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m*a=m*g_constant & F_constant @ r.
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May 6th 06, 01:51 PM posted to sci.space.policy,sci.philosophy.tech,sci.astro,rec.org.mensa
brian a m stuckless
external usenet poster
Posts: n/a
m*a=m*g_constant & F_constant @ r.
$$ [CORRECTED RePOST ..see BOTTOM section.]
$$ Mike wrote:
wrote:
Gravitational mass, on the other hand,
is the mass that appears in Newton's gravitational force law,
F=GMm/r^2.
$$ F=G*M*m/(n-1)*r^2 ..GUESS standard.
-=-
Steve [the Buffoon who ought have BETTER sense] Carlip
$$ Steve [..and SMURF mass measures the SMURFness] Carlip
-=-
| actually accelerations of those kinds are locally
| indistinguishable according to GR, not forces,
| because there is no such thing as a
| gravitational force in GR.
-=-
| F = m(i)a = GMm(g)/r^2,
$$ F = m_i*a = G*M*m_g/(n-1)*r^2 = m_g*g.
$$ m_i = inertial mass, m_g = gravitational mass.
| Mike
$$ There's NO inertial (iNTRiNSiC REST) mass is Newton's equation.
$$ M*v = m*v_g.
$$ "Gravitational" mass is M, where m is Newton's GiVEN test-mass.
$$ NOTE edited BOTTOM section (added new EQUATiON & [BOTTOM line]):
$$
$$ GEDANKEN acceleration EXPERiMENTAL data ANALYSiS:
$$ Apparatus..
$$ F_constant G*M v^2
$$ Acceleration, if a = -- - -- -- = g_constant = -- -- -- -- = ---
$$ m (n - 1)*r^2 r .
$$ Conclusion..
$$ With a LOCAL CONSTANT FORCE, F, (where m*a = m*g), g is CONSTANT.
$$ [This means, if the acceleration a varies, TEST mass, m, varies.]
$$ This is PROOF LATERAL acceleration a VARiEs, where g is CONSTANT.
$$ [This means, if given TEST mass m varies, mass M ..OR n, varies.]
$$ This is PROOF GRAViTATiONAL acceleration g iNDEPENDENT of mass m.
$$ [This means, if given TEST mass m varies, velocity v OR r, vary.]
What are the two kinds of Masses ?? [SORRY previous post VAGUE].
m*a=m*g_constant & F_constant @ r. End of CORRECTED RePOST.
brian a m stuckless
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