you have at least tried to address the issue this time. I feel we can make some progress now. The only progress you are making is into the mire,you give the rotation period of the Earth as 23 hours 56 min while your beloved experiments with Foucault's pendulum tell you it is 24 hours per 360 degrees off the Earth's axis. http://www.si.edu/resource/faq/nmah/pendulum.htm Oh dear, some web sites over-simplify for the general public to the point of error. ... A brief search shows there are others that round off to the nearest hour too. At least this page gets it right: Take it up with the Smithsonian, I have done so. I'll leave this for the moment. Good,while your at it take it up with the royal observatory as well,with so much confusion surrounding the Equation of Time even these guys get it wrong (the Smithsonian is correct BTW). "There are two great standard clocks at the Observatory: the mean solar clock and the sidereal clock. The latter registers twenty-four hours in the precise time that the earth rotates on its axis. A 'day' in our ordinary use of the term is somewhat longer than this; it is the average time from one noon to the next, and as the earth whilst turning round on its axis is also travelling round the sun, it has to rather more than complete a rotation in order to bring the sun again on to the same meridian. A solar day is therefore some four minutes longer than an actual rotation of the earth, i.e. a sidereal day, as it is called, since such rotation brings a star back again to the same meridian." http://atschool.eduweb.co.uk/bookman.../ROG/ROG06.HTM The Equation of Time adds and substracts minutes depending on where the Earth is in its annual orbit,this is how navigators for their purposes and astronomers for seperate ones could determine an equal day of 24 hours through 360 degrees without having to justify an external observed motion of the Sun corresponding to 24 hrs/360 degrees.If you were to guage natural noon or the alignment of a longitude meridian with the Sun directly (noon) depending on the time of year it swings from 23 hrs 44 min to 24 hrs 14 min.All the navigators did was reverse the process,took observation of natural noon and subtracted or added the appropriate minutes for their clocks were determining rotation through 360 degrees in 24 hrs. if any measurement taken along two points of latitude will indicate at the polar axis the Earth rotates through 360 degrees in 24 hours and this makes sense in terms of longitude,clocks,geometry and astronomy,you will have to live with it. "If" is the key there, they actually indicate the lesser time. http://www.griffithobs.org/exhibits/.../pendulum.html Much of the rest of your post is related to this so I'll have to come back to that but perhaps we can clarify one other aspect in the meantime. ... Are you denying that the Earth moves around the Sun? I can't honestly believe you would, yet either you do or you seem to ignore its consequences. You become emboldened because this material does'nt generate participation from others,the precision required to seperate axial rotation of 24 hours/360 degrees from the natural variation of axial rotation as the Earth rotates to face the Sun directly,the alignment is called 'Noon' does'nt leave much room for the simplistic 'Earth moves around the Sun'. So you _are_ denying Copernicus! The Earth moves round the sun once in a year of 365.25 days so it moves round by 0.9856 degrees per day _on_average_. Men designated the average or _mean_ time from noon to noon as 24h exactly, that is why our original universal standard was called Greenwich MEAN Time. ..Kepler's second law tells you that there is a variation in the distance covered by the Earth from one point in its elliptical orbit to another(if this elliptical orbit were broken into 360 degree segments)and still there is no 'time' involved just pure geometry. Kepler's second law is that the segments of the orbit include equal areas in equal _times_. Perhaps you may think I have not given your diagrams much thought but I did George but it amounts to astronomical forensics and that I dislike.The sidereal parameter is observer based, Your "forensics" are flawed, my diagrams are not "observer based". to someone else the diagrams in your website look reasonable but unfortunately you place the apical angle at the Sun ... I had assumed you were familiar with Kepler's Second Law since you have brought it up many times. Although the natural days vary, in a constant period (say 24h), the line from the Earth to the Sun will sweep out a constant area. That area is given by (a * r^2)/2 where a is the angle at the Sun and r is the radius. (The angle is in radians of course.) Have you ever actually used Kepler's Second Law? George Yes,the Equation of Time reflects Kepler's second law with only a slight variation due to the effects of finite light distance,the alignment of a longitude meridian with the Sun (noon) to when it axially repeats it reflects the variation in distance covered by the Earth in its annual orbit.All you have to do is check the alignment with noon at your location,check it again as your location axially rotates to repeat the alignment (use a stopwatch if you have to) and use the appropriate Equation of Time correction for that day. http://www.jgiesen.de/SunView/index.htm George,why go to all this trouble when many people already know that clocks act as rulers of distance,they might not be familiar with the principles but it does involve adding and subtracting minutes on appropriate days.The sidereal parameter just adds 4 minutes and is altogether different than the Equation of Time due to its addition/subtraction of minutes. Did you ever imagine that people may wish to know what heritage they inherited with clocks,geometry and astronomy and ultimately everyone gains.I am just presenting what is already known in principle but the nuts and bolts of it may initially be difficult but it is satisfying,pity you won't put your intelligence towards making things better. |
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