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#21
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Jonathan Silverlight wrote:
Thinking about your other post about the mechanism, it occurs to me that once the orientation of the sun had settled down in the very early solar system there would be nothing to change it, because the Sun is a perfect sphere. You won't get tidal effects as you do on the Earth, with the Moon constantly tugging it. But Jupiter (and to some extent the other gas giants) must exert a certain influence on the inner planets; I would think that over time the orbital planes of the smaller bodies -- Mars especially -- would tend to be drawn into closer alignment with the 'dominant' planet's plane. -- Odysseus |
#22
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"Odysseus" wrote...
in message ... I don't think you can just add the inclinations; the planes of the planets' orbits -- WRT, say, the sun's equator -- don't all pass through a common line, i.e. their nodes don't all lie in the same direction. Moreover the nodes all precess at various rates (along with the perihelia IIANM), so their relations to each other are rather complicated and change over time. -- Odysseus Thanks, Odysseus... with further thought, it does appear that i jumped the gun on the adding of the inclinations. In a perfect stellar system with no collisions and such, there would be no anomalies like Mercury's orbit. The question makes me wonder if tidal-locking includes more than just locking one face of a body toward its primary? E.g., could the Moon have been inclined less than 5 degrees off the ecliptic in the past? or IOW, has tidal-locking caused the Moon's orbit of the Earth to move away from the ecliptic and toward Earth's equator? Is Mercury's orbit, while Mercury is gradually tidal-locking to the Sun, moving closer to the Sun's equator? Can't find much on this stuff, but it's fascinating! happy days and... starry starry nights! -- a Secret of the Universe... so please don't breathe a word of this-- the Moon above will smile perverse whene'er it sees two lovers kiss; (breathe not a single word of this!) Paine Ellsworth |
#23
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"Odysseus" wrote...
in message ... I don't think you can just add the inclinations; the planes of the planets' orbits -- WRT, say, the sun's equator -- don't all pass through a common line, i.e. their nodes don't all lie in the same direction. Moreover the nodes all precess at various rates (along with the perihelia IIANM), so their relations to each other are rather complicated and change over time. -- Odysseus Thanks, Odysseus... with further thought, it does appear that i jumped the gun on the adding of the inclinations. In a perfect stellar system with no collisions and such, there would be no anomalies like Mercury's orbit. The question makes me wonder if tidal-locking includes more than just locking one face of a body toward its primary? E.g., could the Moon have been inclined less than 5 degrees off the ecliptic in the past? or IOW, has tidal-locking caused the Moon's orbit of the Earth to move away from the ecliptic and toward Earth's equator? Is Mercury's orbit, while Mercury is gradually tidal-locking to the Sun, moving closer to the Sun's equator? Can't find much on this stuff, but it's fascinating! happy days and... starry starry nights! -- a Secret of the Universe... so please don't breathe a word of this-- the Moon above will smile perverse whene'er it sees two lovers kiss; (breathe not a single word of this!) Paine Ellsworth |
#24
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Hi Painius I would think the moon should orbit the Earth going over
its poles. My reason being the poles have a half of one percent greater gravitation force. Bert |
#25
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Hi Painius I would think the moon should orbit the Earth going over
its poles. My reason being the poles have a half of one percent greater gravitation force. Bert |
#26
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"G=EMC^2 Glazier" wrote in message
... Hi Painius I would think the moon should orbit the Earth going over its poles. My reason being the poles have a half of one percent greater gravitation force. Bert That's silly. You failed to think. The gravitational acceleration at the poles is greater for an object *at the surface* of the Earth due to a combination of the geometry of the Earth (the poles are closer, radially, to the center of mass than are points at the equator), and the centrifugal effect at non-polar regions due to the Earth's rotation. For an object in orbit at a given radius from the center of mass of the Earth, the greater force will be at the equator due to the mass of the equatorial bulge. |
#27
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"G=EMC^2 Glazier" wrote in message
... Hi Painius I would think the moon should orbit the Earth going over its poles. My reason being the poles have a half of one percent greater gravitation force. Bert That's silly. You failed to think. The gravitational acceleration at the poles is greater for an object *at the surface* of the Earth due to a combination of the geometry of the Earth (the poles are closer, radially, to the center of mass than are points at the equator), and the centrifugal effect at non-polar regions due to the Earth's rotation. For an object in orbit at a given radius from the center of mass of the Earth, the greater force will be at the equator due to the mass of the equatorial bulge. |
#28
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Greg Right you are. it is only good for surface gravity effect. I jumped
to soon. The fact is the moon is 13 miles further from the poles than the equator. Bert |
#29
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Greg Right you are. it is only good for surface gravity effect. I jumped
to soon. The fact is the moon is 13 miles further from the poles than the equator. Bert |
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