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Parametric down-conversion in the Solar system
# http://ssd.jpl.nasa.gov/?planet_phys_par
From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 # http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16 latitude) 25.38 days [1] 25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: Sun_Sidereal_rotation_period = 25.05 days 2. The characteristic period of the solar system as a whole: characteristic period = 49.05799539 days |
#2
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Parametric down-conversion in the Solar system
On Sat, 9 Jul 2011 12:45:16 -0700 (PDT), Aleksandr Timofeev wrote:
# http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 # http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16 latitude) 25.38 days [1] 25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: Sun_Sidereal_rotation_period = 25.05 days 2. The characteristic period of the solar system as a whole: characteristic period = 49.05799539 days Characteristic how? What happens every 49 days? |
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Parametric down-conversion in the Solar system
On Jul 10, 12:45*am, Wally W. wrote:
On Sat, 9 Jul 2011 12:45:16 -0700 (PDT), Aleksandr Timofeev wrote: #http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 #http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16 latitude) 25.38 days [1] *25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. *Sun Sidereal rotation period at equator: * * * * *Sun_Sidereal_rotation_period = 25.05 days 2. *The characteristic period of the solar system as a whole: * * * * *characteristic period = 49.05799539 days Characteristic how? What happens every 49 days? "Parametric resonance is the parametrical resonance phenomenon of mechanical excitation and oscillation at certain frequencies (and the associated harmonics). This effect is different from regular resonance because it exhibits the instability phenomenon. Parametric resonance occurs in a mechanical system when a system is parametrically excited and oscillates at one of its resonant frequencies.Parametric resonance takes place when the external excitation frequency equals to twice the natural frequency of the system. " http://en.wikipedia.org/wiki/Paramet...ric_excitation Sun_Sidereal_rotation_period of the convection zone = 25.05 days The characteristic period of the solar system as a whole: = 49.05799539 days "Parametric resonance takes place when the external excitation frequency equals to twice the natural frequency of the system. " |
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Parametric down-conversion in the Solar system
Aleksandr Timofeev wrote:
# http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 # http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16 latitude) 25.38 days [1] 25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: Sun_Sidereal_rotation_period = 25.05 days 2. The characteristic period of the solar system as a whole: characteristic period = 49.05799539 days As Wally asked, characteristic how? And shouldn't you weight these frequencies by mass? If not, why not? Is the orbital frequency of Earth as important (in some way not yet defined) as the orbital frequency of Jupiter? If not, why not? And why are you not taking the rotation periods of each planet into consideration somehow, if you are including the rotation period of the Sun? Finally, the rotation period of the Sun is stated for the equator, but it varies by latitude. Why is zero latitude the only value considered? Surely some sort of weighted average would be more characteristic? -- Mike Dworetsky (Remove pants sp*mbl*ck to reply) |
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Parametric down-conversion in the Solar system
On Jul 10, 12:24*pm, "Mike Dworetsky"
wrote: Aleksandr Timofeev wrote: #http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 #http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16° latitude) 25.38 days [1] *25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: * * * * * Sun_Sidereal_rotation_period = 25.05 days 2. The characteristic period of the solar system as a whole: * * * * * characteristic period = 49.05799539 days As Wally asked, characteristic how? And shouldn't you weight these frequencies by mass? *If not, why not? Is the orbital frequency of Earth as important (in some way not yet defined) as the orbital frequency of Jupiter? If not, why not? And why are you not taking the rotation periods of each planet into consideration somehow, if you are including the rotation period of the Sun? " A parametric oscillator is a harmonic oscillator whose parameters oscillate in time. For example, a well known parametric oscillator is a child on a swing where periodically changing the child's center of gravity causes the swing to oscillate.[1][2] The varying of the parameters drives the system. Examples of parameters that may be varied are its resonance frequency ω and damping β. Parametric oscillators are used in many applications. The classical varactor parametric oscillator will oscillate when the diode's capacitance is varied periodically. The circuit that varies the diode's capacitance is called the "pump" or "driver". In microwave electronics, waveguide/YAG based parametric oscillators operate in the same fashion. The designer varies a parameter periodically in order to induce oscillations. Parametric oscillators have been developed as low-noise amplifiers, especially in the radio and microwave frequency range. Thermal noise is minimal, since a reactance (not a resistance) is varied. Another common use is frequency conversion, e.g., conversion from audio to radio frequencies. For example, the Optical parametric oscillator converts an input laser wave into two output waves of lower frequency (ωs,ωi). Parametric resonance occurs in a mechanical system when a system is parametrically excited and oscillates at one of its resonant frequencies. Parametric excitation differs from forcing since the action appears as a time varying modification on a system parameter. This effect is different from regular resonance because it exhibits the instability phenomenon." http://en.wikipedia.org/wiki/Parametric_oscillator "Parametric resonance is the parametrical resonance phenomenon of mechanical excitation and oscillation at certain frequencies (and the associated harmonics). This effect is different from regular resonance because it exhibits the instability phenomenon. Parametric resonance occurs in a mechanical system when a system is parametrically excited and oscillates at one of its resonant frequencies.Parametric resonance takes place when the external excitation frequency equals to twice the natural frequency of the system. Parametric excitation differs from forcing since the action appears as a time varying modification on a system parameter. The classical example of parametric resonance is that of the vertically forced pendulum. For small amplitudes and by linearising, the stability of the periodic solution is given by : \ddot{u} + (a + B \cos t)u =0 \ where u is some perturbation from the periodic solution. Here the B\ \cos(t) term acts as an ‘energy’ source and is said to parametrically excite the system. The Mathieu equation describes many other physical systems to a sinusoidal parametric excitation such as an LC Circuit where the capacitor plates move sinusoidally." Finally, the rotation period of the Sun is stated for the equator, but it varies by latitude. *Why is zero latitude the only value considered? temporal gravitational variations at the bottom of the convection zone... Tidal forces of the detailed modern picture of the internal rotation of the Sun... http://solarphysics.livingreviews.or...009-1Color.pdf Solar Interior Rotation and its Variation Rachel Howe National Solar Observatory, 950 N. Cherry Ave., Tucson AZ 85719, U.S.A. http://www.noao.edu/staff/rhowe/ http://www.noao.edu/staff/rhowe/present.htm Accepted on 10 February 2009 Published on 23 February 2009 Abstract «This article surveys the development of observational understanding of the interior rotation of the Sun and its temporal variation over approximately forty years, starting with the 1960s attempts to determine the solar core rotation from oblateness and proceeding through the development of helioseismology to the detailed modern picture of the internal rotation deduced from continuous helioseismic observations during solar cycle 23. After introducing some basic helioseismic concepts, it covers, in turn, the rotation of the core and radiative interior, the “tachocline” shear layer at the base of the convection zone, the differential rotation in the convection zone, the near- surface shear, the pattern of migrating zonal flows known as the torsional oscillation, and the possible temporal variations at the bottom of the convection zone. For each area, the article also briefly explores the relationship between observations and models.» *Surely some sort of weighted average would be more characteristic? -- Mike Dworetsky (Remove pants sp*mbl*ck to reply) |
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Parametric down-conversion in the Solar system
On Sun, 10 Jul 2011 09:24:46 +0100, Mike Dworetsky wrote:
Aleksandr Timofeev wrote: # http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 # http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16 latitude) 25.38 days [1] 25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: Sun_Sidereal_rotation_period = 25.05 days 2. The characteristic period of the solar system as a whole: characteristic period = 49.05799539 days As Wally asked, characteristic how? And shouldn't you weight these frequencies by mass? If not, why not? Is the orbital frequency of Earth as important (in some way not yet defined) as the orbital frequency of Jupiter? If not, why not? And why are you not taking the rotation periods of each planet into consideration somehow, if you are including the rotation period of the Sun? Finally, the rotation period of the Sun is stated for the equator, but it varies by latitude. Why is zero latitude the only value considered? Surely some sort of weighted average would be more characteristic? Also, does not every object in the Solar System contribute to the calculation? If so, it would seem that the calculation can't be done. We certainly haven't cataloged every speck speck orbiting in the asteroid belt. On what basis can we exclude them from the sum of frequencies calculated above? |
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Parametric down-conversion in the Solar system
On 10 июл, 17:58, Wally W. wrote:
On Sun, 10 Jul 2011 09:24:46 +0100, Mike Dworetsky wrote: Aleksandr Timofeev wrote: #http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 #http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16° latitude) 25.38 days [1] *25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: * * * * * Sun_Sidereal_rotation_period = 25..05 days 2. The characteristic period of the solar system as a whole: * * * * * characteristic period = 49.05799539 days As Wally asked, characteristic how? And shouldn't you weight these frequencies by mass? *If not, why not? Is the orbital frequency of Earth as important (in some way not yet defined) as the orbital frequency of Jupiter? If not, why not? And why are you not taking the rotation periods of each planet into consideration somehow, if you are including the rotation period of the Sun? Finally, the rotation period of the Sun is stated for the equator, but it varies by latitude. *Why is zero latitude the only value considered? *Surely some sort of weighted average would be more characteristic? Also, does not every object in the Solar System contribute to the calculation? If so, it would seem that the calculation can't be done. We certainly haven't cataloged every speck speck orbiting in the asteroid belt. On what basis can we exclude them from the sum of frequencies calculated above? The solar system is nonlinear system of interacting bodies. From the power point of view, in this system the main bodies are the Sun and planets. Other bodies can be neglected, since their total weight is insignificant. |
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Parametric down-conversion in the Solar system
The solar system is nonlinear system of interacting *bodies. From the power point of view, in this system the main bodies are the Sun and planets. Other bodies can be neglected, since their total weight is insignificant. Please, take a long hard look at: http://www.youtube.com/watch?v=yVkdfJ9PkRQ |
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Parametric down-conversion in the Solar system
Finally, the rotation period of the Sun is stated for the equator, but it
varies by latitude. *Why is zero latitude the only value considered? *Surely some sort of weighted average would be more characteristic? Orbits of planets lie close to an ecliptic plane. The ecliptic plane passes through the centre of a plane of equator of the Sun. http://en.wikipedia.org/wiki/Ecliptic_plane 'The plane of the ecliptic (also known as the ecliptic plane) is the plane of the Earth's orbit around the Sun.[1] It is the primary reference plane when describing the position of bodies in the Solar System,[2] with celestial latitude being measured relative to the ecliptic plane.[3] In the course of a year, the Sun's apparent path through the sky lies in this plane. The planetary bodies of our Solar System all tend to lie near this plane, since they were formed from the Sun's spinning, flattened, protoplanetary disk.[1]' |
#10
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Parametric down-conversion in the Solar system
On Jul 10, 10:24*am, "Mike Dworetsky"
wrote: Aleksandr Timofeev wrote: #http://ssd.jpl.nasa.gov/?planet_phys_par From the table of physical parametres of planets we choose column Sidereal Orbit Period. Then (frequency in terms of [1 / (sidereal year)]): f_Mercury: = 1/0.2408467; f_Venus: = 1/0.61519726; f_Earth: = 1/1.0000174; f_Mars: = 1/1.8808476; f_Jupiter: = 1/11.862615; f_Saturn: = 1/29.447498; f_Uranus: = 1/84.016846; f_Neptune: = 1/164.79132; Now we find value of the sum of frequencies for all planets: f_Sys: = f_Mercury+f_Venus+f_Earth+f_Mars+f_Jupiter+f_Satur n+f_Uranus+f_Neptune; f_Sys: = 7.445399207 #http://ssd.jpl.nasa.gov/?constants From Astrodynamic Constants we find duration of the sidereal year in days sidereal_year: = 365.25636; [d] sidereal_year/f_Sys; sidereal_year/f_Sys = 49.05799539 days http://en.wikipedia.org/wiki/Sun Sun Sidereal rotation period: (at equator) 25.05 days [1] (at 16 latitude) 25.38 days [1] *25d 9h 7min 12s [8] (at poles) 34.4 days [1] So we have parametric down-conversion in the Solar system: 1. Sun Sidereal rotation period at equator: * * * * * Sun_Sidereal_rotation_period = 25.05 days 2. The characteristic period of the solar system as a whole: * * * * * characteristic period = 49.05799539 days As Wally asked, characteristic how? And shouldn't you weight these frequencies by mass? *If not, why not? Is the orbital frequency of Earth as important (in some way not yet defined) as the orbital frequency of Jupiter? If not, why not? And why are you not taking the rotation periods of each planet into consideration somehow, if you are including the rotation period of the Sun? Finally, the rotation period of the Sun is stated for the equator, but it varies by latitude. *Why is zero latitude the only value considered? *Surely some sort of weighted average would be more characteristic? -- Mike Dworetsky (Remove pants sp*mbl*ck to reply) All celestial objects with rotating fluid compositions,including the Earth display differential rotation but empiricists have organized the Earth's fluid viscosity to suit a stationary Earth mechanism of 'convection cells' and completely ignored not only the spherical deviation of the planet across equatorial and polar diameters but actual visual affirmation of the actual viscosity poring out of ever crack,volcano and rupture at the Earth's crustal boundaries or isolated as volcanoes - http://www.youtube.com/watch?v=Xaa8H98Mpn0 The equatorial Earth has a circumference of 24901 miles with an equatorial speed of 1037.5/15 degrees per hour and turns a full circumference in 24 hours,the interesting material is the distinction between the even rotational gradient of the surface crust between equatorial and polar latitudes and the uneven rotational gradient (differential rotation) of the fluid interior. Dead eyes would never get it however this proposal which uses differential rotation as a common mechanism for planetary spherical deviation and crustal evolution/motion will eventually be the norm as it represents the highest probability for more productive studies where planetary dynamics and terrestrial effects mesh.Most commentators here will only represent an unfortunate condition that afflicted humanity for a few centuries,you might even be know the the 'right ascensionist' cult. |
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