Again: Relativity for Thought Experiments

On Nov 17, 1:23 pm, PD wrote:
On 11/17/2011 2:41 PM, Aetherist wrote:

There is one itty bitty problem with all of this, it is
the traveling twin must undergoes physical acceleration and
the one at home does not. Now, make those speed changes
instanteous, i.e. Home twin no motion. Second twin
initially, no motion. One twin jumps instantly to 0.86c
goes for 10 year on his clock.

The acceleration that counts is the one where the traveling twin TURNS
AROUND to return to home. This asymmetry is unambiguous. The traveling
twin feels this acceleration and the home twin does not.

Quit bull****ting and preaching about garbage. Show some math. Your
bluff is once again called. shrug

You make a statement below that once the traveling twin starts turning
around, SR makes no statement or that you can't use SR to solve the
problem. That's not true. The entire problem is completely analyzable in
SR.

Bull****. SR definitively shows an unresolvable mutual time dilation
before or after this MAGICAL TURN-AROUND BULL****. shrug

However, what is no longer true is a statement that the home clock
should run slow relative to the traveling clock because of its relative
motion. That statement is a statement made by SR *specifically* in the
case where the moving clock is observed from a single inertial reference
frame, which is not the case here, precisely because of the asymmetry.

This is another bull****. The Lorentz transform does not remember
which one had turned around. The Lorentz transform has no memories,
and you must integrate the pertinent parameters to keep the sanity of
yourself. After a twin accelerates to a high speed and coasts over
there with no more acceleration, the mutual time dilation is building
up according to the Lorentz transform. So, answer this. Given the
Lorentz transform of two INERTIAL frames, how can you tell which one
had previously accelerated to that said speed? shrug

Frankly, I'm shocked, Paul, that this simple lesson from a basic puzzle
in relativity still eludes you.

Just be shocked at yourself, the imbecile, who was a college physics
professor and do not understand anything about physics and what
science is all about. shrug

there isn't any "mutual dilation."

just look at what tthe travelling twin will see
in front of him, a blueshifting;
what does that say about the relative rate of time,
or existence, at the turnaround destination?

the same blueshifting will appear of the twins' home star.
so, we've got redshifting of the stay-at-home
on the out-go, and blueshifting on the in-go.

in order to have a realistic integration,
ther can be no "instant acceleration," so stick
with the classical acceleration til midway followed
by deceleration to landing, and back again.

After a twin accelerates to a high speed and coasts over
there with no more acceleration, the mutual time dilation is building
up according to the Lorentz transform. *So, answer this. *Given the
Lorentz transform of two INERTIAL frames, how can you tell which one
had previously accelerated to that said speed?

1treePetrifiedForestLane write:

the relative rate of time

d(d) (t)?

there can be no "instant acceleration

Perhaps in the bang...

here is what I forgot:
the travelling twin's photoreception is constrained
by the by the cones of his eyes being slowed-down;
exactly ho, that might be, would need further investigation.

any volunteers?... Okay,
I'll go!