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#2
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How far to beam power up a Beanstalk?
Earl Colby Pottinger wrote:
(Henry Spencer) : In article , Fred B. McGalliard wrote: ...I can imagine a narrow beam radar providing power, through most weather conditions anyway... Unfortunately, the comparatively long wavelength of radar means you need a huge antenna system to form a narrow beam. It's very poorly suited to providing power to small vehicles. However the BeanStalk is fixed in position mostly. Can not the beam just be treated as a fixed beam also running beside the beanstalk? Does not that mean all you would only need a fixed antenna on the ground with no moving parts nor electronic steering. If possible that should be relativly cheap to make. The stalk will move a bit. The problem is that the ground antennas need to be damn huge. To get a target spot of 500m at 50000Km, you need a dish of several kilometers diameter. but the only way to get power out of a light pulse is to run a heat engine, or to run a solar cell, the efficiency of which is low enough that power dissipation is a big deal. Note that simple solar cells are 50%+ efficient when illuminated by laser light at a well-chosen wavelength. Their inefficiency in sunlight is because so much of the incoming energy is at wavelengths poorly matched to the cell characteristics. Another question, at 4000 miles up the gravity drag only a quarter that is on the surface, at 8000 miles only a ninth. Instead of trying to make a system that can hit a target for about 40,000 miles, why not switch to just sunlight after 8000 miles up, the lower power from the solar cells is countered by the lower power needed to over come gravity for each fix unit of lenght you climb. There are a few issues with eclipses early on. |
#3
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How far to beam power up a Beanstalk?
In article ,
Ian Stirling wrote: The stalk will move a bit. The problem is that the ground antennas need to be damn huge. To get a target spot of 500m at 50000Km, you need a dish of several kilometers diameter. How about a phased array, rather than one big dish? You should be able to adjust the beam a little to compensate for the deflection without physically moving the antennas. And how about only using ground power up to 5000-10000km, or whatever height solar becomes more useful at? There are a few issues with eclipses early on. Just let it stop? No reason it couldn't... -- Christopher James Huff http://home.earthlink.net/~cjameshuff/ POV-Ray TAG: http://tag.povray.org/ |
#4
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How far to beam power up a Beanstalk?
Christopher James Huff wrote:
In article , Ian Stirling wrote: The stalk will move a bit. The problem is that the ground antennas need to be damn huge. To get a target spot of 500m at 50000Km, you need a dish of several kilometers diameter. How about a phased array, rather than one big dish? Doesn't help much if any. The problem is that you need emitters closer together than the wavelength- otherwise the gaps act as a diffraction grating. So the array ends up with the same total area. You also have the problem that each emitter has to emit pretty accurately towards the destination anyway- otherwise you're wasting energy- you can't just spray the photons around in random directions and assume the phasing will magically kill off the ones that aren't heading towards the elevator car. Unless I'm missing some strange quantum effect that doesn't happen. This is a different problem to normal uses of phased array- in those cases you are trying to receive faint signals and you are using the phasing to attenuate a signal based on its direction. Here attenuation results in loss of expensive power. You should be able to adjust the beam a little to compensate for the deflection without physically moving the antennas. And how about only using ground power up to 5000-10000km, or whatever height solar becomes more useful at? Carrying two receivers might work, rectennas are likely to be quite lightweight, but the ground transmitter still needs to be about 5 orders of magnitude bigger than an optical system. There are a few issues with eclipses early on. Just let it stop? No reason it couldn't... Costs lots of money, because you are reducing the usage of the elevator proportionately. |
#5
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How far to beam power up a Beanstalk?
Ian Woollard wrote:
Christopher James Huff wrote: In article , Ian Stirling wrote: The stalk will move a bit. The problem is that the ground antennas need to be damn huge. To get a target spot of 500m at 50000Km, you need a dish of several kilometers diameter. snip You also have the problem that each emitter has to emit pretty accurately towards the destination anyway- otherwise you're wasting energy- you can't just spray the photons around in random directions and assume the phasing will magically kill off the ones that aren't heading towards the elevator car. Unless I'm missing some strange quantum effect that doesn't happen. Yep, you are. You can consider it properly in quantum terms, but it gets rapidly complex, but it works just as well considering it classically as waves. As I understand it, I'm sure someone will post if I've got it drastically wrong. Considering a transmitter. Imagine a 1Km parabolic dish, fed from one feedhorn 2Km away. The whole dish is evenly illuminated by the feedhorn, and creates a parallel beam. The key to understanding this is that each position on the dish acts as a little transmitter. If you replace the dish with an array of onmidirectional transmitters fed by signals with equivalient delay to the distance from the feedhorn, then there is no difference to the signal in the far field. (you can also add extra delays to reshape the dish so that it's "flat") (the spacing needs to be well under a wavelength to closely approach the performance of a dish) As the number of transmitters falls, if the overall power is kept constant, and the overall shape and size of the array does not change, then the size of the focal point does not change. However, as you decrease the number of transmitters, the amount of constructive interference that happens outside the beam increases, and this wastes energy. This constructive interference happens in all directions for omnidirectional antennas. If you replace the omnidirectional antennas with more directional ones, then all that happens is that the constructive interference that would have happened in the directions that the new tighter beams miss does not happen. There is probably some very complicated formula for determining the minimum number of transmitters to achieve a certain percentage of power into a given angle, but if I ever knew it I've forgotten it. |
#6
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How far to beam power up a Beanstalk?
In article ,
Ian Woollard wrote: Doesn't help much if any. The problem is that you need emitters closer together than the wavelength- otherwise the gaps act as a diffraction grating. Diffraction works with single photons. Yeah, it's weird. Anyway, the idea would be that you can make very small adjustments to the beam direction and focus without having to have extremely precise machinery, which is likely to be less reliable. This is a different problem to normal uses of phased array- in those cases you are trying to receive faint signals and you are using the phasing to attenuate a signal based on its direction. Here attenuation results in loss of expensive power. It'll be lossier than an ideal dish, but I'm assuming power won't be extremely expensive, and it may actually be better than any giant dish we could build for a reasonable cost. Carrying two receivers might work, rectennas are likely to be quite lightweight, but the ground transmitter still needs to be about 5 orders of magnitude bigger than an optical system. Or have a two-stage elevator...the lower stage carries little more than rectennas and a power link, the upper stage carries the payload and solar panels. When it reaches the point where solar is more useful, the lower stage unhooks itself and descends back to Earth. Perhaps 3 stage...with the middle stage being mainly fuel cells to carry the payload through the eclipse zone. There are a few issues with eclipses early on. Just let it stop? No reason it couldn't... Costs lots of money, because you are reducing the usage of the elevator proportionately. But it may be an acceptable compromise early on. -- Christopher James Huff http://home.earthlink.net/~cjameshuff/ POV-Ray TAG: http://tag.povray.org/ |
#7
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How far to beam power up a Beanstalk?
In article ,
Earl Colby Pottinger wrote: Another question, at 4000 miles up the gravity drag only a quarter that is on the surface, at 8000 miles only a ninth. Instead of trying to make a system that can hit a target for about 40,000 miles, why not switch to just sunlight after 8000 miles up, the lower power from the solar cells is countered by the lower power needed to over come gravity for each fix unit of lenght you climb. Whether that works out depends on the numbers. If the laser system is putting several times as much power into the array, it may not be worth switching, especially since it will probably add complexity (e.g. the need to track the Sun -- a laser-receiver array can probably be fixed). It's just not all that hard to put essentially all of a laser's output power into a few square meters of solar array at 40,000km. It's not worth accepting major compromises just to avoid it. -- "Think outside the box -- the box isn't our friend." | Henry Spencer -- George Herbert | |
#8
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How far to beam power up a Beanstalk?
In article ,
Christopher James Huff wrote: The problem is that the ground antennas need to be damn huge. To get a target spot of 500m at 50000Km, you need a dish of several kilometers diameter. How about a phased array, rather than one big dish? Oh, you'd probably use a phased array, just because it's easier to build than a dish that size. But it still has to be huge and densely packed with emitters. Despite the annoying issues with weather, lasers work a lot better for this application. -- "Think outside the box -- the box isn't our friend." | Henry Spencer -- George Herbert | |
#9
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How far to beam power up a Beanstalk?
(Henry Spencer) :
It's just not all that hard to put essentially all of a laser's output power into a few square meters of solar array at 40,000km. It's not worth accepting major compromises just to avoid it. How hard/expensive? Basicly how much diffirence in aiming 8000 miles vs 40000 miles is there in terms of costs. Earl Colby Pottinger -- I make public email sent to me! Hydrogen Peroxide Rockets, OpenBeos, SerialTransfer 3.0, RAMDISK, BoatBuilding, DIY TabletPC. What happened to the time? http://webhome.idirect.com/~earlcp |
#10
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How far to beam power up a Beanstalk?
In article ,
Earl Colby Pottinger wrote: It's just not all that hard to put essentially all of a laser's output power into a few square meters of solar array at 40,000km. It's not worth accepting major compromises just to avoid it. How hard/expensive? Basicly how much diffirence in aiming 8000 miles vs 40000 miles is there in terms of costs. The only real difference is bigger optics. Not *simpler* optics, mind you, because even for much shorter distances you'll need active optics to compensate for atmospheric turbulence. But even in quite large sizes, this is very nearly off-the-shelf hardware now; the Keck telescope has everything you'd need except for power-handling capability. The cost would be higher but not a lot higher. -- "Think outside the box -- the box isn't our friend." | Henry Spencer -- George Herbert | |
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